7.4 Multi-Stage & Cascade Refrigeration Systems: Intercooling & Flash Gas Removal

Key Takeaways

  • Single-stage refrigeration systems suffer severe volumetric efficiency losses and extreme compressor discharge temperatures (> 275°F) when overall pressure ratios exceed r_p = P_{\text{cond}} / P_{\text{evap}} > 8 \text{ to } 10, necessitating multi-stage compound or cascade system configurations.
  • Two-stage compound systems utilize low-stage (booster) and high-stage compressors operating with a single refrigerant, with optimal intermediate pressure governed by P_{\text{int}} = \sqrt{P_{\text{evap}} \cdot P_{\text{cond}}} to equalize compression ratios and minimize combined shaft work.
  • Direct-contact flash intercoolers perform two critical functions simultaneously: desuperheating booster discharge vapor to dry saturated vapor at P_{\text{int}} and subcooling the liquid refrigerant feed to T_{\text{sat}}(P_{\text{int}}) while routing flash gas directly to the high-stage compressor suction.
  • Cascade refrigeration systems employ two hermetically separated refrigerant circuits linked via an intermediate cascade condenser/evaporator heat exchanger, allowing the pairing of specialized high-pressure (low-temperature) and moderate-pressure (high-temperature) refrigerants.
  • The mass flow ratio across a cascade heat exchanger is governed by thermal equilibrium: \dot{m}_{\text{high}} / \dot{m}_{\text{low}} = (h_{2,\text{low}} - h_{3,\text{low}}) / (h_{1,\text{high}} - h_{4,\text{high}}), incorporating the thermal approach difference (\Delta T_{\text{cascade}} = T_{\text{cond,low}} - T_{\text{evap,high}} \approx 5^\circ\text{F to } 10^\circ\text{F}).
Last updated: August 2026

7.4 Multi-Stage & Cascade Refrigeration Systems: Intercooling & Flash Gas Removal

When refrigeration applications demand large temperature lifts—such as industrial blast freezers ($-40^\circ\text{F}\text{ to }-60^\circ\text{F}$), pharmaceutical freeze dryers, and liquefied gas storage—a single-stage vapor-compression cycle becomes thermodynamically unfeasible. High overall pressure ratios ($r_p = P_{\text{cond}} / P_{\text{evap}} > 8\text{ to }10$) cause extreme clearance volumetric efficiency degradation, excessive compressor discharge temperatures exceeding lubrication breakdown limits ($> 275^\circ\text{F}$), and severe COP deterioration. To overcome these constraints, mechanical engineers deploy Multi-Stage Compound Systems (single refrigerant with intercooling) and Cascade Refrigeration Systems (dual isolated refrigerant loops).


1. Single-Stage Operational Limitations & The Compression Ratio Ceiling

As the evaporator temperature drops, the evaporating saturation pressure ($P_{\text{evap}}$) plummets exponentially, resulting in three severe mechanical and thermodynamic penalties:

+-----------------------------------------------------------------------------------------+
| PENALTIES OF HIGH PRESSURE RATIO (r_p = P_cond / P_evap > 8 to 10)                      |
+-----------------------------------------------------------------------------------------+
| 1. Volumetric Efficiency Collapse:   eta_v = 1 - c * (r_p^(1/k) - 1)  --> Mass flow -> 0|
| 2. Oil Breakdown & Valve Failure:    Discharge Temp T_2 > 275°F to 325°F               |
| 3. High Throttling Irreversibility:  Flash gas x_4 > 35% -> Low Net Refrigeration Effect|
+-----------------------------------------------------------------------------------------+

To prevent equipment damage and restore thermodynamic efficiency, the total pressure lift is divided across two or more stages.


2. Multi-Stage Compound Compression Systems (Single Refrigerant)

A two-stage compound system utilizes two compressors connected in series operating on a single continuous refrigerant charge:

