5.3 Sequences, Series & Logarithms
Key Takeaways
- AP: aₙ = a + (n − 1)d and Sₙ = n/2 · [2a + (n − 1)d]; GP: aₙ = arⁿ⁻¹ and Sₙ = a(rⁿ − 1)/(r − 1) for r ≠ 1.
- Infinite GP converges only if |r| < 1, with sum S_∞ = a/(1 − r).
- Log laws: log(xy) = log x + log y, log(x/y) = log x − log y, log(xᵏ) = k log x; change of base log_b a = log_k a / log_k b.
- Exponential and log equations convert via aˣ = y ⇔ x = log_a y (a > 0, a ≠ 1, y > 0).
- Under ~30 s/question pacing, identify AP/GP first, then apply the matching closed form—avoid writing every term.
Sequences & Series on a Timed Engineering Paper
Sequences (AP/GP), series sums, and logarithms appear throughout FSc maths and are standard in PAF CAE-oriented banks. With maths often described as ~50 MCQs in ~25 minutes (treat as a commonly reported pattern, not a guaranteed official constant), closed-form recall beats listing terms.
Arithmetic Progression (AP)
An AP has constant common difference d.
| Quantity | Formula |
|---|---|
| nth term | aₙ = a + (n − 1)d |
| Sum of n terms | Sₙ = n/2 · [2a + (n − 1)d] = n/2 · (a + aₙ) |
Worked nth term. AP: 7, 10, 13, … Find a₂₀.
a = 7, d = 3 → a₂₀ = 7 + 19·3 = 7 + 57 = 64.
Worked sum. Sum of first 20 terms: S₂₀ = 20/2 · [2·7 + 19·3] = 10·[14 + 57] = 10·71 = 710. Or S₂₀ = 20/2 · (7 + 64) = 10·71 = 710.
Three terms in AP. Often written a − d, a, a + d so the middle is the average—useful in word problems.
Geometric Progression (GP)
A GP has constant common ratio r.
| Quantity | Formula |
|---|---|
| nth term | aₙ = arⁿ⁻¹ |
| Sum of n terms (r ≠ 1) | Sₙ = a(rⁿ − 1)/(r − 1) |
| Sum if r = 1 | Sₙ = na |
| Infinite sum ( | r |
Worked. GP: 3, 6, 12, … Find a₈ and S₈.
r = 2, a₈ = 3·2⁷ = 3·128 = 384.
S₈ = 3(2⁸ − 1)/(2 − 1) = 3(256 − 1) = 765.
Infinite GP. 1 + 1/2 + 1/4 + 1/8 + … → a = 1, r = 1/2, |r| < 1 → S_∞ = 1/(1 − 1/2) = 2.
If |r| ≥ 1, the infinite sum does not converge to a finite value—classic distractor.
Inserting Means
n arithmetic means between a and b: divide (b − a) into (n + 1) equal parts so d = (b − a)/(n + 1).
Worked. Three AMs between 4 and 16: d = (16 − 4)/4 = 3 → means 7, 10, 13.
Geometric means between a and b: common ratio satisfies rⁿ⁺¹ = b/a.
Relation Between AM and GM
For positive a, b: AM = (a + b)/2, GM = √(ab), and AM ≥ GM, equality iff a = b. Occasional theory MCQ.
Logarithms: Definition and Laws
Definition: log_b a = c ⇔ bᶜ = a, with b > 0, b ≠ 1, a > 0.
| Law | Identity |
|---|---|
| Product | log_b (xy) = log_b x + log_b y |
| Quotient | log_b (x/y) = log_b x − log_b y |
| Power | log_b (xᵏ) = k log_b x |
| Change of base | log_b a = log_k a / log_k b |
| Reciprocal | log_b a = 1 / log_a b |
Special values: log_b 1 = 0, log_b b = 1, log_b (bᵏ) = k.
Natural log ln x = log_e x; common log log x often means log₁₀ x in FSc contexts—read the stem.
Worked expansion. log(100√10) base 10: 100 = 10², √10 = 10^{1/2}, so log₁₀(10² · 10^{1/2}) = 2 + 1/2 = 2.5.
Worked change of base. log₂ 8 = ln 8 / ln 2 = 3 ln 2 / ln 2 = 3 (since 2³ = 8).
Worked equation. Solve log₁₀(x − 1) + log₁₀(x + 1) = log₁₀ 8.
Combine: log₁₀[(x − 1)(x + 1)] = log₁₀ 8 ⇒ x² − 1 = 8 ⇒ x² = 9 ⇒ x = ±3. Domain requires x − 1 > 0 and x + 1 > 0 for real logs of each factor (product form still needs x² − 1 > 0 and usually each positive depending on how the original was written). From the original sum of logs, need x > 1. So x = 3 only.
Exponential Equations
Worked. 3^{x+1} = 81. Note 81 = 3⁴, so 3^{x+1} = 3⁴ ⇒ x + 1 = 4 ⇒ x = 3.
Worked mixed. 2^{x} = 5 ⇒ x = log₂ 5 = ln 5 / ln 2 (leave in log form unless a decimal is offered).
Exponentials, Logs, and Graphs (Quick)
- y = aˣ (a > 1) increasing; y = aˣ (0 < a < 1) decreasing; horizontal asymptote y = 0.
- y = log_b x domain (0, ∞), vertical asymptote x = 0; passes through (1, 0) and (b, 1).
Series Notation
Σ from k = 1 to n of k = n(n + 1)/2.
Σ k² = n(n + 1)(2n + 1)/6.
Σ k³ = [n(n + 1)/2]².
Worked. Σ_{k=1}^{10} k = 10·11/2 = 55. Useful when an AP of natural numbers is disguised as sigma notation.
On the Exam
Pattern-match AP vs GP in under five seconds (constant difference vs constant ratio). For logs, expand products/powers before substituting numbers. Reject negative or zero arguments for real logarithms even if algebra produces extra roots.
The 20th term of the AP 7, 10, 13, … is:
For the infinite GP 1 + 1/2 + 1/4 + 1/8 + …, the sum to infinity is:
log₁₀(100√10) equals:
Solving log₁₀(x − 1) + log₁₀(x + 1) = log₁₀ 8 for real x in the domain of the original equation gives: