14.1 Overcurrent Protection & Time-Current Characteristic (TCC) Curves

14.1 Overcurrent Protection & Time-Current Characteristic (TCC) Curves

Executive Overview: Overcurrent protection is the foundational protection philosophy across electric utility distribution, industrial networks, and commercial power systems. On the NCEES PE Power examination, overcurrent protection problems require absolute mastery of ANSI 50 (Instantaneous) vs. ANSI 51 (Time-Overcurrent) operating dynamics, mathematical parameterization of IEEE C37.112 and IEC 60255 inverse-time curves, Current Transformer (CT) tap/pickup current sizing, Time Dial ($TD$) calibration, and the interpretation of log-log Time-Current Characteristic (TCC) plots across transformer voltage boundaries.

---

1. ANSI 50 vs. ANSI 51 Functional Architecture

Overcurrent relays detect abnormal current magnitudes resulting from phase-to-phase, three-phase bolted, or phase-to-ground faults. The fundamental ANSI device designations define their operating speed and time-delay mechanics:

Overcurrent Relay Functional Elements & Operating Time Profile:

Time (s) ^
         |
    10.0 |---.  ANSI 51: Time-Overcurrent Characteristic
         |    \
     1.0 |     \  t(I) = TD * [ A / (M^p - 1) + B ]
         |      `.
     0.1 |        `--. 
         |           |  ANSI 50: Instantaneous Element
    0.02 |-----------+-------------------> Operating Time (< 2 cycles / 33 ms)
         |           |                   Intentional Delay = 0
         +-----------+---------------------> Current (A)
                   I_pickup   I_inst_pickup

Instantaneous Overcurrent (ANSI 50)

• Operating Principle: Evaluates current magnitude continuously against a fixed threshold $I_{inst}$. When $I_{measured} > I_{inst}$, the relay issues a trip command to the circuit breaker with no intentional time delay.
• Operating Speed: Total clearing time is governed solely by relay measurement/filtering algorithms ($10-25\text{ ms}$) and circuit breaker contact parting time ($30-50\text{ ms}$ for standard 3-cycle or 5-cycle breakers), yielding total clearing in $<40-80\text{ ms}$.
• Setting Constraint: To maintain selectivity, ANSI 50 pickup must be set above the maximum symmetrical fault current available at the next downstream protective device terminal ($I_{50} \ge 1.20 - 1.30 \times I_{fault,downstream}$) to prevent "overreaching" and tripping on out-of-zone faults.

Time-Overcurrent (ANSI 51)

• Operating Principle: Operates along an inverse time-current characteristic where the operating time $t_{op}$ decreases non-linearly as current magnitude increases.
• Functional Benefit: Provides thermal protection for conductors and equipment at moderate overloads while enabling selective time-grading between series-connected protective devices.
• Secondary Designations:
  • 51P / 50P: Phase overcurrent elements driven by phase CTs.
  • 51N / 50N: Residual ground overcurrent elements calculating $3\mathbf{I}_0 = \mathbf{I}_a + \mathbf{I}_b + \mathbf{I}_c$ internally or from residual CT connections.
  • 51G / 50G: Dedicated zero-sequence ground overcurrent elements driven by a core-balance (toroidal / window-type) CT encircling all three phase conductors.

---

2. Standardized Inverse-Time Curve Equations

IEEE C37.112-2018 Standard Equation

The standard mathematical representation for IEEE/ANSI inverse-time overcurrent relays is defined by:

$$t(I) = TD \left( \frac{A}{M^p - 1} + B \right) \quad [\text{seconds}]$$

where:

• $TD$ = Time Dial setting (multiplier adjusting the vertical position of the curve, typically $0.5$ to $15.0$ in electromechanical relays or $0.05$ to $10.0$ in digital relays).
• $M$ = Multiple of pickup current, defined as $M = \frac{I_{actual}}{I_{pickup}} = \frac{I_{secondary}}{I_{tap}} = \frac{I_{primary}}{I_{pickup,pri}}$.
• $A, B, p$ = Dimensionless curve shape constants defining the degree of inverseness.

Comparison of IEEE Time-Current Curve Slopes (at TD = 1.0):

Time (s) ^
    10.0 |  Moderately Inverse (gentle slope)
         |   \ 
     1.0 |    \   Very Inverse (steeper slope)
         |     \   \ 
     0.1 |      \   \   Extremely Inverse (steepest: ~ 1/I^2)
         |       \   \   \
    0.01 +--------+---+---+-------------------> Multiple of Pickup (M = I / I_pu)
                  2   5   10  20

IEC 60255-151 Standard Curve Formulation

In international and industrial applications, the IEC standard curve family is formulated as:

$$t(I) = TMS \cdot \left( \frac{k}{M^\alpha - 1} \right) \quad [\text{seconds}]$$

where $TMS$ is the Time Multiplier Setting ($0.01$ to $1.0$) and parameters are:

• IEC Class A (Standard Inverse): $k = 0.14, \alpha = 0.02$
• IEC Class B (Very Inverse): $k = 13.5, \alpha = 1.0$
• IEC Class C (Extremely Inverse): $k = 80.0, \alpha = 2.0$
• IEC Long-Time Inverse: $k = 120.0, \alpha = 1.0$

---

3. Overcurrent Relay Setting Methodology

Setting an ANSI 51 time-overcurrent relay requires establishing two primary parameters: the Pickup Current ($I_{pickup}$) and the Time Dial ($TD$).

Relay Setting Optimization Window:

   0 A -----------------[ Security Boundary ]================[ Sensitivity Boundary ]-----------------> Fault kA
                         |                                    |
   Normal Peak Load ---->|   ALLOWABLE PICKUP SETTING RANGE   |<---- Minimum End-of-Line Fault
   (I_load,max * 1.25)   |        ( I_pickup )                |      ( I_fault,min * 0.80 )

Criterion 1: Pickup Current Setting ($I_{pickup}$ or Tap Setting)

1. Continuous Load Security (Lower Bound): The relay must never pick up under maximum anticipated continuous load, emergency overload, or cold-load pickup inrush: $$I_{pickup,pri} \ge 1.25 \text{ to } 1.50 \times I_{load,max}$$ For transformer primaries, $I_{pickup,pri} \ge 1.25 \text{ to } 1.50 \times I_{FLA,OA}$ (where $FLA$ is full-load amperes at maximum cooling rating).
2. Minimum Fault Sensitivity (Upper Bound): The relay must reliably detect the smallest possible fault current at the remote boundary of the protected zone under minimum generation conditions (line-to-line or minimum arcing line-to-ground fault): $$I_{pickup,pri} \le 0.50 \text{ to } 0.80 \times I_{fault,min}$$
3. Secondary Relay Tap Calculation: $$I_{tap,sec} = \frac{I_{pickup,pri}}{CTR} \quad [\text{Amperes secondary}]$$ where $CTR = \frac{I_{pri,rated}}{I_{sec,rated}}$ is the Current Transformer Ratio (typically $X:5\text{ A}$ or $X:1\text{ A}$).

Criterion 2: Time Dial Selection ($TD$)

The Time Dial is selected to achieve a target Coordination Time Interval ($CTI$) above the total clearing time of the immediate downstream protective device at the maximum through-fault current $I_{fault,max}$:

$$t_{upstream}(I_{fault,max}) \ge t_{downstream}(I_{fault,max}) + CTI$$

Substituting into the IEEE C37.112 equation and solving for $TD$:

$$TD = \frac{t_{target}}{\frac{A}{M^p - 1} + B} = \frac{t_{downstream}(I_{fault,max}) + CTI}{\frac{A}{\left( \frac{I_{fault,max}}{I_{pickup}} \right)^p - 1} + B}$$

---

4. Reset Characteristics: Electromechanical vs. Digital Relays

When a fault occurs and is cleared by a downstream device before an upstream relay reaches its trip threshold, the upstream relay must reset to its resting state. The reset mechanism fundamentally influences multi-shot automatic reclosing coordination.

Induction Disk Dynamics vs. Microprocessor Linear Reset:

Relay Travel ^
   100% (TRIP)+-------------------------------------------------------
              |       Fault 1       Clearing        Fault 2 (Reclose)
              |      /             /               /       
    50%       |     /  . - - - - -'               /  . - - - - (TRIP!)
              |    /  / (Disk Coast/Reset)       /  /
     0% ------+---o-----------------------------o---------------------> Time (s)
                  Electromechanical: Partial Reset -> Premature Tripping (Ratcheting)
                  Digital Relay: Instantaneous / Programmed Reset to 0%

Electromechanical Induction Disk Relays (ANSI C37.90)

• Operating Physics: An induction disk rotates against a restraining spiral spring. During an overcurrent condition, electromagnetic torque overcomes spring torque, driving the moving contact toward the stationary contact.
• Disk Overtravel & Coasting: When current drops below pickup, rotational momentum causes the disk to continue moving forward for $0.05 - 0.10\text{ s}$ ("overtravel") before the spring reverses direction.
• Reset Time Formulation: Disk reset time from the point of trip is given by: $$t_{reset} = TD \left( \frac{t_r}{1 - M^2} \right) \quad \text{for } M < 1.0$$ where $t_r$ is the characteristic reset constant (typically $10 - 40\text{ seconds}$ for full travel). Because reset takes several seconds, fast auto-reclosers ($0.3-0.5\text{ s}$ open interval) cause the disk to ratchet forward on successive shots, leading to premature upstream tripping.

Microprocessor (Digital / Numerical) Relays

• Instantaneous Reset: Can be configured to reset the internal energy integrator to zero within 1 cycle ($16.7\text{ ms}$) after current drops below $0.95 \times I_{pickup}$.
• Emulated Electromechanical Reset: Microprocessor relays can also be programmed with linear or electromechanical induction disk reset characteristics to coordinate properly with legacy upstream electromechanical relays.

---

5. Log-Log TCC Curve Plotting Mechanics

Time-Current Characteristic curves are universally plotted on log-log coordinate grids spanning:

• Vertical Axis (Time): $0.01\text{ s}$ ($10\text{ ms}$) to $1000\text{ s}$ ($16.6\text{ minutes}$).
• Horizontal Axis (Current): $10\text{ A}$ to $100,000\text{ A}$ ($100\text{ kA}$) plotted on a specified reference voltage base.

Essential TCC Construction Rules

1. Common Voltage Reference Base: When plotting devices across a transformer (e.g., $13.8\text{ kV}$ primary relay and $480\text{ V}$ secondary main breaker), all currents must be converted to a single reference base voltage using the turns ratio: $$I_{ref} = I_{actual} \times \left( \frac{V_{actual}}{V_{ref}} \right)$$
2. Transformer Inrush Point: An ANSI 51 relay curve must lie above and to the right of the transformer magnetizing inrush point:
   • Liquid-Filled Transformers: $8 \times FLA$ for $0.1\text{ s}$ and $12 \times FLA$ for $0.1\text{ s}$ (ANSI/IEEE C57.109).
   • Dry-Type Transformers: $12 - 14 \times FLA$ for $0.1\text{ s}$.
3. Cable and Transformer Thermal Damage Curves:
   • Cable Damage Curve: $t = \frac{K_{cu} \cdot A_{cmil}^2}{I_{sc}^2}$ (Onderdonk equation).
   • The upstream relay curve must sit strictly to the left and below the thermal damage curve of the protected equipment.

---

6. Comprehensive Worked Relay Setting Calculation

Problem Statement

A $13.8\text{ kV}$, 3-phase, $60\text{ Hz}$ distribution feeder is fed through a substation circuit breaker equipped with a microprocessor time-overcurrent relay (ANSI 51) using an IEEE Very Inverse curve ($A = 19.61, B = 0.491, p = 2.0$).

• CT Ratio: $600:5\text{ A}$ ($CTR = 120$)
• Maximum Continuous Peak Load: $I_{load,max} = 320\text{ A}$
• Minimum Line-to-Line Fault Current (End of Feeder): $I_{fault,min} = 1,800\text{ A}$
• Maximum Through-Fault Current at Downstream Recloser: $I_{fault,max} = 4,200\text{ A}$
• Downstream Recloser Total Clearing Time at $4,200\text{ A}$: $t_{down} = 0.180\text{ s}$
• Required Coordination Time Interval ($CTI$): $0.250\text{ s}$
• Maximum Bus Symmetrical Fault Current: $I_{sc,bus} = 11,500\text{ A}$

Calculate:

1. The optimal primary pickup current $I_{pickup,pri}$ and secondary tap setting $I_{tap,sec}$.
2. Verify security against full load and sensitivity to minimum fault.
3. The multiple of pickup $M$ at the coordination fault current ($4,200\text{ A}$).
4. The required Time Dial ($TD$) setting to achieve the $0.250\text{ s}$ CTI.
5. The relay operating time at the maximum bus fault current ($11,500\text{ A}$).
6. The instantaneous overcurrent (ANSI 50) pickup setting with a $125\%$ security margin above downstream through-fault.

