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9.2 Vector Addition, Components, Scalar & Vector Products in Physics

Key Takeaways

  • Scalars are fully specified by magnitude and algebraic units alone, whereas vectors require magnitude, physical orientation, and compliance with the head-to-tail triangle law of vector addition.

  • Orthogonal vector resolution decomposes a coplanar vector into Ax=Acos⁡θA_x = A\cos\theta and Ay=Asin⁡θA_y = A\sin\theta, allowing the resultant of multiple coplanar vectors to be solved via R=(∑Ax)2+(∑Ay)2R = \sqrt{(\sum A_x)^2 + (\sum A_y)^2} with quadrant-specific angle corrections.

  • The scalar (dot) product A⋅B=ABcos⁡θ\mathbf{A} \cdot \mathbf{B} = AB\cos\theta is commutative and governs mechanical work (W=F⋅dW = \mathbf{F} \cdot \mathbf{d}), instantaneous power (P=F⋅vP = \mathbf{F} \cdot \mathbf{v}), and magnetic flux (ΦB=B⋅A\Phi_B = \mathbf{B} \cdot \mathbf{A}), vanishing when vectors are orthogonal.

  • The vector (cross) product A×B=(ABsin⁡θ)n^\mathbf{A} \times \mathbf{B} = (AB\sin\theta)\hat{\mathbf{n}} is anti-commutative (A×B=−(B×A)\mathbf{A} \times \mathbf{B} = -(\mathbf{B} \times \mathbf{A})) and yields an axial vector perpendicular to both vectors via the right-hand rule, governing torque (τ=r×F\boldsymbol{\tau} = \mathbf{r} \times \mathbf{F}), angular momentum (L=r×p\mathbf{L} = \mathbf{r} \times \mathbf{p}), and magnetic Lorentz forces (F=qv×B\mathbf{F} = q\mathbf{v} \times \mathbf{B}).

  • The geometric magnitude ∣A×B∣|\mathbf{A} \times \mathbf{B}| equals the area of the parallelogram formed by the vectors, while 12∣A×B∣\frac{1}{2}|\mathbf{A} \times \mathbf{B}| yields the enclosed triangle area; both cross products vanish identically for collinear or antiparallel vectors.

Last updated: October 2026

Vector Addition, Components, Scalar & Vector Products in Physics

In the Intermediate Physics Part I syllabus and the ECAT examination, vector mechanics serves as the core mathematical framework for kinematics, dynamics, and electrodynamics. ECAT questions frequently require candidates to resolve forces into perpendicular components, determine resultant vectors across different quadrants, and evaluate dot and cross products to compute physical quantities such as work, instantaneous power, torque, and magnetic forces under strict time limits.


1. Scalars, Vectors & Geometric Representations

Physical quantities are divided into two fundamental groups based on their directional dependence:

  1. Scalars: Quantities possessing magnitude and physical units but no spatial direction. Scalars combine according to ordinary arithmetic. Examples include mass, time, speed, distance, temperature, electric charge, work, energy, electrical potential, and density.
  2. Vectors: Quantities possessing both magnitude and spatial direction that combine strictly according to vector addition laws (such as the parallelogram or head-to-tail triangle law). Examples include displacement, velocity, acceleration, force, weight, linear momentum, impulse, torque, electric field intensity, and magnetic flux density.

Essential Vector Classifications

  • Unit Vector (A^\hat{\mathbf{A}}): A dimensionless vector with a magnitude of exactly 1 used solely to designate a spatial direction. Defined as the ratio of a vector to its magnitude:

A^=A∣A∣\hat{\mathbf{A}} = \frac{\mathbf{A}}{|\mathbf{A}|}

In 3D Cartesian coordinates, orthogonal unit vectors i^,j^,k^\hat{\mathbf{i}}, \hat{\mathbf{j}}, \hat{\mathbf{k}} designate the positive x,y,zx, y, z axes respectively, with magnitudes ∣i^∣=∣j^∣=∣k^∣=1|\hat{\mathbf{i}}| = |\hat{\mathbf{j}}| = |\hat{\mathbf{k}}| = 1.

