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12.2 Wave Theory of Light, Interference & Young's Double-Slit Experiment

Key Takeaways

  • Huygens' wave principle asserts that every point on an advancing wavefront serves as a secondary source of spherical wavelets, with the new envelope tangent to these wavelets forming the subsequent wavefront, explaining reflection and Snell's law.

  • Sustained light interference requires two mutually coherent, monochromatic sources possessing identical polarization; constructive interference occurs at path difference Δx=dsin⁡θ=mλ\Delta x = d\sin\theta = m\lambda, while destructive interference occurs at Δx=(m+12)λ\Delta x = (m + \frac{1}{2})\lambda.

  • In Young's Double-Slit Experiment (YDSE), the uniform fringe spacing is Δy=λLd\Delta y = \frac{\lambda L}{d}; immersing the entire apparatus into a medium of refractive index nn scales down the wavelength (λ′=λn\lambda' = \frac{\lambda}{n}) and compresses fringe width to Δy′=Δyn\Delta y' = \frac{\Delta y}{n}.

  • Stokes' phase shift establishes that electromagnetic waves reflecting from an optically denser medium (n2>n1n_2 > n_1) undergo an intrinsic phase reversal of π\pi radians (180∘180^\circ), introducing an effective optical path addition of λ2\frac{\lambda}{2}.

  • Newton's rings produce circular interference fringes of equal thickness between a convex lens and an optical flat; the central spot viewed in reflected light is dark due to destructive interference caused by the π\pi boundary reflection phase shift.

Last updated: October 2026

Wave Theory of Light, Interference & Young's Double-Slit Experiment

In the Intermediate Physics Part I syllabus and the UET ECAT entry test, physical optics represents one of the most conceptually demanding and frequently examined domains. While geometric optics treats light as rectilinear rays, physical optics treats light as an electromagnetic wave phenomenon. ECAT problems require rapid calculation of Young's fringe spacing, thin-film optical path shifts, phase changes upon reflection, and Newton's rings geometry without numerical calculators.


1. Wavefronts and Huygens' Principle

Definition and Types of Wavefronts

A wavefront is defined as the continuous locus of all adjacent points in a wave field that oscillate with identical phase. A light ray is an oriented line drawn perpendicular to the wavefront representing the local direction of energy propagation.

Wavefront geometries depend on source topology and propagation distance:

  1. Spherical Wavefront: Emanates from an idealized isotropic point source in a homogeneous, isotropic medium. As wave energy propagates radially outward, the surfaces of constant phase are concentric spherical shells.
  2. Cylindrical Wavefront: Emanates from an extended linear slit source. The surfaces of constant phase form coaxial cylinders.
  3. Plane Wavefront: When a spherical or cylindrical wavefront travels a very large distance from its source, any small segment of the expanding curved surface approximates a flat plane. A parallel beam of light (such as sunlight reaching Earth) corresponds to plane wavefronts.

Huygens' Principle

In 1678, the Dutch physicist Christiaan Huygens formulated a geometrical construction to predict the future position of a wavefront:

  1. Every point on a primary wavefront acts as a secondary source of spherical wavelets, which spread out in all forward directions with a speed equal to the propagation speed of the wave in that medium.
  2. The new position of the wavefront at a later time t+Δtt + \Delta t is the forward surface of tangency (envelope) that touches all these secondary wavelets.

Applying Huygens' principle explains the laws of reflection (θi=θr\theta_i = \theta_r) and the laws of refraction (Snell's law: n1sin⁡θ1=n2sin⁡θ2n_1\sin\theta_1 = n_2\sin\theta_2). When a plane wavefront enters an optically denser medium (n2>n1n_2 > n_1), the wavelets travel slower (v=cnv = \frac{c}{n}), bending the advancing envelope toward the normal.


2. Interference of Light & Coherence Conditions

Interference is the physical phenomenon whereby two or more overlapping light waves superpose to produce regions of enhanced brightness (constructive interference) and reduced or zero brightness (destructive interference).

