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4.1 Algebraic and Geometric Representations of Complex Numbers

Key Takeaways

  • A complex number z=a+biz = a + bi (a,b∈Ra, b \in \mathbb{R}) is uniquely identified by its real part Re⁡(z)=a\operatorname{Re}(z) = a and imaginary part Im⁡(z)=b\operatorname{Im}(z) = b, with i2=−1i^2 = -1. Purely imaginary numbers satisfy a=0a = 0 and b≠0b \neq 0.

  • In the Argand plane (complex plane), z=a+biz = a + bi corresponds bijectively to the point P(a,b)P(a, b) and the position vector OP⃗=(a,b)\vec{OP} = (a, b), establishing a fundamental isomorphism between complex numbers and 2D vectors.

  • The modulus ∣z∣=a2+b2|z| = \sqrt{a^2 + b^2} measures the Euclidean distance from the origin to P(a,b)P(a, b), while the complex conjugate zˉ=a−bi\bar{z} = a - bi represents the reflection of zz across the real axis, satisfying zzˉ=∣z∣2z \bar{z} = |z|^2.

  • Polar form z=r(cos⁡θ+isin⁡θ)=reiθz = r(\cos\theta + i\sin\theta) = r e^{i\theta} connects complex numbers to trigonometry and Euler's formula, where r=∣z∣r = |z| and θ=arg⁡(z)\theta = \arg(z) is the principal argument (θ∈(−π,π]\theta \in (-\pi, \pi] or [0,2π)[0, 2\pi)).

Last updated: July 2026

4.1 Algebraic and Geometric Representations of Complex Numbers

The expansion of the real number system R\mathbb{R} to the complex number system C\mathbb{C} represents one of the most profound developments in mathematics. In the real number field R\mathbb{R}, equations such as x2+1=0x^2 + 1 = 0 have no solutions because the square of any real number is non-negative. By introducing the imaginary unit ii, defined by i2=−1i^2 = -1, mathematicians constructed the complex number system C\mathbb{C}, providing solutions to all polynomial equations and establishing a deep bridge between algebra, geometry, and trigonometry.


1. Algebraic Definitions and Classifications

A complex number is an expression of the form:

z=a+bi(a,b∈R)z = a + bi \quad (a, b \in \mathbb{R})

where aa is called the real part of zz, denoted as Re⁡(z)=a\operatorname{Re}(z) = a, and bb is called the imaginary part of zz, denoted as Im⁡(z)=b\operatorname{Im}(z) = b. Note that both the real part and the imaginary part are real numbers themselves.

Classification of Complex Numbers

The set of all complex numbers is denoted by C\mathbb{C}. Based on the values of aa and bb, complex numbers are classified as follows:

  • Real Numbers (R\mathbb{R}): When b=0b = 0, z=a∈Rz = a \in \mathbb{R}. Thus, R⊂C\mathbb{R} \subset \mathbb{C}.
  • Imaginary Numbers: When b≠0b \neq 0, z=a+biz = a + bi is an imaginary number.
  • Purely Imaginary Numbers: When a=0a = 0 and b≠0b \neq 0, z=biz = bi is called a purely imaginary number.

Equality of Complex Numbers

Two complex numbers z1=a+biz_1 = a + bi and z2=c+diz_2 = c + di (a,b,c,d∈Ra, b, c, d \in \mathbb{R}) are equal if and only if their real parts are equal and their imaginary parts are equal:

z1=z2  ⟺  a=candb=dz_1 = z_2 \iff a = c \quad \text{and} \quad b = d

Gaokao Strategy Note: Inequality relationships (z1>z2z_1 > z_2 or z1<z2z_1 < z_2) are generally not defined for non-real complex numbers. If an inequality z1>z2z_1 > z_2 is stated in a Gaokao question, it implicitly implies that both z1z_1 and z2z_2 must be real numbers.


2. Geometric Representation: The Complex Plane

Every complex number z=a+biz = a + bi can be uniquely paired with an ordered pair of real numbers (a,b)(a, b). This establishes a natural bijection between the set of complex numbers C\mathbb{C} and points in the two-dimensional Cartesian plane:

C⟷R2viaz=a+bi⟷P(a,b)\mathbb{C} \longleftrightarrow \mathbb{R}^2 \quad \text{via} \quad z = a + bi \longleftrightarrow P(a, b)

When the Cartesian coordinate plane is used to represent complex numbers, it is called the complex plane (or Argand diagram):

  • The horizontal axis is called the real axis (representing Re⁡(z)\operatorname{Re}(z)).
  • The vertical axis is called the imaginary axis (representing Im⁡(z)\operatorname{Im}(z)), excluding the origin for purely imaginary numbers.

Vector Interpretation

Furthermore, there is a one-to-one correspondence between complex numbers z=a+biz = a + bi and position vectors starting from the origin:

z=a+bi⟷OP⃗=(a,b)z = a + bi \longleftrightarrow \vec{OP} = (a, b)

This vector interpretation allows complex addition and subtraction to be understood as vector addition and subtraction obeying the parallelogram rule.


