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100+ Free FAA PLA Knowledge Test — Private Pilot Airship Practice Questions

Prepare for the FAA Private Pilot Airship Knowledge Test (Test Code: PLA) exam with instant access — no signup required.

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Key Facts: FAA PLA Knowledge Test — Private Pilot Airship Exam

PLA

Test Code

FAA Airman Knowledge Testing Matrix

60 Questions

Official Question Count

FAA Airman Knowledge Testing Matrix

2.5 Hours (150 Min)

Time Limit

FAA Airman Knowledge Testing Matrix

70%

Passing Score

FAA Airman Knowledge Testing Matrix

Prepare for the FAA PLA Private Pilot Airship Knowledge Test with 100 practice questions covering FAA Part 61/91 regulations, aerostatics, envelope and ballonet systems, ground handling, weigh-off procedures, and weather. Test consists of 60 questions with a 2.5-hour time limit and 70% passing threshold.

Sample FAA PLA Knowledge Test — Private Pilot Airship Practice Questions

Try these sample questions to test your FAA PLA Knowledge Test — Private Pilot Airship exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1According to Archimedes' principle as applied to aerostats, what determines the gross static lift produced by an airship's envelope?
A.The weight of the atmospheric air displaced minus the weight of the lifting gas contained within the envelope
B.The total dynamic pressure generated by the airship's forward velocity over the envelope
C.The temperature differential between the ambient air and the air inside the ballonets
D.The weight of the lifting gas divided by the ambient barometric pressure
Explanation: Archimedes' principle states that any body completely or partially submerged in a fluid is buoyed up by a force equal to the weight of the fluid displaced. For an airship, gross static lift equals the total weight of the ambient air displaced by the envelope minus the weight of the contained lifting gas (helium).
2Under standard atmospheric conditions (59°F / 15°C and 29.92 in Hg), what is the approximate net static lift provided by 1,000 cubic feet of 100% pure helium?
A.62 to 65 pounds
B.76 to 80 pounds
C.40 to 44 pounds
D.100 to 105 pounds
Explanation: At standard atmosphere, 1,000 cu ft of air weighs approximately 76.5 lbs, while 1,000 cu ft of pure helium weighs approximately 10.5 lbs. Subtracting the weight of helium from the weight of air displaced yields a net static lift of approximately 62 to 65 lbs per 1,000 cu ft.
3What is the definition of 'pressure height' in airship operations?
A.The altitude at which the ballonets become completely empty and the lifting gas fully expands to fill the entire envelope
B.The maximum altitude at which the envelope gas valves begin to open automatically during descent
C.The pressure altitude at which dynamic lift equals static heaviness during cruise flight
D.The altitude where atmospheric pressure drops to exactly half of sea level pressure
Explanation: Pressure height is the altitude at which the expanding lifting gas completely fills the envelope, forcing all air out of the ballonets. Climbing above pressure height will cause gas to discharge through the overpressure safety relief valves to prevent envelope rupture.
4What occurs when an airship envelope experiences 'positive superheat'?
A.The temperature of the helium inside the envelope becomes higher than the surrounding ambient air temperature
B.The pressure inside the ballonets exceeds ambient atmospheric pressure by more than 5 inches of water
C.The temperature of the ambient air rises faster than the temperature of the lifting gas
D.The airship engine cylinder head temperature exceeds maximum continuous limits
Explanation: Positive superheat occurs when solar radiation heats the envelope, causing the internal lifting gas temperature to exceed the ambient air temperature. This increases gas volume (or pressure) and expands lift capability beyond standard static equilibrium.
5An airship envelope contains 200,000 cubic feet of helium. If the helium temperature increases by 10°F due to solar radiation while ambient air temperature remains constant (10°F positive superheat below pressure height), what is the approximate change in static lift?
A.Static lift increases by approximately 240 pounds
B.Static lift decreases by approximately 150 pounds
C.Static lift remains completely unchanged until reaching pressure height
D.Static lift increases by approximately 1,200 pounds
Explanation: Below pressure height, a 1°F increase in superheat expands the helium and displaces additional air, increasing lift by approximately 0.2% per °F (or ~1 lb per 1,000 cu ft per 5°F superheat). For 200,000 cu ft with 10°F superheat: (200,000 / 1,000) * (10 / 5) * 60 lbs * 0.02 ≈ 240 lbs lift gain.
6During ascent from sea level up to pressure height, what happens to the air volume inside the ballonets and the total gross static lift of the airship?
A.Ballonet air volume decreases while total gross static lift remains practically constant
B.Ballonet air volume increases while total gross static lift increases proportionally
C.Ballonet air volume remains constant while gross static lift decreases due to lower air density
D.Ballonet air volume decreases while gross static lift decreases at a rate of 100 lbs per 1,000 feet
Explanation: As the airship climbs below pressure height, atmospheric pressure decreases, allowing the helium inside the envelope to expand. Air is vented from the ballonets to accommodate this expansion. Because the expanding helium continues to displace a constant mass of air, gross static lift remains virtually constant up to pressure height.
7If an airship continues climbing above its pressure height, what action must occur to prevent damage to the envelope?
A.Helium must be vented through automatic or manual envelope gas valves, resulting in a loss of static lift
B.Air must be pumped into the ballonets under high pressure using auxiliary electric blowers
C.The engine throttle must be reduced to flight idle while maintaining a nose-down pitch trim
D.The rip cords must be pulled partially to vent excess air from the bow compartment
Explanation: Above pressure height, the ballonets are fully deflated, so expanding helium has no room to expand. To prevent overpressurization and envelope rupture, helium is automatically vented through envelope gas valves, permanently reducing total static lift.
8How does dynamic lift differ from static lift in an airship?
A.Dynamic lift is created by air acting aerodynamically on the pitched hull during forward motion, whereas static lift is created purely by buoyant gas displacement
B.Dynamic lift is produced by internal ballonet air pressure, while static lift is produced by vectorable engine thrust
C.Dynamic lift is present only during hover, while static lift operates only at high airspeed
D.Dynamic lift is generated by superheat, whereas static lift is generated by helium purity
Explanation: Static lift is buoyant lift generated according to Archimedes' principle regardless of movement. Dynamic lift is aerodynamic lift created when the airship moves forward at an angle of attack (inclined hull attitude), generating aerodynamic force similar to an aircraft wing.
9What structural arrangement provides an airship with its inherent static pitch and roll stability?
A.Locating the Center of Gravity (CG) well below the Center of Buoyancy (CB)
B.Positioning the Center of Buoyancy below the heavy car and engines
C.Placing water ballast tanks at the extreme bow and stern of the envelope
D.Setting the vertical fins at a negative dihedral angle relative to the hull centerline
Explanation: An airship derives static pendulum stability by placing heavy components (gondola, engines, fuel, ballast) below the envelope, positioning the Center of Gravity (CG) significantly below the Center of Buoyancy (CB). This creates a restoring moment whenever the airship tilts in roll or pitch.
10If helium purity inside an airship envelope drops from 99% to 94% due to air contamination, what effect does this have on airship performance?
A.Gross static lift decreases significantly, and pressure height is reduced
B.Gross static lift increases because air is denser than pure helium
C.Pressure height increases, while gross static lift remains unchanged
D.Dynamic lift capability increases to compensate for loss of hull weight
Explanation: Contaminating helium with air increases the average density of the gas mixture inside the envelope. This reduces net static lift per unit volume and lowers the effective pressure height of the airship.

