4.1 Arithmetic Foundations: Percentages, Profit & Loss, Ratio & Proportion

Key Takeaways

  • Mastery of fractional equivalents (e.g., $1/7 \approx 14.28\%$, $1/8 = 12.5\%$, $1/12 \approx 8.33\%$, $1/16 = 6.25\%$) accelerates mental arithmetic and eliminates pencil-and-paper latency in CIL MT Paper-I.
  • Successive percentage changes compound according to $\Delta\% = a + b + \frac{ab}{100}$; two equal and opposite changes of $\pm x\%$ inevitably produce a net percentage loss of $\frac{x^2}{100}\%$.
  • Under product constancy ($A \times B = K$), an increase in variable $A$ by $\frac{a}{b}$ mandates a compensatory decrease in variable $B$ by $\frac{a}{a+b}$ to hold the total product invariant.
  • Commercial markup and discount interact via $\frac{MP}{CP} = \frac{100 + \text{Profit}\%}{100 - \text{Discount}\%}$, establishing an immediate linkage between procurement cost and final realization.
  • Dishonest dealer profit is calculated strictly on the true versus false measure as $\text{Gain}\% = \frac{\text{Error}}{\text{True Measure} - \text{Error}} \times 100\%$, while partnership profits divide strictly by capital-time investment product sums $\sum (C_i \times T_i)$.
Last updated: August 2026

Arithmetic Foundations: Percentages, Profit & Loss, Ratio & Proportion

In the Coal India Limited Management Trainee (CIL MT) Paper-I examination, Numerical Ability constitutes 25 vital marks. Speed and numerical agility are paramount: candidates must solve quantitative problems in approximately 45 to 50 seconds per item. Navigating arithmetic through standard algebraic variables often induces unnecessary computational friction. Instead, candidates must master fraction-to-percentage conversions, product constancy relationships, commercial pricing chains, and proportional balancing.


1. Fraction-to-Percentage Equivalence & Decimal Multipliers

Direct translation between fractions and percentages converts complex division into rapid mental multiplication. In engineering and commercial contexts—such as coal washing yields, stripping ratios, and equipment depreciation—these fractions appear repeatedly.

Standard Conversion Matrix

FractionPercentageDecimal EquivalentKey Derived Multiples
$1/2$$50.00%$$0.50$$3/2 = 150%$
$1/3$$33.33%$ ($33\frac{1}{3}%$)$0.3333$$2/3 = 66.67%$
$1/4$$25.00%$$0.25$$3/4 = 75.00%$
$1/5$$20.00%$$0.20$$2/5 = 40%, 3/5 = 60%, 4/5 = 80%$
$1/6$$16.67%$ ($16\frac{2}{3}%$)$0.1667$$5/6 = 83.33%$
$1/7$$14.28%$ ($14\frac{2}{7}%$)$0.1428$$2/7 = 28.57%, 3/7 = 42.86%, 4/7 = 57.14%$
$1/8$$12.50%$ ($12\frac{1}{2}%$)$0.1250$$3/8 = 37.50%, 5/8 = 62.50%, 7/8 = 87.50%$
$1/9$$11.11%$ ($11\frac{1}{9}%$)$0.1111$$2/9 = 22.22%, 4/9 = 44.44%, 7/9 = 77.78%$
$1/10$$10.00%$$0.10$$3/10 = 30%, 7/10 = 70%, 9/10 = 90%$
$1/11$$9.09%$ ($9\frac{1}{11}%$)$0.0909$$2/11 = 18.18%, 3/11 = 27.27%, 5/11 = 45.45%$
$1/12$$8.33%$ ($8\frac{1}{3}%$)$0.0833$$5/12 = 41.67%, 7/12 = 58.33%, 11/12 = 91.67%$
$1/13$$7.69%$ ($7\frac{9}{13}%$)$0.0769$$2/13 = 15.38%$
$1/14$$7.14%$ ($7\frac{1}{7}%$)$0.0714$$3/14 = 21.43%$
$1/15$$6.67%$ ($6\frac{2}{3}%$)$0.0667$$4/15 = 26.67%, 7/15 = 46.67%$
$1/16$$6.25%$ ($6\frac{1}{4}%$)$0.0625$$3/16 = 18.75%, 5/16 = 31.25%, 7/16 = 43.75%$

Multiplying Factors ($MF$)

When a quantity $X$ changes by $r%$, the new quantity $X'$ is evaluated via the Multiplying Factor ($MF$):

X=X×MF=X×(1±r100)X' = X \times MF = X \times \left(1 \pm \frac{r}{100}\right)

  • Growth ($+r%$): A $37.5%$ increase implies $MF = 1 + \frac{3}{8} = \frac{11}{8} = 1.375$.
  • Decay ($-r%$): A $16.67%$ reduction implies $MF = 1 - \frac{1}{6} = \frac{5}{6} \approx 0.8333$.

