9.2 Standard and General Equations of Circles

Key Takeaways

  • The standard equation $(x - a)^2 + (y - b)^2 = r^2$ ($r > 0$) reveals center $C(a, b)$ and radius $r$, while general form $x^2 + y^2 + Dx + Ey + F = 0$ represents a real circle if and only if $D^2 + E^2 - 4F > 0$.
  • Parametric equations $x = a + r\cos\theta, y = b + r\sin\theta$ ($\theta \in [0, 2\pi)$) convert distance and optimization problems on circles into single-variable trigonometric functions.
  • An Apollonius circle is the locus of a point $P$ moving such that the ratio of its distances to two fixed points $A$ and $B$ is a constant $k \neq 1$ ($|PA| = k |PB|$).
  • Positional relationships of two circles depend on center distance $d$ vs radii $R, r$; subtracting intersecting circle equations yields their radical axis and common chord of length $L = 2\sqrt{R^2 - d_{center}^2}$.
Last updated: July 2026

9.2 Standard and General Equations of Circles

A circle is the geometric locus of all points in a plane that are at a fixed distance (the radius $r > 0$) from a fixed point (the center $C(a, b)$). In Gaokao analytic geometry, questions on circles test structural algebraic transformations, geometric properties (such as chord length, tangency, and symmetry), parametric optimizations, locus derivations, and interactions between multiple circles.


1. Standard and General Forms of Circle Equations

Standard Form

Applying the distance formula between a dynamic point $P(x, y)$ and fixed center $C(a, b)$ set equal to radius $r > 0$: (xa)2+(yb)2=r    (xa)2+(yb)2=r2\sqrt{(x - a)^2 + (y - b)^2} = r \implies (x - a)^2 + (y - b)^2 = r^2

  • Key Advantage: Standard Form explicitly reveals the center coordinates $(a, b)$ and radius $r$. It is preferred when geometric conditions involve center coordinates or radius explicitly.

General Form

Expanding the standard form equation: x22ax+a2+y22by+b2r2=0x^2 - 2ax + a^2 + y^2 - 2by + b^2 - r^2 = 0 Letting $D = -2a$, $E = -2b$, and $F = a^2 + b^2 - r^2$, we obtain the General Form: x2+y2+Dx+Ey+F=0x^2 + y^2 + Dx + Ey + F = 0

To recover geometric parameters from the general form, complete the square for $x$ and $y$: (x+D2)2+(y+E2)2=D2+E24F4\left(x + \frac{D}{2}\right)^2 + \left(y + \frac{E}{2}\right)^2 = \frac{D^2 + E^2 - 4F}{4}

Discriminant Analysis of General Form

The equation $x^2 + y^2 + Dx + Ey + F = 0$ is governed by the discriminant $\Delta_{circle} = D^2 + E^2 - 4F$:

  1. $\Delta_{circle} > 0$: Represents a real circle with center $C\left(-\frac{D}{2}, -\frac{E}{2}\right)$ and radius $r = \frac{1}{2}\sqrt{D^2 + E^2 - 4F}$.
  2. $\Delta_{circle} = 0$: Represents a single point $C\left(-\frac{D}{2}, -\frac{E}{2}\right)$ (a degenerate circle with radius $r = 0$).
  3. $\Delta_{circle} < 0$: Represents no real locus (empty set in $\mathbb{R}^2$).

Gaokao Caution: Never assume an equation of the form $x^2 + y^2 + Dx + Ey + F = 0$ represents a circle without first checking or enforcing $D^2 + E^2 - 4F > 0$.


2. Parametric Equations of a Circle

For a circle $(x - a)^2 + (y - b)^2 = r^2$, introducing parameter angle $\theta \in [0, 2\pi)$ (measured counterclockwise from the positive horizontal direction centered at $C(a, b)$) gives the parametric equations: {x=a+rcosθy=b+rsinθ(θ[0,2π))\begin{cases} x = a + r \cos \theta \\ y = b + r \sin \theta \end{cases} \quad (\theta \in [0, 2\pi))

Applications of Parametric Equations

  • Algebraic Extremum Problems: To find the maximum or minimum of a linear objective function $z = Ax + By$ for points $(x, y)$ on circle $(x - a)^2 + (y - b)^2 = r^2$, substitute parametric coordinates: z=A(a+rcosθ)+B(b+rsinθ)=(Aa+Bb)+r(Acosθ+Bsinθ)=(Aa+Bb)+rA2+B2sin(θ+ϕ)z = A(a + r\cos\theta) + B(b + r\sin\theta) = (Aa + Bb) + r(A\cos\theta + B\sin\theta) = (Aa + Bb) + r\sqrt{A^2 + B^2}\sin(\theta + \phi) where $\tan\phi = \frac{A}{B}$. Thus $z_{\max} = Aa + Bb + r\sqrt{A^2 + B^2}$ and $z_{\min} = Aa + Bb - r\sqrt{A^2 + B^2}$.

