4.4 Algebra, Mensuration, Geometry & Data Interpretation (DI)

Key Takeaways

  • Quadratic roots are governed by discriminant Δ=b2−4ac\Delta = b^2 - 4ac, sum α+β=−ba\alpha + \beta = -\frac{b}{a}, and product αβ=ca\alpha\beta = \frac{c}{a}, allowing quick equation construction and sign analysis.

  • Symmetric algebraic identities and reciprocal powers (x+1x=k  ⟹  x2+1x2=k2−2,x3+1x3=k3−3kx + \frac{1}{x} = k \implies x^2 + \frac{1}{x^2} = k^2 - 2, x^3 + \frac{1}{x^3} = k^3 - 3k) simplify high-degree polynomials in competitive tests.

  • 2D and 3D mensuration relies on fundamental volume and surface area relationships (cylinders πr2h\pi r^2 h, cones 13πr2h\frac{1}{3}\pi r^2 h, spheres 43πr3\frac{4}{3}\pi r^3), governed by the principle of volume conservation during metal/material recasting.

  • Data Interpretation (DI) requires mastery of tabular data, bar graphs, line charts, and pie chart angle conversions (1%=3.6∘1\% = 3.6^{\circ}), emphasizing percentage growth, year-on-year analysis, and ratio evaluation.

  • Speed in DI is achieved by calculating approximate percentages, using common denominators, and avoiding complete manual arithmetic when options have distinct divergence.

Last updated: August 2026

Algebra, Mensuration, Geometry & Data Interpretation (DI)

Quantitative Aptitude in CIL MT Paper-I culminates in advanced algebraic relationships, 2D/3D mensuration geometry, and Data Interpretation (DI). Engineers are expected to interpret graphical outputs, calculate geometrical material clearances, and manipulate polynomial equations with precision.


1. Algebraic Identities & Quadratic Polynomials

Core Polynomial Identities

  1. Standard Binomial & Trinomial Expansions:

    (a±b)2=a2±2ab+b2(a \pm b)^2 = a^2 \pm 2ab + b^2 (a+b+c)2=a2+b2+c2+2(ab+bc+ca)(a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca) a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b) (a±b)3=a3±3a2b+3ab2±b3=a3±b3±3ab(a±b)(a \pm b)^3 = a^3 \pm 3a^2b + 3ab^2 \pm b^3 = a^3 \pm b^3 \pm 3ab(a \pm b) a3+b3=(a+b)(a2−ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2) a3−b3=(a−b)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2)
  2. The Conditional Cubic Identity:

    a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca) =12(a+b+c)[(a−b)2+(b−c)2+(c−a)2]= \frac{1}{2}(a + b + c)\left[(a - b)^2 + (b - c)^2 + (c - a)^2\right] If a+b+c=0,then a3+b3+c3=3abc\text{If } a + b + c = 0, \quad \text{then } a^3 + b^3 + c^3 = 3abc
  3. Reciprocal Powers (x+1/x=kx + 1/x = k):

    • x2+1x2=k2−2x^2 + \frac{1}{x^2} = k^2 - 2
    • x3+1x3=k3−3kx^3 + \frac{1}{x^3} = k^3 - 3k
    • x4+1x4=(k2−2)2−2x^4 + \frac{1}{x^4} = (k^2 - 2)^2 - 2
    • If x−1x=k  ⟹  x2+1x2=k2+2,x3−1x3=k3+3kx - \frac{1}{x} = k \implies x^2 + \frac{1}{x^2} = k^2 + 2, \quad x^3 - \frac{1}{x^3} = k^3 + 3k

Quadratic Equations & Nature of Roots

For ax2+bx+c=0ax^2 + bx + c = 0 with roots α\alpha and β\beta:

x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
  • Sum of Roots: α+β=−ba\alpha + \beta = -\frac{b}{a}
  • Product of Roots: αβ=ca\alpha \beta = \frac{c}{a}
  • Discriminant Analysis (Δ=b2−4ac\Delta = b^2 - 4ac):
    • Δ>0\Delta > 0: Two distinct real roots (rational if Δ\Delta is a perfect square).
    • Δ=0\Delta = 0: Two equal real roots (α=β=−b/2a\alpha = \beta = -b/2a).
    • Δ<0\Delta < 0: Complex conjugate roots.

