9.3 Soil Permeability, Seepage, Flow Nets, and Effective Stress

Key Takeaways

  • Darcy's law (v=kiv = k i) establishes that discharge velocity is proportional to hydraulic gradient (i=Δh/Li = \Delta h / L), whereas pore fluid travels at the significantly higher seepage velocity vs=v/nv_s = v / n through interconnected void channels.

  • Laboratory hydraulic conductivity is determined via the Constant Head test (k=QLAhtk = \frac{QL}{Aht}) for coarse cohesionless soils and the Falling Head test (k=aLAtln⁡[h1/h2]k = \frac{aL}{At} \ln[h_1/h_2]) for low-permeability cohesive soils.

  • Stratified soil profiles exhibit directional anisotropy: equivalent conductivity parallel to bedding (kh,eq=∑kiHi∑Hik_{h,eq} = \frac{\sum k_i H_i}{\sum H_i}) is dominated by permeable aquifers, while vertical perpendicular flow (kv,eq=∑Hi∑[Hi/ki]k_{v,eq} = \frac{\sum H_i}{\sum [H_i/k_i]}) is restricted by impermeable aquitards.

  • Two-dimensional steady-state seepage satisfies the Laplace equation (∇2h=0\nabla^2 h = 0), graphically solved via orthogonal flow nets to compute under-seepage rate (q=kHNfNdq = k H \frac{N_f}{N_d}), base uplift pressures, and exit gradients (iexit=Δh/li_{exit} = \Delta h / l).

  • Terzaghi's effective stress principle (σ′=σ−u\sigma' = \sigma - u) dictates structural shear strength and settlement; upward seepage reduces effective stress, culminating in total shear failure (boiling/quicksand) when the hydraulic gradient reaches icr=γ′γw=Gs−11+ei_{cr} = \frac{\gamma'}{\gamma_w} = \frac{G_s - 1}{1+e}.

Last updated: October 2026

9.3 Soil Permeability, Seepage, Flow Nets, and Effective Stress

Water flow through soil media dictates critical geotechnical design problems—including seepage losses beneath concrete gravity dams, hydraulic uplift forces on basements and dry docks, piping erosion at weir toes, slope stability under transient seepage, and 1D consolidation settlement under building footings. In the CELE Hydraulics and Geotechnical Engineering examination cluster, seepage and effective stress principles represent the most analytically rigorous problem sets.


Subsurface Water & Darcy's Law

Subsurface soil water is classified into three physical categories:

  1. Gravitational Water (Free Water): Water that moves through interconnected void channels under the driving influence of gravity and hydraulic gradients, governed by fluid flow principles.
  2. Capillary Water: Water held in void pores above the phreatic surface (groundwater table) by surface tension forces acting along soil grain menisci. Capillary rise induces negative pore water pressure (matric suction): u=−γwhcu = -\gamma_w h_c, which mathematically increases effective stress and apparent cohesion.
  3. Adsorbed (Hygroscopic) Water: Dipolar water molecules held tenaciously to the electrically charged surfaces of clay minerals by hydrogen bonding and van der Waals forces. Adsorbed water does not circulate freely and cannot transmit hydrostatic pressure.

Total Hydraulic Head & Darcy's Formulations

In geotechnical hydraulics, the total head (hh) at any subsurface point is expressed through Bernoulli's equation. Because groundwater seepage occurs at very low velocities, the kinetic velocity head term (v22g≈0\frac{v^2}{2g} \approx 0) is negligible:

h=uγw+zh = \frac{u}{\gamma_w} + z

where uγw\frac{u}{\gamma_w} is the pressure head (hph_p), zz is the elevation head relative to a chosen datum, and hh is the piezometric (total) head.

In 1856, Henry Darcy formulated the empirical governing law for laminar flow through saturated sand filters:

v=k⋅iv = k \cdot i

q=v⋅A=k⋅i⋅Aq = v \cdot A = k \cdot i \cdot A

where:

  • vv = discharge velocity (or superficial Darcy velocity), calculated across the gross cross-sectional area AA of the soil specimen.
  • kk = hydraulic conductivity (or coefficient of permeability) with units of velocity (cm/scm/s or m/sm/s).
  • ii = hydraulic gradient, defined as head loss per unit flow length: i=ΔhLi = \frac{\Delta h}{L}.

Discharge Velocity vs. Actual Seepage Velocity

Water does not flow through the solid soil skeleton; it is constrained strictly to the tortuous void pathways. By equating total discharge across gross area AA and void area AvA_v:

q=v⋅A=vs⋅Avq = v \cdot A = v_s \cdot A_v

vs=v⋅AAv≈v⋅VVv=vn=v(1+ee)v_s = v \cdot \frac{A}{A_v} \approx v \cdot \frac{V}{V_v} = \frac{v}{n} = v \left(\frac{1+e}{e}\right)

where vsv_s is the seepage velocity (actual interstitial pore velocity) and nn is porosity. Because n<1.0n < 1.0, the true seepage velocity is strictly greater than Darcy's discharge velocity (vs>vv_s > v).


Laboratory Permeability Testing Methods

Laboratory hydraulic conductivity is measured using two standardized testing apparatuses depending on soil texture:

1. Constant Head Permeability Test (ASTM D2434)

Utilized for coarse-grained soils with relatively high hydraulic conductivity (k>10−4 cm/sk > 10^{-4}\text{ cm/s}, such as clean sands and gravels). A constant head difference (hh) is maintained across a soil specimen of length LL and area AA. The water volume QQ collected over elapsed time tt is measured:

Q=q⋅t=(k⋅i⋅A)t=k(hL)A⋅tQ = q \cdot t = (k \cdot i \cdot A) t = k \left(\frac{h}{L}\right) A \cdot t

k=Q⋅LA⋅h⋅tk = \frac{Q \cdot L}{A \cdot h \cdot t}

2. Falling (Variable) Head Permeability Test (ASTM D5856)

Utilized for fine-grained soils with low permeability (k<10−4 cm/sk < 10^{-4}\text{ cm/s}, such as silts and clays). Water flows from a narrow standpipe of area aa through a soil specimen of area AA and length LL. As water seeps into the soil, the hydraulic head in the standpipe drops from h1h_1 at time t=0t = 0 to h2h_2 at time tt:

Inflow Rate: qin=−adhdt\text{Inflow Rate: } q_{in} = -a \frac{dh}{dt}

Outflow Rate (Darcy): qout=k(hL)A\text{Outflow Rate (Darcy): } q_{out} = k \left(\frac{h}{L}\right) A

Equating inflow and outflow gives the governing separable differential equation:

−adhdt=k(hL)A  ⟹  −dhh=(kAaL)dt-a \frac{dh}{dt} = k \left(\frac{h}{L}\right) A \implies -\frac{dh}{h} = \left(\frac{k A}{a L}\right) dt

Integrating between limits [h1,h2][h_1, h_2] and [0,t][0, t]:

−∫h1h2dhh=kAaL∫0tdt  ⟹  ln⁡(h1h2)=kAtaL-\int_{h_1}^{h_2} \frac{dh}{h} = \frac{k A}{a L} \int_0^t dt \implies \ln\left(\frac{h_1}{h_2}\right) = \frac{k A t}{a L}

k=a⋅LA⋅tln⁡(h1h2)=2.303a⋅LA⋅tlog⁡10(h1h2)k = \frac{a \cdot L}{A \cdot t} \ln\left(\frac{h_1}{h_2}\right) = 2.303 \frac{a \cdot L}{A \cdot t} \log_{10}\left(\frac{h_1}{h_2}\right)


Equivalent Permeability in Stratified / Layered Soils

Natural sedimentary and alluvial soil deposits are horizontally stratified. Because permeability varies drastically across consecutive strata, equivalent hydraulic conductivities must be derived for directional seepage.

1. Flow Parallel to Stratification (kh,eqk_{h,eq})

When groundwater flows horizontally parallel to horizontal soil layers of individual thicknesses H1,H2,…,HnH_1, H_2, \dots, H_n and permeabilities k1,k2,…,knk_1, k_2, \dots, k_n:

  • The hydraulic gradient is uniform across all layers: i1=i2=⋯=ii_1 = i_2 = \dots = i.
  • Total discharge is the sum of individual layer discharges: q=∑qi=∑(viAi)=∑(kiiHi⋅1)q = \sum q_i = \sum (v_i A_i) = \sum (k_i i H_i \cdot 1).

kh,eq=∑kiHi∑Hi=k1H1+k2H2+⋯+knHnH1+H2+⋯+Hnk_{h,eq} = \frac{\sum k_i H_i}{\sum H_i} = \frac{k_1 H_1 + k_2 H_2 + \dots + k_n H_n}{H_1 + H_2 + \dots + H_n}

Note

Parallel equivalent permeability (kh,eqk_{h,eq}) is a weighted arithmetic mean governed predominantly by the layer with the highest hydraulic conductivity (the most permeable aquifer).

