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16.3 Chemical Bonding: Ionic, Covalent & Coordinate Bonds, VSEPR, Hybridization & MOT

Key Takeaways

  • Ionic bonds form by electron transfer between atoms of low ionization energy and high electron affinity; covalent bonds form by sharing electron pairs; a coordinate (dative) bond is a shared pair donated by one atom, as in NH4+\text{NH}_4^+ and H3O+\text{H}_3\text{O}^+.

  • VSEPR theory predicts shape from electron pairs around the central atom, with repulsion order lone pair–lone pair > lone pair–bond pair > bond pair–bond pair: CH4\text{CH}_4 109.5∘109.5^\circ, NH3\text{NH}_3 107∘107^\circ, H2O\text{H}_2\text{O} 104.5∘104.5^\circ.

  • Hybridization explains these shapes: sp3sp^3 tetrahedral, sp2sp^2 trigonal planar (120∘120^\circ) and spsp linear (180∘180^\circ); a double bond is one σ\sigma plus one π\pi bond, and a triple bond one σ\sigma plus two π\pi bonds.

  • Molecular orbital theory defines bond order =12(Nb−Na)= \frac{1}{2}(N_b - N_a); it predicts that He2\text{He}_2 does not exist (bond order 0), that N2\text{N}_2 has a triple bond, and that O2\text{O}_2 is paramagnetic with two unpaired electrons.

  • Dipole moment μ=q×d\mu = q \times d (unit debye) measures polarity; symmetric molecules such as CO2\text{CO}_2, BF3\text{BF}_3 and CCl4\text{CCl}_4 are non-polar even though their bonds are polar.

Last updated: October 2026

Chemical Bonding: Ionic, Covalent & Coordinate Bonds, VSEPR, Hybridization & MOT

Chemical bonding explains why atoms combine, what shapes molecules take, and why some substances are polar, magnetic or unusually stable. It links atomic structure (Section 16.2) with intermolecular forces (Section 16.5) and the periodic trends in Section 18.1.


1. Why Atoms Bond: The Octet Rule

Atoms bond to reach a lower-energy, more stable arrangement, usually a noble-gas configuration of eight valence electrons (two for hydrogen). The octet rule has exceptions:

  • Incomplete octet: BF3\text{BF}_3 (boron has 6 valence electrons), BeCl2\text{BeCl}_2 (4).
  • Expanded octet: PCl5\text{PCl}_5 (10), SF6\text{SF}_6 (12), possible for Period 3 and heavier elements.
  • Odd-electron molecules: NO\text{NO}, NO2\text{NO}_2.

2. Types of Chemical Bond

Ionic (Electrovalent) Bond

Formed by complete transfer of electrons from a metal of low ionization energy to a non-metal of high electron affinity, followed by electrostatic attraction between the ions. Example: Na→Na++e−\text{Na} \rightarrow \text{Na}^+ + e^- and Cl+e−→Cl−\text{Cl} + e^- \rightarrow \text{Cl}^-. Ionic compounds have high melting points, conduct when molten or dissolved, and are often soluble in water. Formation is favoured by a large lattice energy.

Covalent Bond

Formed by sharing a pair of electrons: single (H−H\text{H}-\text{H}), double (O=O\text{O}=\text{O}) or triple (N≡N\text{N} \equiv \text{N}). A covalent bond between atoms of different electronegativity is polar (Hδ+−Clδ−\text{H}^{\delta+}-\text{Cl}^{\delta-}).

Coordinate Covalent (Dative) Bond

Both electrons of the shared pair come from one atom (the donor) and go to an atom with a vacant orbital (the acceptor). Once formed, it is identical to any other covalent bond.

  • NH3+H+→NH4+\text{NH}_3 + \text{H}^+ \rightarrow \text{NH}_4^+ (all four N–H bonds become equivalent)
  • H2O+H+→H3O+\text{H}_2\text{O} + \text{H}^+ \rightarrow \text{H}_3\text{O}^+
  • NH3→BF3\text{NH}_3 \rightarrow \text{BF}_3 forms the adduct H3N→BF3\text{H}_3\text{N}\rightarrow\text{BF}_3

3. VSEPR Theory and Molecular Shapes

The valence shell electron pair repulsion theory states that electron pairs around a central atom arrange themselves as far apart as possible. Lone pairs repel more strongly than bonding pairs:

lone pair–lone pair>lone pair–bond pair>bond pair–bond pair\text{lone pair–lone pair} > \text{lone pair–bond pair} > \text{bond pair–bond pair}

Electron pairs (bond + lone)Lone pairsShapeBond angleExample
20Linear180∘180^\circBeCl2\text{BeCl}_2, CO2\text{CO}_2
30Trigonal planar120∘120^\circBF3\text{BF}_3
31Bent (angular)about 119∘119^\circSO2\text{SO}_2
40Tetrahedral109.5∘109.5^\circCH4\text{CH}_4
41Trigonal pyramidal107∘107^\circNH3\text{NH}_3
42Bent (angular)104.5∘104.5^\circH2O\text{H}_2\text{O}
50Trigonal bipyramidal90∘90^\circ, 120∘120^\circPCl5\text{PCl}_5
60Octahedral90∘90^\circSF6\text{SF}_6

The steady fall from 109.5∘109.5^\circ to 107∘107^\circ to 104.5∘104.5^\circ as lone pairs replace bond pairs is a classic question. In CO2\text{CO}_2, each double bond counts as one electron-pair region.