============================== STEP-BY-STEP SOLUTION ==============================

Step 1: Determine Primary Pickup Current (I_pickup,pri)
  Lower limit (Load Security): 
    I_pu,min = 1.25 * I_load,max = 1.25 * 320 A = 400 A
  Upper limit (Fault Sensitivity):
    I_pu,max = 0.67 * I_fault,min = 0.67 * 1,800 A = 1,206 A
  
  Select primary pickup current: I_pickup,pri = 480 A
  (Satisfies: 400 A <= 480 A <= 1,206 A)
  
  Secondary Relay Tap Setting:
    I_tap,sec = I_pickup,pri / CTR = 480 A / (600 / 5) = 480 / 120 = 4.00 A sec

Step 2: Verify Load Security and Fault Sensitivity Ratios
  Continuous Load Security Margin = 480 A / 320 A = 1.50 (150% of peak load) -> SECURE
  Sensitivity Multiple at Min Fault = 1,800 A / 480 A = 3.75x pickup -> SENSITIVE (M >= 2.0)

Step 3: Compute Multiple of Pickup (M) at Downstream Coordination Fault
  I_fault,down = 4,200 A
  M_coord = I_fault,down / I_pickup,pri = 4,200 A / 480 A = 8.750

Step 4: Determine Required Upstream Operating Time and Time Dial (TD)
  Target Upstream Time: 
    t_upstream = t_down + CTI = 0.180 s + 0.250 s = 0.430 s
  
  IEEE Very Inverse Parameters: A = 19.61, B = 0.4910, p = 2.000
  
  Evaluate bracketed term at M = 8.750:
    M^2 - 1 = (8.750)^2 - 1 = 76.5625 - 1 = 75.5625
    Term = [ 19.61 / 75.5625 ] + 0.4910 = 0.25952 + 0.4910 = 0.75052
  
  Solve for Time Dial (TD):
    t_upstream = TD * 0.75052 = 0.430 s
    TD = 0.430 / 0.75052 = 0.5729
  
  Select practical relay Time Dial setting: TD = 0.58
  
  Verify actual operating time at 4,200 A:
    t_actual = 0.58 * 0.75052 = 0.4353 s (Provides CTI = 0.4353 - 0.180 = 0.2553 s >= 0.250 s)

Step 5: Compute Relay Operating Time at Maximum Bus Fault (11,500 A)
  M_max = 11,500 A / 480 A = 23.958
  M_max^2 - 1 = (23.958)^2 - 1 = 574.00 - 1 = 573.00
  
  Bracketed Term = [ 19.61 / 573.00 ] + 0.4910 = 0.03422 + 0.4910 = 0.52522
  
  Operating Time at 11,500 A (ANSI 51 only):
    t_51(11.5 kA) = 0.58 * 0.52522 = 0.3046 s (approx 18.3 cycles at 60 Hz)

Step 6: Determine ANSI 50 Instantaneous Overcurrent Pickup Setting
  Downstream through-fault maximum = 4,200 A
  Security factor = 125% (1.25)
  
  I_50,pri = 1.25 * I_fault,max,down = 1.25 * 4,200 A = 5,250 A
  Secondary Instantaneous Setting: 
    I_50,sec = 5,250 A / 120 = 43.75 A sec
  
  At the bus fault of 11,500 A, since 11,500 A > 5,250 A, the ANSI 50 element trips 
  instantaneously with clearing time governed strictly by breaker opening (< 0.050 s / 3 cycles).
===================================================================================

---

7. Common Exam Traps & Strategic Pitfalls

• The Multiple of Pickup Base Mistake: Forgetting that $M = I / I_{pickup}$ must be computed using matching bases (both in primary amperes or both in secondary amperes). Dividing secondary measured current by primary pickup yields an incorrect value for $M$.
• Overlooking CT Saturation at High Fault Currents: Assuming ideal linear transformation when secondary currents exceed $20 \times I_{nominal}$ ($100\text{ A}$ secondary). Severe CT saturation suppresses secondary current, lengthening time-overcurrent operating times and delaying trip commands.
• Electromechanical vs. Digital Reset Neglect: Applying an electromechanical relay downstream of a fast reclosing sequence without accounting for disk ratcheting ($t_{reset}$). If reclose dead time ($0.3\text{ s}$) is less than reset time ($15\text{ s}$), the relay misoperates on the second shot.
• Failing to Translate Voltage Bases Across Transformers: Plotting low-voltage circuit breakers and medium-voltage fuses on the same TCC without scaling by the transformer phase-to-phase voltage ratio ($V_{pri} / V_{sec}$).