5.2 SI Units of Measurement in Electrotechnology

Key Takeaways

  • The International System of Units (SI) establishes four primary base units used in electrotechnology: meter (m) for length, kilogram (kg) for mass, second (s) for time, and ampere (A) for electric current.

  • Derived electrotechnical units are formed from combinations of base units: the Volt (1 V=1 J/C1\text{ V} = 1\text{ J/C}), the Ohm (1 Ω=1 V/A1\ \Omega = 1\text{ V/A}), the Coulomb (1 C=1 A⋅s1\text{ C} = 1\text{ A}\cdot\text{s}), and the Watt (1 W=1 J/s1\text{ W} = 1\text{ J/s}).

  • Magnetic and alternating current parameters have dedicated derived units: magnetic flux in Webers (Wb), magnetic flux density in Teslas (1 T=1 Wb/m21\text{ T} = 1\text{ Wb/m}^2), inductance in Henrys (H), capacitance in Farads (F), and frequency in Hertz (1 Hz=1 s−11\text{ Hz} = 1\text{ s}^{-1}).

  • SI prefixes scale base and derived units in powers of ten; engineering calculations primarily utilize multiples of three: Mega (10610^6), Kilo (10310^3), Milli (10−310^{-3}), Micro (10−610^{-6}), Nano (10−910^{-9}), and Pico (10−1210^{-12}).

  • Converting conductor cross-sectional area from square millimeters (mm2\text{mm}^2) to square meters (m2\text{m}^2) requires multiplying by 10−610^{-6} because area scales with the square of the linear conversion factor (1 mm=10−3 m  ⟹  1 mm2=10−6 m21\text{ mm} = 10^{-3}\text{ m} \implies 1\text{ mm}^2 = 10^{-6}\text{ m}^2).

Last updated: October 2026

5.2 SI Units of Measurement in Electrotechnology

In electrotechnical engineering, accurate communication and calculation depend on the International System of Units (Système International d'Unités, abbreviated SI). Standardized units ensure that electrical quantities measured on site—such as loop impedance, insulation resistance, voltage drop, and luminous flux—can be directly verified against the criteria published in BS 7671 (IET Wiring Regulations).


SI Base Units in Electrotechnology

The SI system is constructed upon seven fundamental base units, four of which form the bedrock of electrical and mechanical calculations:

  1. Length — Meter (m\text{m}): The fundamental unit of distance, cable runs, and physical dimensions.
  2. Mass — Kilogram (kg\text{kg}): The fundamental measure of the quantity of matter in an object, used to calculate gravitational weight and mechanical force.
  3. Time — Second (s\text{s}): The fundamental unit of time duration, used in defining frequency, current rate, velocity, and power.
  4. Electric Current — Ampere (A\text{A}): The fundamental electrical base unit, formally defined in terms of elementary charge flow (1 A≈6.242×10181\text{ A} \approx 6.242 \times 10^{18} electrons passing a cross-section per second).

Note

In the SI system, the Ampere (A) is the base unit, not the Coulomb (C). The Coulomb is a derived unit defined as the quantity of electric charge transported by a constant current of one ampere in one second (1 C=1 A⋅s1\text{ C} = 1\text{ A}\cdot\text{s}).


Derived Electrotechnical Units

All electrical and magnetic units other than the Ampere are derived units, constructed by combining the base units of mass, length, time, and electric current.