  • Position Vector (r\mathbf{r}): Locates a point P(x,y,z)P(x, y, z) in space relative to an origin O(0,0,0)O(0, 0, 0):

r=xi^+yj^+zk^,∣r∣=x2+y2+z2\mathbf{r} = x\hat{\mathbf{i}} + y\hat{\mathbf{j}} + z\hat{\mathbf{k}}, \quad |\mathbf{r}| = \sqrt{x^2 + y^2 + z^2}

  • Null Vector (0\mathbf{0}): A vector with zero magnitude and an arbitrary or indeterminate direction. It arises when a vector is subtracted from itself or added to its negative: A+(−A)=0\mathbf{A} + (-\mathbf{A}) = \mathbf{0}.

  • Negative of a Vector (−A-\mathbf{A}): A vector with the same magnitude as A\mathbf{A} but oriented in the exactly opposite direction (rotated by 180∘180^\circ).


2. Geometric Vector Addition and Subtraction

The Head-to-Tail Rule

To find the resultant R=A+B\mathbf{R} = \mathbf{A} + \mathbf{B} geometrically:

  1. Draw vector A\mathbf{A} to scale in its specified direction.
  2. Place the tail of vector B\mathbf{B} at the head of vector A\mathbf{A}.
  3. The resultant vector R\mathbf{R} is the directed line segment drawn from the tail of A\mathbf{A} to the head of B\mathbf{B}.

Vector addition obeys both the commutative property (A+B=B+A\mathbf{A} + \mathbf{B} = \mathbf{B} + \mathbf{A}) and the associative property ((A+B)+C=A+(B+C)(\mathbf{A} + \mathbf{B}) + \mathbf{C} = \mathbf{A} + (\mathbf{B} + \mathbf{C})).

Vector Subtraction

Vector subtraction is defined as the addition of a negative vector:

A−B=A+(−B)\mathbf{A} - \mathbf{B} = \mathbf{A} + (-\mathbf{B})

Resultant Magnitude of Two Vectors

For two vectors A\mathbf{A} and B\mathbf{B} separated by angle θ\theta:

R=A2+B2+2ABcos⁡θR = \sqrt{A^2 + B^2 + 2AB\cos\theta}

  • Parallel Vectors (θ=0∘\theta = 0^\circ): Rmax⁡=A+BR_{\max} = A + B
  • Antiparallel Vectors (θ=180∘\theta = 180^\circ): Rmin⁡=∣A−B∣R_{\min} = |A - B|
  • Perpendicular Vectors (θ=90∘\theta = 90^\circ): R=A2+B2R = \sqrt{A^2 + B^2}

ECAT Speed Insight: If ∣A+B∣=∣A−B∣|\mathbf{A} + \mathbf{B}| = |\mathbf{A} - \mathbf{B}|, squaring both sides yields A2+B2+2ABcos⁡θ=A2+B2−2ABcos⁡θ  ⟹  4ABcos⁡θ=0  ⟹  cos⁡θ=0  ⟹  θ=90∘A^2 + B^2 + 2AB\cos\theta = A^2 + B^2 - 2AB\cos\theta \implies 4AB\cos\theta = 0 \implies \cos\theta = 0 \implies \theta = 90^\circ. The vectors must be mutually perpendicular.