2. Flow Perpendicular to Stratification (kv,eqk_{v,eq})

When groundwater seeps vertically through horizontal soil layers:

  • The discharge velocity is identical across all layers to preserve fluid mass continuity: v1=v2=⋯=vv_1 = v_2 = \dots = v.
  • Total head loss is the sum of individual layer head losses: Δh=∑Δhi=∑(iiHi)=∑(vHiki)\Delta h = \sum \Delta h_i = \sum (i_i H_i) = \sum \left(\frac{v H_i}{k_i}\right).

kv,eq=∑Hi∑(Hiki)=HH1k1+H2k2+⋯+Hnknk_{v,eq} = \frac{\sum H_i}{\sum \left(\frac{H_i}{k_i}\right)} = \frac{H}{\frac{H_1}{k_1} + \frac{H_2}{k_2} + \dots + \frac{H_n}{k_n}}

Note

Perpendicular equivalent permeability (kv,eqk_{v,eq}) is a harmonic mean governed predominantly by the layer with the lowest hydraulic conductivity (the least permeable aquitard). Consequently, in stratified deposits, kh,eq>kv,eqk_{h,eq} > k_{v,eq} always.


Two-Dimensional Seepage & Flow Nets

Combining Darcy's law with the 2D fluid continuity equation for an incompressible fluid moving through isotropic, homogeneous soil yields the classical Laplace Equation of steady-state seepage:

∂2h∂x2+∂2h∂z2=0\frac{\partial^2 h}{\partial x^2} + \frac{\partial^2 h}{\partial z^2} = 0

A flow net is a graphical solution to Laplace's equation comprising two mutually orthogonal families of curves:

  1. Flow Lines (Ψ\Psi): Streamlines tracing the trajectory of seeping water particles. The region bounded between two adjacent flow lines is a flow channel. Total number of flow channels = NfN_f.
  2. Equipotential Lines (Φ\Phi): Contours connecting points of equal total hydraulic head (hh). The head drop between any two adjacent equipotential lines is the potential drop Δh=HNd\Delta h = \frac{H}{N_d}, where HH is the total driving head (upstream minus downstream) and NdN_d is the total number of potential drops.
Upstream Water (H1)                     Downstream Tailwater (H2)
   |                                                |
===+========= Concrete Dam / Impervious Base =======+===
   |                                                |
   +~~~~~~~~~~~~~~~~ Soil Foundation ~~~~~~~~~~~~~~~+
   |  -> Flow Line 1 --------------------------->   |  (Nf = Flow Channels)
   |  -> Flow Line 2 --------------------------->   |
   |   |        |        |        |        |        |  (Nd = Potential Drops)
   |  Φ1       Φ2       Φ3       Φ4       Φ5       Φ6

1. Seepage Quantity Under Hydraulic Structures

For a flow net constructed with curvilinear squares (element aspect ratio ΔsΔl≈1.0\frac{\Delta s}{\Delta l} \approx 1.0), the seepage discharge (qq) per unit length (1.0 m1.0\text{ m} perpendicular to the cross-section) is:

q=k⋅H(NfNd)q = k \cdot H \left(\frac{N_f}{N_d}\right)

2. Uplift Pressure Under Concrete Structures

At any point ii along the base of a concrete weir or gravity dam, the pore water pressure (uiu_i) is computed from total head and elevation:

hi=hupstream−ni⋅(HNd)h_i = h_{upstream} - n_i \cdot \left(\frac{H}{N_d}\right)

ui=(hi−zi)γwu_i = (h_i - z_i)\gamma_w

where nin_i is the number of potential drops experienced from the upstream reservoir to point ii, and ziz_i is the elevation of the base point above the chosen datum.