  1. Low-Stage (Booster) Compressor: Draws large volumetric flow of low-density vapor from $P_{\text{evap}}$ and compresses it to intermediate pressure $P_{\text{int}}$.
  2. High-Stage Compressor: Draws dense vapor from $P_{\text{int}}$ and compresses it to final condensing pressure $P_{\text{cond}}$.
+-----------------------------------------------------------------------------------------+
| TWO-STAGE COMPOUND SYSTEM WITH DIRECT-CONTACT FLASH INTERCOOLER                         |
+-----------------------------------------------------------------------------------------+
|                                 CONDENSER (P_cond)                                      |
|                         +---------------------------------+                             |
|                         | Condensation to Saturated Liquid|                             |
|                         +---------------------------------+                             |
|                                         | State 5 (h_f at P_cond)                       |
|                                         v                                               |
|                              [ High-Stage Expansion Valve ]                             |
|                                         |                                               |
|                                         v State 6 (Two-Phase at P_int)                  |
|                           +---------------------------+                                 |
|     State 2 (Superheated) |   FLASH INTERCOOLER /     | State 3 (Saturated Vapor)       |
|     from Booster Comp --->|   DESUPERHEATER VESSEL    |---> to High-Stage Compressor    |
|                           +---------------------------+     (Compresses to P_cond)      |
|                                         |                                               |
|                                         v State 7 (Saturated Liquid at P_int)           |
|                              [ Low-Stage Expansion Valve ]                              |
|                                         |                                               |
|                                         v State 8 (Two-Phase at P_evap)                 |
|                         +---------------------------------+                             |
|                         |       EVAPORATOR (P_evap)       |                             |
|                         +---------------------------------+                             |
|                                         | State 1 (Saturated Vapor at P_evap)           |
|                                         v                                               |
|                            [ Booster (Low-Stage) Comp ]                                 |
|                            (Compresses from P_evap to P_int)                            |
+-----------------------------------------------------------------------------------------+

1. Optimal Intermediate Pressure Formulation ($P_{\text{int}}$)

For an ideal two-stage system with perfect intercooling, total compressor work is minimized when the pressure ratio of each stage is identical ($r_{p,1} = r_{p,2}$):

PintPevap=PcondPintPint, opt=PevapPcond\frac{P_{\text{int}}}{P_{\text{evap}}} = \frac{P_{\text{cond}}}{P_{\text{int}}} \quad \Longrightarrow \quad \mathbf{P_{\text{int, opt}} = \sqrt{P_{\text{evap}} \cdot P_{\text{cond}}}}

2. Direct-Contact Flash Intercooler Functions & Balances

The flash intercooler performs two essential thermodynamic functions:

  1. Desuperheating Booster Discharge Vapor: Hot discharge vapor from the booster compressor (State 2) bubbles through the saturated liquid pool in the vessel, desuperheating to dry saturated vapor (State 3, $h_3 = h_{g,\text{int}}$) before entering the high-stage compressor. This prevents overheating the high-stage compressor.
  2. Liquid Subcooling & Flash Gas Removal: High-pressure liquid throttled from $P_{\text{cond}}$ into the vessel separates into flash gas (which bypasses the evaporator entirely) and saturated liquid at $P_{\text{int}}$ (State 7, $h_7 = h_{f,\text{int}}$), which feeds the low-stage expansion valve.

Mathematical Mass Balance across Flash Intercooler

Applying mass and energy conservation to the intercooler vessel:

  • Inflows: Booster vapor ($\dot{m}{\text{low}} h_2$) + Condenser liquid ($\dot{m}{\text{high}} h_5$)
  • Outflows: High-stage suction ($\dot{m}{\text{high}} h_3$) + Liquid to evaporator ($\dot{m}{\text{low}} h_7$)

m˙lowh2+m˙highh5=m˙highh3+m˙lowh7\dot{m}_{\text{low}} h_2 + \dot{m}_{\text{high}} h_5 = \dot{m}_{\text{high}} h_3 + \dot{m}_{\text{low}} h_7

m˙high(h3h5)=m˙low(h2h7)\dot{m}_{\text{high}} (h_3 - h_5) = \dot{m}_{\text{low}} (h_2 - h_7)

m˙highm˙low=h2hf,inthg,inthf,cond\mathbf{\frac{\dot{m}_{\text{high}}}{\dot{m}_{\text{low}}} = \frac{h_2 - h_{f,\text{int}}}{h_{g,\text{int}} - h_{f,\text{cond}}}}

m˙low=Q˙evaph1h7=Q˙evaph1hf,int\dot{m}_{\text{low}} = \frac{\dot{Q}_{\text{evap}}}{h_1 - h_7} = \frac{\dot{Q}_{\text{evap}}}{h_1 - h_{f,\text{int}}}

W˙total=m˙low(h2h1)+m˙high(h4h3)\dot{W}_{\text{total}} = \dot{m}_{\text{low}} (h_2 - h_1) + \dot{m}_{\text{high}} (h_4 - h_3)


