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12.1 Waves, Speed of Sound, Standing Waves & Doppler Effect

Key Takeaways

  • Mechanical waves require an elastic material medium for propagation, dividing into transverse waves (particles oscillate perpendicular to wave velocity, propagating through solids and liquid surfaces) and longitudinal waves (particles oscillate parallel to wave velocity as compressions and rarefactions, propagating through solids, liquids, and gases).

  • The speed of sound in air is governed by the Laplace adiabatic correction v=γPρv = \sqrt{\frac{\gamma P}{\rho}} (where γ=1.4\gamma = 1.4 for diatomic air) rather than Newton's isothermal formula v=Pρv = \sqrt{\frac{P}{\rho}}, exhibiting temperature dependence vt≈v0+0.61tv_t \approx v_0 + 0.61 t where v0≈332 m/sv_0 \approx 332\text{ m/s} at 0∘C0^\circ\text{C}.

  • Superposition of two identical counter-propagating waves produces stationary (standing) waves characterized by permanent nodes (zero displacement, maximum pressure variation) and antinodes (maximum displacement, minimum pressure variation) spaced at intervals of λ2\frac{\lambda}{2}, with adjacent node-antinode separation of λ4\frac{\lambda}{4}.

  • Boundary conditions dictate resonant harmonic series: fixed strings and open organ pipes generate all integer harmonics (fn=nv2Lf_n = n \frac{v}{2L} for n=1,2,3,…n=1,2,3,\dots), whereas closed organ pipes generate only odd integer harmonics (fn=(2n−1)v4Lf_n = (2n-1)\frac{v}{4L} for n=1,2,3,…n=1,2,3,\dots), making open pipes acoustically richer.

  • The Doppler effect produces observed frequency shifts due to relative motion: source motion alters the physical wavelength (f′=fvv∓usf' = f \frac{v}{v \mp u_s}), whereas observer motion alters the rate of wavefront interception (f′=fv±uovf' = f \frac{v \pm u_o}{v}), serving as the foundational tool for astronomical redshift and blueshift.

Last updated: October 2026

Waves, Speed of Sound, Standing Waves & Doppler Effect

In the Intermediate Physics Part I syllabus and the University of Engineering and Technology (UET) ECAT entry test, wave mechanics, acoustics, and the Doppler effect are heavily weighted areas. Engineering entrance questions test speed-of-sound corrections, boundary-dependent standing wave harmonics, beat frequencies, and multi-case Doppler shift calculations without calculators. Mastering the fundamental derivations and physical mechanisms behind these concepts provides immediate analytical advantages.


1. Nature of Waves and Wave Kinematics

A wave is a physical disturbance that travels through space or an elastic medium, transporting energy and momentum from one location to another without transporting matter. Waves are broadly classified into two categories:

  1. Mechanical Waves: Require an elastic, inertial material medium for propagation (e.g., sound waves, water ripples, seismic waves, vibrations in stretched strings).
  2. Electromagnetic Waves: Periodic oscillations of orthogonal electric and magnetic fields that propagate through vacuum at the speed of light c=3.0×108 m/sc = 3.0 \times 10^8\text{ m/s} as well as through transparent material media (e.g., light, radio waves, X-rays).

Mechanical Waves: Transverse vs. Longitudinal

Mechanical waves depend entirely on the restoring force (elasticity) and inertial properties (density) of the transmitting medium:

  • Transverse Waves: The particles of the medium oscillate perpendicular to the direction of wave propagation. Transverse mechanical waves propagate as alternating crests (points of maximum positive displacement) and troughs (points of maximum negative displacement). Because transverse waves require shear elasticity to sustain lateral displacements, they can propagate only through solid media and across liquid surfaces (under surface tension and gravity), but cannot travel through the interior of liquids or gases.
  • Longitudinal Waves: The particles of the medium oscillate parallel to the direction of wave propagation. Longitudinal waves propagate as alternating regions of compressions (high density, high pressure) and rarefactions (low density, low pressure). Because all states of matter (solids, liquids, and gases) possess volume elasticity (bulk modulus), longitudinal waves travel through all three phases. Sound in air is strictly longitudinal.