Conditions for Observable, Sustained Interference

To produce a stationary, high-contrast interference pattern on a screen, the interfering beams must satisfy four strict physical criteria:

  1. Coherence: The two light sources must maintain a constant phase difference over time. Two independent incandescent lamps, candles, or unlinked LEDs can never produce interference because emission occurs via spontaneous de-excitation of independent atoms lasting roughly 10−8 s10^{-8}\text{ s}, creating random phase fluctuations.
  2. Monochromaticity: The light waves must possess a single, identical wavelength λ\lambda (and frequency ff). If polychromatic white light is used, different wavelengths form overlapping fringes of different widths, washing out contrast except for a few colored bands.
  3. Equal or Comparable Amplitudes: If amplitudes A1≈A2A_1 \approx A_2, the resultant minimum intensity Imin⁡∝(A1−A2)2≈0I_{\min} \propto (A_1 - A_2)^2 \approx 0, yielding total darkness and maximum fringe contrast.
  4. Small Slit Separation & Large Screen Distance: The slit separation dd must be small (fractions of a millimeter) and screen distance LL large (a meter or more) to ensure wide, distinguishable fringes.

Path Difference and Phase Difference

If two coherent waves of wavelength λ\lambda travel distances x1x_1 and x2x_2 to reach a point PP, their path difference is:

Δx=∣x2−x1∣\Delta x = |x_2 - x_1|

The corresponding phase difference Δϕ\Delta \phi is related by:

Δϕ=2πλΔx\Delta \phi = \frac{2\pi}{\lambda}\Delta x

  • Constructive Interference (Bright Fringes / Maxima): Occurs when the two waves arrive in identical phase (crest meets crest, trough meets trough). This requires the path difference to be an integer multiple of the wavelength:

Δx=mλ(m=0,±1,±2,±3,… )\Delta x = m\lambda \quad (m = 0, \pm 1, \pm 2, \pm 3, \dots)

Δϕ=2mπ\Delta \phi = 2m\pi

  • Destructive Interference (Dark Fringes / Minima): Occurs when the two waves arrive in opposite phase (crest meets trough). This requires the path difference to be an odd half-integer multiple of the wavelength:

Δx=(m+12)λ(m=0,±1,±2,… )\Delta x = \left(m + \frac{1}{2}\right)\lambda \quad (m = 0, \pm 1, \pm 2, \dots)

Δϕ=(2m+1)π\Delta \phi = (2m + 1)\pi


3. Young's Double-Slit Experiment (YDSE)

In 1801, Thomas Young performed the historic double-slit experiment that conclusively established the wave nature of light. By passing sunlight through a single pinhole and then dividing it between two parallel pinholes S1S_1 and S2S_2, Young created two coherent sources from a single primary source.

Analytical Derivation of Fringe Positions

Consider two narrow parallel slits S1S_1 and S2S_2 separated by distance dd. A screen is placed at a distance LL parallel to the plane of the slits (L≫dL \gg d). Let OO be the central point on the screen equidistant from S1S_1 and S2S_2, and let PP be an arbitrary observation point at distance yy from OO.

The optical path difference between the waves arriving at PP from S2S_2 and S1S_1 is:

Δx=S2P−S1P\Delta x = S_2 P - S_1 P

Dropping a perpendicular from S1S_1 onto S2PS_2 P, for L≫dL \gg d, the angle θ\theta between the normal to the slits and the line to PP gives:

Δx=dsin⁡θ\Delta x = d\sin\theta

From screen geometry, tan⁡θ=yL\tan\theta = \frac{y}{L}. Because L≫yL \gg y, the angle θ\theta is small, permitting the small-angle approximation sin⁡θ≈tan⁡θ≈θ\sin\theta \approx \tan\theta \approx \theta (in radians):

Δx≈d(yL)\Delta x \approx d\left(\frac{y}{L}\right)

1. Positions of Bright Fringes (Maxima)

Setting Δx=mλ\Delta x = m\lambda:

d(ymL)=mλ  ⟹  ym=mλLd(m=0,±1,±2,… )d\left(\frac{y_m}{L}\right) = m\lambda \implies y_m = m\frac{\lambda L}{d} \quad (m = 0, \pm 1, \pm 2, \dots)

  • Central maximum (m=0m = 0): y0=0y_0 = 0 (at point OO).
  • First bright fringe (m=1m = 1): y1=λLdy_1 = \frac{\lambda L}{d}.
  • Second bright fringe (m=2m = 2): y2=2λLdy_2 = \frac{2\lambda L}{d}.