3. Methods for Determining Equations of Circles

Determining a circle's equation requires finding three independent algebraic coefficients (either $a, b, r$ or $D, E, F$). Two principal methods exist:

Algebraic Method (Undetermined Coefficients)

  1. Assume general form $x^2 + y^2 + Dx + Ey + F = 0$.
  2. Set up a system of three linear equations using three given non-collinear points $P_1, P_2, P_3$.
  3. Solve for $D, E, F$ and verify $D^2 + E^2 - 4F > 0$.

Geometric Method

  1. Use geometric properties to locate center $C(a, b)$:
    • Center $C$ lies on the perpendicular bisectors of any chords formed by given points.
    • Center $C$ lies at distance $r$ from tangent lines.
  2. Compute radius $r = |CP_1|$.
  3. Write the standard form $(x - a)^2 + (y - b)^2 = r^2$.

Diameter Form of a Circle

If segment $AB$ with endpoints $A(x_1, y_1)$ and $B(x_2, y_2)$ is a diameter of circle $C$, then any point $P(x, y)$ on the circle (except $A, B$) satisfies $\vec{PA} \perp \vec{PB} \iff \vec{PA} \cdot \vec{PB} = 0$. Expanded equation: (xx1)(xx2)+(yy1)(yy2)=0(x - x_1)(x - x_2) + (y - y_1)(y - y_2) = 0

Apollonius Circle (阿波罗尼斯圆)

In the plane, the locus of point $P$ such that the ratio of its distances to two fixed points $A$ and $B$ is a constant $k$ ($k > 0, k \neq 1$) is a circle: PAPB=k    PA2=k2PB2\frac{|PA|}{|PB|} = k \implies |PA|^2 = k^2 |PB|^2 Derivation: Place $A(-c, 0)$ and $B(c, 0)$ on the $x$-axis. Expanding $(x + c)^2 + y^2 = k^2 [(x - c)^2 + y^2]$ yields a quadratic equation with equal non-zero coefficients for $x^2$ and $y^2$ and no $xy$ term, representing a circle.


4. Positional Relationships Between Two Circles

Let two circles be $C_1: (x - a_1)^2 + (y - b_1)^2 = R^2$ and $C_2: (x - a_2)^2 + (y - b_2)^2 = r^2$ with $R \ge r > 0$. Let $d = |C_1 C_2| = \sqrt{(a_1 - a_2)^2 + (b_1 - b_2)^2}$ be the center-to-center distance.

Positional RelationshipDistance CriterionNumber of Intersection PointsNumber of Common Tangents
Outer Separation (外离)$d > R + r$$0$$4$ (2 outer, 2 inner)
External Tangency (外切)$d = R + r$$1$$3$ (2 outer, 1 inner)
Intersection (相交)$R - r< d < R + r$
Internal Tangency (内切)$d = R - r > 0$$1$$1$ (1 outer)
Inner Inclusion (内含)$0 \le d < R - r$$0$$0$

Common Chord and Radical Axis (相交弦与等幂轴)

When two circles $C_1: x^2 + y^2 + D_1 x + E_1 y + F_1 = 0$ and $C_2: x^2 + y^2 + D_2 x + E_2 y + F_2 = 0$ intersect at two points $A$ and $B$, subtracting $C_2$ from $C_1$ eliminates $x^2$ and $y^2$: (D1D2)x+(E1E2)y+(F1F2)=0(D_1 - D_2)x + (E_1 - E_2)y + (F_1 - F_2) = 0 This linear equation represents the radical axis (等幂轴) of the two circles. For intersecting circles, it is precisely the line equation of their common chord $AB$.

  • Common Chord Length Formula: Perpendicular distance $d_1$ from center $C_1$ to line $AB$ gives chord length: LAB=2R2d12L_{AB} = 2 \sqrt{R^2 - d_1^2}
Loading diagram...
Classification of Two-Circle Positional Relationships and Common Chord Derivation
Test Your Knowledge

For what value of parameter $m$ does the equation $x^2 + y^2 - 2x + 4y + m = 0$ represent a circle with radius $r = 3$?

A
B
C
D
Test Your Knowledge

What is the length of the common chord of the two intersecting circles $C_1: x^2 + y^2 = 10$ and $C_2: x^2 + y^2 - 4x - 4y + 6 = 0$?

A
B
C
D
Test Your Knowledge

Given two fixed points $A(-1, 0)$ and $B(2, 0)$, a moving point $P(x, y)$ satisfies $|PA| = 2 |PB|$. What is the standard equation of the locus of $P$ (the Apollonius Circle)?

A
B
C
D