9.4 Water Chillers: Centrifugal, Screw & Scroll with ASHRAE 90.1 Path A/B IPLV Ratings

Key Takeaways

  • Water chiller capacity is governed by the hydronic heat balance q˙=500×GPMCHW×(TCHWR−TCHWS)\dot{q} = 500 \times \text{GPM}_{\text{CHW}} \times (T_{\text{CHWR}} - T_{\text{CHWS}}); standard AHRI rating conditions specify 54∘F54^\circ\text{F} entering and 44∘F44^\circ\text{F} leaving chilled water (2.4 GPM/ton2.4\text{ GPM/ton} for a 10∘F ΔT10^\circ\text{F}\text{ }\Delta T).

  • Chiller efficiency metrics are interconverted via kW/ton=3.51685COP=12EER\text{kW/ton} = \frac{3.51685}{\text{COP}} = \frac{12}{\text{EER}}; total heat of rejection to the condenser is THR=Tons×12,000+kWinput×3,412.14\text{THR} = \text{Tons} \times 12,000 + \text{kW}_{\text{input}} \times 3,412.14.

  • AHRI Standard 550/590 Integrated Part-Load Value (IPLV.IP) weights four distinct operating points: 1%1\% at 100%100\% load (85∘F85^\circ\text{F} ECWT), 42%42\% at 75%75\% load (75∘F75^\circ\text{F} ECWT), 45%45\% at 50%50\% load (65∘F65^\circ\text{F} ECWT), and 12%12\% at 25%25\% load (65∘F65^\circ\text{F} ECWT).

  • For kW/ton\text{kW/ton}, IPLV.IP uses a weighted harmonic mean: IPLV (kW/ton)=10.01A+0.42B+0.45C+0.12D\text{IPLV (kW/ton)} = \frac{1}{\frac{0.01}{A} + \frac{0.42}{B} + \frac{0.45}{C} + \frac{0.12}{D}}; for EER or COP, IPLV.IP uses an arithmetic mean: IPLV=0.01A+0.42B+0.45C+0.12D\text{IPLV} = 0.01 A + 0.42 B + 0.45 C + 0.12 D.

  • ASHRAE Standard 90.1 defines two compliance paths: Path A requires higher full-load efficiency (ideal for baseload chillers), while Path B permits lower full-load efficiency in exchange for aggressive part-load IPLV performance (ideal for VFD chillers with condenser water relief).

Last updated: August 2026

9.4 Water Chillers: Centrifugal, Screw & Scroll with ASHRAE 90.1 Path A/B IPLV Ratings

Water chillers are the cornerstone of commercial, institutional, and district central chilled water plants. A water chiller integrates the four primary refrigeration cycle components—compressor, condenser, expansion device, and evaporator—into a packaged machine engineered to produce cold water (typically 40∘F40^\circ\text{F} to 45∘F45^\circ\text{F}) for building air conditioning or process cooling. On the PE Mechanical: HVAC and Refrigeration exam, chiller questions evaluate hydronic heat balances, energy efficiency unit conversions, part-load performance under AHRI Standard 550/590, and energy code compliance under ASHRAE Standard 90.1.


1. Chiller Capacity & Primary Hydronic Energy Balances

Chiller cooling capacity represents the rate of heat removed from the circulating chilled water loop:

Q˙evap (Btu/hr)=m˙CHW⋅cp,water⋅(TCHWR−TCHWS)=500×GPMCHW×ΔTCHW\dot{Q}_{\text{evap}}\text{ (Btu/hr)} = \dot{m}_{\text{CHW}} \cdot c_{p,\text{water}} \cdot (T_{\text{CHWR}} - T_{\text{CHWS}}) = 500 \times \text{GPM}_{\text{CHW}} \times \Delta T_{\text{CHW}} Cooling Capacity (Tons)=500×GPMCHW×(TCHWR−TCHWS)12,000=GPMCHW×ΔTCHW24\text{Cooling Capacity (Tons)} = \frac{500 \times \text{GPM}_{\text{CHW}} \times (T_{\text{CHWR}} - T_{\text{CHWS}})}{12,000} = \frac{\text{GPM}_{\text{CHW}} \times \Delta T_{\text{CHW}}}{24}
+-----------------------------------------------------------------------------------------+
| STANDARD AHRI 550/590 WATER-COOLED CHILLER RATING BASELINE                              |
+-----------------------------------------------------------------------------------------+
| Evaporator Entering Water Temp (CHWR): 54.0°F (12.2°C)                                  |
| Evaporator Leaving Water Temp (CHWS):  44.0°F (6.67°C)   --> Delta_T = 10.0°F           |
| Chilled Water Flow Rate per Ton:       2.40 GPM/ton                                     |
| Condenser Entering Water Temp (ECWT):  85.0°F (29.4°C)                                  |
| Condenser Leaving Water Temp (LCWT):   95.0°F (35.0°C)   --> Delta_T = 10.0°F           |
| Condenser Water Flow Rate per Ton:     3.00 GPM/ton                                     |
| Evaporator Waterside Fouling Factor:   0.00010 hr·ft²·°F/Btu                            |
| Condenser Waterside Fouling Factor:    0.00025 hr·ft²·°F/Btu                            |
+-----------------------------------------------------------------------------------------+

Condenser Heat Rejection Balance

THR (Btu/hr)=Q˙evap+W˙comp=(Tons×12,000)+(kWinput×3,412.14)\text{THR (Btu/hr)} = \dot{Q}_{\text{evap}} + \dot{W}_{\text{comp}} = (\text{Tons} \times 12,000) + (\text{kW}_{\text{input}} \times 3,412.14) THR (Btu/hr)=500×GPMCW×(TLCWT−TECWT)\text{THR (Btu/hr)} = 500 \times \text{GPM}_{\text{CW}} \times (T_{\text{LCWT}} - T_{\text{ECWT}}) GPMCW=(Tons×12,000)+(kW×3,412.14)500×(TLCWT−TECWT)\text{GPM}_{\text{CW}} = \frac{(\text{Tons} \times 12,000) + (\text{kW} \times 3,412.14)}{500 \times (T_{\text{LCWT}} - T_{\text{ECWT}})}

2. Chiller Efficiency Metrics & Interconversions

Chiller efficiency is expressed in multiple imperial and metric engineering metrics:

+-----------------------------------------------------------------------------------------+
| CHILLER EFFICIENCY METRIC CONVERSION FORMULAS                                           |
+-----------------------------------------------------------------------------------------+
|                                 3.51685           12.000                                |
|             kW/ton       =   ------------   =   ----------                              |
|                                  COP               EER                                  |
|                                                                                         |
|                                 3.51685           EER                                   |
|              COP         =   ------------   =   ----------                              |
|                                 kW/ton            3.41214                               |
|                                                                                         |
|                                 12.000                                                  |
|              EER         =   ------------   =   3.41214 * COP                           |
|                                 kW/ton                                                  |
+-----------------------------------------------------------------------------------------+

Practical Benchmarks by Compressor Architecture

Compressor TypeTypical Capacity RangeFull-Load Efficiency (kW/ton)Full-Load COPPart-Load IPLV (kW/ton)
Air-Cooled Scroll20 to 180 Tons1.10−1.30 kW/ton1.10 - 1.30\text{ kW/ton}2.70−3.202.70 - 3.200.75−0.90 kW/ton0.75 - 0.90\text{ kW/ton}
Air-Cooled Screw100 to 500 Tons1.00−1.20 kW/ton1.00 - 1.20\text{ kW/ton}2.93−3.522.93 - 3.520.65−0.80 kW/ton0.65 - 0.80\text{ kW/ton}
Water-Cooled Scroll30 to 200 Tons0.70−0.85 kW/ton0.70 - 0.85\text{ kW/ton}4.14−5.024.14 - 5.020.50−0.65 kW/ton0.50 - 0.65\text{ kW/ton}
Water-Cooled Screw100 to 600 Tons0.58−0.70 kW/ton0.58 - 0.70\text{ kW/ton}5.02−6.065.02 - 6.060.40−0.55 kW/ton0.40 - 0.55\text{ kW/ton}
Water-Cooled Centrifugal (Fixed Speed)200 to 3,000+ Tons0.52−0.62 kW/ton0.52 - 0.62\text{ kW/ton}5.67−6.765.67 - 6.760.45−0.55 kW/ton0.45 - 0.55\text{ kW/ton}
Water-Cooled Centrifugal (VFD Mag-Bearing)200 to 1,500 Tons0.50−0.58 kW/ton0.50 - 0.58\text{ kW/ton}6.06−7.036.06 - 7.030.28−0.38 kW/ton0.28 - 0.38\text{ kW/ton}

3. AHRI Standard 550/590 Integrated Part-Load Value (IPLV)

Commercial chillers operate at 100% design capacity for less than 1% to 2% of their total annual operating hours. The vast majority of runtime occurs between 40% and 75% load when outdoor wet-bulb temperatures are lower than design conditions. To reflect real-world annual energy consumption, AHRI Standard 550/590 established the Integrated Part-Load Value (IPLV.IP) rating.