The Fundamental Wave Speed Equation

For any periodic wave of frequency ff, period T=1fT = \frac{1}{f}, and wavelength λ\lambda (the spatial distance between two successive points in identical phase, such as two consecutive crests or compressions):

v=DistanceTime=λT=fλv = \frac{\text{Distance}}{\text{Time}} = \frac{\lambda}{T} = f\lambda

In angular notation, with angular frequency ω=2πf\omega = 2\pi f and wave number (propagation constant) k=2πλk = \frac{2\pi}{\lambda}:

v=ωkv = \frac{\omega}{k}

ECAT Conceptual Rule: The frequency ff of a wave is determined exclusively by the source and remains strictly invariant when the wave crosses the boundary between two different media. By contrast, the wave speed vv is determined strictly by the physical properties of the medium. Consequently, when a wave enters a medium where its speed changes, its wavelength λ=vf\lambda = \frac{v}{f} changes proportionally.


2. Speed of Sound in Gases: Newton vs. Laplace

The speed of a longitudinal mechanical wave through an elastic fluid of bulk modulus EE and density ρ\rho is given by the hydrodynamic relation:

v=Eρv = \sqrt{\frac{E}{\rho}}

Newton's Formula (Isothermal Assumption)

Sir Isaac Newton assumed that when sound travels through air, the compressions and rarefactions occur so slowly that heat generated during compression escapes to the surroundings, and heat lost during rarefaction is absorbed from the surroundings. Consequently, Newton assumed the acoustic process is isothermal (T=constantT = \text{constant}).

Applying Boyle's law for an ideal gas at constant temperature:

PV=constantP V = \text{constant}

Differentiating both sides with respect to volume:

P(dV)+V(dP)=0  ⟹  P=−dPdV/V=ETP(dV) + V(dP) = 0 \implies P = -\frac{dP}{dV / V} = E_T

Thus, the isothermal bulk modulus ETE_T equals the ambient equilibrium pressure PP. Substituting ET=PE_T = P into the wave speed formula yields Newton's formula for the speed of sound:

v=Pρv = \sqrt{\frac{P}{\rho}}

At standard temperature and pressure (STP: P=1.013×105 N/m2P = 1.013 \times 10^5\text{ N/m}^2, ρ=1.293 kg/m3\rho = 1.293\text{ kg/m}^3 for dry air):

vNewton=1.013×1051.293≈280 m/sv_{\text{Newton}} = \sqrt{\frac{1.013 \times 10^5}{1.293}} \approx 280\text{ m/s}

The experimentally observed speed of sound in air at 0∘C0^\circ\text{C} is approximately 332 m/s332\text{ m/s}. Newton's theoretical value is about 16%16\% lower than the true physical value. This discrepancy proved that Newton's isothermal assumption was incorrect.

Laplace's Correction (Adiabatic Assumption)

In 1816, the French mathematician Pierre-Simon Laplace identified the flaw in Newton's reasoning. Sound waves in air oscillate at audible frequencies (20 Hz20\text{ Hz} to 20,000 Hz20{,}000\text{ Hz}). At these rapid oscillation rates:

  1. Compressions and rarefactions occur extremely fast.
  2. Air is a poor thermal conductor.

Therefore, heat has no time to flow between compressions and rarefactions. The propagation of sound is an adiabatic process (Q=0Q = 0), not an isothermal one.

For an adiabatic process in an ideal gas:

PVγ=constantP V^\gamma = \text{constant}

where γ=CpCv\gamma = \frac{C_p}{C_v} is the ratio of molar heat capacities (the adiabatic index). Differentiating both sides:

P(γVγ−1dV)+VγdP=0P(\gamma V^{\gamma-1} dV) + V^\gamma dP = 0

Dividing through by Vγ−1V^{\gamma-1}:

γPdV+VdP=0  ⟹  γP=−dPdV/V=ES\gamma P dV + V dP = 0 \implies \gamma P = -\frac{dP}{dV / V} = E_S

Thus, the adiabatic bulk modulus ESE_S is γ\gamma times the pressure: ES=γPE_S = \gamma P. Substituting this into the hydrodynamic formula yields Laplace's corrected formula for the speed of sound:

v=γPρv = \sqrt{\frac{\gamma P}{\rho}}

Air consists primarily of diatomic molecules (N2\text{N}_2 and O2\text{O}_2), for which γ=1.40\gamma = 1.40 (or 75\frac{7}{5}). Substituting STP values:

vLaplace=1.4×1.013×1051.293=1.4×280 m/s≈1.183×280 m/s≈332 m/sv_{\text{Laplace}} = \sqrt{\frac{1.4 \times 1.013 \times 10^5}{1.293}} = \sqrt{1.4} \times 280\text{ m/s} \approx 1.183 \times 280\text{ m/s} \approx 332\text{ m/s}

Laplace's corrected theoretical value matches experimental measurements within experimental uncertainty.