3. Modulus and Complex Conjugate

Modulus of a Complex Number

The modulus (or absolute value) of a complex number z=a+biz = a + bi, denoted by ∣z∣|z|, is defined as the Euclidean distance from the origin O(0,0)O(0,0) to the point P(a,b)P(a,b) in the complex plane:

∣z∣=a2+b2|z| = \sqrt{a^2 + b^2}

Fundamental Properties of Modulus:

  1. Non-negativity: ∣z∣≥0|z| \geq 0, with ∣z∣=0  ⟺  z=0|z| = 0 \iff z = 0.
  2. Multiplicativity: ∣z1z2∣=∣z1∣⋅∣z2∣|z_1 z_2| = |z_1| \cdot |z_2| and ∣z1z2∣=∣z1∣∣z2∣\left|\frac{z_1}{z_2}\right| = \frac{|z_1|}{|z_2|} (for z2≠0z_2 \neq 0).
  3. Triangle Inequality: ∣z1+z2∣≤∣z1∣+∣z2∣|z_1 + z_2| \leq |z_1| + |z_2|, with equality holding if and only if OP1⃗\vec{OP_1} and OP2⃗\vec{OP_2} are collinear and point in the same direction.
  4. Distance Formula: The distance between two complex numbers z1=a1+b1iz_1 = a_1 + b_1 i and z2=a2+b2iz_2 = a_2 + b_2 i in the complex plane is given by ∣z1−z2∣=(a1−a2)2+(b1−b2)2|z_1 - z_2| = \sqrt{(a_1 - a_2)^2 + (b_1 - b_2)^2}.

Complex Conjugate

The complex conjugate of z=a+biz = a + bi, denoted by zˉ\bar{z} or z∗z^*, is defined as:

zˉ=a−bi\bar{z} = a - bi

Geometrically, zˉ\bar{z} represents the reflection of zz across the real axis.

Key Algebraic Properties of Conjugates:

  • z1±z2‾=zˉ1±zˉ2\overline{z_1 \pm z_2} = \bar{z}_1 \pm \bar{z}_2
  • z1z2‾=zˉ1zˉ2\overline{z_1 z_2} = \bar{z}_1 \bar{z}_2 and (z1z2)‾=zˉ1zˉ2\overline{\left(\frac{z_1}{z_2}\right)} = \frac{\bar{z}_1}{\bar{z}_2}
  • zzˉ=(a+bi)(a−bi)=a2+b2=∣z∣2z \bar{z} = (a + bi)(a - bi) = a^2 + b^2 = |z|^2
  • Real and Imaginary Part Extraction: Re⁡(z)=z+zˉ2\operatorname{Re}(z) = \frac{z + \bar{z}}{2} and Im⁡(z)=z−zˉ2i\operatorname{Im}(z) = \frac{z - \bar{z}}{2i}
  • zz is a real number   ⟺  z=zˉ\iff z = \bar{z}; zz is a purely imaginary number   ⟺  z=−zˉ≠0\iff z = -\bar{z} \neq 0.

4. Trigonometric and Exponential (Euler) Forms

By introducing polar coordinates (r,θ)(r, \theta) in the complex plane where x=rcos⁡θx = r\cos\theta and y=rsin⁡θy = r\sin\theta:

r=∣z∣=a2+b2,cos⁡θ=ar,sin⁡θ=br(r>0)r = |z| = \sqrt{a^2 + b^2}, \quad \cos\theta = \frac{a}{r}, \quad \sin\theta = \frac{b}{r} \quad (r > 0)

We can express zz in trigonometric form:

z=r(cos⁡θ+isin⁡θ)z = r(\cos\theta + i\sin\theta)

where rr is the modulus and θ\theta is an argument of zz, written as θ=arg⁡(z)\theta = \arg(z). The argument is multi-valued (θ+2kπ,k∈Z\theta + 2k\pi, k \in \mathbb{Z}). The unique value of θ\theta in the interval (−π,π](-\pi, \pi] (or [0,2π)[0, 2\pi)) is called the principal argument, denoted by Arg⁡(z)\operatorname{Arg}(z).

Euler's Formula

Using Euler's formula, eiθ=cos⁡θ+isin⁡θe^{i\theta} = \cos\theta + i\sin\theta, any complex number can be written in exponential form:

z=reiθz = r e^{i\theta}

5. Worked Gaokao Exam Examples

Example 1: Purely Imaginary Condition and Parameter Determination

Problem: Let m∈Rm \in \mathbb{R}. If the complex number z=(m2−3m+2)+(m2−1)iz = (m^2 - 3m + 2) + (m^2 - 1)i is a purely imaginary number, find the value of mm and calculate ∣z∣|z|.