AHRI Standard Part-Load Test Points

+-----------------------------------------------------------------------------------------+
| AHRI 550/590 IPLV.IP TEST CONDITIONS & TIMING WEIGHTS                                   |
+-------+-----------+----------------------+--------------------+-------------------------+
| Point | Capacity  | Water-Cooled ECWT    | Air-Cooled Ambient | Time Weighting Fraction |
+-------+-----------+----------------------+--------------------+-------------------------+
| **A** | **100%**  | **85.0°F (29.4°C)**  | **95.0°F (35.0°C)**| **0.01 (1%)**           |
| **B** | **75%**   | **75.0°F (23.9°C)**  | **80.0°F (26.7°C)**| **0.42 (42%)**          |
| **C** | **50%**   | **65.0°F (18.3°C)**  | **65.0°F (18.3°C)**| **0.45 (45%)**          |
| **D** | **25%**   | **65.0°F (18.3°C)**  | **55.0°F (12.8°C)**| **0.12 (12%)**          |
+-------+-----------+----------------------+--------------------+-------------------------+

Condenser Water Relief: Notice that as chiller cooling load decreases from 100% down to 50%, entering condenser water temperature (ECWT) is allowed to drop from 85∘F85^\circ\text{F} down to 65∘F65^\circ\text{F} (1.0∘F1.0^\circ\text{F} reduction in ECWT for every 2.5%2.5\% drop in load). Below 50% load, ECWT is capped at a minimum of 65.0∘F65.0^\circ\text{F} to prevent oil separation and refrigerant migration issues.

Mathematical Formulation of IPLV

1. When Efficiency is Expressed in EER or COP (Higher is Better):

IPLV.IP=0.01A+0.42B+0.45C+0.12D\text{IPLV.IP} = 0.01 A + 0.42 B + 0.45 C + 0.12 D

Where A,B,C,DA, B, C, D are the measured EER or COP at 100%,75%,50%,25%100\%, 75\%, 50\%, 25\% load.

2. When Efficiency is Expressed in kW/ton (Lower is Better):

Because kW/ton=12/EER\text{kW/ton} = 12 / \text{EER}, the weighted averaging must be performed on the reciprocal (weighted harmonic mean):

IPLV.IP (kW/ton)=10.01A+0.42B+0.45C+0.12D\text{IPLV.IP (kW/ton)} = \frac{1}{\frac{0.01}{A} + \frac{0.42}{B} + \frac{0.45}{C} + \frac{0.12}{D}}

Where A,B,C,DA, B, C, D are the measured kW/ton\text{kW/ton} values at 100%,75%,50%,25%100\%, 75\%, 50\%, 25\% load.

Exam Calculation Trap: Never calculate IPLV in kW/ton\text{kW/ton} using the direct linear formula 0.01A+0.42B+0.45C+0.12D0.01 A + 0.42 B + 0.45 C + 0.12 D. Linear weighting on kW/ton\text{kW/ton} produces mathematical errors of 8%8\% to 15%15\%. You must use the harmonic reciprocal equation above!

Non-Standard Part-Load Value (NPLV.IP)

When a chiller is selected to operate at design conditions differing from AHRI standard conditions (e.g., producing 42.0∘F42.0^\circ\text{F} leaving chilled water instead of 44.0∘F44.0^\circ\text{F}, or with 82.0∘F82.0^\circ\text{F} entering condenser water), the identical formula is applied to calculate NPLV.IP using the non-standard entering water temperature schedule:

ECWT=ECWTdesign−(ECWTdesign−65∘F100−50)×(100%−%Load)\text{ECWT} = \text{ECWT}_{\text{design}} - \left(\frac{\text{ECWT}_{\text{design}} - 65^\circ\text{F}}{100 - 50}\right) \times (100\% - \%\text{Load})

4. ASHRAE Standard 90.1 Chiller Compliance: Path A vs. Path B

ASHRAE Standard 90.1 (Energy Standard for Buildings Except Low-Rise Residential) mandates minimum full-load and part-load efficiency thresholds for water chillers. To accommodate different plant operating profiles, 90.1 provides two alternative compliance paths:

+-----------------------------------------------------------------------------------------+
| ASHRAE STANDARD 90.1 COMPLIANCE PHILOSOPHY: PATH A vs. PATH B                           |
+-----------------------------------+-----------------------------------------------------+
| PATH A (Full-Load Optimized)      | PATH B (Part-Load / VFD Optimized)                  |
+-----------------------------------+-----------------------------------------------------+
| • Strict Full-Load Efficiency     | • Relaxed Full-Load Efficiency                      |
| • Modest Part-Load (IPLV) Target  | • Highly Aggressive Part-Load (IPLV) Target         |
| • Best for: Constant-speed base-  | • Best for: Variable-speed (VFD) chillers operating |
|   load chillers in data centers   |   in variable cooling load applications with       |
|   or industrial process cooling.  |   condenser water temperature relief.               |
+-----------------------------------+-----------------------------------------------------+

ASHRAE Standard 90.1 Minimum Efficiency Table (Representative Values)

Equipment Type & Size RangePath A: Min Full-LoadPath A: Min IPLVPath B: Min Full-LoadPath B: Min IPLV
Air-Cooled Chillers (<150 Tons< 150\text{ Tons})≥10.10 EER\ge 10.10\text{ EER}≥13.70 EER\ge 13.70\text{ EER}≥9.70 EER\ge 9.70\text{ EER}≥15.80 EER\ge 15.80\text{ EER}
Air-Cooled Chillers (≥150 Tons\ge 150\text{ Tons})≥10.10 EER\ge 10.10\text{ EER}≥14.00 EER\ge 14.00\text{ EER}≥9.70 EER\ge 9.70\text{ EER}≥16.10 EER\ge 16.10\text{ EER}
Water-Cooled Positive Disp (Screw/Scroll) (150−300 Tons150-300\text{ Tons})≤0.660 kW/ton\le 0.660\text{ kW/ton}≤0.540 kW/ton\le 0.540\text{ kW/ton}≤0.740 kW/ton\le 0.740\text{ kW/ton}≤0.400 kW/ton\le 0.400\text{ kW/ton}
Water-Cooled Centrifugal (300−600 Tons300-600\text{ Tons})≤0.560 kW/ton\le 0.560\text{ kW/ton}≤0.500 kW/ton\le 0.500\text{ kW/ton}≤0.590 kW/ton\le 0.590\text{ kW/ton}≤0.360 kW/ton\le 0.360\text{ kW/ton}
Water-Cooled Centrifugal (>600 Tons> 600\text{ Tons})≤0.540 kW/ton\le 0.540\text{ kW/ton}≤0.480 kW/ton\le 0.480\text{ kW/ton}≤0.560 kW/ton\le 0.560\text{ kW/ton}≤0.330 kW/ton\le 0.330\text{ kW/ton}

Key Code Rule: A chiller must comply with BOTH the full-load and part-load IPLV requirements of either Path A or Path B. Mixing Path A full-load with Path B IPLV is strictly prohibited.


5. Chiller Lift Reduction & VFD Energy Savings

The fundamental thermodynamic driver of part-load chiller efficiency is compressor lift reduction:

Lift=Pcondenser, sat−Pevaporator, sat∝Tcondenser, sat−Tevaporator, sat\text{Lift} = P_{\text{condenser, sat}} - P_{\text{evaporator, sat}} \propto T_{\text{condenser, sat}} - T_{\text{evaporator, sat}}

When ambient wet-bulb temperature drops, the cooling tower produces colder condenser water (85∘F→75∘F→65∘F85^\circ\text{F} \to 75^\circ\text{F} \to 65^\circ\text{F}). In a constant-speed centrifugal chiller, lowering the ECWT saves energy, but the compressor must throttle using inlet guide vanes, creating aerodynamic drag. In a Variable Frequency Drive (VFD) chiller, reducing compressor speed directly matches the reduced pressure lift requirement according to the affinity laws (H∝N2H \propto N^2, Power∝N3\text{Power} \propto N^3). At 50% load and 65∘F65^\circ\text{F} ECWT, a VFD centrifugal chiller can operate at 0.250.25 to 0.32 kW/ton0.32\text{ kW/ton} (a COP exceeding 11.011.0!).


