4.3 Time & Work, Pipes & Cisterns, Time, Speed & Distance
Key Takeaways
- The LCM Units method converts reciprocal work rates into integer daily efficiencies, dramatically streamlining multi-worker, alternate-day, and variable-schedule problems.
- The generalized work equivalence identity $\frac{M_1 D_1 H_1 E_1}{W_1} = \frac{M_2 D_2 H_2 E_2}{W_2}$ provides a universal template for contractor workforce adjustments, overtime calculations, and multi-stage tasks.
- Pipes and cisterns operate on algebraic net efficiency, where inlet filling rates are positive ($+E$) and drain/leak rates are negative ($-E$).
- Relative speed is the difference $(u - v)$ for collinear motion in the same direction and the sum $(u + v)$ for opposite directions; train crossing equations must sum physical lengths ($L_1 + L_2$).
- Boats and streams resolve into downstream velocity $D = u + v$ and upstream velocity $U = u - v$, yielding still water speed $u = \frac{D+U}{2}$ and stream current speed $v = \frac{D-U}{2}$.
Time & Work, Pipes & Cisterns, Time, Speed & Distance
Efficiency analysis, project completion timelines, pipeline filling dynamics, and haulage transport logistics form the operational core of mining engineering. In CIL MT Paper-I, questions testing Time & Work and Time, Speed & Distance (TSD) are heavily emphasized. Mastering integer LCM models and relative speed mechanics allows candidates to bypass fraction-heavy systems of equations.
1. Time & Work: The LCM Efficiency Model
Instead of assigning total work as $1$ and handling reciprocal fractions (e.g., $1/12 + 1/15$), assume total work to be the Least Common Multiple (LCM) of the individual completion times. This converts daily work rates into intuitive integer efficiencies.
Step-by-Step LCM Method
- Define Total Work ($W$): $\text{LCM}(T_A, T_B, T_C)$.
- Calculate Daily Efficiencies: $E_A = W / T_A$, $E_B = W / T_B$, $E_C = W / T_C$.
- Calculate Combined Rate: $E_{\text{combined}} = E_A + E_B + E_C$.
- Evaluate Completion Time: $T = \frac{W}{E_{\text{combined}}}$.
Alternate-Day Working Schedules
When workers operate in rotation (e.g., Worker A on Day 1, Worker B on Day 2):
- Determine work accomplished during one complete cycle: $W_{\text{cycle}} = E_A + E_B$.
- Determine number of complete cycles: $k = \lfloor W / W_{\text{cycle}} \rfloor$.
- Calculate remaining work: $W_{\text{rem}} = W - (k \times W_{\text{cycle}})$.
- Allocate $W_{\text{rem}}$ sequentially to the active worker in the next rotation.
Work and Wages Principle
Wages are divided strictly in proportion to the total quantum of work executed by each individual (Efficiency $\times$ Days Worked):
Generalized Work Equivalence Formula
For problems with varying worker headcounts, daily hours, work efficiencies, and project scales, use the universal chain rule:
Where:
- $M = \text{Number of workers}$
- $D = \text{Number of days}$
- $H = \text{Working hours per day}$
- $E = \text{Relative worker efficiency}$
- $W = \text{Quantified work units (volume, length, items)}$
2. Pipes & Cisterns Mechanics
Pipes and cisterns problems mirror Time & Work, with one critical extension: outlet pipes and leaks exert negative efficiency.
- Inlet Pipe ($A$): Fills tank in $T_A$ hours $\implies E_A = +\frac{W}{T_A}$
- Outlet Pipe / Leak ($B$): Empties tank in $T_B$ hours $\implies E_B = -\frac{W}{T_B}$
- Net Efficiency ($E_{\text{net}}$): $E_{\text{net}} = E_A - E_B$
3. Time, Speed & Distance (TSD) Fundamentals
Core Formulas & Unit Conversions
- km/h to m/s: Multiply by $\frac{5}{18}$ (e.g., $72\text{ km/h} = 72 \times \frac{5}{18} = 20\text{ m/s}$).
- m/s to km/h: Multiply by $\frac{18}{5}$ (e.g., $15\text{ m/s} = 15 \times \frac{18}{5} = 54\text{ km/h}$).
Average Speed
- Two Equal Distance Segments: When an object travels equal distances at speeds $S_1$ and $S_2$, the average speed is the harmonic mean:
- Three Equal Distance Segments:
Late and Early Arrival Distance Shortcut
If traveling at speed $S_1$ leads to arriving $t_1$ minutes late, and traveling at speed $S_2$ leads to arriving $t_2$ minutes early (net time difference $\Delta t = t_1 + t_2$ hours):
4. Trains, Relative Velocity, and Boats & Streams
Train Crossing Formulas
| Scenario | Distance Traversed | Speed Formula | Crossing Time ($T$) |
|---|---|---|---|
| Train crossing stationary pole/man | $L_{\text{train}}$ | $S_{\text{train}}$ | $T = \frac{L_{\text{train}}}{S_{\text{train}}}$ |
| Train crossing platform/bridge | $L_{\text{train}} + L_{\text{plat}}$ | $S_{\text{train}}$ | $T = \frac{L_{\text{train}} + L_{\text{plat}}}{S_{\text{train}}}$ |
| Two trains crossing (Opposite dir.) | $L_1 + L_2$ | $S_1 + S_2$ | $T = \frac{L_1 + L_2}{S_1 + S_2}$ |
| Two trains crossing (Same dir.) | $L_1 + L_2$ | $S_1 - S_2$ | $T = \frac{L_1 + L_2}{S_1 - S_2}$ |
Boats and Streams Mechanics
Let speed of boat in still water $= u\text{ km/h}$ and speed of water current $= v\text{ km/h}$:
- Downstream Speed ($D$): Motion with the current $\implies D = u + v$
- Upstream Speed ($U$): Motion against the current $\implies U = u - v$
From these two equations, we obtain:
- Round-Trip Average Speed:
A mining contractor undertakes to excavate a coal trench of 4,000 cubic meters in 35 days by employing 30 workers working 8 hours a day. After 20 days, only 2,000 cubic meters of earthwork has been completed. How many additional workers must the contractor employ for the remaining 15 days, with all workers continuing to work 8 hours a day, to finish the project strictly on schedule?
A coal haulage freight train of length 280 meters travels at a constant speed of 72 km/h. It completely crosses an oncoming passenger train of length 220 meters traveling in the opposite direction on an adjacent parallel track in 15 seconds. What is the speed of the passenger train in km/h?
A survey motorboat travels a distance of 36 km downstream along a river in 3 hours. On the return trip upstream against the current, the motorboat requires 6 hours to cover the same distance of 36 km. What is the speed of the river current and the speed of the motorboat in still water?