3. Cascade Refrigeration Systems (Two Separate Refrigerants)

When target temperatures drop below $-50^\circ\text{F}\text{ to }-120^\circ\text{F}$, a single refrigerant cannot effectively span the entire pressure range. A refrigerant that has a reasonable condensing pressure at $100^\circ\text{F}$ (e.g., R-134a) would have an evaporating pressure at $-60^\circ\text{F}$ in deep vacuum ($< 1.5\text{ psia}$), risking air infiltration and massive cylinder sizing. Conversely, a ultra-low-temperature refrigerant (e.g., R-23 or $\text{CO}2$ / R-744) has an excellent vapor density at $-60^\circ\text{F}$, but exceeds its critical pressure ($P{\text{crit}} = 1,070\text{ psia}$ for $\text{CO}_2$) at ambient condensing temperatures.

The Solution: A Cascade System connects two separate, hermetically isolated refrigeration loops via an intermediate heat exchanger called the Cascade Condenser.

+-----------------------------------------------------------------------------------------+
| CASCADE REFRIGERATION SYSTEM ARCHITECTURE (DUAL REFRIGERANT)                           |
+-----------------------------------------------------------------------------------------+
| [ HIGH-TEMPERATURE STAGE: e.g., R-134a, R-404A, or R-717 (Ammonia) ]                   |
|                                                                                         |
|       +---> [ High-Temp Compressor ] ---> [ High-Temp Condenser (Ambient Air/Water) ]-+ |
|       |                                                                               | |
|       |                                             [ High-Temp Expansion Valve ]     | |
|       |                                                         |                     | |
|       |     +=============================================+     v                     | |
|       +---- | CASCADE CONDENSER / EVAPORATOR HEAT EXCHANGER| <---+                     | |
|             | High-Temp Evaporator  <-- Absorbs Heat --+  |                           | |
|             | Low-Temp Condenser    -- Rejects Heat --+   |                           | |
|             +=============================================+                           | |
|                                                         ^                             | |
|       +-------------------------------------------------+                             | |
|       |                                             [ Low-Temp Expansion Valve ]      | |
|       |                                                         |                     | |
|       +---< [ Low-Temp Compressor ] <--- [ Low-Temp Evaporator (Ultra-Cold Load) ] <--+ |
|                                                                                         |
| [ LOW-TEMPERATURE STAGE: e.g., R-23, R-744 (CO_2), R-508B ]                             |
+-----------------------------------------------------------------------------------------+

1. Thermal Equilibrium Across the Cascade Condenser

The cascade condenser acts as the evaporator for the high-temperature circuit and the condenser for the low-temperature circuit. A finite temperature approach difference ($\Delta T_{\text{cascade}} = T_{\text{cond, low}} - T_{\text{evap, high}} \approx 5^\circ\text{F}\text{ to }10^\circ\text{F}$) drives heat transfer:

Q˙cascade=m˙low(h2,lowh3,low)=m˙high(h1,highh4,high)\dot{Q}_{\text{cascade}} = \dot{m}_{\text{low}} (h_{2,\text{low}} - h_{3,\text{low}}) = \dot{m}_{\text{high}} (h_{1,\text{high}} - h_{4,\text{high}})

2. Cascade Mass Flow Ratio

m˙highm˙low=h2,lowh3,lowh1,highh4,high=h2,lowh3,lowh1,highh3,high\mathbf{\frac{\dot{m}_{\text{high}}}{\dot{m}_{\text{low}}} = \frac{h_{2,\text{low}} - h_{3,\text{low}}}{h_{1,\text{high}} - h_{4,\text{high}}} = \frac{h_{2,\text{low}} - h_{3,\text{low}}}{h_{1,\text{high}} - h_{3,\text{high}}}}

3. Overall Cascade COP

COPcascade=Q˙evap, lowW˙comp, low+W˙comp, high=m˙low(h1,lowh4,low)m˙low(h2,lowh1,low)+m˙high(h2,highh1,high)\text{COP}_{\text{cascade}} = \frac{\dot{Q}_{\text{evap, low}}}{\dot{W}_{\text{comp, low}} + \dot{W}_{\text{comp, high}}} = \frac{\dot{m}_{\text{low}} (h_{1,\text{low}} - h_{4,\text{low}})}{\dot{m}_{\text{low}} (h_{2,\text{low}} - h_{1,\text{low}}) + \dot{m}_{\text{high}} (h_{2,\text{high}} - h_{1,\text{high}})}