6. Worked Example: Comprehensive Chiller Analysis & IPLV Calculation

Problem: A 600-ton water-cooled centrifugal chiller is evaluated for a commercial central plant. The measured performance data at AHRI Standard 550/590 test points are:

  • Point A (100% Load, 600 Tons, 85°F ECWT): Power = 330.0 kW330.0\text{ kW}
  • Point B (75% Load, 450 Tons, 75°F ECWT): Power = 189.0 kW189.0\text{ kW}
  • Point C (50% Load, 300 Tons, 65°F ECWT): Power = 96.0 kW96.0\text{ kW}
  • Point D (25% Load, 150 Tons, 65°F ECWT): Power = 54.0 kW54.0\text{ kW}

Find:

  1. The specific power consumption (kW/ton\text{kW/ton}) and COP at each test point (A,B,C,DA, B, C, D).
  2. The Integrated Part-Load Value in kW/ton\text{kW/ton} (IPLV.IPkW/ton\text{IPLV.IP}_{\text{kW/ton}}).
  3. The Integrated Part-Load Value in COP (IPLV.IPCOP\text{IPLV.IP}_{\text{COP}}).
  4. Determine whether the chiller meets ASHRAE Standard 90.1 Path B requirements for a 600-ton centrifugal chiller (Full-Load ≤0.590 kW/ton\le 0.590\text{ kW/ton}, IPLV ≤0.360 kW/ton\le 0.360\text{ kW/ton}).

Step-by-Step Solution:

Step 1: Compute specific power (kW/ton) and COP at each operating point.

  • Point A (100%):

    kW/tonA=330.0 kW600 tons=0.5500 kW/ton\text{kW/ton}_A = \frac{330.0\text{ kW}}{600\text{ tons}} = 0.5500\text{ kW/ton} COPA=3.516850.5500=6.394\text{COP}_A = \frac{3.51685}{0.5500} = 6.394
  • Point B (75%):

    kW/tonB=189.0 kW450 tons=0.4200 kW/ton\text{kW/ton}_B = \frac{189.0\text{ kW}}{450\text{ tons}} = 0.4200\text{ kW/ton} COPB=3.516850.4200=8.373\text{COP}_B = \frac{3.51685}{0.4200} = 8.373
  • Point C (50%):

    kW/tonC=96.0 kW300 tons=0.3200 kW/ton\text{kW/ton}_C = \frac{96.0\text{ kW}}{300\text{ tons}} = 0.3200\text{ kW/ton} COPC=3.516850.3200=10.990\text{COP}_C = \frac{3.51685}{0.3200} = 10.990
  • Point D (25%):

    kW/tonD=54.0 kW150 tons=0.3600 kW/ton\text{kW/ton}_D = \frac{54.0\text{ kW}}{150\text{ tons}} = 0.3600\text{ kW/ton} COPD=3.516850.3600=9.769\text{COP}_D = \frac{3.51685}{0.3600} = 9.769

Step 2: Calculate IPLV.IP in kW/ton using the harmonic weighting formula.

Denominator=0.01A+0.42B+0.45C+0.12D\text{Denominator} = \frac{0.01}{A} + \frac{0.42}{B} + \frac{0.45}{C} + \frac{0.12}{D} Denominator=0.010.5500+0.420.4200+0.450.3200+0.120.3600\text{Denominator} = \frac{0.01}{0.5500} + \frac{0.42}{0.4200} + \frac{0.45}{0.3200} + \frac{0.12}{0.3600} Denominator=0.018182+1.000000+1.406250+0.333333=2.757765\text{Denominator} = 0.018182 + 1.000000 + 1.406250 + 0.333333 = 2.757765 IPLV.IP (kW/ton)=12.757765=0.3626 kW/ton\text{IPLV.IP (kW/ton)} = \frac{1}{2.757765} = 0.3626\text{ kW/ton}

(Note: If calculated incorrectly using linear weighting: 0.01(0.55)+0.42(0.42)+0.45(0.32)+0.12(0.36)=0.0055+0.1764+0.1440+0.0432=0.3691 kW/ton0.01(0.55) + 0.42(0.42) + 0.45(0.32) + 0.12(0.36) = 0.0055 + 0.1764 + 0.1440 + 0.0432 = 0.3691\text{ kW/ton}, which is mathematically invalid).

Step 3: Calculate IPLV.IP in COP using linear weighting.

IPLV.IPCOP=0.01(COPA)+0.42(COPB)+0.45(COPC)+0.12(COPD)\text{IPLV.IP}_{\text{COP}} = 0.01(\text{COP}_A) + 0.42(\text{COP}_B) + 0.45(\text{COP}_C) + 0.12(\text{COP}_D) IPLV.IPCOP=0.01(6.394)+0.42(8.373)+0.45(10.990)+0.12(9.769)\text{IPLV.IP}_{\text{COP}} = 0.01(6.394) + 0.42(8.373) + 0.45(10.990) + 0.12(9.769) IPLV.IPCOP=0.06394+3.51666+4.94550+1.17228=9.6984≈9.70\text{IPLV.IP}_{\text{COP}} = 0.06394 + 3.51666 + 4.94550 + 1.17228 = 9.6984 \approx 9.70

Check consistency: IPLV (kW/ton)=3.516859.6984=0.3626 kW/ton\text{IPLV (kW/ton)} = \frac{3.51685}{9.6984} = 0.3626\text{ kW/ton} (Exact match!).

