10.3 Synchronous Machines (Operating Principles, Power-Angle Curves & V-Curves)

10.3 Synchronous Machines (Operating Principles, Power-Angle Curves & V-Curves)

Synchronous machines are the primary source of bulk electrical power generation worldwide and serve as specialized high-horsepower industrial drives and dynamic reactive power compensators. Unlike induction machines, synchronous machines operate at strictly synchronous speed ($n_s = 120f/P$) under steady-state conditions, with real power exchange mediated by the rotor power angle ($\delta$) and reactive power exchange controlled by DC field excitation ($I_f$).

---

1. Machine Construction & Rotor Topologies

A synchronous machine consists of a stationary 3-phase armature winding on the stator and a DC-excited field winding on the rotor.

Rotor Topologies

1. Cylindrical (Round) Rotor:

   • Uniform air-gap geometry.
   • High-speed 2-pole or 4-pole machines ($1,800\text{ rpm}$ or $3,600\text{ rpm}$ at $60\text{ Hz}$).
   • Driven by steam or gas turbines (turbogenerators).
   • Characterized by a single per-phase synchronous reactance: $X_s = X_{al} + X_{ar}$ (leakage reactance plus armature reaction reactance).

2. Salient-Pole Rotor:

   • Non-uniform air gap with projecting (salient) pole shoes.
   • Low-speed multipole machines ($72\text{ rpm}$ to $900\text{ rpm}$, e.g., 12 to 72 poles).
   • Driven by hydro turbines or large diesel/gas reciprocating engines.
   • Analyzed using Blondel's Two-Axis Theory: Direct-axis synchronous reactance ($X_d$) along the magnetic pole axis, and Quadrature-axis synchronous reactance ($X_q$) along the interpolar axis ($X_d > X_q$).

DC Field Excitation Systems

The rotor DC field is supplied either through stationary carbon brushes riding on rotating slip rings or via modern brushless exciters (an inverted alternator with shaft-mounted rotating diode rectifiers). Adjusting the field current $I_f$ adjusts the internal generated excitation voltage magnitude ($E_f$) along the open-circuit saturation curve.

---

2. Per-Phase Equivalent Circuit and Phasor Conventions

For a cylindrical-rotor machine on a per-phase (wye) basis:

• $V_t$: Terminal phase voltage ($V_t = V_{LL}/\sqrt{3} \angle 0^\circ$).
• $E_f$: Internal generated excitation voltage ($E_f \angle \delta$).
• $I_a$: Armature phase current ($I_a \angle \theta$).
• $R_a$: Stator armature winding resistance per phase (often neglected in power calculations, $R_a \approx 0$).
• $X_s$: Synchronous reactance per phase ($X_s = X_l + X_a$).

Phasor Equations

• Synchronous Generator Mode (current flowing out of machine to grid): $\mathbf{E}_f = \mathbf{V}_t + \mathbf{I}_a (R_a + jX_s) \approx \mathbf{V}_t + j\mathbf{I}_a X_s$

  • Power angle $\delta > 0^\circ$ ($\mathbf{E}_f$ leads $\mathbf{V}_t$ in the direction of rotation).

• Synchronous Motor Mode (current flowing into machine from grid): $\mathbf{V}_t = \mathbf{E}_f + \mathbf{I}_a (R_a + jX_s) \approx \mathbf{E}_f + j\mathbf{I}_a X_s \implies \mathbf{E}_f = \mathbf{V}_t - j\mathbf{I}_a X_s$

  • Power angle $\delta < 0^\circ$ ($\mathbf{E}_f$ lags $\mathbf{V}_t$).

---

3. Power-Angle Equations and Stability Limits

Neglecting armature resistance ($R_a = 0$), the per-phase complex power delivered by a synchronous generator to an infinite bus is:

$\mathbf{I}_a = \frac{E_f \angle \delta - V_t \angle 0^\circ}{jX_s} = \frac{E_f \sin \delta}{X_s} - j \left( \frac{E_f \cos \delta - V_t}{X_s} \right)$

$\mathbf{S}_{3\phi} = 3 \mathbf{V}_t \mathbf{I}_a^* = 3 V_t \left[ \frac{E_f \sin \delta}{X_s} + j \left( \frac{E_f \cos \delta - V_t}{X_s} \right) \right]$

Active and Reactive Power Formulas

$P_{3\phi} = \frac{3 E_f V_t}{X_s} \sin \delta = \frac{E_{f,LL} V_{t,LL}}{X_s} \sin \delta \quad [\text{W}]$

$Q_{3\phi} = \frac{3 E_f V_t}{X_s} \cos \delta - \frac{3 V_t^2}{X_s} \quad [\text{VAR}]$

where $E_f$ and $V_t in the three-phase formulas are per-phase line-to-neutral magnitudes (or line-to-line magnitudes if the factor of 3 is omitted).