4. Multi-Stage Compound vs. Cascade Systems Comparison

Feature / ParameterMulti-Stage Compound SystemCascade Refrigeration System
Working FluidSingle refrigerant throughout entire systemTwo separate, chemically distinct refrigerants
Lubrication Oil CircuitShared oil circuit; requires interstage oil separatorsCompletely separated oil circuits matched to each refrigerant
Intermediate Heat TransferDirect-contact flash mixing or shell-and-coilIndirect heat exchange across cascade heat exchanger
Intermediate Thermal LossZero temperature approach loss in direct-contact tank$5^\circ\text{F}\text{ to }10^\circ\text{F}$ approach $\Delta T$ penalty across cascade condenser
Temperature RangeDown to $-40^\circ\text{F}$ (Ammonia, R-404A, R-507A)Down to $-120^\circ\text{F}$ ($ ext{CO}_2$/R-134a, R-23/R-404A)
Standstill PressureStandard system pressures at room temperatureLow-stage refrigerant requires expansion tank during shutdown

5. NCEES Reference Handbook Navigation Tactics

  • Intermediate Pressure Formula: Search "Compound Refrigeration" or "Intermediate Pressure" in Section 7 to locate $P_i = \sqrt{P_e P_c}$.
  • Ammonia (R-717) Property Tables: Locate Ammonia tables in Section 7. Look for saturated vapor enthalpy $h_g$, saturated liquid enthalpy $h_f$, and superheated vapor entropy lines.
  • Cascade Energy Balance: Search "Cascade" to verify the mass flow ratio equation $\dot{m}_H / \dot{m}_L = \Delta h_L / \Delta h_H$.

6. Worked Computational Examples

Example 1: Two-Stage Ammonia (R-717) System with Direct Flash Intercooler

An industrial cold storage plant requires $50\text{ Tons}$ of refrigeration at an evaporating temperature of $-30^\circ\text{F}$ ($P_{\text{evap}} = 13.90\text{ psia}$) with a condensing temperature of $95^\circ\text{F}$ ($P_{\text{cond}} = 195.8\text{ psia}$). The plant utilizes a two-stage Ammonia (R-717) compound system with a direct-contact flash intercooler operating at optimal intermediate pressure $P_{\text{int}} = \sqrt{13.90 \times 195.8} = 52.17\text{ psia}$ ($T_{\text{sat, int}} = 24.0^\circ\text{F}$).

  • Booster isentropic efficiency: $\eta_{s,1} = 0.80$
  • High-stage isentropic efficiency: $\eta_{s,2} = 0.82$

Thermodynamic Properties (Ammonia R-717):

  • At $-30^\circ\text{F}$ ($13.90\text{ psia}$): $h_1 = 597.6\text{ Btu/lbm}$, $s_1 = 1.417\text{ Btu/(lbm}\cdot{}^\circ\text{R)}$
  • Booster isentropic compression to $52.2\text{ psia}$: $h_{2s} = 672.0\text{ Btu/lbm}$
  • At $24^\circ\text{F}$ ($52.2\text{ psia}$): $h_3 = h_{g,\text{int}} = 619.1\text{ Btu/lbm}$, $s_3 = 1.287\text{ Btu/(lbm}\cdot{}^\circ\text{R)}$, $h_7 = h_{f,\text{int}} = 69.3\text{ Btu/lbm}$
  • High-stage isentropic compression to $195.8\text{ psia}$: $h_{4s} = 698.5\text{ Btu/lbm}$
  • At $95^\circ\text{F}$ ($195.8\text{ psia}$): $h_5 = h_{f,\text{cond}} = 149.4\text{ Btu/lbm}$

Calculate: (a) Booster refrigerant mass flow rate ($\dot{m}{\text{low}}$), (b) High-stage mass flow rate ($\dot{m}{\text{high}}$), (c) Total compressor power ($\text{kW}$), and (d) Cycle $\text{COP}$.

Solution:

  1. Booster Mass Flow Rate: Q˙evap=50 Tons×12,000 Btu/(hrTon)=600,000 Btu/hr\dot{Q}_{\text{evap}} = 50\text{ Tons} \times 12,000\text{ Btu/(hr}\cdot\text{Ton)} = 600,000\text{ Btu/hr} qevap=h1h7=597.669.3=528.3 Btu/lbmq_{\text{evap}} = h_1 - h_7 = 597.6 - 69.3 = 528.3\text{ Btu/lbm} m˙low=600,000 Btu/hr528.3 Btu/lbm=1,135.72 lbm/hr\dot{m}_{\text{low}} = \frac{600,000\text{ Btu/hr}}{528.3\text{ Btu/lbm}} = \mathbf{1,135.72\text{ lbm/hr}}

  2. Booster Actual Discharge Enthalpy ($h_2$): h2=h1+h2sh1ηs,1=597.6+672.0597.60.80=597.6+74.40.80=597.6+93.0=690.6 Btu/lbmh_2 = h_1 + \frac{h_{2s} - h_1}{\eta_{s,1}} = 597.6 + \frac{672.0 - 597.6}{0.80} = 597.6 + \frac{74.4}{0.80} = 597.6 + 93.0 = \mathbf{690.6\text{ Btu/lbm}}

  3. High-Stage Mass Flow Rate ($\dot{m}_{\text{high}}$): m˙highm˙low=h2hf,inthg,inthf,cond=690.669.3619.1149.4=621.3469.7=1.3228\frac{\dot{m}_{\text{high}}}{\dot{m}_{\text{low}}} = \frac{h_2 - h_{f,\text{int}}}{h_{g,\text{int}} - h_{f,\text{cond}}} = \frac{690.6 - 69.3}{619.1 - 149.4} = \frac{621.3}{469.7} = 1.3228 m˙high=1,135.72 lbm/hr×1.3228=1,502.33 lbm/hr\dot{m}_{\text{high}} = 1,135.72\text{ lbm/hr} \times 1.3228 = \mathbf{1,502.33\text{ lbm/hr}}

  4. High-Stage Actual Discharge Enthalpy ($h_4$): h4=h3+h4sh3ηs,2=619.1+698.5619.10.82=619.1+79.40.82=619.1+96.8=715.9 Btu/lbmh_4 = h_3 + \frac{h_{4s} - h_3}{\eta_{s,2}} = 619.1 + \frac{698.5 - 619.1}{0.82} = 619.1 + \frac{79.4}{0.82} = 619.1 + 96.8 = \mathbf{715.9\text{ Btu/lbm}}

  5. Total Compressor Power: W˙booster=m˙low(h2h1)=1,135.72×(690.6597.6)=1,135.72×93.0=105,622 Btu/hr\dot{W}_{\text{booster}} = \dot{m}_{\text{low}} (h_2 - h_1) = 1,135.72 \times (690.6 - 597.6) = 1,135.72 \times 93.0 = 105,622\text{ Btu/hr} W˙high=m˙high(h4h3)=1,502.33×(715.9619.1)=1,502.33×96.8=145,426 Btu/hr\dot{W}_{\text{high}} = \dot{m}_{\text{high}} (h_4 - h_3) = 1,502.33 \times (715.9 - 619.1) = 1,502.33 \times 96.8 = 145,426\text{ Btu/hr} W˙total=105,622+145,426=251,048 Btu/hr\dot{W}_{\text{total}} = 105,622 + 145,426 = 251,048\text{ Btu/hr} Power [kW]=251,048 Btu/hr3,412.14 Btu/(kWhr)=73.57 kW(1.471 kW/ton)\text{Power [kW]} = \frac{251,048\text{ Btu/hr}}{3,412.14\text{ Btu/(kW}\cdot\text{hr)}} = \mathbf{73.57\text{ kW}} \quad (1.471\text{ kW/ton})

  6. Cycle COP: COP=Q˙evapW˙total=600,000251,048=2.390\text{COP} = \frac{\dot{Q}_{\text{evap}}}{\dot{W}_{\text{total}}} = \frac{600,000}{251,048} = \mathbf{2.390}


Example 2: Cascade System Performance ($ ext{CO}_2$ / R-134a)

A $30\text{-Ton}$ blast freezer is cooled by a cascade system comprising a low-temperature $\text{CO}_2$ (R-744) loop and a high-temperature R-134a loop.

  • $\text{CO}2$ Evaporating: $T{\text{evap, low}} = -50^\circ\text{F}$ ($h_1 = 138.5\text{ Btu/lbm}$, $h_2 = 159.2\text{ Btu/lbm}$, $h_3 = h_4 = 31.8\text{ Btu/lbm}$)
  • Cascade Condenser Approach: $\Delta T_{\text{cascade}} = 10^\circ\text{F}$ ($\text{CO}_2$ condenses at $10^\circ\text{F}$, R-134a boils at $0^\circ\text{F}$)
  • R-134a Loop: $T_{\text{evap, high}} = 0^\circ\text{F}$ ($h_1 = 103.1\text{ Btu/lbm}$, $h_2 = 120.4\text{ Btu/lbm}$, $h_3 = h_4 = 44.4\text{ Btu/lbm}$)

Calculate: (a) $\text{CO}_2$ mass flow rate, (b) Heat rejected across the cascade condenser, (c) R-134a mass flow rate, and (d) Total system COP.