Step 4: Check ASHRAE 90.1 Path B compliance.

  • Full-Load Requirement: 0.550 kW/ton≤0.590 kW/ton0.550\text{ kW/ton} \le 0.590\text{ kW/ton}   ⟹  \implies Complies (PASS)
  • Part-Load IPLV Requirement: 0.3626 kW/ton>0.360 kW/ton0.3626\text{ kW/ton} > 0.360\text{ kW/ton}   ⟹  \implies Marginally Fails (FAIL)
  • To achieve compliance under Path B, the manufacturer must slightly retrim impeller staging or optimize VFD tuning at 50% load to lower IPLV below 0.360 kW/ton0.360\text{ kW/ton}, or evaluate under Path A (0.550 kW/ton≤0.560 kW/ton0.550\text{ kW/ton} \le 0.560\text{ kW/ton} and 0.363 kW/ton≤0.500 kW/ton0.363\text{ kW/ton} \le 0.500\text{ kW/ton}   ⟹  \implies Fully Complies under Path A!).

7. NCEES Reference Handbook Navigation & Exam Tips

  • HVAC Section: Chillers & AHRI Ratings: Find standard IPLV weighting equation coefficients (0.01,0.42,0.45,0.120.01, 0.42, 0.45, 0.12).
  • Harmonic vs. Linear IPLV Rule: Always check whether the question asks for IPLV in kW/ton\text{kW/ton} (harmonic mean) or EER/COP\text{EER} / \text{COP} (linear weighted sum).
  • Path A vs Path B Code Identification: Path A is Full-Load optimized; Path B is Part-Load (VFD) optimized.
Loading diagram...
AHRI 550/590 IPLV Part-Load Test Operating Points
Test Your Knowledge

A 400-ton water-cooled screw chiller operates with the following measured specific power consumptions at AHRI 550/590 test points: Point A (100% load) = 0.620 kW/ton; Point B (75% load) = 0.480 kW/ton; Point C (50% load) = 0.380 kW/ton; Point D (25% load) = 0.440 kW/ton. What is the Integrated Part-Load Value (IPLV.IP) of this chiller in kW/ton?

A

0.426 kW/ton

B

0.452 kW/ton

C

0.480 kW/ton

D

0.395 kW/ton

Test Your Knowledge

A chilled water plant circulates 1,200 GPM of water through an evaporator. Water enters the chiller at 56.0°F and leaves at 42.0°F. If the compressor motor consumes 466.7 kW of electrical power, what is the chiller operating COP and efficiency in kW/ton?

A

COP = 4.39 and Efficiency = 0.800 kW/ton

B

COP = 5.27 and Efficiency = 0.667 kW/ton

C

COP = 3.85 and Efficiency = 0.913 kW/ton

D

COP = 6.12 and Efficiency = 0.575 kW/ton

Test Your Knowledge

Under ASHRAE Standard 90.1, which of the following statements correctly distinguishes Path A from Path B for water-cooled chiller compliance?

A

Path A applies only to air-cooled chillers, while Path B applies exclusively to water-cooled centrifugal chillers

B

Path B requires higher full-load efficiency than Path A and is intended only for constant-speed chillers without VFDs

C

Path A requires lower full-load kW/ton (higher full-load efficiency) but allows higher IPLV kW/ton, making it ideal for baseload chillers

D

A chiller may comply with ASHRAE 90.1 by meeting Path A full-load efficiency combined with Path B IPLV efficiency

Test Your Knowledge

Why does a water-cooled centrifugal chiller equipped with a Variable Frequency Drive (VFD) achieve dramatic efficiency improvements at 50% part load compared to a constant-speed chiller?

A

The VFD increases refrigerant boiling pressure by raising the compressor rotational speed above rated design

B

The VFD eliminates the need for an expansion valve by cycling the condenser fans on and off

C

The VFD converts the centrifugal compression cycle into an isenthalpic positive-displacement process

D

Lowering condenser water temperature reduces required lift, allowing the VFD to reduce impeller speed and exploit cubic power reduction (Power ∝ N^3)

Sections you finish are checked off in the contents.