2. Positions of Dark Fringes (Minima)

Setting Δx=(m+12)λ\Delta x = (m + \frac{1}{2})\lambda:

d(ym′L)=(m+12)λ  ⟹  ym′=(m+12)λLd(m=0,±1,±2,… )d\left(\frac{y_m'}{L}\right) = \left(m + \frac{1}{2}\right)\lambda \implies y_m' = \left(m + \frac{1}{2}\right)\frac{\lambda L}{d} \quad (m = 0, \pm 1, \pm 2, \dots)

  • First dark fringe (m=0m = 0): y0′=12λLdy_0' = \frac{1}{2}\frac{\lambda L}{d}.
  • Second dark fringe (m=1m = 1): y1′=32λLdy_1' = \frac{3}{2}\frac{\lambda L}{d}.

3. Fringe Spacing (Fringe Width Δy\Delta y)

The distance between any two consecutive bright fringes or two consecutive dark fringes is defined as the fringe width Δy\Delta y:

Δy=ym+1−ym=(m+1)λLd−mλLd=λLd\Delta y = y_{m+1} - y_m = (m+1)\frac{\lambda L}{d} - m\frac{\lambda L}{d} = \frac{\lambda L}{d}

Similarly, for dark fringes:

Δy=ym+1′−ym′=(m+32)λLd−(m+12)λLd=λLd\Delta y = y_{m+1}' - y_m' = \left(m + \frac{3}{2}\right)\frac{\lambda L}{d} - \left(m + \frac{1}{2}\right)\frac{\lambda L}{d} = \frac{\lambda L}{d}

Properties of Young's Fringes

  1. Equidistant Spacing: All bright and dark fringes are equally spaced across the center of the pattern.
  2. Proportionality to Wavelength: Fringe width is directly proportional to wavelength (Δy∝λ\Delta y \propto \lambda). Red light (λ≈700 nm\lambda \approx 700\text{ nm}) produces wider fringes than blue light (λ≈400 nm\lambda \approx 400\text{ nm}).
  3. Proportionality to Geometry: Fringe width increases with screen distance (Δy∝L\Delta y \propto L) and decreases as slit separation increases (Δy∝1d\Delta y \propto \frac{1}{d}).

4. Effect of Refractive Index on Interference

When the entire YDSE apparatus is immersed in a liquid of refractive index nn (n>1n > 1):

  1. The frequency ff remains constant (governed by the light source).
  2. The speed of light decreases to v=cnv = \frac{c}{n}.
  3. The wavelength inside the medium shrinks proportionally:

λ′=λn\lambda' = \frac{\lambda}{n}

Consequently, the new fringe spacing Δy′\Delta y' inside the medium becomes:

Δy′=λ′Ld=(λ/n)Ld=Δyn\Delta y' = \frac{\lambda' L}{d} = \frac{(\lambda / n) L}{d} = \frac{\Delta y}{n}

ECAT Key Result: Immersing the double-slit apparatus into water (n=1.33=43n = 1.33 = \frac{4}{3}) compresses the fringe pattern by a factor of nn: Δywater=34Δyair\Delta y_{\text{water}} = \frac{3}{4}\Delta y_{\text{air}}.


5. Stokes' Law: Phase Change on Reflection

In 1849, Sir George Gabriel Stokes established a fundamental wave reflection theorem:

  • When a light wave propagating in an optically rarer medium reflects at the boundary of an optically denser medium (n2>n1n_2 > n_1), it undergoes an intrinsic phase reversal of π\pi radians (180∘180^\circ).
  • A phase shift of π\pi is equivalent to an extra optical path difference of half a wavelength: ΔxStokes=λ2\Delta x_{\text{Stokes}} = \frac{\lambda}{2}.
  • When light reflects from an optically rarer medium (n2<n1n_2 < n_1), no phase change occurs.