2. Successive Percentage Changes & Product Constancy

Successive Percentage Change Formula

When a base quantity undergoes two successive percentage alterations of $a%$ and $b%$ (where positive denotes an increase and negative denotes a decrease), the net percentage change $\Delta_{\text{net}}%$ is given by:

Δnet%=(a+b+a×b100)%\Delta_{\text{net}}\% = \left(a + b + \frac{a \times b}{100}\right)\%

For three successive changes $a%, b%, c%$, apply the formula iteratively or compute the compounded multiplying factor:

MFnet=(1+a100)(1+b100)(1+c100)MF_{\text{net}} = \left(1 + \frac{a}{100}\right)\left(1 + \frac{b}{100}\right)\left(1 + \frac{c}{100}\right)

Δnet%=(MFnet1)×100%\Delta_{\text{net}}\% = (MF_{\text{net}} - 1) \times 100\%

Special Case: Equal and Opposite Changes ($ pm x%$) When a quantity is first increased by $x%$ and subsequently decreased by $x%$, the net result is always an absolute loss given by: Δnet%=+xx+(+x)(x)100=x2100%\Delta_{\text{net}}\% = +x - x + \frac{(+x)(-x)}{100} = -\frac{x^2}{100}\%

Product Constancy ($A \times B = \text{Constant}$)

In many industrial and economic systems, the product of two variables is fixed:

Expenditure=Price×Consumption\text{Expenditure} = \text{Price} \times \text{Consumption} Total Work=Efficiency×Time\text{Total Work} = \text{Efficiency} \times \text{Time} Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}

If variable $A$ increases by a fractional amount $\frac{a}{b}$, variable $B$ must decrease by $\frac{a}{a + b}$ to maintain the invariant product $K$:

A=A(1+ab)=A(a+bb)    B=B(ba+b)=B(1aa+b)A' = A\left(1 + \frac{a}{b}\right) = A\left(\frac{a+b}{b}\right) \implies B' = B\left(\frac{b}{a+b}\right) = B\left(1 - \frac{a}{a+b}\right)

Increase in $A$Required Decrease in $B$Practical Example
$+1/1$ ($+100%$)$-1/2$ ($-50.00%$)Coal price doubles $\implies$ consumption halved
$+1/2$ ($+50%$)$-1/3$ ($-33.33%$)Price $+50% \implies$ consumption down by $1/3$
$+1/3$ ($+33.33%$)$-1/4$ ($-25.00%$)Price $+33.33% \implies$ consumption down by $25%$
$+1/4$ ($+25%$)$-1/5$ ($-20.00%$)Price $+25% \implies$ consumption down by $20%$
$+1/5$ ($+20%$)$-1/6$ ($-16.67%$)Price $+20% \implies$ consumption down by $16.67%$
$+a/b$$-a/(a+b)$General forward transformation
$-a/b$$+a/(b-a)$General reverse transformation (Price drop)

3. Commercial Arithmetic: Profit, Loss, Markup, and Discounts

Commercial transactions involve three baseline financial markers: Cost Price ($CP$), Marked Price ($MP$), and Selling Price ($SP$).

Core Equations

  1. Profit and Loss Percentages: Profit=SPCP(when SP>CP),Profit%=SPCPCP×100%\text{Profit} = SP - CP \quad (\text{when } SP > CP), \quad \text{Profit}\% = \frac{SP - CP}{CP} \times 100\% Loss=CPSP(when CP>SP),Loss%=CPSPCP×100%\text{Loss} = CP - SP \quad (\text{when } CP > SP), \quad \text{Loss}\% = \frac{CP - SP}{CP} \times 100\% Note: Profit and loss percentages are always computed on $CP$ unless explicitly designated on $SP$.

  2. Markup and Discount Relationships: Markup%=MPCPCP×100%    MP=CP(1+Markup%100)\text{Markup}\% = \frac{MP - CP}{CP} \times 100\% \implies MP = CP\left(1 + \frac{\text{Markup}\%}{100}\right) Discount%=MPSPMP×100%    SP=MP(1Discount%100)\text{Discount}\% = \frac{MP - SP}{MP} \times 100\% \implies SP = MP\left(1 - \frac{\text{Discount}\%}{100}\right)

  3. Master Ratio Formula ($CP$ to $MP$): Equating $SP$ expressions yields: CP(1+Profit%100)=MP(1Discount%100)CP\left(1 + \frac{\text{Profit}\%}{100}\right) = MP\left(1 - \frac{\text{Discount}\%}{100}\right) MPCP=100+Profit%100Discount%\frac{MP}{CP} = \frac{100 + \text{Profit}\%}{100 - \text{Discount}\%} (For a net loss, substitute $-\text{Loss}%$ in the numerator).

