11.3 Control Valves: 2-Way vs 3-Way, Valve Authority (N), Cv Calculations & Characteristic Curves

Key Takeaways

  • The valve flow coefficient ($C_v$) represents the volumetric flow of $60^\circ\text{F}$ water in GPM that creates a $1.0\text{ psi}$ pressure drop across the fully open valve: $Q = C_v \sqrt{\Delta P / \text{SG}}$.
  • Equal Percentage ($=\%$) control valve characteristics are paired with nonlinear cooling/heating coils to produce an overall linear thermal output response across valve stroke.
  • Valve Authority ($N = \frac{\Delta P_{\text{valve, 100\%}}}{\Delta P_{\text{branch, total}}}$) quantifies the ratio of wide-open valve pressure drop to total branch pressure drop; design authority should satisfy $N \ge 0.25\text{ to }0.50$ to prevent distortion into quick-opening behavior.
  • Two-way modulating control valves enable variable-flow distribution and pump energy savings, whereas three-way valves (mixing or diverting) maintain constant branch flow.
  • Pressure Independent Control Valves (PICVs) combine a dynamic differential pressure regulator with a modulating control valve, guaranteeing an effective valve authority of $N = 1.0$ under all dynamic system pressures.
Last updated: August 2026

11.3 Control Valves: 2-Way vs 3-Way, Valve Authority (N), Cv Calculations & Characteristic Curves

Automatic control valves regulate the rate of hydronic fluid flow through heat transfer coils in response to temperature, humidity, or process controllers. Selecting the proper valve flow coefficient ($C_v$), inherent trim characteristic, and valve authority ($N$) ensures stable proportional-integral-derivative (PID) control, prevents actuator hunting, preserves chiller/boiler $\Delta T$, and minimizes pumping energy. On the PE Mechanical: HVAC and Refrigeration exam, engineers must perform precise $C_v$ calculations, evaluate installed valve characteristic distortion, calculate valve authority ratios, and distinguish between two-way, three-way, and pressure-independent configurations.


1. Valve Flow Coefficient ($C_v$) & Governing Hydraulics

The flow capacity of a control valve is universally characterized by the Flow Coefficient ($C_v$), defined as the volumetric flow rate of clean water at $60^\circ\text{F}$ ($\text{SG} = 1.00$) in gallons per minute ($\text{GPM}$) that passes through the fully open valve with a pressure drop of exactly $1.0\text{ psi}$ ($2.31\text{ ft w.g.}$).

+---------------------------------------------------------------------------------------------------------+
|                                    CONTROL VALVE HYDRAULIC EQUATIONS                                    |
+---------------------------------------------------------------------------------------------------------+
| Flow Equation:           Q = C_v * sqrt( Delta_P / SG )                                                 |
|                                                                                                         |
| Required Valve C_v:      C_v = Q / sqrt( Delta_P / SG )                                                 |
|                                                                                                         |
| Valve Pressure Drop:     Delta_P = SG * ( Q / C_v )^2   [psi]                                           |
|                          Delta_H = 2.31 * ( Q / C_v )^2 [ft w.g. for water, SG = 1.0]                   |
+---------------------------------------------------------------------------------------------------------+

Where:

  • $Q$ = Volumetric flow rate ($\text{GPM}$)
  • $C_v$ = Valve flow coefficient ($\text{GPM/psi}^{0.5}$)
  • $\Delta P$ = Pressure drop across valve ports ($\text{psi}$)
  • $\Delta H$ = Head loss across valve ($\text{ft w.g.}$)
  • $\text{SG}$ = Specific gravity of fluid ($1.00$ for water at $60^\circ\text{F}$; $\approx 1.03\text{ to }1.08$ for glycol mixtures)

Choked Flow & Cavitation in Hydronic Valves

When water accelerates through the restricted valve orifice (vena contracta), static pressure drops to its minimum ($P_{\text{vc}}$). If $P_{\text{vc}}$ falls below the water's saturation vapor pressure ($P_v$), vapor bubbles form (flashing). As fluid decelerates downstream, pressure recovers; if downstream pressure exceeds $P_v$, the vapor bubbles violently collapse against valve trim surfaces (cavitation), generating high-frequency noise, vibration, and severe pitting erosion.