2. 2D Mensuration & Plane Geometry

ShapePerimeter / CircumferenceArea (AA)Special Properties
Scalene TriangleP=a+b+cP = a + b + cA=s(s−a)(s−b)(s−c)A = \sqrt{s(s-a)(s-b)(s-c)}Semi-perimeter s=(a+b+c)/2s = (a+b+c)/2 (Heron's Formula)
Equilateral TriangleP=3aP = 3aA=34a2A = \frac{\sqrt{3}}{4}a^2Height h=32ah = \frac{\sqrt{3}}{2}a, Inradius r=a23r = \frac{a}{2\sqrt{3}}, Circumradius R=a3R = \frac{a}{\sqrt{3}}
Right TriangleP=a+b+hP = a + b + hA=12×base×heightA = \frac{1}{2} \times \text{base} \times \text{height}Hypotenuse h=a2+b2h = \sqrt{a^2 + b^2}
RectangleP=2(l+w)P = 2(l + w)A=l×wA = l \times wDiagonal d=l2+w2d = \sqrt{l^2 + w^2}
RhombusP=4aP = 4aA=12d1d2A = \frac{1}{2} d_1 d_2Diagonals bisect at 90∘90^{\circ}; Side a=12d12+d22\text{Side } a = \frac{1}{2}\sqrt{d_1^2 + d_2^2}
TrapeziumP=a+b+c+dP = a + b + c + dA=12(a+b)×hA = \frac{1}{2}(a + b) \times ha,ba, b are parallel sides, hh is perpendicular distance
CircleC=2πrC = 2\pi rA=πr2A = \pi r^2Sector Area =θ360∘πr2= \frac{\theta}{360^{\circ}}\pi r^2, Arc Length =θ360∘2πr= \frac{\theta}{360^{\circ}}2\pi r
Annulus (Ring)—A=π(R2−r2)A = \pi(R^2 - r^2)Width w=R−rw = R - r

3. 3D Mensuration: Solids & Volume Conservation

Solid ObjectVolume (VV)Curved / Lateral Surface Area (CSACSA)Total Surface Area (TSATSA)
CuboidV=l×w×hV = l \times w \times hLSA=2h(l+w)LSA = 2h(l + w)TSA=2(lw+wh+hl)TSA = 2(lw + wh + hl), Diagonal =l2+w2+h2= \sqrt{l^2 + w^2 + h^2}
CubeV=a3V = a^3LSA=4a2LSA = 4a^2TSA=6a2TSA = 6a^2, Diagonal =a3= a\sqrt{3}
Right CylinderV=πr2hV = \pi r^2 hCSA=2πrhCSA = 2\pi rhTSA=2πr(h+r)TSA = 2\pi r(h + r)
Hollow CylinderV=π(R2−r2)hV = \pi(R^2 - r^2)hCSA=2π(R+r)hCSA = 2\pi(R + r)hTSA=2π(R+r)h+2π(R2−r2)TSA = 2\pi(R + r)h + 2\pi(R^2 - r^2)
Right ConeV=13πr2hV = \frac{1}{3}\pi r^2 hCSA=πrlCSA = \pi r lTSA=πr(l+r)TSA = \pi r(l + r), Slant Height l=r2+h2l = \sqrt{r^2 + h^2}
SphereV=43πr3V = \frac{4}{3}\pi r^3CSA=4πr2CSA = 4\pi r^2TSA=4πr2TSA = 4\pi r^2
HemisphereV=23πr3V = \frac{2}{3}\pi r^3CSA=2πr2CSA = 2\pi r^2TSA=3πr2TSA = 3\pi r^2

Volume Conservation in Recasting: When a solid metal ingot or billet is melted down and recast into NN identical smaller bodies: Voriginal=N×VnewV_{\text{original}} = N \times V_{\text{new}}

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Data Interpretation Taxonomy and Metric Computation

4. Data Interpretation (DI) Analytical Frameworks

Data Interpretation in CIL MT tests rapid data extraction and percentage comparisons from four primary display formats:

1. Table Charts

Data is arranged in row-by-column grids. Typical questions evaluate:

  • Row/Column Sums: Rapid grouping of values by round tens or hundreds.
  • Ratio Analysis: Expressing output of one division relative to another without high-precision decimals.