This behavior is physically identical to a transverse wave on a string reflecting from a fixed boundary (which inverts phase by 180∘180^\circ) versus a free boundary (which reflects without phase inversion).


6. Thin-Film Interference

When light strikes a thin transparent film (such as an oil slick on water or a soap bubble) of physical thickness tt and refractive index μ\mu, light reflects from both the top boundary and the bottom boundary. Superposition of these two reflected rays produces interference colors.

Effective Path Difference in a Thin Film

For a ray incident at angle ii and refracted at angle rr, the geometric path difference inside the film is 2μtcos⁡r2\mu t\cos r. Under near-normal incidence (cos⁡r≈1\cos r \approx 1), the mechanical round-trip path is 2μt2\mu t.

Consider a soap film in air (any thin film whose refractive index is greater than that of the medium on both sides):

  1. The top reflection occurs at a denser medium   ⟹  \implies undergoes a π\pi phase shift (path addition of λ2\frac{\lambda}{2}).
  2. The bottom reflection occurs at a rarer medium   ⟹  \implies undergoes zero phase shift.

Because exactly one of the two reflections undergoes a phase inversion, the net optical path difference is:

Δ=2μtcos⁡r+λ2\Delta = 2\mu t \cos r + \frac{\lambda}{2}

Modified Interference Conditions for Reflected Light

  • Constructive Interference (Bright Film):

2μtcos⁡r+λ2=mλ  ⟹  2μtcos⁡r=(m−12)λ(m=1,2,3,… )2\mu t\cos r + \frac{\lambda}{2} = m\lambda \implies 2\mu t\cos r = \left(m - \frac{1}{2}\right)\lambda \quad (m = 1, 2, 3, \dots)

Relabelling m−1m - 1 as mm gives the familiar form 2μtcos⁡r=(m+12)λ2\mu t\cos r = \left(m + \frac{1}{2}\right)\lambda with m=0,1,2,…m = 0, 1, 2, \dots; both describe the same set of bright films.

  • Destructive Interference (Dark Film):

2μtcos⁡r+λ2=(m+12)λ  ⟹  2μtcos⁡r=mλ2\mu t\cos r + \frac{\lambda}{2} = \left(m + \frac{1}{2}\right)\lambda \implies 2\mu t\cos r = m\lambda

ECAT Key Case (Zero Thickness Film): As a soap bubble becomes extremely thin just before bursting (t→0t \to 0), the geometric path 2μt→02\mu t \to 0. The net path difference is solely due to Stokes' reflection: Δ=λ2\Delta = \frac{\lambda}{2}. Destructive interference occurs for all visible wavelengths, making the top edge of a draining soap film appear completely black in reflected light.


7. Newton's Rings

When a plano-convex lens with a large radius of curvature RR is placed on an optical flat glass plate, a wedge-shaped air film of progressively increasing thickness is formed between them.

When illuminated with monochromatic light at normal incidence, circular concentric alternate bright and dark interference rings—known as Newton's rings—are observed around the point of contact.

Why the Central Spot is Dark in Reflected Light

At the central point of contact between the lens and the glass plate:

  • The thickness of the air film is zero (t=0t = 0).
  • The ray reflecting from the bottom curved surface of the lens undergoes no phase change (glass to air, rarer boundary).
  • The ray reflecting from the top surface of the flat plate undergoes a π\pi phase change (air to glass, denser boundary).
  • The path difference is Δ=0+λ2=λ2\Delta = 0 + \frac{\lambda}{2} = \frac{\lambda}{2}.

Because the path difference is exactly half a wavelength, destructive interference occurs. Therefore, the central spot is always dark in reflected light.