3. Resolution of Vectors & Component Addition

Rectangular Components in 2D

A vector A\mathbf{A} making an angle θ\theta with the positive xx-axis decomposes into two perpendicular rectangular components:

Ax=Acos⁡θ,Ay=Asin⁡θA_x = A\cos\theta, \quad A_y = A\sin\theta

A=Axi^+Ayj^\mathbf{A} = A_x\hat{\mathbf{i}} + A_y\hat{\mathbf{j}}

A=∣A∣=Ax2+Ay2,θ=arctan⁡(AyAx)A = |\mathbf{A}| = \sqrt{A_x^2 + A_y^2}, \quad \theta = \arctan\left(\frac{A_y}{A_x}\right)

Analytical Addition by Rectangular Components

For a system of nn coplanar vectors A1,A2,…,An\mathbf{A}_1, \mathbf{A}_2, \dots, \mathbf{A}_n:

  1. Calculate the algebraic sum of all horizontal components:

Rx=∑i=1nAix=A1x+A2x+⋯+AnxR_x = \sum_{i=1}^n A_{ix} = A_{1x} + A_{2x} + \dots + A_{nx}

  1. Calculate the algebraic sum of all vertical components:

Ry=∑i=1nAiy=A1y+A2y+⋯+AnyR_y = \sum_{i=1}^n A_{iy} = A_{1y} + A_{2y} + \dots + A_{ny}

  1. Determine the magnitude of the resultant vector:

R=Rx2+Ry2R = \sqrt{R_x^2 + R_y^2}

  1. Determine the direction θ\theta relative to the positive xx-axis by first computing the reference acute angle ϕ=arctan⁡(∣Ry∣∣Rx∣)\phi = \arctan\left(\frac{|R_y|}{|R_x|}\right) and applying quadrant corrections:
QuadrantComponent SignsDirection Angle θ\theta
Quadrant IRx>0,Ry>0R_x > 0, R_y > 0θ=ϕ\theta = \phi
Quadrant IIRx<0,Ry>0R_x < 0, R_y > 0θ=180∘−ϕ\theta = 180^\circ - \phi
Quadrant IIIRx<0,Ry<0R_x < 0, R_y < 0θ=180∘+ϕ\theta = 180^\circ + \phi
Quadrant IVRx>0,Ry<0R_x > 0, R_y < 0θ=360∘−ϕ\theta = 360^\circ - \phi

4. The Scalar (Dot) Product in Physics

The scalar product of two vectors A\mathbf{A} and B\mathbf{B} is a scalar quantity defined as the product of their magnitudes and the cosine of the angle θ\theta between them:

A⋅B=ABcos⁡θ\mathbf{A} \cdot \mathbf{B} = AB\cos\theta

In rectangular components:

A⋅B=AxBx+AyBy+AzBz\mathbf{A} \cdot \mathbf{B} = A_x B_x + A_y B_y + A_z B_z

Fundamental Properties of the Dot Product

  1. Commutative Property: A⋅B=B⋅A\mathbf{A} \cdot \mathbf{B} = \mathbf{B} \cdot \mathbf{A}.
  2. Orthogonality Criterion: Two non-zero vectors are perpendicular if and only if their dot product vanishes:

A⊥B  ⟺  A⋅B=0\mathbf{A} \perp \mathbf{B} \iff \mathbf{A} \cdot \mathbf{B} = 0

  1. Unit Vector Relations:
    • i^⋅i^=j^⋅j^=k^⋅k^=1\hat{\mathbf{i}} \cdot \hat{\mathbf{i}} = \hat{\mathbf{j}} \cdot \hat{\mathbf{j}} = \hat{\mathbf{k}} \cdot \hat{\mathbf{k}} = 1
    • i^⋅j^=j^⋅k^=k^⋅i^=0\hat{\mathbf{i}} \cdot \hat{\mathbf{j}} = \hat{\mathbf{j}} \cdot \hat{\mathbf{k}} = \hat{\mathbf{k}} \cdot \hat{\mathbf{i}} = 0
  2. Self-Product: A⋅A=A2  ⟹  A=A⋅A\mathbf{A} \cdot \mathbf{A} = A^2 \implies A = \sqrt{\mathbf{A} \cdot \mathbf{A}}.
  3. Angle Between Two Vectors:

cos⁡θ=A⋅BAB=AxBx+AyBy+AzBzAx2+Ay2+Az2Bx2+By2+Bz2\cos\theta = \frac{\mathbf{A} \cdot \mathbf{B}}{AB} = \frac{A_x B_x + A_y B_y + A_z B_z}{\sqrt{A_x^2 + A_y^2 + A_z^2}\sqrt{B_x^2 + B_y^2 + B_z^2}}