4. Valence Bond Theory: Sigma and Pi Bonds

A covalent bond forms when half-filled atomic orbitals overlap, and the greater the overlap, the stronger the bond.

  • Sigma (σ\sigma) bond: head-on overlap along the internuclear axis (ss–ss, ss–pp, pp–pp). Free rotation is possible about a single σ\sigma bond.
  • Pi (π\pi) bond: sideways overlap of parallel pp orbitals above and below the axis. It is weaker than a σ\sigma bond and prevents rotation, which is why alkenes show cis–trans isomerism.

A single bond is one σ\sigma bond; a double bond is 1σ+1π1\sigma + 1\pi; a triple bond is 1σ+2π1\sigma + 2\pi. Ethyne, HC≡CH\text{HC}\equiv\text{CH}, therefore contains 3σ3\sigma and 2π2\pi bonds.


5. Hybridization

Atomic orbitals of similar energy on the central atom mix to form equivalent hybrid orbitals.

HybridizationOrbitals mixedGeometryAngleExamples
sp3sp^3one ss + three ppTetrahedral109.5∘109.5^\circCH4\text{CH}_4, NH3\text{NH}_3, H2O\text{H}_2\text{O} (including lone pairs)
sp2sp^2one ss + two ppTrigonal planar120∘120^\circBF3\text{BF}_3, C2H4\text{C}_2\text{H}_4, benzene
spspone ss + one ppLinear180∘180^\circBeCl2\text{BeCl}_2, C2H2\text{C}_2\text{H}_2, CO2\text{CO}_2 (carbon)

In ethene each carbon is sp2sp^2: the hybrid orbitals form σ\sigma bonds, and the unhybridized pp orbitals overlap sideways to form the π\pi bond. In ethyne each carbon is spsp with two unhybridized pp orbitals forming two π\pi bonds. Greater ss-character makes a hybrid orbital shorter and more electronegative, so C–H bonds shorten from ethane to ethene to ethyne.


6. Molecular Orbital Theory (MOT)

Atomic orbitals combine to form bonding molecular orbitals (lower energy, electron density between the nuclei) and antibonding orbitals (higher energy, marked ∗*). Electrons fill them by the Aufbau principle, Pauli principle and Hund's rule.

Bond order=12(Nb−Na)\text{Bond order} = \frac{1}{2}(N_b - N_a)

where NbN_b and NaN_a are the numbers of bonding and antibonding electrons. A higher bond order means a stronger, shorter bond; a bond order of zero means the molecule is not stable.

SpeciesBond orderMagnetic behaviourComment
H2\text{H}_21DiamagneticStable
He2\text{He}_20—Does not exist
N2\text{N}_23DiamagneticVery strong triple bond; explains nitrogen's inertness
O2\text{O}_22Paramagnetic (two unpaired electrons in π∗\pi^* orbitals)Explained by MOT, not by the Lewis structure
O2+\text{O}_2^+2.5ParamagneticStronger bond than O2\text{O}_2
O2−\text{O}_2^-1.5ParamagneticWeaker bond than O2\text{O}_2

The paramagnetism of liquid oxygen, which is attracted to a magnet, was a key success of MOT.


7. Bond Energy, Bond Length and Dipole Moment

  • Bond energy is the energy needed to break one mole of a given bond in the gas phase. It increases with bond order: C–C about 348, C=C about 614 and C≡C about 839 kJ/mol.
  • Bond length decreases as bond order increases, and increases with atomic size: H–F < H–Cl < H–Br < H–I.
  • Dipole moment μ=q×d\mu = q \times d measures the separation of charge in a polar molecule; its unit is the debye (1 D=3.34×10−30 C⋅m1\text{ D} = 3.34 \times 10^{-30}\text{ C}\cdot\text{m}).

A molecule's dipole moment is the vector sum of its bond dipoles, so shape matters:

MoleculeShapeDipole moment
CO2\text{CO}_2Linear, symmetricZero (bond dipoles cancel)
BF3\text{BF}_3, CCl4\text{CCl}_4SymmetricZero
H2O\text{H}_2\text{O}BentAbout 1.85 D (polar)
NH3\text{NH}_3PyramidalAbout 1.47 D (polar)
HCl\text{HCl}Linear diatomicAbout 1.03 D (polar)

A zero dipole moment is evidence of a symmetric shape: CO2\text{CO}_2 must be linear, whereas H2O\text{H}_2\text{O}, with a large dipole moment, must be bent.

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Predicting Shape from Electron Pairs (VSEPR)
Test Your Knowledge

Which molecule has a zero dipole moment even though it contains polar bonds?

A

NH3\text{NH}_3

B

H2O\text{H}_2\text{O}

C

BF3\text{BF}_3

D

HCl\text{HCl}

Test Your Knowledge

According to molecular orbital theory, what is the bond order of O2\text{O}_2 and how does it behave in a magnetic field?

A

Bond order 2; paramagnetic

B

Bond order 2; diamagnetic

C

Bond order 3; diamagnetic

D

Bond order 1; paramagnetic

Test Your Knowledge

How many sigma and pi bonds are present in one molecule of ethyne, HC≡CH\text{HC}\equiv\text{CH}?

A

2σ2\sigma and 3π3\pi

B

5σ5\sigma and 0π0\pi

C

3σ3\sigma and 1π1\pi

D

3σ3\sigma and 2π2\pi

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