Quantitative Radii of Newton's Rings

From the geometry of a circle of radius RR containing an air film of thickness tt at radial distance rr, by the chord theorem:

r2=t(2R−t)≈2Rt  ⟹  t=r22Rr^2 = t(2R - t) \approx 2R t \implies t = \frac{r^2}{2R}

Substituting tt into the interference conditions for an air film (μ=1\mu = 1, normal incidence cos⁡r=1\cos r = 1):

  1. Dark Rings (Destructive Interference):

2t=mλ  ⟹  2(rm22R)=mλ  ⟹  rm2=mλR2t = m\lambda \implies 2\left(\frac{r_m^2}{2R}\right) = m\lambda \implies r_m^2 = m\lambda R

rm=mλR(m=0,1,2,3,… )r_m = \sqrt{m\lambda R} \quad (m = 0, 1, 2, 3, \dots)

  • The radius of the mm-th dark ring is directly proportional to the square root of the ring order: rm∝mr_m \propto \sqrt{m}.
  • Radii ratio of successive dark rings: r1:r2:r3:r4=1:2:3:4=1:1.414:1.732:2r_1 : r_2 : r_3 : r_4 = \sqrt{1} : \sqrt{2} : \sqrt{3} : \sqrt{4} = 1 : 1.414 : 1.732 : 2.
  1. Bright Rings (Constructive Interference):

2t=(m+12)λ  ⟹  rm′=(m+12)λR(m=0,1,2,… )2t = \left(m + \frac{1}{2}\right)\lambda \implies r_m' = \sqrt{\left(m + \frac{1}{2}\right)\lambda R} \quad (m = 0, 1, 2, \dots)

Transmitted Light System

In transmitted light, no phase shift occurs upon transmission. Consequently, the conditions for bright and dark rings are exactly reversed: the central spot in transmitted light is bright, and the transmitted pattern is strictly complementary to the reflected pattern.


8. Michelson's Interferometer

The Michelson interferometer is a high-precision optical instrument designed by Albert A. Michelson in 1881 to measure tiny displacements and wavelengths of light by splitting a beam into two perpendicular paths.

Working Principle

  1. Light from an extended source strikes a half-silvered glass beam splitter oriented at 45∘45^\circ.
  2. Exactly 50%50\% of the light is reflected along Path 1 to movable mirror M1M_1, and 50%50\% is transmitted along Path 2 to fixed mirror M2M_2.
  3. A compensating glass plate of identical thickness is placed in Path 2 to ensure both beams traverse identical thicknesses of glass.
  4. Both beams reflect normally from their respective mirrors and recombine at the beam splitter, entering an observer's telescope where interference fringes are viewed.

Precision Distance Formula

If mirror M1M_1 is displaced linearly by distance dd, the optical path length changes by 2d2d (because light travels back and forth). Each time the path changes by one full wavelength λ\lambda, one fringe shifts across the crosshairs of the telescope:

2d=mλ  ⟹  d=mλ22d = m\lambda \implies d = m\frac{\lambda}{2}

This equation allows determination of unknown wavelengths to within nanometer precision, and Michelson used it in 1892–93 to measure the standard metre in wavelengths of cadmium red light (the metre was later defined by a krypton-86 wavelength in 1960 and, since 1983, by the speed of light).