QuantitySymbolUnit NameUnit Abbr.Base SI / Physical DefinitionElectrical Relationship
Potential Difference / EMFVV or EEVoltV\text{V}1 V=1 J/C=1 W/A1\text{ V} = 1\text{ J/C} = 1\text{ W/A}Energy transferred per unit electric charge
Electrical ResistanceRROhmΩ\Omega1 Ω=1 V/A1\ \Omega = 1\text{ V/A}Opposition to the flow of electric current
Electric ChargeQQCoulombC\text{C}1 C=1 A⋅s1\text{ C} = 1\text{ A}\cdot\text{s}Charge transferred by 1 A1\text{ A} in 1 s1\text{ s} (Q=I×tQ = I \times t)
Electrical PowerPPWattW\text{W}1 W=1 J/s=1 V⋅A1\text{ W} = 1\text{ J/s} = 1\text{ V}\cdot\text{A}Rate of doing work or transferring electrical energy
Energy / WorkWW or EEJouleJ\text{J}1 J=1 N⋅m=1 W⋅s1\text{ J} = 1\text{ N}\cdot\text{m} = 1\text{ W}\cdot\text{s}Work done when a force of 1 N1\text{ N} moves through 1 m1\text{ m}
FrequencyffHertzHz\text{Hz}1 Hz=1 cycle/s=1 s−11\text{ Hz} = 1\text{ cycle/s} = 1\text{ s}^{-1}Number of complete alternating cycles per second
Magnetic FluxΦ\PhiWeberWb\text{Wb}1 Wb=1 V⋅s1\text{ Wb} = 1\text{ V}\cdot\text{s}Total quantity of magnetic field lines produced
Magnetic Flux DensityBBTeslaT\text{T}1 T=1 Wb/m21\text{ T} = 1\text{ Wb/m}^2Magnetic flux passing per unit perpendicular area
CapacitanceCCFaradF\text{F}1 F=1 C/V1\text{ F} = 1\text{ C/V}Charge stored per unit potential difference
InductanceLLHenryH\text{H}1 H=1 V⋅s/A1\text{ H} = 1\text{ V}\cdot\text{s/A}Induced EMF of 1 V1\text{ V} when current changes at 1 A/s1\text{ A/s}

In-Depth Unit Analysis

  • The Volt (V\text{V}): A potential difference of one volt exists between two points if one joule of energy is released or absorbed in moving one coulomb of charge between those points (V=WQV = \frac{W}{Q}). It also represents the potential difference that drives one ampere of current through a resistance of one ohm (V=I×RV = I \times R).
  • The Ohm (Ω\Omega): Named after Georg Simon Ohm, one ohm is the electrical resistance between two points of a conductor when a constant potential difference of one volt applied between these points produces a current of one ampere (R=VIR = \frac{V}{I}).
  • The Watt (W\text{W}): Named after James Watt, one watt represents one joule of energy transferred per second (P=WtP = \frac{W}{t}). In direct current circuits, one watt is produced when a current of one ampere flows under a pressure of one volt (P=V×IP = V \times I).
  • The Joule (J\text{J}) and the Kilowatt-Hour (kWh\text{kWh}): While the Joule is the coherent SI unit of energy, commercial electricity metering uses the kilowatt-hour (kWh\text{kWh}), commonly called a "Unit" of electricity: 1 kWh=1,000 W×3,600 s=3,600,000 J=3.6×106 J=3.6 MJ1\text{ kWh} = 1,000\text{ W} \times 3,600\text{ s} = 3,600,000\text{ J} = 3.6 \times 10^6\text{ J} = 3.6\text{ MJ}

SI Prefixes and Scaling Multipliers

Metric prefixes are attached to base and derived units to represent very large or very small quantities. In electrotechnology, prefixes generally scale in steps of 10310^3 (thousands):

Prefix NameSymbolMathematical FactorPower of 10Electrotechnical Practical Example
GigaG\text{G}1,000,000,0001,000,000,00010910^9National grid generation capacity: 2.5 GW2.5\text{ GW}
MegaM\text{M}1,000,0001,000,00010610^6Insulation resistance test minimum: ≥1.0 MΩ\ge 1.0\text{ M}\Omega
Kilok\text{k}1,0001,00010310^3Substation line voltage: 11 kV11\text{ kV}; Fault level: 6 kA6\text{ kA}
(Unit)—1110010^0Supply voltage: 230 V230\text{ V}; Current: 16 A16\text{ A}
Millim\text{m}0.0010.00110−310^{-3}RCD trip sensitivity: 30 mA30\text{ mA}; Millivolts: mV/A/mmV/A/m
Microμ\mu0.0000010.00000110−610^{-6}Power factor correction capacitor: 47 μF47\ \mu\text{F}
Nanon\text{n}0.0000000010.00000000110−910^{-9}High-frequency cable capacitance: 120 nF/km120\text{ nF/km}
Picop\text{p}0.0000000000010.00000000000110−1210^{-12}Radio frequency filter capacitor: 220 pF220\text{ pF}

Tip

When converting from a smaller prefix to a larger prefix (e.g., mA\text{mA} to A\text{A}), divide by the factor (or multiply by 10−310^{-3}). When converting from a larger prefix to a smaller prefix (e.g., kΩ\text{k}\Omega to Ω\Omega), multiply by the factor (or multiply by 10310^3).