  4. Successive Discounts: Two successive discounts $d_1%$ and $d_2%$ produce a single equivalent discount $D_{\text{eq}}%$: Deq%=(d1+d2d1×d2100)%D_{\text{eq}}\% = \left(d_1 + d_2 - \frac{d_1 \times d_2}{100}\right)\%

Dishonest Dealer & Faulty Weighing Systems

In raw material procurement and coal dispatch logistics, dishonest dealer scenarios test faulty scales and adulteration.

  • Case 1: Sells at Cost Price but Uses False Weight If a trader claims to sell goods at $CP$ but delivers a false measure $W_{\text{false}}$ instead of the true measure $W_{\text{true}}$: Gain%=(WtrueWfalseWfalse)×100%=(ErrorTrue MeasureError)×100%\text{Gain}\% = \left(\frac{W_{\text{true}} - W_{\text{false}}}{W_{\text{false}}}\right) \times 100\% = \left(\frac{\text{Error}}{\text{True Measure} - \text{Error}}\right) \times 100\%

  • Case 2: Combined Markup/Discount with False Measure Let a trader mark up goods by $m%$ (or discount by $d%$) and simultaneously deliver $W_{\text{false}}$ grams instead of $W_{\text{true}}$ grams. The overall multiplying factor is: MFoverall=(WtrueWfalse)×(1+m100)×(1d100)MF_{\text{overall}} = \left(\frac{W_{\text{true}}}{W_{\text{false}}}\right) \times \left(1 + \frac{m}{100}\right) \times \left(1 - \frac{d}{100}\right) Net Profit%=(MFoverall1)×100%\text{Net Profit}\% = (MF_{\text{overall}} - 1) \times 100\%


4. Ratio, Proportion, and Partnership Profit Distribution

Properties of Ratios and Proportions

  1. Compound Ratio: For ratios $a:b$ and $c:d$, the compound ratio is $(a \times c) : (b \times d)$.
  2. Duplicate & Sub-duplicate Ratios:
    • Duplicate ratio of $a:b$ is $a^2 : b^2$.
    • Sub-duplicate ratio of $a:b$ is $\sqrt{a} : \sqrt{b}$.
    • Triplicate ratio of $a:b$ is $a^3 : b^3$.
  3. Proportional Variations ($a : b :: c : d$): ab=cd    a×d=b×c\frac{a}{b} = \frac{c}{d} \implies a \times d = b \times c
    • Mean Proportional between $a$ and $c$: $b = \sqrt{a \times c}$.
    • Third Proportional to $a$ and $b$: $c = \frac{b^2}{a}$.
    • Fourth Proportional to $a, b,$ and $c$: $d = \frac{b \times c}{a}$.

Partnership Capital-Time Allocations

When multiple entities partner in a joint venture, the total profit is distributed strictly in proportion to the product of their invested capital ($C$) and the duration of investment ($T$):

Profit Ratio (P1:P2:P3)=(C1×T1):(C2×T2):(C3×T3)\text{Profit Ratio } (P_1 : P_2 : P_3) = (C_1 \times T_1) : (C_2 \times T_2) : (C_3 \times T_3)

If a managing partner receives a dedicated salary or managerial commission ($S%$) from the gross profit $P_{\text{gross}}$ before distribution:

Pdistributable=Pgross×(1S100)P_{\text{distributable}} = P_{\text{gross}} \times \left(1 - \frac{S}{100}\right)

Each partner $i$ then receives their share from $P_{\text{distributable}}$, with the managing partner additionally retaining their salary $S$.

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Commercial Pricing Flow: CP to MP to SP
Test Your Knowledge

A mining equipment vendor marks an excavator at 50% above its cost price and subsequently offers two successive trade discounts of 20% and 10% to Coal India Limited. If the vendor incurs Rs. 5,000 on pre-delivery freight inspections and still realizes a net profit of Rs. 15,000, what was the initial cost price (CP) of the excavator?

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D
Test Your Knowledge

Due to geopolitical supply constraints, the unit price of imported coking coal increases by 25%. A thermal power utility decides that its total monthly financial expenditure on coal must only rise by 10%. By what percentage must the utility curtail its physical monthly consumption of coal?

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B
C
D
Test Your Knowledge

A dishonest coal vendor uses a rigged electronic weighbridge that displays 1,000 kg when only 800 kg of coal is loaded. Furthermore, the vendor claims to sell the coal at a nominal discount of 10% below its purchase cost price. What is the vendor's actual net gain percentage on this transaction?

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D