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14.1 Alternating Current: RMS Values, Reactance, Impedance, Resonance & Power

Key Takeaways

  • For a sinusoidal supply V=V0sin⁡ωtV = V_0\sin\omega t, the rms values are Vrms=V02V_{\text{rms}} = \frac{V_0}{\sqrt{2}} and Irms=I02I_{\text{rms}} = \frac{I_0}{\sqrt{2}}; Pakistan's 220 V mains is an rms value with a peak of about 311 V.

  • In a pure resistor VV and II are in phase; in a pure inductor the current lags the voltage by 90∘90^\circ with XL=ωLX_L = \omega L; in a pure capacitor the current leads by 90∘90^\circ with XC=1ωCX_C = \frac{1}{\omega C}.

  • A series RLC circuit has impedance Z=R2+(XL−XC)2Z = \sqrt{R^2 + (X_L - X_C)^2} and phase angle tan⁡ϕ=XL−XCR\tan\phi = \frac{X_L - X_C}{R}.

  • At resonance XL=XCX_L = X_C, so f0=12πLCf_0 = \frac{1}{2\pi\sqrt{LC}}; a series circuit then has minimum impedance Z=RZ = R and maximum current, while a parallel circuit has maximum impedance.

  • Average power is P=VrmsIrmscos⁡ϕP = V_{\text{rms}}I_{\text{rms}}\cos\phi; pure inductors and capacitors consume no average power, which is why a choke can limit current with little energy loss.

Last updated: October 2026

Alternating Current: RMS Values, Reactance, Impedance, Resonance & Power

An alternating current (AC) reverses direction periodically. The AC generator of Section 13.3 produces a sinusoidal emf, and almost all power distribution uses AC because transformers can step its voltage up or down efficiently. This section builds the circuit rules for AC.


1. Describing an Alternating Voltage

V=V0sin⁡ωt,ω=2πfV = V_0\sin\omega t, \qquad \omega = 2\pi f

  • V0V_0 is the peak value; the peak-to-peak value is 2V02V_0.
  • ff is the frequency (50 Hz in Pakistan) and T=1fT = \frac{1}{f} the period (20 ms at 50 Hz).
  • The average of a full sine wave is zero, so AC is described by its root-mean-square (rms) value, the steady DC value that produces the same heating in a resistor:

Vrms=V02≈0.707V0,Irms=I02V_{\text{rms}} = \frac{V_0}{\sqrt{2}} \approx 0.707V_0, \qquad I_{\text{rms}} = \frac{I_0}{\sqrt{2}}

Mains voltage quoted as 220 V is an rms value, so its peak is 2202≈311 V220\sqrt{2} \approx 311\text{ V}. AC meters normally read rms values.

The phase of an AC quantity is the angle ωt+ϕ\omega t + \phi that fixes its position in the cycle. Two quantities with the same frequency can be represented by rotating vectors (phasors) whose angle between them is the phase difference.


2. Resistor, Inductor and Capacitor in AC

ElementOpposition to currentPhase relationAverage power
Resistor RRResistance RR (independent of ff)VV and II in phaseIrms2RI_{\text{rms}}^2 R
Inductor LLInductive reactance XL=ωL=2πfLX_L = \omega L = 2\pi fLCurrent lags voltage by 90∘90^\circZero
Capacitor CCCapacitive reactance XC=1ωC=12πfCX_C = \frac{1}{\omega C} = \frac{1}{2\pi fC}Current leads voltage by 90∘90^\circZero

Memory aid: in an inductor (LL) the emf (EE) comes before the current (II): ELI; in a capacitor (CC) the current comes first: ICE.

  • XLX_L increases with frequency: an inductor blocks high frequencies. For DC (f=0f = 0), XL=0X_L = 0.
  • XCX_C decreases with frequency: a capacitor passes high frequencies and blocks DC (XC→∞X_C \to \infty as f→0f \to 0).

Example: A 0.1 H0.1\text{ H} inductor on 50 Hz mains has XL=2π(50)(0.1)≈31.4 ΩX_L = 2\pi(50)(0.1) \approx 31.4\,\Omega. A 100 μF100\,\mu\text{F} capacitor has XC=12π(50)(100×10−6)≈31.8 ΩX_C = \frac{1}{2\pi(50)(100 \times 10^{-6})} \approx 31.8\,\Omega.


3. Impedance of Series Circuits

When elements are in series, the same current flows through each, but their voltages are out of phase, so they add as phasors, not as plain numbers.

CircuitImpedance ZZPhase angle ϕ\phi (voltage relative to current)
RC seriesR2+XC2\sqrt{R^2 + X_C^2}tan⁡ϕ=−XCR\tan\phi = -\frac{X_C}{R} (current leads)
RL seriesR2+XL2\sqrt{R^2 + X_L^2}tan⁡ϕ=XLR\tan\phi = \frac{X_L}{R} (current lags)
RLC seriesR2+(XL−XC)2\sqrt{R^2 + (X_L - X_C)^2}tan⁡ϕ=XL−XCR\tan\phi = \frac{X_L - X_C}{R}

Ohm's law becomes Vrms=IrmsZV_{\text{rms}} = I_{\text{rms}}Z. The rms voltages across the separate elements can add up to more than the supply voltage; only their phasor sum equals it.

