7.2 Conic Sections Basics

Why Conics Appear on the CAE Academic Paper

Conic sections close out plane analytic geometry in the FSc Pre-Engineering syllabus. On Pakistan Air Force CAE and related engineering initial tests, expect identification and one-step formula questions: “which equation is an ellipse?”, “radius of this circle?”, or “length of the latus rectum?”. Full locus derivations are rare under a ~30-second-per-item pace, but you must recognise each standard form instantly.

Engineering intuition helps memory: circular arcs approximate wheel and gear sections, parabolic mirrors appear in optics and some antenna dishes, elliptical orbits and stress trajectories show up later in aerospace coursework, and hyperbolic paths model certain fly-by geometries. The exam still tests textbook equations, not mission design.

Circle

Definition: set of points at fixed distance (radius r) from a fixed centre (h, k).

Standard equation: (x − h)² + (y − k)² = r².

General second-degree form (no xy term, equal coefficients of x² and y²):

x² + y² + Dx + Ey + F = 0,

with centre (−D/2, −E/2) and r = √[(D/2)² + (E/2)² − F], provided the expression under the square root is positive.

Worked Example 1 — Completing the square

Find the centre and radius of x² + y² − 6x + 4y − 3 = 0.

Solution: (x² − 6x) + (y² + 4y) = 3 → (x − 3)² − 9 + (y + 2)² − 4 = 3 → (x − 3)² + (y + 2)² = 16.

Centre (3, −2), radius 4.

Worked Example 2 — Equation from centre and point

A circle has centre (−1, 2) and passes through (3, 5). Find its equation.

Solution: r² = (3 − (−1))² + (5 − 2)² = 16 + 9 = 25.

Equation: (x + 1)² + (y − 2)² = 25 → x² + y² + 2x − 4y − 20 = 0.

Parabola

Definition: set of points equidistant from a fixed point (focus) and a fixed line (directrix).

Standard forms with vertex at the origin:

Eccentricity of every parabola is e = 1.

Worked Example 3 — Focus and directrix

For y² = 12x, find focus, directrix, and latus rectum length.

Solution: 4a = 12 ⇒ a = 3. Focus (3, 0), directrix x = −3, latus rectum 12.

Worked Example 4 — Vertex shifted

Identify the parabola (y − 1)² = −8(x + 2).

Solution: Vertex (−2, 1), 4a = 8 ⇒ a = 2, opens left. Focus: (−2 − 2, 1) = (−4, 1). Directrix: x = −2 + 2 = 0.

Ellipse

Standard form (major axis along x): x²/a² + y²/b² = 1 with a > b > 0.

• Semi-major axis a, semi-minor axis b.
• Eccentricity e = √(1 − b²/a²) (0 < e < 1).
• Foci (±ae, 0); directrices x = ±a/e.
• Relation: b² = a²(1 − e²).

If the major axis is vertical: x²/b² + y²/a² = 1 (still a > b), foci (0, ±ae).

Worked Example 5 — Ellipse parameters

For x²/25 + y²/9 = 1, find e and the foci.

Solution: a² = 25, b² = 9 ⇒ a = 5, b = 3. e = √(1 − 9/25) = √(16/25) = 4/5. Foci (±ae, 0) = (±4, 0).

Worked Example 6 — Which axis is major?

For 9x² + 4y² = 36, rewrite and identify axes.

Solution: Divide by 36: x²/4 + y²/9 = 1. Here a² = 9 along y, b² = 4 along x. Major axis is vertical; a = 3, b = 2; e = √(1 − 4/9) = √(5/9) = √5 / 3; foci (0, ±√5).

Hyperbola

Standard form (transverse axis along x): x²/a² − y²/b² = 1.

• Eccentricity e = √(1 + b²/a²) (e > 1).
• Foci (±ae, 0); directrices x = ±a/e.
• Asymptotes: y = ±(b/a)x.
• Relation: b² = a²(e² − 1).

Conjugate form y²/a² − x²/b² = 1 opens up/down with asymptotes y = ±(a/b)x.

Worked Example 7 — Hyperbola basics

For x²/16 − y²/9 = 1, find e, foci, and asymptotes.

Solution: a = 4, b = 3. e = √(1 + 9/16) = √(25/16) = 5/4. Foci (±5, 0). Asymptotes y = ±(3/4)x.

Recognition Table for Mixed Equations

For Ax² + Bxy + Cy² + Dx + Ey + F = 0 with B = 0 (axis-aligned conics on the PAF syllabus):

Worked Example 8 — Identify the conic

Classify 3x² − 2y² + 6x + 4y − 1 = 0.

Solution: Coefficients of x² and y² have opposite signs → hyperbola (complete the square only if the stem asks for centre/vertices).

Exam Traps

1. Ellipse vs circle: equal denominators (or A = C) make a circle; unequal positive denominators make an ellipse.
2. Hyperbola sign pattern: x²/a² − y²/b² = 1 is not the same as y²/a² − x²/b² = 1—check which variable is positive.
3. Parabola “4a”: the coefficient of the linear side is 4a, not a; focus distance from vertex is a, not 4a.
4. Expanded circle: if the x² and y² coefficients differ, it is not a circle in Cartesian orthogonal axes.

Keep the four standard pictures and the eccentricity cut-offs (e = 1 parabola; e < 1 ellipse; e > 1 hyperbola; circle as e = 0 limiting ellipse) ready for rapid MCQ elimination.