3. Physical Factors Affecting the Speed of Sound in Air

1. Effect of Pressure

Using the ideal gas equation PM=ρRT  ⟹  Pρ=RTMP M = \rho R T \implies \frac{P}{\rho} = \frac{R T}{M}, we express Laplace's formula as:

v=γRTMv = \sqrt{\frac{\gamma R T}{M}}

If the pressure of a gas changes while its temperature TT remains constant, the density ρ\rho changes in direct proportion (Boyle's law: Pρ=constant\frac{P}{\rho} = \text{constant}). Consequently, the speed of sound is completely independent of pressure changes at constant temperature.

2. Effect of Temperature

Because v=γRTMv = \sqrt{\frac{\gamma R T}{M}}, the speed of sound is directly proportional to the square root of the absolute thermodynamic temperature TT (in Kelvin):

v∝T  ⟹  v1v2=T1T2v \propto \sqrt{T} \implies \frac{v_1}{v_2} = \sqrt{\frac{T_1}{T_2}}

To find the speed of sound vtv_t at a temperature tt in Celsius (T=T0+tT = T_0 + t, where T0=273.15 KT_0 = 273.15\text{ K}):

vt=v0T0+tT0=v0(1+t273.15)1/2v_t = v_0\sqrt{\frac{T_0 + t}{T_0}} = v_0\left(1 + \frac{t}{273.15}\right)^{1/2}

Applying the binomial expansion for t≪273.15t \ll 273.15:

vt≈v0(1+12⋅t273.15)=v0+(v0546.3)tv_t \approx v_0\left(1 + \frac{1}{2} \cdot \frac{t}{273.15}\right) = v_0 + \left(\frac{v_0}{546.3}\right)t

Taking v0=332 m/sv_0 = 332\text{ m/s}:

332546.3≈0.61 m/s per ∘C\frac{332}{546.3} \approx 0.61\text{ m/s per }^\circ\text{C}

vt=v0+0.61tv_t = v_0 + 0.61 t

ECAT Speed Rule: For every 1∘C1^\circ\text{C} rise in temperature, the speed of sound in air increases by approximately 0.61 m/s0.61\text{ m/s} (about 61 cm/s61\text{ cm/s}); the linear rule is an approximation that works near ordinary temperatures.

3. Effect of Moisture (Humidity)

The molar mass of water vapor (MH2O=18 g/molM_{\text{H}_2\text{O}} = 18\text{ g/mol}) is significantly less than the effective molar mass of dry air (Mair≈29 g/molM_{\text{air}} \approx 29\text{ g/mol}). Consequently, adding moisture decreases the effective density ρ\rho of humid air relative to dry air at identical temperature and pressure. Because v=γPρv = \sqrt{\frac{\gamma P}{\rho}}, sound travels faster in humid air than in dry air.

4. Effect of Wind

If wind blows with velocity ww at an angle θ\theta relative to the sound propagation vector, the effective speed of sound observed on the ground is the vector sum:

veff=v+wcos⁡θv_{\text{eff}} = v + w\cos\theta


4. Principle of Superposition & Standing (Stationary) Waves

The Superposition Principle

When two or more waves traverse the same elastic medium simultaneously, the resultant displacement of any particle of the medium at any instant is the vector sum of the individual displacements caused by each wave:

y(x,t)=y1(x,t)+y2(x,t)+⋯+yn(x,t)y(x, t) = y_1(x, t) + y_2(x, t) + \dots + y_n(x, t)

Depending on the frequencies, directions, and phases of the interfering waves, superposition manifests as:

  1. Interference: Superposition of two waves of identical frequency propagating in the same direction.
  2. Beats: Superposition of two waves of slightly different frequencies propagating in the same direction.
  3. Stationary (Standing) Waves: Superposition of two waves of identical amplitude, frequency, and wavelength propagating in opposite directions.