2. Bar Charts & Stacked Bars

Bars represent discrete categories (e.g., subsidiary-wise annual production in Million Tonnes). Visual height corresponds directly to magnitude.

3. Pie Charts (Angular vs. Percentage Mapping)

A full circular pie chart represents 100%100\% of data distributed across 360∘360^{\circ}:

100%=360∘  ⟺  1%=3.6∘  ⟺  1∘=1036%=518%100\% = 360^{\circ} \iff 1\% = 3.6^{\circ} \iff 1^{\circ} = \frac{10}{36}\% = \frac{5}{18}\% Value of Sector=(θ∘360∘)×Total Value\text{Value of Sector} = \left(\frac{\theta^{\circ}}{360^{\circ}}\right) \times \text{Total Value}

4. Line Graphs & Trend Metrics

Used for continuous time series (monthly coal dispatches, overburden removal over years).

  • Percentage Increase / Decrease: Δ%=(Valuecurrent−ValuebaseValuebase)×100%\Delta\% = \left(\frac{\text{Value}_{\text{current}} - \text{Value}_{\text{base}}}{\text{Value}_{\text{base}}}\right) \times 100\%
  • Compound Annual Growth Rate (CAGR) Approximation: CAGR=(VfinalVinitial)1/n−1\text{CAGR} = \left(\frac{V_{\text{final}}}{V_{\text{initial}}}\right)^{1/n} - 1

Worked Example: Subsidiary Production Table

Consider annual coal dispatch data across five CIL subsidiaries:

Subsidiary2024 Dispatch (MT)2025 Dispatch (MT)Growth (MT)Growth Rate (%)
ECL50.055.0+5.0+5.0+10.00%+10.00\%
BCCL40.046.0+6.0+6.0+15.00%+15.00\%
CCL60.072.0+12.0+12.0+20.00%+20.00\%
NCL120.0132.0+12.0+12.0+10.00%+10.00\%
SECL150.0165.0+15.0+15.0+10.00%+10.00\%
Total420.0470.0+50.0+11.90%
  • CCL achieved the highest individual growth rate (20.00%20.00\%).
  • SECL contributed the largest absolute incremental tonnage (15.0 MT15.0\text{ MT}).
  • Total CIL dispatch grew by 50420×100%=11.90%\frac{50}{420} \times 100\% = 11.90\%.
Test Your Knowledge

If α and β are the real roots of the quadratic equation 2x² - 6x + 3 = 0, what is the exact value of the algebraic expression (α/β) + (β/α) + 3(α + β)?

A

10.0

B

11.5

C

13.0

D

15.0

Test Your Knowledge

A solid metallic right circular cylinder of base radius 6 cm and height 24 cm is melted down and recast into identical small solid spheres, each of radius 3 cm. Assuming zero loss of metal during the recasting process, how many such spherical balls can be formed?

A

18

B

24

C

28

D

32

Test Your Knowledge

In a Coal India dispatch pie chart representing total subsidiary production of 180 million tonnes (MT), the central sector angle allocated to South Eastern Coalfields Limited (SECL) is 108°, while Northern Coalfields Limited (NCL) is allocated 72°. What is the absolute difference in coal production between SECL and NCL, and what percentage of total production does SECL represent?

A

Difference: 12 MT; SECL Share: 25.0%

B

Difference: 15 MT; SECL Share: 28.5%

C

Difference: 24 MT; SECL Share: 33.3%

D

Difference: 18 MT; SECL Share: 30.0%

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