  • Cavitation Index ($\sigma$): σ=Pinlet, absPvPinlet, absPoutlet, abs=P1PvΔP\sigma = \frac{P_{\text{inlet, abs}} - P_v}{P_{\text{inlet, abs}} - P_{\text{outlet, abs}}} = \frac{P_1 - P_v}{\Delta P} Cavitation occurs when $\sigma < \sigma_{\text{critical}}$ (typically $\sigma < 1.5\text{ to }2.0$). To prevent cavitation, engineers must avoid excessive single-valve pressure drops in high-temperature hot water loops.

2. Inherent vs. Installed Valve Characteristic Curves

The inherent characteristic describes the relationship between valve flow capacity ($C_v$) and valve stem position (stroke, $h/h_{\text{max}}$) under a constant pressure drop across the valve.

   Flow (% of Q_max)
      100 +                                    . - - - - - - [ Quick Opening ]
          |                              . - '
          |                      . - '                 / [ Linear ]
          |              . - '                       /
          |      . - '                             /   . - - [ Equal Percentage ]
          |  . '                                 / . '
       50 +                                    / . '
          |                                  / . '
          |                                / . '
          |                              /. '
          |                            / . '
          |                         /. '
        0 +------------------------+-------------------------------------------> Valve Stroke (%)
          0                       50                                         100%

A. The Three Inherent Flow Characteristics

  1. Quick Opening: Provides maximum flow at low stem travel ($80%$ flow at $25%$ stroke). Primarily used for two-position (on/off) isolation or safety dump bypass service.
  2. Linear: Flow rate is directly proportional to stem stroke: $\frac{Q}{Q_{\text{max}}} = \frac{h}{h_{\text{max}}}$. Used in constant-pressure applications, steam coils, or liquid level control.
  3. Equal Percentage ($=%$): Equal increments of stem travel produce equal percentage changes in the existing flow rate: dQdh=cQ    Q=QmaxR(hhmax1)\frac{dQ}{dh} = c \cdot Q \implies Q = Q_{\text{max}} \cdot R^{\left(\frac{h}{h_{\text{max}}} - 1\right)} Where $R$ is the valve rangeability ($R = Q_{\text{max}} / Q_{\text{min}}$, typically $30\text{ to }50$). At low stroke, small absolute changes occur; at high stroke, large absolute changes occur.

B. Why Equal Percentage Valves are Essential for Hydronic Coils

Hydronic cooling and heating coils exhibit a highly non-linear, concave-downward thermal heat transfer characteristic. Because the logarithmic mean temperature difference (LMTD) and turbulent tube heat transfer coefficients saturate early, $50%$ water flow delivers approximately $85%\text{ to }90%$ of total coil heat transfer.

IDEAL THERMAL LINEARIZATION VIA EQUAL PERCENTAGE TRIM:

[ Non-linear Coil Heat Transfer ]   x   [ Equal % Valve Flow Curve ]   =   [ Linear Installed Thermal Output ]
 (Concave Downward Response)             (Convex Upward Response)              (Direct Proportional Control)

    Thermal Output (%)                      Water Flow (%)                        Thermal Output (%)
   100 +        . - - - - -                100 +                 . - '           100 +                 /
       |    . '                                |             . - '                   |               /
       |  /                                    |         . - '                       |             /
    50 + /                                  50 +     . - '                        50 +           /
       |/                                      | . - '                               |         /
     0 +----+----+----+----+                 0 +----+----+----+----+               0 +----+----+----+----+
       0   25   50   75  100                   0   25   50   75  100                 0   25   50   75  100
          Water Flow (%)                          Valve Stroke (%)                      Valve Stroke (%)

By pairing an Equal Percentage valve (convex upward) with a Hydronic Coil (concave downward), the non-linearities cancel each other out, producing an overall linear thermal response ($Q_{\text{thermal}} \propto \text{valve stroke}$) essential for stable PID loop tuning.

3. Valve Authority ($N$) & Installed Characteristic Distortion

In an actual operating piping circuit, the pressure drop across the control valve is not constant. As the valve closes, total circuit flow decreases, causing friction losses in the coil and piping to decrease towards zero. Consequently, the differential pressure across the closing valve increases toward the total available pump head.