About the FAA PLA Knowledge Test — Private Pilot Airship Exam

The FAA PLA Knowledge Test is required for pilot candidates seeking an FAA Private Pilot Certificate with a Lighter-Than-Air Category and Airship Class Rating under 14 CFR Part 61. It tests knowledge of FAA federal aviation regulations (Part 61/91), aerostatics (buoyancy, superheat, static heaviness/lightness, pressure height), airship envelope and ballonet systems, ground handling, mooring mast operations, weigh-off, airship weather factors, and flight maneuvers.

Assessment

60 multiple-choice questions administered via computer at PSI testing centers covering FAA regulations, aerostatics, airship systems, ground handling, weather, and flight operations.

Time Limit

2.5 hours (150 minutes)

Passing Score

70%

Exam Fee

$175 (Federal Aviation Administration (FAA) / PSI Services)

FAA PLA Knowledge Test — Private Pilot Airship Exam Content Outline

25%

14 CFR Part 61 / 91 Regulations for Airship Operations

Private pilot aeronautical experience under § 61.109(h), privileges and limitations, medical certificates, right-of-way rules (§ 91.113), minimum safe altitudes (§ 91.119), position/anchor lighting (§ 91.209), and maintenance requirements.

25%

Aerostatics & Airship Aerodynamics

Archimedes' principle, static heaviness vs lightness, superheat effects, pressure height, ballonet operation, static vs dynamic lift, vectorable thrust, and airship stability.

25%

Airship Systems, Ground Handling & Weigh-Off

Envelope fabric, rip panels, gas valves, dampers, air blowers, ballast distribution, mobile mooring mast operations, ground crew signals, and weigh-off procedure.

25%

Weather, Flight Operations & Navigation

Micro-meteorology, wind shear, inversions, thermals, envelope icing, METAR/TAF interpretation, airspace classes, crosswind components, drift correction, and emergency procedures.

How to Pass the FAA PLA Knowledge Test — Private Pilot Airship Exam

What You Need to Know

  • Passing score: 70%
  • Assessment: 60 multiple-choice questions administered via computer at PSI testing centers covering FAA regulations, aerostatics, airship systems, ground handling, weather, and flight operations.
  • Time limit: 2.5 hours (150 minutes)
  • Exam fee: $175

Keys to Passing

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

FAA PLA Knowledge Test — Private Pilot Airship Study Tips from Top Performers

1Understand aerostatics principles: how helium expansion affects ballonet volume up to pressure height, and what happens above pressure height.
2Memorize superheat effects: 1°F of superheat increases gas volume/lift equivalent to roughly a 1°F rise in temperature (approx 1 lb per 1000 cu ft per 5°F superheat).
3Study ground handling procedures: weigh-off steps, ground crew commands, mast entry/exit maneuvers, and ballast management.
4Practice real numerical calculations for density altitude, pressure altitude, crosswind components, fuel burn, static heaviness/lightness, and weight & balance.
5Review Part 91 right-of-way rules (§ 91.113): airships have right-of-way over powered fixed-wing aircraft and rotorcraft, but yield to balloons and gliders.

Frequently Asked Questions

What is the FAA PLA Knowledge Test?

The FAA PLA Knowledge Test is the written examination required to obtain an FAA Private Pilot Certificate with a Lighter-Than-Air Category and Airship Class Rating under 14 CFR Part 61.

How many questions are on the official FAA PLA exam and what is the passing score?

The official exam consists of 60 multiple-choice questions with a 2.5-hour (150 minutes) time limit. The passing score is 70% (at least 42 correct answers out of 60).

Where is the exam taken and how much does it cost?

The test is administered on computer at authorized PSI testing centers nationwide. The fee is $175.

What topics are covered on the FAA PLA exam?

The exam covers 14 CFR Part 61 and 91 regulations, aerostatics (buoyancy, pressure height, superheat), airship envelope and ballonet systems, ground crew handling, mooring mast operations, weigh-off, micro-meteorology, and emergency procedures.