Salient-Pole Power Equation (Reluctance Torque)

In salient-pole machines, the saliency ($X_d \neq X_q$) creates a reluctance power component that operates independently of field excitation:

$P_{3\phi} = \underbrace{\frac{3 E_f V_t}{X_d} \sin \delta}_{\text{Field Excitation Power}} + \underbrace{\frac{3 V_t^2}{2} \left( \frac{1}{X_q} - \frac{1}{X_d} \right) \sin 2\delta}_{\text{Reluctance Power}}$

Steady-State Stability Limit (Pull-Out Power)

• Cylindrical Machine: Maximum theoretical power occurs at $\delta = 90^\circ$: $P_{max,3\phi} = \frac{3 E_f V_t}{X_s}$ If mechanical turbine power exceeds $P_{max}$ (or if electrical load increases such that $\delta > 90^\circ$), the synchronizing power coefficient $\frac{dP}{d\delta}$ becomes negative, causing the generator to lose synchronism and "slip poles."
• Salient-Pole Machine: Peak power occurs at $\delta < 90^\circ$ (typically $\delta \approx 65^\circ - 75^\circ$) due to the second-harmonic reluctance term ($\sin 2\delta$).

---

4. Excitation Regimes, Reactive Power Control & Synchronous Condensers

By adjusting field current $I_f$ (and hence $E_f$), the synchronous machine can supply or absorb reactive power independently of active power delivery:

Synchronous Condenser Operation

A Synchronous Condenser is a synchronous machine connected to the electrical grid with no mechanical load on its shaft ($P_{shaft} \approx 0 \implies \delta \approx 0^\circ$):

$Q_{3\phi} \approx \frac{3 V_t (E_f - V_t)}{X_s}$

• When overexcited ($E_f > V_t$), it supplies variable capacitive VARs to the substation bus, supporting system voltage during heavy transmission loading.
• When underexcited ($E_f < V_t$), it acts as an adjustable shunt reactor, absorbing inductive VARs during light load / Ferranti effect conditions.

---

5. Synchronous Machine V-Curves & Generator Capability Limits

V-Curves ($I_a$ vs. $I_f$)

Plotting armature current $I_a$ against field current $I_f$ for constant mechanical power outputs generates a family of V-shaped curves:

• The bottom vertex of each V-curve corresponds to unity power factor where armature current $I_a$ is minimized for that MW level.
• Operating to the right of the vertex represents the overexcited regime (lagging PF for generator, leading PF for motor).
• Operating to the left of the vertex represents the underexcited regime (leading PF for generator, lagging PF for motor).

Generator Capability Curve (P-Q Operating Envelope)

A synchronous generator's safe operating region in the P-Q plane is constrained by three physical limits:

1. Armature Current Limit (Stator Heating): A circle centered at $(P=0, Q=0)$ with radius equal to rated MVA: $P^2 + Q^2 \le S_{rated}^2$.
2. Field Current Limit (Rotor Heating): A circle centered at $(0, -3V_t^2/X_s)$ with radius $\frac{3 E_{f,max} V_t}{X_s}$. Limits maximum overexcited lagging VAR output.
3. Stator End-Core Heating & Stability Limit: Limits maximum underexcited leading VAR absorption to prevent localized eddy-current heating in stator core laminations and preserve steady-state transient stability margins.

---

6. Worked Numeric Example: Synchronous Generator Excitation & Power Angle

Problem Statement

A 3-phase, 25 MVA, 13.8 kV, 60 Hz, Y-connected cylindrical-rotor synchronous generator has a synchronous reactance of $X_s = 6.4,\Omega$ per phase and negligible armature resistance ($R_a \approx 0$). The generator is connected to an infinite bus operating at rated 13.8 kV and delivers $20.0\text{ MW}$ at $0.80$ power factor lagging.

Calculate:

1. Stator terminal phase voltage $V_t$ and armature current phasor $\mathbf{I}_a$.
2. Internal excitation voltage phasor $\mathbf{E}_f$ (magnitude in line-to-neutral and line-to-line, and power angle $\delta$).
3. Total three-phase reactive power $Q_{3\phi}$ supplied by the generator.
4. Steady-state maximum pull-out power ($P_{max,3\phi}$) under this field excitation.

Step-by-Step Solution

Step 1: Terminal Voltage and Armature Current Phasors

Terminal line-to-neutral voltage: $V_t = \frac{13,800}{\sqrt{3}} = 7,967.43\text{ V} \angle 0^\circ$

Apparent power: $S_{3\phi} = \frac{P}{\cos \theta} = \frac{20.0\text{ MW}}{0.80} = 25.0\text{ MVA}$

Armature current magnitude: $I_a = \frac{S_{3\phi}}{\sqrt{3} V_{LL}} = \frac{25,000,000}{\sqrt{3} \times 13,800} = 1,045.92\text{ A}$

Power factor angle for lagging current: $\theta = -\arccos(0.80) = -36.87^\circ$ $\mathbf{I}_a = 1,045.92 \angle -36.87^\circ\text{ A} = (836.74 - j627.55)\text{ A}$

Step 2: Internal Excitation Voltage Phasor ($\mathbf{E}_f$)

$\mathbf{E}_f = \mathbf{V}_t + j \mathbf{I}_a X_s$ $j \mathbf{I}_a X_s = j (836.74 - j627.55) \times 6.4 = j 5,355.14 + 4,016.32 = 4,016.32 + j 5,355.14\text{ V}$

Summing with $\mathbf{V}_t$: $\mathbf{E}_f = 7,967.43 + 4,016.32 + j 5,355.14 = 11,983.75 + j 5,355.14\text{ V}$

Converting to polar coordinates: $|E_f| = \sqrt{(11,983.75)^2 + (5,355.14)^2} = \sqrt{143,610,264 + 28,677,525} = \sqrt{172,287,789} = 13,125.84\text{ V (line-to-neutral)}$

$\delta = \arctan\left(\frac{5,355.14}{11,983.75}\right) = \arctan(0.44686) = 24.08^\circ$

Line-to-line excitation voltage: $E_{f,LL} = \sqrt{3} \times 13,125.84\text{ V} = 22,734.6\text{ V} = 22.73\text{ kV}$

$\mathbf{E}_f = 13.13\text{ kV} \angle 24.08^\circ$

Step 3: Reactive Power Supplied

$Q_{3\phi} = P \times \tan \theta = 20.0\text{ MW} \times \tan(36.87^\circ) = 20.0 \times 0.750 = 15.0\text{ MVAR}$

Verification via reactive power formula: $Q_{3\phi} = \frac{3 E_f V_t}{X_s} \cos \delta - \frac{3 V_t^2}{X_s} = \frac{3 \times 13,125.84 \times 7,967.43}{6.4} \cos(24.08^\circ) - \frac{3 \times (7,967.43)^2}{6.4}$ $Q_{3\phi} = (48,995,780 \times 0.91299) - 29,756,238 = 44,732,860 - 29,756,238 = 14,976,622\text{ VAR} \approx 15.0\text{ MVAR}$

Step 4: Maximum Pull-Out Power ($P_{max}$)

Pull-out power occurs at $\delta = 90^\circ$ ($\sin 90^\circ = 1.0$): $P_{max,3\phi} = \frac{3 E_f V_t}{X_s} = \frac{3 \times 13,125.84 \times 7,967.43}{6.4} = 48,995,780\text{ W} = 49.0\text{ MW}$

---

7. Common Exam Traps & High-Yield Summary

[!WARNING] Exam Trap 1: Confusing Generator vs. Motor Power Angle Signs In synchronous generators, field excitation leads terminal voltage ($\delta > 0^\circ$). In synchronous motors, mechanical shaft load retards the rotor so field excitation lags terminal voltage ($\delta < 0^\circ$).

[!WARNING] Exam Trap 2: Generator vs. Motor Overexcitation Conventions

• An overexcited generator supplies lagging reactive power ($+Q$) to the grid.
• An overexcited motor operates at a leading power factor, which also supplies capacitive reactive power ($+Q$) to the local distribution bus.

[!IMPORTANT] Exam Trap 3: Infinite Bus Voltage & Frequency Invariance An infinite bus has constant voltage and frequency. Increasing turbine governor mechanical input $P_{mech}$ increases active power $P$ and power angle $\delta$, but does NOT change machine speed. Increasing field current $I_f$ increases reactive power $Q$ and terminal voltage support, but does NOT change active power $P$.