Mathematical Definition of Valve Authority ($N$)

Valve Authority ($N$) (also designated as $a$) is the ratio of the pressure drop across the fully open control valve at design flow to the total pressure drop across the entire variable-flow branch circuit (valve + coil + balance valve + branch piping):

N=ΔPvalve, 100%ΔPbranch, total=ΔPvalve, 100%ΔPvalve, 100%+ΔPcoil+ΔPpiping\mathbf{N = \frac{\Delta P_{\text{valve, 100\%}}}{\Delta P_{\text{branch, total}}} = \frac{\Delta P_{\text{valve, 100\%}}}{\Delta P_{\text{valve, 100\%}} + \Delta P_{\text{coil}} + \Delta P_{\text{piping}}}}

+---------------------------------------------------------------------------------------------------------+
|                                    VALVE AUTHORITY DESIGN BOUNDARIES                                    |
+-----------------------+---------------------------------------------------------------------------------+
| Authority Ratio (N)   | Operational Control Impact                                                      |
+-----------------------+---------------------------------------------------------------------------------+
| **N >= 0.50**         | **Ideal Design Standard:** Inherent equal percentage curve is minimally         |
| (50% to 100%)         | distorted; provides precise, stable modulating control across full load range.  |
+-----------------------+---------------------------------------------------------------------------------+
| **0.25 <= N < 0.50**  | **Acceptable Commercial Range:** Slight distortion towards linear; acceptable   |
|                       | control for typical variable-speed distribution systems.                        |
+-----------------------+---------------------------------------------------------------------------------+
| **N < 0.25**          | **Unacceptable (Oversized Valve):** Inherent equal percentage curve distorts    |
| (Severe Distortion)   | into a Quick Opening profile. Valve acts like an on/off switch near the seat,   |
|                       | causing violent temperature hunting, valve wear, and Low Delta-T Syndrome.      |
+-----------------------+---------------------------------------------------------------------------------+

Mathematical Relation for Installed Flow:

Qinstalled(h)=Qdesign1+N[(Cv,maxCv(h))21]Q_{\text{installed}}(h) = \frac{Q_{\text{design}}}{\sqrt{1 + N \left[ \left(\frac{C_{v,\text{max}}}{C_v(h)}\right)^2 - 1 \right]}}

INSTALLED CHARACTERISTIC SHIFT AS AUTHORITY (N) DECREASES:

   Flow (%)
      100 +--------------------------------------------/ (N = 0.50 - Proper Equal % Curve)
          |                                        . -'
          |                                  . - '
          |                          . - - '
          |                  . - - '             (N = 0.10 - Distorts to Quick Opening!)
          |          . - - '
          |  . - - '
       50 + '
          |
          |
        0 +------------------------+-------------------------------------------> Stroke (%)
          0                       50                                         100%

When $N = 0.10$ (valve pressure drop is only $10%$ of branch total), an Equal Percentage valve behaves as a Quick Opening valve, releasing over $70%$ of design flow at only $20%$ stem travel.

4. 2-Way vs. 3-Way Valves & Pressure Independent Valves (PICV)

+---------------------------------------------------------------------------------------------------------+
|                                 CONTROL VALVE ARCHITECTURE COMPARISON                                   |
+-----------------------+-----------------------------+---------------------------------------------------+
| Valve Type            | Flow Modulated              | Primary Applications & Mechanical Behavior        |
+-----------------------+-----------------------------+---------------------------------------------------+
| **2-Way Modulating**  | Variable coil flow;         | Standard for variable-volume primary and          |
|                       | variable system flow        | secondary systems; requires VFD pumps.            |
+-----------------------+-----------------------------+---------------------------------------------------+
| **3-Way Mixing**      | Variable coil flow;         | Two inlets, one common outlet. Constant total     |
|                       | constant system loop flow   | loop flow; installed on coil RETURN line.         |
+-----------------------+-----------------------------+---------------------------------------------------+
| **3-Way Diverting**   | Variable coil flow;         | One common inlet, two outlets. Constant total     |
|                       | constant system loop flow   | loop flow; installed on coil SUPPLY line.         |
+-----------------------+-----------------------------+---------------------------------------------------+
| **PICV (Pressure**    | Variable coil flow;         | Combines DP regulator, control valve, and balance |
| **Independent)**      | constant N = 1.0 authority  | valve; immune to upstream/downstream pressure.    |
+-----------------------+-----------------------------+---------------------------------------------------+
3-WAY VALVE CONFIGURATIONS:

       3-WAY MIXING (Installed on Return):           3-WAY DIVERTING (Installed on Supply):
       2 Inlets (A & B) -> 1 Common Outlet (AB)      1 Common Inlet (AB) -> 2 Outlets (A & B)

       From Supply ===> [ COIL ] ===> Port A         From Supply ===> Port AB ===+===> [ COIL ] ===> Return
                                        |                                        |     (Port A)
                                        v                                        v
                                    [ MIXING ] ===> Return                   [ DIVERT ] ===> Bypass Pipe
                                        ^
                                        |                                      (Port B)
       Bypass Pipe ================= Port B

Pressure Independent Control Valves (PICVs)

A Pressure Independent Control Valve (PICV) integrates three mechanical devices into a single valve body:

  1. An internal modulating control valve (actuated by DDC/thermostat).
  2. An internal mechanical differential pressure regulator (spring-loaded diaphragm).
  3. An adjustable flow limiter / manual balance valve.
+---------------------------------------------------------------------------------------------------------+
|                                    HOW A PICV REGULATES SYSTEM FLOW                                     |
+---------------------------------------------------------------------------------------------------------+
| 1. System pressure fluctuations (caused by other valves opening/closing) act on the internal diaphragm. |
| 2. The diaphragm automatically adjusts an internal variable orifice to absorb the pressure variation,   |
|    maintaining a constant Delta_P across the control valve plug at all times.                           |
| 3. Because Delta_P across the control plug is held perfectly constant:                                 |
|                                                                                                         |
|                        Valve Authority is ALWAYS N = 1.0 (100%)                                         |
|                                                                                                         |
| 4. Hunting, overflow, dynamic balancing labor, and Low Delta-T Syndrome are completely eliminated.       |
+---------------------------------------------------------------------------------------------------------+

5. Worked Engineering Calculation: Control Valve Sizing & Authority

Problem Statement

An air handling unit (AHU) chilled water cooling coil delivers $600,000\text{ Btu/hr}$ of sensible and latent cooling. Chilled water enters the coil at $44.0^\circ\text{F}$ and leaves at $56.0^\circ\text{F}$ ($\Delta T = 12.0^\circ\text{F}$). The fluid is clean water ($\text{SG} = 1.00$).

Hydraulic piping data for the branch circuit:

  • Cooling coil pressure drop at design flow: $\Delta P_{\text{coil}} = 5.80\text{ psi}$ ($13.40\text{ ft w.g.}$)
  • Branch circuit piping, isolation valves, and strainer drop: $\Delta P_{\text{piping}} = 1.70\text{ psi}$ ($3.93\text{ ft w.g.}$)
  • Target design valve authority: $N = 0.50$ (50%)

Available commercial equal-percentage 2-way control valves have the following standard rated $C_v$ values: Available Cv:[25.0,  35.0,  45.0,  60.0,  80.0]\text{Available } C_v: \quad [\, 25.0, \; 35.0, \; 45.0, \; 60.0, \; 80.0 \,]

Calculate:

  1. The design water flow rate ($Q$) in GPM.
  2. The ideal target valve pressure drop ($\Delta P_{\text{valve, target}}$) and target $C_v$.
  3. Select the closest standard commercial valve $C_v$ and compute the actual wide-open valve pressure drop ($\Delta P_{\text{valve, actual}}$).
  4. Compute the actual installed valve authority ($N_{\text{actual}}$) and verify if it satisfies engineering standards.

Step-by-Step Solution

Step 1: Calculate Design Water Flow Rate ($Q$)

q˙=500QΔT    Q=q˙500ΔT\dot{q} = 500 \cdot Q \cdot \Delta T \implies Q = \frac{\dot{q}}{500 \cdot \Delta T}

Q=600,000 Btu/hr500×12.0F=600,0006,000=100.0 GPMQ = \frac{600,000\text{ Btu/hr}}{500 \times 12.0^\circ\text{F}} = \frac{600,000}{6,000} = \mathbf{100.0\text{ GPM}}

Step 2: Determine Target Valve $\Delta P$ and Target $C_v$

Total circuit resistance excluding the valve: ΔPcircuit=ΔPcoil+ΔPpiping=5.80 psi+1.70 psi=7.50 psi\Delta P_{\text{circuit}} = \Delta P_{\text{coil}} + \Delta P_{\text{piping}} = 5.80\text{ psi} + 1.70\text{ psi} = 7.50\text{ psi}

Applying the valve authority definition for $N = 0.50$: N=ΔPvalveΔPvalve+ΔPcircuit=0.50    ΔPvalve, target=ΔPcircuit=7.50 psiN = \frac{\Delta P_{\text{valve}}}{\Delta P_{\text{valve}} + \Delta P_{\text{circuit}}} = 0.50 \implies \Delta P_{\text{valve, target}} = \Delta P_{\text{circuit}} = \mathbf{7.50\text{ psi}}