Step-by-Step Unit Conversion Worked Examples

Example 1: Current and Resistance Conversions

  • Convert a leakage current of 750 μA750\ \mu\text{A} to Amperes (A\text{A}): 750 μA=750×10−6 A=0.00075 A750\ \mu\text{A} = 750 \times 10^{-6}\text{ A} = 0.00075\text{ A}
  • Convert an insulation resistance reading of 200 MΩ200\text{ M}\Omega to Ohms (Ω\Omega): 200 MΩ=200×106 Ω=200,000,000 Ω200\text{ M}\Omega = 200 \times 10^6\ \Omega = 200,000,000\ \Omega
  • Convert a prospective fault current of 4.5 kA4.5\text{ kA} to Amperes (A\text{A}): 4.5 kA=4.5×103 A=4,500 A4.5\text{ kA} = 4.5 \times 10^3\text{ A} = 4,500\text{ A}

Example 2: Cable Cross-Sectional Area (mm2\text{mm}^2 to m2\text{m}^2)

This conversion is a critical step in conductor resistance calculations using R=ρLAR = \frac{\rho L}{A}. Resistivity ρ\rho is given in ohm-meters (Ω⋅m\Omega\cdot\text{m}), and length LL is in meters (m\text{m}). Consequently, the cross-sectional area AA must be expressed in square meters (m2\text{m}^2), not square millimeters (mm2\text{mm}^2).

Because 1 m=1,000 mm=103 mm1\text{ m} = 1,000\text{ mm} = 10^3\text{ mm}: 1 m2=1,000 mm×1,000 mm=1,000,000 mm2=106 mm21\text{ m}^2 = 1,000\text{ mm} \times 1,000\text{ mm} = 1,000,000\text{ mm}^2 = 10^6\text{ mm}^2 Therefore, to convert from mm2\text{mm}^2 to m2\text{m}^2, you must divide by 10610^6 (multiply by 10−610^{-6}): 1 mm2=1×10−6 m21\text{ mm}^2 = 1 \times 10^{-6}\text{ m}^2

  • For a 2.5 mm22.5\text{ mm}^2 conductor: A=2.5 mm2=2.5×10−6 m2A = 2.5\text{ mm}^2 = 2.5 \times 10^{-6}\text{ m}^2
  • For a 16 mm216\text{ mm}^2 sub-main conductor: A=16 mm2=16×10−6 m2=1.6×10−5 m2A = 16\text{ mm}^2 = 16 \times 10^{-6}\text{ m}^2 = 1.6 \times 10^{-5}\text{ m}^2

Warning

Never multiply mm2\text{mm}^2 by 10−310^{-3} to convert to m2\text{m}^2. A factor of 10−310^{-3} converts linear millimeters to linear meters (1 mm=10−3 m1\text{ mm} = 10^{-3}\text{ m}). Area requires squaring the linear factor: (10−3)2=10−6(10^{-3})^2 = 10^{-6}. Using 10−310^{-3} will cause calculated cable resistance to be incorrect by a factor of 1,0001,000.

Example 3: Period to Frequency Conversion

An alternating waveform displays a single cycle periodic time of T=20 msT = 20\text{ ms}. Calculate the supply frequency (ff):

  1. Convert periodic time to seconds: 20 ms=20×10−3 s=0.02 s20\text{ ms} = 20 \times 10^{-3}\text{ s} = 0.02\text{ s}.
  2. Use the frequency formula f=1Tf = \frac{1}{T}: f=10.02 s=50 Hzf = \frac{1}{0.02\text{ s}} = 50\text{ Hz} This confirms the standard UK mains electrical supply frequency.

Other SI Quantities in Unit 202

The Unit 202 range also covers the SI units for everyday physical quantities and for the a.c. quantities you meet later:

QuantitySI unitSymbolNotes
Areasquare metrem²Cable cross-sections are quoted in mm² (1 mm2=10−6 m21\text{ mm}^2 = 10^{-6}\text{ m}^2)
Volumecubic metrem³1 m3=1,0001\text{ m}^3 = 1{,}000 litres, so a 150-litre cylinder holds 0.15 m30.15\text{ m}^3
Densitykilogram per cubic metrekg/m³Mass divided by volume; copper is about 8,900 kg/m³ and aluminium about 2,700 kg/m³
Velocitymetre per secondm/sDistance divided by time in a stated direction
TemperaturekelvinKPractical work uses degrees Celsius; a temperature difference of 1 K equals 1°C, and 0°C is about 273 K
ImpedanceohmΩThe total opposition to alternating current (ZZ)
Inductive reactanceohmΩXL=2πfLX_L = 2\pi f L, where inductance LL is in henrys (H)
Capacitive reactanceohmΩXC=12πfCX_C = \frac{1}{2\pi f C}, where capacitance CC is in farads (F)
Power factorno unitnoneA ratio between 0 and 1 (cos⁡ϕ=P÷S\cos\phi = P \div S)