3. Exit Gradient & Quicksand / Piping Phenomenon

At the downstream toe of a hydraulic structure, water emerges vertically. The exit hydraulic gradient (iexiti_{exit}) across the final flow field of length lexitl_{exit} is:

iexit=Δhlexit=H/Ndlexiti_{exit} = \frac{\Delta h}{l_{exit}} = \frac{H / N_d}{l_{exit}}

As upward seepage force increases, it counteracts the gravitational submerged weight of the soil particles. The critical hydraulic gradient (icri_{cr}) occurs when the upward seepage force per unit volume (j=iγwj = i \gamma_w) exactly equals the submerged unit weight (γ′\gamma'):

icr⋅γw=γ′  ⟹  icr=γ′γw=γsat−γwγw=Gs−11+ei_{cr} \cdot \gamma_w = \gamma' \implies i_{cr} = \frac{\gamma'}{\gamma_w} = \frac{\gamma_{sat} - \gamma_w}{\gamma_w} = \frac{G_s - 1}{1+e}

When iexit≥icri_{exit} \ge i_{cr}, the effective stress drops to zero (σ′=0\sigma' = 0). Cohesionless soil completely loses its internal shear strength, transforming into a boiling suspension known as quicksand. This triggers subsurface retrogressive erosion called piping. The design Factor of Safety against piping must satisfy:

FSpiping=icriexit≥3.0 to 5.0FS_{piping} = \frac{i_{cr}}{i_{exit}} \ge 3.0 \text{ to } 5.0


Terzaghi's Principle of Effective Stress

Formulated by Karl Terzaghi in 1925, the Principle of Effective Stress is the single most important concept in geotechnical engineering. Soil deformations (compression, consolidation) and shearing resistance are governed not by total stress alone, but by intergranular stresses transmitted across solid grain contact points:

σ=σ′+u  ⟹  σ′=σ−u\sigma = \sigma' + u \implies \sigma' = \sigma - u

where:

  • σ\sigma = total vertical stress, representing the total weight of soil and water above a given depth per unit area: σ=∑γihi\sigma = \sum \gamma_i h_i.
  • uu = pore water pressure, the hydrostatic fluid pressure in void spaces: u=γwhwu = \gamma_w h_w.
  • σ′\sigma' = effective vertical stress, representing the net skeletal stress resisting deformation.

Seepage Influence on Effective Stress Profiles

  1. Hydrostatic (No Flow) Condition: σ=γsat⋅z\sigma = \gamma_{sat} \cdot z u=γw⋅zu = \gamma_w \cdot z σ′=σ−u=(γsat−γw)z=γ′⋅z\sigma' = \sigma - u = (\gamma_{sat} - \gamma_w) z = \gamma' \cdot z
  2. Upward Seepage Condition (Hydraulic gradient ii): Upward flow exerts an upward drag on soil particles, increasing pore pressure by Δu=+izγw\Delta u = +i z \gamma_w: σ′=γ′z−izγw=z(γ′−iγw)\sigma' = \gamma' z - i z \gamma_w = z(\gamma' - i \gamma_w)
    • At i=icr=γ′γwi = i_{cr} = \frac{\gamma'}{\gamma_w}, effective stress vanishes (σ′=0\sigma' = 0), producing boiling/liquefaction.
  3. Downward Seepage Condition (Hydraulic gradient ii): Downward flow exerts a downward drag on soil particles, decreasing pore pressure by Δu=−izγw\Delta u = -i z \gamma_w: σ′=γ′z+izγw=z(γ′+iγw)\sigma' = \gamma' z + i z \gamma_w = z(\gamma' + i \gamma_w)
    • Downward seepage enhances soil stability and effective stress.

CELE Board-Exam Worked Situational Problem

Problem Statement

A concrete gravity dam retains an upstream head of water H1=12.0 mH_1 = 12.0\text{ m} and a downstream tailwater head H2=1.5 mH_2 = 1.5\text{ m}. The dam foundation rests on a homogeneous sand layer with thickness H=9.0 mH = 9.0\text{ m}, underlain by impermeable basalt bedrock. The sand has hydraulic conductivity k=4.0×10−5 m/sk = 4.0 \times 10^{-5}\text{ m/s}, void ratio e=0.65e = 0.65, and solid specific gravity Gs=2.66G_s = 2.66. Take γw=9.81 kN/m3\gamma_w = 9.81\text{ kN/m}^3.

A flow net drawn for the foundation geometry reveals Nf=4N_f = 4 flow channels and Nd=12N_d = 12 equipotential drops. The final flow element at the downstream exit has a length of lexit=1.60 ml_{exit} = 1.60\text{ m}.