Calculate target flow coefficient ($C_v$): Cv,target=QΔPvalve/SG=100.0 GPM7.50/1.00=100.02.7386=36.51C_{v,\text{target}} = \frac{Q}{\sqrt{\Delta P_{\text{valve}} / \text{SG}}} = \frac{100.0\text{ GPM}}{\sqrt{7.50 / 1.00}} = \frac{100.0}{2.7386} = \mathbf{36.51}

Step 3: Select Standard Valve and Compute Actual $\Delta P_{\text{valve}}$

From the available commercial options ($[25, 35, 45, 60, 80]$), the closest standard size is $C_v = 35.0$.

Compute actual wide-open pressure drop with $C_v = 35.0$: ΔPvalve, actual=SG(QCv)2=1.00×(100.035.0)2=(2.8571)2=8.16 psi(18.86 ft w.g.)\Delta P_{\text{valve, actual}} = \text{SG} \cdot \left(\frac{Q}{C_v}\right)^2 = 1.00 \times \left(\frac{100.0}{35.0}\right)^2 = (2.8571)^2 = \mathbf{8.16\text{ psi}} \quad (18.86\text{ ft w.g.})

(Note: If an engineer improperly selected the oversized $C_v = 60.0$ valve, the valve drop would plummet to $(100/60)^2 = 2.78\text{ psi}$).

Step 4: Calculate Actual Installed Valve Authority ($N_{\text{actual}}$)

ΔPbranch, total=ΔPvalve, actual+ΔPcircuit=8.16 psi+7.50 psi=15.66 psi\Delta P_{\text{branch, total}} = \Delta P_{\text{valve, actual}} + \Delta P_{\text{circuit}} = 8.16\text{ psi} + 7.50\text{ psi} = 15.66\text{ psi}

Nactual=ΔPvalve, actualΔPbranch, total=8.16 psi15.66 psi=0.521(52.1%)N_{\text{actual}} = \frac{\Delta P_{\text{valve, actual}}}{\Delta P_{\text{branch, total}}} = \frac{8.16\text{ psi}}{15.66\text{ psi}} = \mathbf{0.521} \quad (\mathbf{52.1\%})

Engineering Conclusion: The selected $C_v = 35.0$ valve achieves an actual authority of $52.1%$, perfectly satisfying the target design standard ($N \ge 0.50$). The installed characteristic will maintain its equal percentage profile with virtually zero distortion, ensuring stable PID modulation across the full operating range.


6. NCEES Reference Handbook Navigation Strategies

  • Valve Flow Equations: Look up $Q = C_v \sqrt{\Delta P / SG}$ and $\Delta P = SG (Q / C_v)^2$ in the Hydraulics / Fluids section. Remember that pressure drop $\Delta P$ is in psi, while head loss $\Delta H$ is in feet of water ($\Delta H = 2.31 \times \Delta P$).
  • Specific Gravity (SG) Conversions: For glycol mixtures (propylene or ethylene glycol), always incorporate fluid specific gravity ($\text{SG} > 1.0$) into $C_v$ calculations; omitting $\text{SG}$ leads to undersized control valves.
  • Valve Authority Definition: Search "Valve Authority" ($N = \Delta P_{\text{valve}} / \Delta P_{\text{total}}$). Remember that total branch drop in the denominator MUST include the valve's own pressure drop.
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Control Valve Authority & Installed Characteristic Behavior
Test Your Knowledge

A heating hot water terminal coil requires 40.0 GPM of water (SG = 1.00). The coil pressure drop is 4.0 psi and branch piping drop is 2.0 psi. If the designer specifies an equal percentage 2-way control valve with a target authority of N = 0.50, what is the required valve flow coefficient (Cv)?

A
B
C
D
Test Your Knowledge

Why are Equal Percentage (=%) inherent flow characteristics universally specified for modulating control valves on hydronic cooling and heating coils rather than Linear characteristics?

A
B
C
D
Test Your Knowledge

An air handling unit cooling coil branch has a total pressure drop of 16.0 psi at design flow. The 2-way control valve installed in the branch has a wide-open pressure drop of 2.0 psi. What is the valve authority (N), and what operational problem will occur?

A
B
C
D
Test Your Knowledge

Which statement correctly describes the hydraulic operation and benefits of a Pressure Independent Control Valve (PICV)?

A
B
C
D