Mathematical Formulation of Standing Waves

Consider two identical sinusoidal waves travelling along a stretched string in opposite directions:

y1(x,t)=Asin⁡(kx−ωt),y2(x,t)=Asin⁡(kx+ωt)y_1(x, t) = A\sin(kx - \omega t), \quad y_2(x, t) = A\sin(kx + \omega t)

Applying the trigonometric identity sin⁡(A−B)+sin⁡(A+B)=2sin⁡Acos⁡B\sin(A - B) + \sin(A + B) = 2\sin A\cos B:

y(x,t)=y1+y2=2Asin⁡(kx)cos⁡(ωt)y(x, t) = y_1 + y_2 = 2A\sin(kx)\cos(\omega t)

This expression describes a stationary wave:

  • The spatial term A′(x)=2Asin⁡(kx)A'(x) = 2A\sin(kx) represents the position-dependent amplitude of oscillation.
  • The temporal term cos⁡(ωt)\cos(\omega t) shows that all particles oscillate in simple harmonic motion with frequency ω\omega, but with different amplitudes.
  • There is no travelling phase factor of the form (kx±ωt)(kx \pm \omega t); hence, wave energy is trapped between boundaries and does not propagate along the medium.

Nodes and Antinodes

  1. Nodes (NN): Points where the amplitude is permanently zero: A′(x)=0A'(x) = 0.

sin⁡(kx)=0  ⟹  kx=nπ  ⟹  2πλx=nπ  ⟹  x=nλ2(n=0,1,2,3,… )\sin(kx) = 0 \implies kx = n\pi \implies \frac{2\pi}{\lambda}x = n\pi \implies x = n\frac{\lambda}{2} \quad (n = 0, 1, 2, 3, \dots)

  • Position of nodes: x=0,λ2,λ,3λ2,…x = 0, \frac{\lambda}{2}, \lambda, \frac{3\lambda}{2}, \dots
  • Distance between two consecutive nodes: dN−N=λ2d_{N-N} = \frac{\lambda}{2}.
  • At nodes, displacement is zero, but strain and pressure variations are maximum.
  1. Antinodes (AA): Points where the amplitude reaches maximum value: A′(x)=±2AA'(x) = \pm 2A.

sin⁡(kx)=±1  ⟹  kx=(n+12)π  ⟹  2πλx=(2n+1)π2  ⟹  x=(2n+1)λ4\sin(kx) = \pm 1 \implies kx = \left(n + \frac{1}{2}\right)\pi \implies \frac{2\pi}{\lambda}x = (2n+1)\frac{\pi}{2} \implies x = (2n+1)\frac{\lambda}{4}

  • Position of antinodes: x=λ4,3λ4,5λ4,…x = \frac{\lambda}{4}, \frac{3\lambda}{4}, \frac{5\lambda}{4}, \dots
  • Distance between two consecutive antinodes: dA−A=λ2d_{A-A} = \frac{\lambda}{2}.
  • Distance between an adjacent node and antinode: dN−A=λ4d_{N-A} = \frac{\lambda}{4}.

5. Resonant Standing Waves in Stretched Strings & Organ Pipes

1. Stretched String Fixed at Both Ends

A string of length LL, tension TT, and linear mass density (mass per unit length) m=MLm = \frac{M}{L} supports transverse waves with speed:

v=Tmv = \sqrt{\frac{T}{m}}

Because both ends are rigidly clamped, displacement nodes must occur at x=0x = 0 and x=Lx = L. This boundary condition requires that the length LL equals an integer number of half-wavelengths:

L=nλn2  ⟹  λn=2Ln(n=1,2,3,… )L = n\frac{\lambda_n}{2} \implies \lambda_n = \frac{2L}{n} \quad (n = 1, 2, 3, \dots)

The resonant natural frequencies (harmonics) are:

fn=vλn=nv2L=n2LTm=nf1f_n = \frac{v}{\lambda_n} = n\frac{v}{2L} = \frac{n}{2L}\sqrt{\frac{T}{m}} = n f_1

  • Fundamental Frequency (First Harmonic, n=1n = 1): f1=v2L=12LTmf_1 = \frac{v}{2L} = \frac{1}{2L}\sqrt{\frac{T}{m}}, with 2 nodes and 1 antinode.
  • Second Harmonic (First Overtone, n=2n = 2): f2=2f1f_2 = 2f_1, with 3 nodes and 2 antinodes.
  • Third Harmonic (Second Overtone, n=3n = 3): f3=3f1f_3 = 3f_1, with 4 nodes and 3 antinodes.
  • Harmonic Series: Stretched strings produce all integer harmonics (f1:f2:f3:⋯=1:2:3:…f_1 : f_2 : f_3 : \dots = 1 : 2 : 3 : \dots).

2. Standing Waves in Organ Pipes

In an acoustic pipe, air molecules at a closed end cannot oscillate longitudinally, creating a displacement node (pressure antinode). At an open end, air molecules oscillate freely into the open atmosphere, creating a displacement antinode (pressure node).

A. Open Organ Pipe (Both Ends Open)

Both ends must be displacement antinodes. The resonant condition requires:

L=nλn2  ⟹  λn=2Ln  ⟹  fn=nv2L=nf1(n=1,2,3,… )L = n\frac{\lambda_n}{2} \implies \lambda_n = \frac{2L}{n} \implies f_n = n\frac{v}{2L} = n f_1 \quad (n = 1, 2, 3, \dots)

  • Fundamental mode (n=1n = 1): L=λ12  ⟹  f1,open=v2LL = \frac{\lambda_1}{2} \implies f_{1,\text{open}} = \frac{v}{2L}.
  • Open organ pipes produce all integer harmonics (1:2:3:4:…1 : 2 : 3 : 4 : \dots).

B. Closed Organ Pipe (One End Closed, One End Open)

The closed end is a displacement node; the open end is an antinode. The length must accommodate an odd number of quarter-wavelengths:

L=(2n−1)λn4  ⟹  λn=4L2n−1  ⟹  fn=(2n−1)v4L=(2n−1)f1(n=1,2,3,… )L = (2n - 1)\frac{\lambda_n}{4} \implies \lambda_n = \frac{4L}{2n - 1} \implies f_n = (2n - 1)\frac{v}{4L} = (2n - 1)f_1 \quad (n = 1, 2, 3, \dots)

  • Fundamental mode (n=1n = 1): L=λ14  ⟹  f1,closed=v4LL = \frac{\lambda_1}{4} \implies f_{1,\text{closed}} = \frac{v}{4L}.
  • Third harmonic (First overtone, n=2n = 2): f2=3f1,closedf_2 = 3f_{1,\text{closed}}.
  • Fifth harmonic (Second overtone, n=3n = 3): f3=5f1,closedf_3 = 5f_{1,\text{closed}}.
  • Closed organ pipes produce only odd harmonics (1:3:5:7:…1 : 3 : 5 : 7 : \dots).

ECAT Key Relationship: For pipes of identical physical length LL: f1,closed=12f1,openf_{1,\text{closed}} = \frac{1}{2} f_{1,\text{open}} An open pipe has twice the fundamental frequency of a closed pipe of the same length and is acoustically richer in tonal quality because all harmonics are present.


6. Acoustic Beats

When two sound waves of slightly different frequencies f1f_1 and f2f_2 (typically ∣f1−f2∣≤10 Hz|f_1 - f_2| \le 10\text{ Hz}) travel along the same path in the same direction, their superposition produces periodic waxing and waning of sound intensity known as beats.

Let the displacements be y1=Asin⁡(2πf1t)y_1 = A\sin(2\pi f_1 t) and y2=Asin⁡(2πf2t)y_2 = A\sin(2\pi f_2 t). By trigonometric identity:

y=y1+y2=[2Acos⁡(2πf1−f22t)]sin⁡(2πf1+f22t)y = y_1 + y_2 = \left[2A\cos\left(2\pi\frac{f_1 - f_2}{2}t\right)\right] \sin\left(2\pi\frac{f_1 + f_2}{2}t\right)

The modulated amplitude is Amod=2Acos⁡(2πf1−f22t)A_{\text{mod}} = 2A\cos\left(2\pi\frac{f_1 - f_2}{2}t\right). Intensity is proportional to Amod2A_{\text{mod}}^2, reaching maximum when cos⁡=±1\cos = \pm 1:

Frequency of intensity maxima (Beat Frequency):fbeat=∣f1−f2∣\text{Frequency of intensity maxima (Beat Frequency):} \quad f_{\text{beat}} = |f_1 - f_2|

Practical Applications of Beats

  1. Tuning Musical Instruments: A musician sounds an instrument alongside a standard tuning fork. The tension is adjusted until the beat frequency decreases to zero, indicating perfect unison (f1=f2f_1 = f_2).
  2. Detection of Toxic Mine Gases: Two identical resonant pipes, one filled with pure air and the other exposed to mine air, sound simultaneously. If methane or coal gas is present, the speed of sound inside changes, producing audible beats that warn miners.

7. The Doppler Effect

The Doppler effect is the apparent change in the observed frequency (or pitch) of a wave when there is relative motion between the source of waves and the observer.

Let vv be the speed of sound in the stationary medium, ff the true source frequency, and λ=vf\lambda = \frac{v}{f} the stationary wavelength.

Case 1: Observer Moving, Source Stationary (us=0u_s = 0)

When the source is stationary, the physical wavelength λ\lambda in the medium remains unchanged. The observer moves relative to the wavefronts, altering the relative speed of wave interception:

  • Observer moves toward stationary source with speed uou_o: Relative speed of sound is v′=v+uov' = v + u_o.

f′=v′λ=v+uov/f=f(v+uov)>ff' = \frac{v'}{\lambda} = \frac{v + u_o}{v / f} = f\left(\frac{v + u_o}{v}\right) > f

  • Observer moves away from stationary source with speed uou_o: Relative speed of sound is v′=v−uov' = v - u_o.

f′=v′λ=v−uov/f=f(v−uov)<ff' = \frac{v'}{\lambda} = \frac{v - u_o}{v / f} = f\left(\frac{v - u_o}{v}\right) < f

Case 2: Source Moving, Observer Stationary (uo=0u_o = 0)

When the source moves, it compresses or stretches the physical wavelength in the medium before the waves reach the observer:

  • Source moves toward stationary observer with speed usu_s: Wavefronts are compressed in front of the source. During one period T=1fT = \frac{1}{f}, the source advances by distance usTu_s T. The modified wavelength is λ′=λ−usT=v−usf\lambda' = \lambda - u_s T = \frac{v - u_s}{f}.

f′=vλ′=f(vv−us)>ff' = \frac{v}{\lambda'} = f\left(\frac{v}{v - u_s}\right) > f

  • Source moves away from stationary observer with speed usu_s: Wavefronts are stretched behind the source: λ′=λ+usT=v+usf\lambda' = \lambda + u_s T = \frac{v + u_s}{f}.

f′=vλ′=f(vv+us)<ff' = \frac{v}{\lambda'} = f\left(\frac{v}{v + u_s}\right) < f

Generalized Doppler Formula

Combining both motions into a single universal equation:

f′=f(v±uov∓us)f' = f\left(\frac{v \pm u_o}{v \mp u_s}\right)

  • Upper signs (+uo,−us+u_o, -u_s): Used for approaching motion (frequency increases).
  • Lower signs (−uo,+us-u_o, +u_s): Used for receding motion (frequency decreases).

Asymmetry of the Doppler Effect in Sound

Because sound requires a material medium, motion of the source is physically distinct from motion of the observer:

  • If observer moves toward stationary source at u=0.5vu = 0.5v: f′=f(1+0.5)=1.5ff' = f(1 + 0.5) = 1.5 f.
  • If source moves toward stationary observer at u=0.5vu = 0.5v: f′=f(11−0.5)=2.0ff' = f\left(\frac{1}{1 - 0.5}\right) = 2.0 f.

Thus, the frequency shift is greater when the source moves than when the observer moves at the same speed.

Astronomical Doppler Effect: Redshift and Blueshift

For light, electromagnetic waves do not require a material medium. For velocities u≪cu \ll c:

Δff=∣Δλ∣λ≈uc\frac{\Delta f}{f} = \frac{|\Delta \lambda|}{\lambda} \approx \frac{u}{c}

  1. Redshift (Receding Celestial Bodies): If a distant star or galaxy recedes from Earth, the observed wavelength increases toward the longer-wavelength red end of the optical spectrum. Edwin Hubble used this redshift to discover cosmic expansion (Hubble's Law: v=H0dv = H_0 d).
  2. Blueshift (Approaching Celestial Bodies): If a celestial object moves toward Earth, the observed wavelength shifts toward shorter blue wavelengths (f′>ff' > f).