Calculate:

  1. The total under-seepage rate (qq) per meter length of dam in cubic meters per day (m3/day/mm^3/day/m).
  2. The critical hydraulic gradient (icri_{cr}) and the exit hydraulic gradient (iexiti_{exit}) at the downstream toe.
  3. The Factor of Safety (FSFS) against piping, and the effective vertical stress (σ′\sigma') at a depth of z=3.0 mz = 3.0\text{ m} directly beneath the downstream toe under this upward seepage condition.

Step-by-Step Solution

Part 1: Under-Seepage Rate Calculation

  1. Net Driving Head (HH): H=H1−H2=12.0 m−1.5 m=10.5 mH = H_1 - H_2 = 12.0\text{ m} - 1.5\text{ m} = 10.5\text{ m}
  2. Seepage Discharge per Unit Width (qq): q=k⋅H(NfNd)=(4.0×10−5 m/s)×10.5 m×(412)q = k \cdot H \left(\frac{N_f}{N_d}\right) = (4.0 \times 10^{-5}\text{ m/s}) \times 10.5\text{ m} \times \left(\frac{4}{12}\right) q=4.0×10−5×10.5×0.3333=1.400×10−4 m3/s/mq = 4.0 \times 10^{-5} \times 10.5 \times 0.3333 = 1.400 \times 10^{-4}\text{ m}^3\text{/s/m}
  3. Conversion to Daily Discharge: qday=1.400×10−4 m3/s×86,400 s/day=12.096 m3/day/m≈12.10 m3/day/mq_{day} = 1.400 \times 10^{-4}\text{ m}^3\text{/s} \times 86,400\text{ s/day} = 12.096\text{ m}^3\text{/day/m} \approx 12.10\text{ m}^3\text{/day/m}

Part 2: Critical and Exit Hydraulic Gradients

  1. Critical Hydraulic Gradient (icri_{cr}): icr=Gs−11+e=2.66−11+0.65=1.661.65=1.0061≈1.01i_{cr} = \frac{G_s - 1}{1+e} = \frac{2.66 - 1}{1 + 0.65} = \frac{1.66}{1.65} = 1.0061 \approx 1.01
  2. Head Drop per Equipotential Step (Δh\Delta h): Δh=HNd=10.5 m12=0.875 m\Delta h = \frac{H}{N_d} = \frac{10.5\text{ m}}{12} = 0.875\text{ m}
  3. Exit Gradient (iexiti_{exit}): iexit=Δhlexit=0.875 m1.60 m=0.5469≈0.547i_{exit} = \frac{\Delta h}{l_{exit}} = \frac{0.875\text{ m}}{1.60\text{ m}} = 0.5469 \approx 0.547

Part 3: Factor of Safety and Effective Stress

  1. Factor of Safety against Piping (FSFS): FS=icriexit=1.00610.5469=1.84FS = \frac{i_{cr}}{i_{exit}} = \frac{1.0061}{0.5469} = 1.84 (Note: Because FS=1.84<3.0FS = 1.84 < 3.0, the dam toe is vulnerable to piping; downstream protective filters or relief wells are mandatory).
  2. Submerged Unit Weight of Sand (γ′\gamma'): γsat=(Gs+e)γw1+e=(2.66+0.65)×9.811.65=3.31×9.811.65=19.68 kN/m3\gamma_{sat} = \frac{(G_s + e)\gamma_w}{1+e} = \frac{(2.66 + 0.65) \times 9.81}{1.65} = \frac{3.31 \times 9.81}{1.65} = 19.68\text{ kN/m}^3 γ′=γsat−γw=19.68−9.81=9.87 kN/m3\gamma' = \gamma_{sat} - \gamma_w = 19.68 - 9.81 = 9.87\text{ kN/m}^3
  3. Effective Vertical Stress with Upward Seepage at z=3.0 mz = 3.0\text{ m}: At the downstream toe, seepage is directed upward with gradient i≈iexit=0.5469i \approx i_{exit} = 0.5469: σ′=z(γ′−iγw)=3.0 m×[9.87 kN/m3−(0.5469×9.81 kN/m3)]\sigma' = z(\gamma' - i \gamma_w) = 3.0\text{ m} \times [9.87\text{ kN/m}^3 - (0.5469 \times 9.81\text{ kN/m}^3)] σ′=3.0×[9.87−5.365]=3.0×4.505=13.52 kPa\sigma' = 3.0 \times [9.87 - 5.365] = 3.0 \times 4.505 = 13.52\text{ kPa} Hydrostatic check (without seepage): σhydro′=3.0×9.87=29.61 kPa\sigma'_{hydro} = 3.0 \times 9.87 = 29.61\text{ kPa}. Notice that upward seepage has reduced the in-situ effective stress by over 54%.