Instruments for Measuring Electrical Quantities

Unit 202 LO2 also asks you to identify the right instrument for each electrical quantity:

QuantityInstrumentHow it is connected
CurrentAmmeter (or clamp meter)In series with the load so that all the current passes through it; an ammeter has a very low resistance. A clamp meter measures current without breaking the circuit by clamping around a single conductor.
VoltageVoltmeterIn parallel (across) the component or supply; a voltmeter has a very high resistance so it draws almost no current.
ResistanceOhmmeter (or a multimeter's resistance range; a low-resistance ohmmeter for continuity tests)Across the component with the circuit isolated and dead, because the meter drives its own test current from a battery.
PowerWattmeterCurrent coil in series and voltage coil in parallel with the load.
EnergyEnergy (kWh) meterInstalled at the supply intake, recording the kilowatt-hours used.

A multimeter combines several of these functions, but remember the rule from Section 3.1: never use a multimeter to prove an installation dead.

Tip

Series measures current (ammeter); parallel measures voltage (voltmeter). Connecting an ammeter in parallel across a supply creates a near short circuit and can blow the meter's fuse or damage it.


Measurement Tolerances and Instrument Scales

When using test equipment (such as multifunction installation testers complying with BS EN 61557), readings must be interpreted with an understanding of measurement resolution and scale tolerance.

  • Analogue Meter Scales: Feature a physical pointer moving over a graduated arc. Reading analogue scales requires avoiding parallax error (viewing the needle from an angle). Quality analogue instruments incorporate an anti-parallax mirrored scale strip behind the needle; the user aligns their line of sight so the needle directly obscures its own reflection.
  • Digital Meter Resolution: Displays numerical values on an LCD/OLED screen. A meter reading 0.05 Ω0.05\ \Omega on a 0.01 Ω0.01\ \Omega resolution scale has an inherent quantization uncertainty of ±1\pm 1 least significant digit.
  • Instrument Accuracy Tolerance: Typically expressed as ±(% of reading+number of digits)\pm (\%\text{ of reading} + \text{number of digits}). For instance, an instrument rated at ±(2%+3 digits)\pm (2\% + 3\text{ digits}) displaying 230.0 V230.0\text{ V} has an allowable variance of (230×0.02)+0.3=4.6+0.3=±4.9 V(230 \times 0.02) + 0.3 = 4.6 + 0.3 = \pm 4.9\text{ V}, meaning the actual voltage lies between 225.1 V225.1\text{ V} and 234.9 V234.9\text{ V}.
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Derivation Hierarchy of Electrotechnical Units from SI Base Units
Test Your Knowledge

Which of the following correctly defines the derived electrotechnical unit 'Volt' in terms of fundamental mechanical and electrical work?

A

One Watt of power expended over a distance of one meter

B

One Ampere of current flowing through a force of one Newton

C

One Coulomb of charge stored across a magnetic flux of one Weber

D

One Joule of electrical energy transferred per Coulomb of charge

Test Your Knowledge

In a calculation to determine conductor resistance using R = (ρ × L) / A, the cross-sectional area of a cable is specified as 4.0 mm². What numerical value must be entered into the equation for area (A) in square meters?

A

4.0 × 10⁻³ m²

B

4.0 × 10⁻⁶ m²

C

4.0 × 10⁻⁹ m²

D

4.0 × 10⁻² m²

Test Your Knowledge

What is the SI unit of magnetic flux density, and what is its equivalent physical definition?

A

Weber (Wb), defined as one Volt-second per meter

B

Henry (H), defined as one Ohm per second

C

Tesla (T), defined as one Weber per square meter (Wb/m²)

D

Coulomb (C), defined as one Ampere per second

Test Your Knowledge

How should an ammeter be connected to measure the current taken by an immersion heater?

A

In parallel across the heater terminals, so it sees the full supply voltage

B

In series with the heater, so the load current flows through the meter

C

Between the line conductor and earth

D

Across the supply with the heater disconnected

Sections you finish are checked off in the contents.