9. Interference Conditions Reference Table

Optical ConfigurationPath Difference / Phase ShiftCondition for Bright Fringes (Constructive)Condition for Dark Fringes (Destructive)Key ECAT Exam Takeaway
General Two-Beam InterferencePath difference Δx\Delta xΔx=mλ\Delta x = m\lambdaΔx=(m+12)λ\Delta x = \left(m + \frac{1}{2}\right)\lambdaInteger vs. half-integer wavelength criteria for in-phase vs. out-of-phase arrival
Young's Double-Slit (Air)Δx=dsin⁡θ≈dyL\Delta x = d\sin\theta \approx d\frac{y}{L}ym=mλLdy_m = m\frac{\lambda L}{d}ym′=(m+12)λLdy_m' = \left(m + \frac{1}{2}\right)\frac{\lambda L}{d}Fringe width Δy=λLd\Delta y = \frac{\lambda L}{d}; all fringes are strictly equidistant
Young's Double-Slit (in Medium nn)Wavelength compressed: λ′=λn\lambda' = \frac{\lambda}{n}ym′=mλLndy_m' = m\frac{\lambda L}{n d}ym′′=(m+12)λLndy_m'' = \left(m + \frac{1}{2}\right)\frac{\lambda L}{n d}Fringe width scales as Δy′=Δyn\Delta y' = \frac{\Delta y}{n}; immersion compresses the fringe pattern
Stokes' Reflection Phase RuleDenser reflection: Δϕ=π\Delta \phi = \piΔxStokes=+λ2\Delta x_{\text{Stokes}} = +\frac{\lambda}{2}No shift at rarer medium boundaryEquivalent to half-wavelength optical path addition upon reflection at denser interface
Thin Film (One Phase Inversion)Δ=2μtcos⁡r+λ2\Delta = 2\mu t\cos r + \frac{\lambda}{2}2μtcos⁡r=(m+12)λ2\mu t\cos r = \left(m + \frac{1}{2}\right)\lambda2μtcos⁡r=mλ2\mu t\cos r = m\lambdaZero thickness film (t→0t \to 0) appears completely black in reflected light
Thin Film (Zero or Two Inversions)Δ=2μtcos⁡r\Delta = 2\mu t\cos r2μtcos⁡r=mλ2\mu t\cos r = m\lambda2μtcos⁡r=(m+12)λ2\mu t\cos r = \left(m + \frac{1}{2}\right)\lambdaStandard conditions restored when phase shifts at top and bottom cancel
Newton's Rings (Reflected Light)Wedge air film: t=r22Rt = \frac{r^2}{2R}rm′=(m+12)λRr_m' = \sqrt{\left(m + \frac{1}{2}\right)\lambda R}rm=mλRr_m = \sqrt{m\lambda R}Central spot is dark in reflection (m=0  ⟹  r0=0m=0 \implies r_0 = 0); dark radii scale as m\sqrt{m}
Newton's Rings (Transmitted Light)No reflection phase shiftrm=mλRr_m = \sqrt{m\lambda R}rm′=(m+12)λRr_m' = \sqrt{\left(m + \frac{1}{2}\right)\lambda R}Central spot is bright; pattern is exactly complementary to reflected pattern
Michelson InterferometerRoundtrip displacement 2d2dShift of mm fringes: 2d=mλ2d = m\lambdaMirror displacement: d=mλ2d = m\frac{\lambda}{2}Moving mirror by λ4\frac{\lambda}{4} changes path by λ2\frac{\lambda}{2}, turning bright to dark
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Interference Fringe & Path Difference Diagnostic Flowchart
Test Your Knowledge

In a Young's double-slit experiment performed in air, the fringe width is measured to be 0.8 mm0.8\text{ mm}. If the entire apparatus is completely immersed in a liquid of refractive index n=1.6n = 1.6, what will be the new fringe width?

A

1.28 mm1.28\text{ mm}

B

0.80 mm0.80\text{ mm}

C

0.50 mm0.50\text{ mm}

D

0.32 mm0.32\text{ mm}

Test Your Knowledge

In a Newton's rings experiment illuminated with monochromatic light, why is the central fringe observed in reflected light completely dark?

A

At the point of contact the air film thickness is zero, and an intrinsic phase change of π\pi occurs at the air-glass reflection, yielding destructive interference

B

The glass plate absorbs all reflected light at the point of contact

C

The plano-convex lens focuses all incident light rays to a point behind the glass plate

D

Destructive interference occurs because light undergoes phase reversals of π\pi at both the lens and the glass plate

Test Your Knowledge

A soap film (n=1.33n = 1.33) in air is illuminated normally with monochromatic light of wavelength λ=532 nm\lambda = 532\text{ nm}. What is the absolute minimum non-zero physical thickness tt of the film that will produce strongly constructive reflection?

A

266 nm266\text{ nm}

B

200 nm200\text{ nm}

C

133 nm133\text{ nm}

D

100 nm100\text{ nm}

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