8. Standing Waves and Doppler Formulas Summary Table

Phenomenon / Acoustic SystemBoundary / Physical ConditionGoverning FormulaKey Physical Characteristics
Newton's Speed of SoundIsothermal process (T=constT = \text{const})v=Pρv = \sqrt{\frac{P}{\rho}}Theoretical value 280 m/s280\text{ m/s} (16%16\% error due to ignoring rapid heat insulation)
Laplace's Speed of SoundAdiabatic process (Q=0,γ=1.4Q = 0, \gamma = 1.4)v=γPρv = \sqrt{\frac{\gamma P}{\rho}}Theoretical value 332 m/s332\text{ m/s} at STP; matches experimental velocity in air
Temperature DependenceThermal expansion of gasvt=v0+0.61tv_t = v_0 + 0.61 tSpeed increases by 0.61 m/s0.61\text{ m/s} for each 1∘C1^\circ\text{C} rise; v∝Tv \propto \sqrt{T}
Stretched StringBoth ends fixed (displacement nodes)fn=nv2L=n2LTmf_n = n\frac{v}{2L} = \frac{n}{2L}\sqrt{\frac{T}{m}}Produces all integer harmonics (n=1,2,3,…n = 1, 2, 3, \dots); transverse waves
Open Organ PipeBoth ends open (displacement antinodes)fn=nv2L=nf1f_n = n\frac{v}{2L} = n f_1Produces all integer harmonics (1:2:3:4:…1:2:3:4:\dots); longitudinal waves
Closed Organ PipeOne end closed (node), one open (antinode)fn=(2n−1)v4Lf_n = (2n-1)\frac{v}{4L}Produces only odd integer harmonics (1:3:5:7:…1:3:5:7:\dots); f1,closed=12f1,openf_{1,\text{closed}} = \frac{1}{2}f_{1,\text{open}}
Acoustic BeatsTwo waves of frequencies f1,f2f_1, f_2fbeat=∣f1−f2∣f_{\text{beat}} = \lvert f_1 - f_2 \rvertPeriodic amplitude modulation; used for tuning and hazardous mine gas detection
Doppler: Observer ApproachesSource stationary (us=0u_s = 0), uou_o towardf′=f(v+uov)f' = f\left(\frac{v + u_o}{v}\right)Relative velocity increases; physical wavelength λ\lambda remains unchanged
Doppler: Observer RecedesSource stationary (us=0u_s = 0), uou_o awayf′=f(v−uov)f' = f\left(\frac{v - u_o}{v}\right)Relative velocity decreases; physical wavelength λ\lambda remains unchanged
Doppler: Source ApproachesObserver stationary (uo=0u_o = 0), usu_s towardf′=f(vv−us)f' = f\left(\frac{v}{v - u_s}\right)Wavelength compresses (λ′=λ−usT\lambda' = \lambda - u_s T); larger shift than observer motion
Doppler: Source RecedesObserver stationary (uo=0u_o = 0), usu_s awayf′=f(vv+us)f' = f\left(\frac{v}{v + u_s}\right)Wavelength stretches (λ′=λ+usT\lambda' = \lambda + u_s T); pitch decreases
General Doppler RelationArbitrary collinear motionf′=f(v±uov∓us)f' = f\left(\frac{v \pm u_o}{v \mp u_s}\right)Upper signs for approaching; lower signs for receding
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Comprehensive Doppler Effect Decision Flowchart
Test Your Knowledge

An open organ pipe of length L1L_1 and a closed organ pipe of length L2L_2 are vibrating in their fundamental modes. If their fundamental frequencies are identical, what is the ratio of their lengths L1L2\frac{L_1}{L_2}?

A

1:11 : 1

B

2:12 : 1

C

1:21 : 2

D

4:14 : 1

Test Your Knowledge

A railway engine sounding a whistle of frequency 500 Hz500\text{ Hz} approaches a stationary observer on a platform with a uniform speed equal to 15\frac{1}{5} of the speed of sound in air (us=0.2vu_s = 0.2v). What frequency does the observer perceive?

A

400 Hz400\text{ Hz}

B

550 Hz550\text{ Hz}

C

600 Hz600\text{ Hz}

D

625 Hz625\text{ Hz}

Test Your Knowledge

At what Celsius temperature will the speed of sound in air become double its value measured at 0∘C0^\circ\text{C}?

A

819∘C819^\circ\text{C}

B

546∘C546^\circ\text{C}

C

1092∘C1092^\circ\text{C}

D

273∘C273^\circ\text{C}

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