  1. Projection of A\mathbf{A} onto B\mathbf{B}:

ProjBA=Acos⁡θ=A⋅BB=A⋅B^\text{Proj}_{\mathbf{B}}\mathbf{A} = A\cos\theta = \frac{\mathbf{A} \cdot \mathbf{B}}{B} = \mathbf{A} \cdot \hat{\mathbf{B}}

Primary Physical Applications of the Dot Product

  • Mechanical Work (WW): The work performed by a constant force F\mathbf{F} causing a displacement d\mathbf{d} is:

W=F⋅d=Fdcos⁡θW = \mathbf{F} \cdot \mathbf{d} = F d \cos\theta

When force is perpendicular to displacement (θ=90∘\theta = 90^\circ), such as normal reactions on level ground or centripetal force in circular motion, W=0W = 0.

  • Instantaneous Mechanical Power (PP): The rate at which work is performed:

P=dWdt=F⋅dddt=F⋅vP = \frac{dW}{dt} = \mathbf{F} \cdot \frac{d\mathbf{d}}{dt} = \mathbf{F} \cdot \mathbf{v}

  • Magnetic Flux (ΦB\Phi_B): The magnetic field passing through an area vector A\mathbf{A}:

ΦB=B⋅A=BAcos⁡θ\Phi_B = \mathbf{B} \cdot \mathbf{A} = BA\cos\theta

  • Electric Flux (ΦE\Phi_E): ΦE=E⋅A\Phi_E = \mathbf{E} \cdot \mathbf{A}.
  • Potential Energy of a Dipole in a Field: U=−p⋅EU = -\mathbf{p} \cdot \mathbf{E} (electric dipole) and U=−μ⋅BU = -\boldsymbol{\mu} \cdot \mathbf{B} (magnetic dipole).

5. The Vector (Cross) Product in Physics

The vector product of two vectors A\mathbf{A} and B\mathbf{B} yields a vector C\mathbf{C} perpendicular to the plane containing both vectors:

A×B=(ABsin⁡θ)n^\mathbf{A} \times \mathbf{B} = (AB\sin\theta)\hat{\mathbf{n}}

where n^\hat{\mathbf{n}} is a unit normal vector whose direction is determined by the Right-Hand Rule: curl the fingers of your right hand from A\mathbf{A} toward B\mathbf{B} through the smaller angle θ\theta; your extended thumb points in the direction of n^\hat{\mathbf{n}}.

Determinant Form in Cartesian Coordinates

A×B=∣i^j^k^AxAyAzBxByBz∣=(AyBz−AzBy)i^−(AxBz−AzBx)j^+(AxBy−AyBx)k^\mathbf{A} \times \mathbf{B} = \begin{vmatrix} \hat{\mathbf{i}} & \hat{\mathbf{j}} & \hat{\mathbf{k}} \\ A_x & A_y & A_z \\ B_x & B_y & B_z \end{vmatrix} = (A_y B_z - A_z B_y)\hat{\mathbf{i}} - (A_x B_z - A_z B_x)\hat{\mathbf{j}} + (A_x B_y - A_y B_x)\hat{\mathbf{k}}

Fundamental Properties of the Cross Product

  1. Anti-Commutative Property: Reversing the order of vectors inverts the resulting direction:

A×B=−(B×A)\mathbf{A} \times \mathbf{B} = -(\mathbf{B} \times \mathbf{A})

  1. Collinearity / Parallel Criterion: If two non-zero vectors are parallel (θ=0∘\theta = 0^\circ) or antiparallel (θ=180∘\theta = 180^\circ), their cross product is zero:

A∥B  ⟺  A×B=0\mathbf{A} \parallel \mathbf{B} \iff \mathbf{A} \times \mathbf{B} = \mathbf{0}

  1. Unit Vector Cyclic Relations:
    • i^×i^=j^×j^=k^×k^=0\hat{\mathbf{i}} \times \hat{\mathbf{i}} = \hat{\mathbf{j}} \times \hat{\mathbf{j}} = \hat{\mathbf{k}} \times \hat{\mathbf{k}} = \mathbf{0}
    • i^×j^=k^,j^×k^=i^,k^×i^=j^\hat{\mathbf{i}} \times \hat{\mathbf{j}} = \hat{\mathbf{k}}, \quad \hat{\mathbf{j}} \times \hat{\mathbf{k}} = \hat{\mathbf{i}}, \quad \hat{\mathbf{k}} \times \hat{\mathbf{i}} = \hat{\mathbf{j}} (cyclic order)
    • j^×i^=−k^,k^×j^=−i^,i^×k^=−j^\hat{\mathbf{j}} \times \hat{\mathbf{i}} = -\hat{\mathbf{k}}, \quad \hat{\mathbf{k}} \times \hat{\mathbf{j}} = -\hat{\mathbf{i}}, \quad \hat{\mathbf{i}} \times \hat{\mathbf{k}} = -\hat{\mathbf{j}} (anti-cyclic)
  2. Geometric Interpretations:
    • Area of a parallelogram formed by adjacent sides A\mathbf{A} and B\mathbf{B}:

Areaparallelogram=∣A×B∣=ABsin⁡θ\text{Area}_{\text{parallelogram}} = |\mathbf{A} \times \mathbf{B}| = AB\sin\theta

  • Area of a triangle formed by vectors A\mathbf{A} and B\mathbf{B}:

Areatriangle=12∣A×B∣\text{Area}_{\text{triangle}} = \frac{1}{2}|\mathbf{A} \times \mathbf{B}|

Primary Physical Applications of the Cross Product

  • Torque (τ\boldsymbol{\tau}): The moment of a force F\mathbf{F} applied at position r\mathbf{r} relative to a pivot:

τ=r×F\boldsymbol{\tau} = \mathbf{r} \times \mathbf{F}

  • Angular Momentum (L\mathbf{L}): The moment of linear momentum p=mv\mathbf{p} = m\mathbf{v} about a reference point:

L=r×p=m(r×v)\mathbf{L} = \mathbf{r} \times \mathbf{p} = m(\mathbf{r} \times \mathbf{v})

  • Magnetic Lorentz Force on a Moving Charge:

F=q(v×B)\mathbf{F} = q(\mathbf{v} \times \mathbf{B})

  • Magnetic Force on a Current-Carrying Conductor:

F=I(L×B)\mathbf{F} = I(\mathbf{L} \times \mathbf{B})

  • Linear Velocity in Rotational Kinematics:

v=ω×r\mathbf{v} = \boldsymbol{\omega} \times \mathbf{r}


6. Comparison of Dot and Cross Products in Physics

FeatureScalar (Dot) ProductVector (Cross) Product
Mathematical FormulaA⋅B=ABcos⁡θ\mathbf{A} \cdot \mathbf{B} = AB\cos\thetaA×B=(ABsin⁡θ)n^\mathbf{A} \times \mathbf{B} = (AB\sin\theta)\hat{\mathbf{n}}
Result NaturePure scalar (magnitude, signed)Axial vector (perpendicular to plane of A,B\mathbf{A}, \mathbf{B})
CommutativityCommutative: A⋅B=B⋅A\mathbf{A} \cdot \mathbf{B} = \mathbf{B} \cdot \mathbf{A}Anti-commutative: A×B=−(B×A)\mathbf{A} \times \mathbf{B} = -(\mathbf{B} \times \mathbf{A})
Parallel Vectors (θ=0∘\theta = 0^\circ)Maximum: A⋅B=AB\mathbf{A} \cdot \mathbf{B} = ABVanishing: A×B=0\mathbf{A} \times \mathbf{B} = \mathbf{0}
Perpendicular Vectors (θ=90∘\theta = 90^\circ)Vanishing: A⋅B=0\mathbf{A} \cdot \mathbf{B} = 0Maximum: ∣A×B∣=AB\lvert\mathbf{A} \times \mathbf{B}\rvert = AB
Key Physics ExamplesWork (W=F⋅dW = \mathbf{F}\cdot\mathbf{d}), Power (P=F⋅vP = \mathbf{F}\cdot\mathbf{v}), Magnetic Flux (ΦB=B⋅A\Phi_B = \mathbf{B}\cdot\mathbf{A})Torque (τ=r×F\boldsymbol{\tau} = \mathbf{r}\times\mathbf{F}), Angular Momentum (L=r×p\mathbf{L} = \mathbf{r}\times\mathbf{p}), Lorentz Force (F=qv×B\mathbf{F} = q\mathbf{v}\times\mathbf{B})
ECAT Equality ConditionIf ∣A⋅B∣=∣A×B∣\lvert\mathbf{A} \cdot \mathbf{B}\rvert = \lvert\mathbf{A} \times \mathbf{B}\rvert, then AB∣cos⁡θ∣=ABsin⁡θ  ⟹  ∣tan⁡θ∣=1  ⟹  θ=45∘AB\lvert\cos\theta\rvert = AB\sin\theta \implies \lvert\tan\theta\rvert = 1 \implies \theta = 45^\circ or 135∘135^\circ (the angle between two vectors lies in [0∘,180∘][0^\circ, 180^\circ])
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Vector Addition and Resultant Determination by Rectangular Components
Test Your Knowledge

If the magnitude of the cross product of two non-zero vectors is 3\sqrt{3} times their scalar product, meaning ∣A×B∣=3(A⋅B)|\mathbf{A} \times \mathbf{B}| = \sqrt{3}(\mathbf{A} \cdot \mathbf{B}), what is the angle θ\theta between the two vectors?

A

30∘30^\circ

B

60∘60^\circ

C

45∘45^\circ

D

90∘90^\circ

Test Your Knowledge

A particle moves with an instantaneous velocity v=2i^−3j^+5k^ m/s\mathbf{v} = 2\hat{\mathbf{i}} - 3\hat{\mathbf{j}} + 5\hat{\mathbf{k}}\text{ m/s} under the influence of a constant force F=3i^+4j^−2k^ N\mathbf{F} = 3\hat{\mathbf{i}} + 4\hat{\mathbf{j}} - 2\hat{\mathbf{k}}\text{ N}. What is the instantaneous mechanical power delivered to the particle?

A

4 W4\text{ W}

B

−4 W-4\text{ W}

C

−16 W-16\text{ W}

D

16 W16\text{ W}

Test Your Knowledge

A force F=4i^+5j^ N\mathbf{F} = 4\hat{\mathbf{i}} + 5\hat{\mathbf{j}}\text{ N} acts at a point whose position vector relative to the origin is r=2i^−3j^ m\mathbf{r} = 2\hat{\mathbf{i}} - 3\hat{\mathbf{j}}\text{ m}. What is the torque τ=r×F\boldsymbol{\tau} = \mathbf{r} \times \mathbf{F} produced about the origin?

A

22k^ N⋅m22\hat{\mathbf{k}}\text{ N}\cdot\text{m}

B

−22k^ N⋅m-22\hat{\mathbf{k}}\text{ N}\cdot\text{m}

C

2k^ N⋅m2\hat{\mathbf{k}}\text{ N}\cdot\text{m}

D

−2k^ N⋅m-2\hat{\mathbf{k}}\text{ N}\cdot\text{m}

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