Solution:

  1. $\text{CO}_2$ Mass Flow Rate: Q˙evap=30 Tons×12,000 Btu/(hrTon)=360,000 Btu/hr\dot{Q}_{\text{evap}} = 30\text{ Tons} \times 12,000\text{ Btu/(hr}\cdot\text{Ton)} = 360,000\text{ Btu/hr} m˙low=360,000h1,lowh4,low=360,000138.531.8=360,000106.7=3,373.95 lbm/hr\dot{m}_{\text{low}} = \frac{360,000}{h_{1,\text{low}} - h_{4,\text{low}}} = \frac{360,000}{138.5 - 31.8} = \frac{360,000}{106.7} = \mathbf{3,373.95\text{ lbm/hr}}
  2. Heat Rejected in Cascade Condenser: Q˙cascade=m˙low(h2,lowh3,low)=3,373.95×(159.231.8)=3,373.95×127.4=429,841 Btu/hr\dot{Q}_{\text{cascade}} = \dot{m}_{\text{low}} (h_{2,\text{low}} - h_{3,\text{low}}) = 3,373.95 \times (159.2 - 31.8) = 3,373.95 \times 127.4 = \mathbf{429,841\text{ Btu/hr}}
  3. R-134a Mass Flow Rate: m˙high=Q˙cascadeh1,highh4,high=429,841103.144.4=429,84158.7=7,322.67 lbm/hr\dot{m}_{\text{high}} = \frac{\dot{Q}_{\text{cascade}}}{h_{1,\text{high}} - h_{4,\text{high}}} = \frac{429,841}{103.1 - 44.4} = \frac{429,841}{58.7} = \mathbf{7,322.67\text{ lbm/hr}}
  4. Compressor Work & System COP: W˙low=3,373.95×(159.2138.5)=3,373.95×20.7=69,841 Btu/hr\dot{W}_{\text{low}} = 3,373.95 \times (159.2 - 138.5) = 3,373.95 \times 20.7 = 69,841\text{ Btu/hr} W˙high=7,322.67×(120.4103.1)=7,322.67×17.3=126,682 Btu/hr\dot{W}_{\text{high}} = 7,322.67 \times (120.4 - 103.1) = 7,322.67 \times 17.3 = 126,682\text{ Btu/hr} W˙total=69,841+126,682=196,523 Btu/hr\dot{W}_{\text{total}} = 69,841 + 126,682 = 196,523\text{ Btu/hr} COPcascade=360,000 Btu/hr196,523 Btu/hr=1.832\text{COP}_{\text{cascade}} = \frac{360,000\text{ Btu/hr}}{196,523\text{ Btu/hr}} = \mathbf{1.832}
Test Your Knowledge

What is the primary thermodynamic rationale for selecting a cascade refrigeration system over a multi-stage compound system for ultra-low temperature applications (-60°F to -100°F)?

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Test Your Knowledge

An industrial two-stage Ammonia (R-717) refrigeration cycle operates between an evaporating pressure of 16.0 psia and a condensing pressure of 196.0 psia. What is the optimal intermediate pressure (P_int) that minimizes total compressor work?

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Test Your Knowledge

In a two-stage compound refrigeration system with a direct-contact flash intercooler, the booster compressor delivers 2,000 lbm/hr of vapor at discharge enthalpy h_2 = 680 Btu/lbm. Saturated vapor leaves the intercooler at h_g,int = 615 Btu/lbm, saturated liquid leaves at h_f,int = 70 Btu/lbm, and condenser liquid enters at h_f,cond = 145 Btu/lbm. What is the mass flow rate handled by the high-stage compressor?

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Test Your Knowledge

A cascade condenser heat exchanger transfers heat from a low-stage CO2 circuit to a high-stage R-134a circuit. The CO2 enters at h_in = 155.0 Btu/lbm and condenses to h_out = 35.0 Btu/lbm at a flow rate of 1,500 lbm/hr. If the R-134a enters at h_in = 45.0 Btu/lbm and evaporates to h_out = 105.0 Btu/lbm, what is the required mass flow rate of R-134a?

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