Worked example: R=30 ΩR = 30\,\Omega, XL=80 ΩX_L = 80\,\Omega, XC=40 ΩX_C = 40\,\Omega in series on a 100 V rms supply.

Z=302+(80−40)2=900+1600=50 Ω,I=10050=2 AZ = \sqrt{30^2 + (80 - 40)^2} = \sqrt{900 + 1600} = 50\,\Omega, \qquad I = \frac{100}{50} = 2\text{ A}

VR=60 VV_R = 60\text{ V}, VL=160 VV_L = 160\text{ V}, VC=80 VV_C = 80\text{ V}; check: 602+(160−80)2=100 V\sqrt{60^2 + (160 - 80)^2} = 100\text{ V}. The power factor is cos⁡ϕ=RZ=0.6\cos\phi = \frac{R}{Z} = 0.6, and the circuit is inductive (current lags).


4. Resonance

Series Resonance

As frequency changes, XLX_L rises and XCX_C falls. At the resonant frequency they are equal:

ω0L=1ω0C  ⟹  f0=12πLC\omega_0 L = \frac{1}{\omega_0 C} \implies f_0 = \frac{1}{2\pi\sqrt{LC}}

At series resonance: Z=RZ = R (minimum), the current is maximum, VV and II are in phase, and the power factor is 1. The voltage across LL or CC alone can be much larger than the supply voltage. Tuning a radio receiver adjusts CC until f0f_0 matches the wanted station.

Parallel Resonance

For LL and CC in parallel, the same resonant frequency applies, but now the circuit's impedance is maximum and the current drawn from the supply is minimum. Such a circuit (a "rejector" or tank circuit) is used to select or reject one frequency.

Property at f0f_0Series RLCParallel LC
ImpedanceMinimum (=R= R)Maximum
Line currentMaximumMinimum
UseAcceptor circuitRejector circuit

Example: L=10 mHL = 10\text{ mH} and C=1 μFC = 1\,\mu\text{F} give f0=12π10−2×10−6=12π×10−4≈1.6 kHzf_0 = \frac{1}{2\pi\sqrt{10^{-2} \times 10^{-6}}} = \frac{1}{2\pi \times 10^{-4}} \approx 1.6\text{ kHz}.


5. Power in AC Circuits

Pavg=VrmsIrmscos⁡ϕP_{\text{avg}} = V_{\text{rms}}I_{\text{rms}}\cos\phi

  • cos⁡ϕ\cos\phi is the power factor. It is 1 for a pure resistor and 0 for a pure inductor or capacitor.
  • A choke (an inductor with low resistance) can reduce the current in a circuit, for example in fluorescent lamps, while wasting very little energy, unlike a series resistor that dissipates I2RI^2R as heat.
  • Utilities prefer loads with a power factor close to 1, because a low power factor means a larger current (and larger line losses) for the same useful power.

6. Three-Phase Supply and AC Applications

  • A three-phase generator has three coils 120∘120^\circ apart, giving three voltages that are 120∘120^\circ out of phase. For a star connection, the line voltage is 3\sqrt{3} times the phase voltage: 230 V230\text{ V} phase gives about 400 V400\text{ V} between lines. Three-phase supply delivers smoother power and drives industrial motors.
  • Metal detectors use a resonant LC circuit; a metal object near the coil changes its inductance and shifts the resonant frequency, which triggers an alarm.

7. Electromagnetic Waves and Modulation

Maxwell showed that a changing electric field produces a magnetic field and vice versa, so oscillating charges radiate electromagnetic waves travelling at

c=1μ0ε0≈3×108 m/sc = \frac{1}{\sqrt{\mu_0\varepsilon_0}} \approx 3 \times 10^8\text{ m/s}

with E\mathbf{E} and B\mathbf{B} perpendicular to each other and to the direction of travel. An LC oscillator connected to an antenna generates radio waves.

To carry information, a high-frequency carrier wave is modulated by the signal:

TypeWhat changesNotes
Amplitude modulation (AM)Amplitude of the carrierMedium-wave broadcasts (hundreds of kHz to about 1.6 MHz); more affected by electrical noise
Frequency modulation (FM)Frequency of the carrierBroadcast band about 88–108 MHz; less noise, better sound quality, shorter range
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Series RLC Circuit: Reading the Phase from the Reactances
Test Your Knowledge

An AC voltmeter connected across a mains socket reads 220 V. What is the peak voltage of the supply?

A

About 155 V

B

About 311 V

C

About 440 V

D

Exactly 220 V

Test Your Knowledge

A series circuit has R=40 ΩR = 40\,\Omega, XL=50 ΩX_L = 50\,\Omega and XC=20 ΩX_C = 20\,\Omega connected to a 100 V rms supply. What is the rms current?

A

1.0 A

B

1.4 A

C

0.9 A

D

2.0 A

Test Your Knowledge

What happens to the inductive and capacitive reactances in a circuit when the supply frequency is doubled?

A

Inductive reactance doubles and capacitive reactance halves

B

Both reactances double

C

Inductive reactance halves and capacitive reactance doubles

D

Both reactances stay the same because they depend only on L and C

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