CELE Board Examination Traps & Critical Pitfalls

Warning

Trap 1: Confusing Discharge Velocity (vv) with Seepage Velocity (vsv_s) Darcy's law yields discharge velocity: v=kiv = k i. Board problems regularly ask for the time required for a contaminant plume or dye tracer to travel between two observation wells. Travel time depends on the actual seepage velocity: t=L/vs=L/(v/n)t = L / v_s = L / (v / n). Using vv instead of vsv_s understates fluid velocity by a factor of 22 to 33 and overestimates travel time significantly.

Warning

Trap 2: Forgetting Tailwater in Driving Head (HH) When computing seepage quantity (q=kHNf/Ndq = k H N_f / N_d), HH is the net head differential across the structure (H=Hupstream−HdownstreamH = H_{upstream} - H_{downstream}), NOT the upstream water depth alone. If the downstream tailwater is 2.0 m2.0\text{ m} and upstream depth is 10.0 m10.0\text{ m}, H=8.0 mH = 8.0\text{ m}.

Warning

Trap 3: Counting Equipotential Lines Instead of Drops (NdN_d) A frequent Scantron blunder is counting the total number of drawn equipotential lines instead of potential drops. If a flow net contains 13 equipotential lines including boundary contours, the number of head drops is Nd=13−1=12N_d = 13 - 1 = 12.

Warning

Trap 4: Upward Seepage Sign in Effective Stress Calculations Always remember: upward seepage reduces effective stress (σ′=γ′z−izγw\sigma' = \gamma' z - i z \gamma_w), whereas downward seepage increases effective stress (σ′=γ′z+izγw\sigma' = \gamma' z + i z \gamma_w). When flow is upward, water drags the soil grains upward against gravity, loosening grain contacts and risking quicksand conditions.

Loading diagram...
Two-Dimensional Seepage Flow Net and Effective Stress Gradient Distribution
Test Your Knowledge

A laboratory falling-head permeability test is performed on an undisturbed cylindrical silt specimen of length L = 15.0 cm and diameter D = 10.0 cm (cross-sectional area A = 78.54 cm²). The standpipe tube has an internal diameter d = 0.60 cm (area a = 0.2827 cm²). During the test, the hydraulic head drops from h1 = 90.0 cm to h2 = 45.0 cm in a duration of 12.0 minutes (720 seconds). What is the hydraulic conductivity (k) of the silt in cm/s?

A

2.26 × 10⁻⁵ cm/s

B

3.12 × 10⁻³ cm/s

C

5.20 × 10⁻⁵ cm/s

D

1.20 × 10⁻⁴ cm/s

Test Your Knowledge

A uniform sand stratum underlying a sheet-pile cofferdam excavation has a void ratio e = 0.62 and a specific gravity Gs = 2.65. Dewatering of the excavation induces upward vertical seepage toward the pit floor. At what critical hydraulic gradient (icr) will the sand experience quicksand (boiling) failure with total loss of effective stress?

A

0.81

B

0.63

C

1.65

D

1.02

Test Your Knowledge

A stratified foundation soil deposit consists of three distinct horizontal layers: Layer 1 has thickness H1 = 1.50 m and k1 = 4.0 × 10⁻³ cm/s; Layer 2 has thickness H2 = 2.50 m and k2 = 5.0 × 10⁻⁴ cm/s; Layer 3 has thickness H3 = 4.00 m and k3 = 2.0 × 10⁻⁵ cm/s. Total stratum thickness is H = 8.00 m. What is the equivalent vertical hydraulic conductivity (kv,eq) for groundwater flow perpendicular to the stratification planes?

A

3.90 × 10⁻⁵ cm/s

B

1.51 × 10⁻³ cm/s

C

9.16 × 10⁻⁴ cm/s

D

7.25 × 10⁻⁵ cm/s

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