6.6 Farm Load Calculations (2026 NEC 120.102 & 120.103)
Key Takeaways
Table 120.102 takes loads expected to operate simultaneously at 100%, but not less than 125% of the largest motor's full-load current and not less than the first 60 A of load.
After the 100% portion, Table 120.102 takes the next 60 A of other loads at 50% and the remainder at 25%.
Table 120.103 combines individual farm building loads on a common service at 100% for the largest, 75% for the second largest, 65% for the third largest, and 50% for all remaining loads.
The farm dwelling load is calculated by the standard or optional dwelling method and added to the Table 120.103 total.
The optional method may not be used for a farm dwelling with electric heat on a common service with an electric grain-drying system.
Why farm calculations matter in Minnesota
Minnesota has thousands of farms with barns, machine sheds, grain bins, and dryers fed from one utility service. Farm load calculations are in Part V of Article 120 (formerly 220.100 to 220.103). They apply to farm buildings and loads other than the dwelling, and they recognize that farm loads in different buildings rarely peak at the same time.
Step 1: each farm building or load (120.102)
120.102(A) Dwelling unit: the farm dwelling is calculated by the standard method or the optional method in 120.82. If the dwelling has electric heat and the farm has electric grain-drying systems, the optional method may not be used for the dwelling when the dwelling and farm loads share a common service.
120.102(B) Other than dwelling unit: where a feeder or service supplies a farm building or other load with two or more separate branch circuits, the load for feeders, service conductors, and service equipment is calculated with demand factors not less than those in Table 120.102:
| Ampere load at 240 V maximum | Demand factor |
|---|---|
| Loads expected to operate simultaneously, but not less than 125% of the full-load current of the largest motor and not less than the first 60 A of load | 100% |
| Next 60 A of all other loads | 50% |
| Remainder of other load | 25% |
The first line uses the largest of the three values: the simultaneous load, 125% of the largest motor, or 60 A.
Step 2: total farm load on a common service (120.103)
Where the farm buildings and loads are supplied by a common service, calculate each building or load under Table 120.102, then combine them:
| Individual loads calculated under Table 120.102 | Demand factor |
|---|---|
| Largest load | 100% |
| Second largest load | 75% |
| Third largest load | 65% |
| Remaining loads | 50% |
Add the farm dwelling load, calculated under Step 1, to this total.
Typical farm loads
Farm buildings combine motors, heating, and lighting that run on very different schedules, which is why the demand factors are so generous:
- Grain drying: dryer fans and burners, augers, and bin aeration fans run hard during harvest and little the rest of the year. The dryer site is often the largest load on the farm.
- Dairy: vacuum pumps, milk coolers, water heaters, and ventilation fans run every day, often for long periods.
- Hog and poultry confinement: ventilation fans run continuously, with heaters and lighting on controls.
- Shops and machine sheds: welders, air compressors, and heaters run intermittently.
- Heated stock waterers and heat tape: small but long-running winter loads in Minnesota.
Table 120.102 is stated in amperes at 240 V maximum, so convert other loads to amperes before applying it. The demand factors only reduce the calculated load; feeder and service conductors must still be sized under 215.2 and 230.42, with continuous loads at 125%.
Worked example: a dairy barn
A barn has a total connected load of 150 A at 240 V. The largest motor is a 10 hp, 230 V single-phase vacuum pump with a Table 430.248 full-load current of 50 A. Loads expected to run together total 70 A.
- 125% of the largest motor: A. The first line uses the largest of 70 A, 62.5 A, and 60 A, so 70 A at 100% = 70 A.
- Next 60 A at 50%: A.
- Remainder: A at 25% = A.
- Barn demand: A.
Worked example: total farm service
The same farm has these building loads, each already calculated under Table 120.102: barn 105 A, grain dryer and bins 90 A, machine shed 60 A, shop 40 A. The house calculates to 120 A by the standard method.
| Load | Rank | Factor | Demand |
|---|---|---|---|
| Barn | Largest | 100% | 105.0 A |
| Grain dryer and bins | Second | 75% | 67.5 A |
| Machine shed | Third | 65% | 39.0 A |
| Shop | Remaining | 50% | 20.0 A |
| Farm buildings subtotal | 231.5 A | ||
| Dwelling | Added at its own calculation | 120.0 A | |
| Total farm load | 351.5 A |
A 400 A service, or a 400 A distribution point, is needed.
How farm calculations connect to other rules
- Agricultural buildings (Article 547): a farm's distribution point, often a pole-mounted site-isolating device, feeds the buildings as separate structures. The 2026 NEC adds detailed construction rules for equipotential planes in livestock confinement areas.
- Outside feeders (Article 225): each building fed from the distribution point needs its own disconnecting means, located at or within sight of the building under 225.31 and 110.29.
- Grounding of separate buildings (250.32): each building needs a grounding electrode system and an equipment grounding conductor run with the feeder; the neutral and equipment grounding conductor are not bonded at the building.
Tip
On a farm question, do the building calculations first, rank the results from largest to smallest, and only then apply Table 120.103. Applying the 75% and 65% factors before ranking is the most common error.
A farm machine shed has a total load of 130 A at 240 V. The largest motor has a full-load current of 40 A, and the loads expected to run together total 50 A. What is the demand load under Table 120.102?
130.0 A
85.0 A
75.0 A
92.5 A
Three farm buildings on a common service have calculated loads of 80 A, 100 A, and 60 A. What is their combined load under Table 120.103, before adding the dwelling?
240 A
180 A
199 A
212 A
A farm dwelling with electric heat shares a common service with an electric grain-drying system. How must the dwelling load be calculated?
By the standard method; 120.102(A) bars the optional method here
By the optional method of 120.82 only, with the farm loads added
At 65% as the third-largest load under Table 120.103
At 50% as one of the remaining farm loads under Table 120.103
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