Solution:

  1. For zz to be a purely imaginary number, its real part must equal zero while its imaginary part must be non-zero: {Re⁡(z)=m2−3m+2=0Im⁡(z)=m2−1≠0\begin{cases} \operatorname{Re}(z) = m^2 - 3m + 2 = 0 \\ \operatorname{Im}(z) = m^2 - 1 \neq 0 \end{cases}
  2. Solve the quadratic equation for the real part: m2−3m+2=(m−1)(m−2)=0  ⟹  m=1 or m=2m^2 - 3m + 2 = (m - 1)(m - 2) = 0 \implies m = 1 \text{ or } m = 2
  3. Check the non-zero condition for the imaginary part:
    • If m=1m = 1, Im⁡(z)=12−1=0\operatorname{Im}(z) = 1^2 - 1 = 0, which makes z=0+0i=0z = 0 + 0i = 0 (a real number, not purely imaginary). Thus m=1m = 1 is rejected.
    • If m=2m = 2, Im⁡(z)=22−1=3≠0\operatorname{Im}(z) = 2^2 - 1 = 3 \neq 0.
  4. Thus, m=2m = 2. Substituting m=2m = 2 into zz gives z=0+3i=3iz = 0 + 3i = 3i.
  5. The modulus is ∣z∣=∣3i∣=02+32=3|z| = |3i| = \sqrt{0^2 + 3^2} = 3.

Example 2: Complex Locus and Distance Analysis

Problem: In the complex plane, let zz satisfy the equation ∣z−(1+2i)∣=5|z - (1 + 2i)| = \sqrt{5}. Describe the geometric locus of zz and find the maximum value of ∣z∣|z|.

Solution:

  1. Let z=x+yiz = x + yi (x,y∈Rx, y \in \mathbb{R}). The given equation becomes: ∣(x−1)+(y−2)i∣=5  ⟹  (x−1)2+(y−2)2=5|(x - 1) + (y - 2)i| = \sqrt{5} \implies \sqrt{(x - 1)^2 + (y - 2)^2} = \sqrt{5} Squaring both sides yields (x−1)2+(y−2)2=5(x - 1)^2 + (y - 2)^2 = 5.
  2. Geometrically, this equation represents a circle centered at C(1,2)C(1, 2) with radius R=5R = \sqrt{5}.
  3. ∣z∣|z| represents the distance from the origin O(0,0)O(0,0) to the point P(x,y)P(x,y) on the circle.
  4. The distance from the origin O(0,0)O(0,0) to the center C(1,2)C(1,2) is: ∣OC∣=12+22=5|OC| = \sqrt{1^2 + 2^2} = \sqrt{5}
  5. Since the center is at distance 5\sqrt{5} from the origin and the radius is R=5R = \sqrt{5}, the circle passes through the origin O(0,0)O(0,0).
  6. The maximum distance ∣z∣max⁡|z|_{\max} occurs at the point diametrically opposite to the origin: ∣z∣max⁡=∣OC∣+R=5+5=25|z|_{\max} = |OC| + R = \sqrt{5} + \sqrt{5} = 2\sqrt{5}

6. Summary Comparison of Complex Representations

RepresentationFormula / FormPrimary Use / Geometric Insight
Algebraic Formz=a+biz = a + bi (a,b∈Ra,b \in \mathbb{R})Standard arithmetic, solving algebraic equations
Coordinate FormP(a,b)∈R2P(a, b) \in \mathbb{R}^2Plotting points on the Argand plane
Vector FormOP⃗=(a,b)\vec{OP} = (a, b)Vector addition/subtraction, parallelogram rule
Modulus & Conjugate∣z∣=a2+b2,zˉ=a−bi\vert z\vert= \sqrt{a^2+b^2}, \bar{z} = a - biDistance calculations, zzˉ=∣z∣2z\bar{z} = \vert z\vert^2 simplification
Trigonometric Formz=r(cos⁡θ+isin⁡θ)z = r(\cos\theta + i\sin\theta)Multiplication, division, powers, De Moivre's Theorem
Exponential Formz=reiθz = r e^{i\theta}Euler's formula, rotational transformations
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Interconnected Representations of Complex Numbers
Test Your Knowledge

Given z=(k2−4)+(k+2)iz = (k^2 - 4) + (k + 2)i where k∈Rk \in \mathbb{R}, for what value of kk is zz a purely imaginary number?

A

k=2k = 2

B

k=−2k = -2

C

k=±2k = \pm 2

D

k=0k = 0

Test Your Knowledge

What is the modulus ∣z∣|z| of the complex number z=3−4iz = 3 - 4i?

A

11

B

77

C

55

D

7\sqrt{7}

Test Your Knowledge

In the complex plane, what geometric figure is defined by the complex equation ∣z−2+i∣=3|z - 2 + i| = 3?

A

A line passing through the point (2,−1)(2, -1)

B

A circle centered at (2,−1)(2, -1) with radius 33

C

A circle centered at (−2,1)(-2, 1) with radius 99

D

A parabola with vertex at (2,−1)(2, -1)

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