13.2 Electromagnetic Waves & Transmission Line Fields

Key Takeaways

  • Uniform plane wave propagation in lossy media is governed by the complex propagation constant \gamma = \alpha + j\beta = \sqrt{j\omega\mu (\sigma + j\omega\epsilon)}, where \alpha represents the attenuation constant in \text{Np/m} and \beta represents the phase constant in \text{rad/m}.
  • Intrinsic impedance \eta = \sqrt{\frac{j\omega\mu}{\sigma + j\omega\epsilon}} defines the ratio of electric to magnetic field strength, simplifying to \eta_0 = \sqrt{\frac{\mu_0}{\epsilon_0}} \approx 377\ \Omega (or 120\pi\ \Omega) in free space, with phase velocity v_p = \frac{1}{\sqrt{\mu \epsilon}} = 3 \times 10^8\ \text{m/s}.
  • The Poynting vector \mathbf{S} = \mathbf{E} \times \mathbf{H} represents instantaneous electromagnetic power flux density (\text{W/m}^2), with time-average power density \mathbf{P}_{\text{avg}} = \frac{1}{2} \text{Re}\{\mathbf{E} \times \mathbf{H}^*\} = \frac{|E_0|^2}{2\eta}\ \mathbf{a}_z.
  • Transmission line field behavior is modeled by distributed primary parameters (R, L, G, C) yielding characteristic impedance Z_0 = \sqrt{\frac{R + j\omega L}{G + j\omega C}}, which reduces to Z_0 = \sqrt{\frac{L}{C}} for lossless lines.
  • Impedance mismatch at line terminations creates wave reflections governed by the voltage reflection coefficient \Gamma_L = \frac{Z_L - Z_0}{Z_L + Z_0} and Voltage Standing Wave Ratio VSWR = \frac{1 + |\Gamma_L|}{1 - |\Gamma_L|}, while transient switching surges propagate as traveling step waves.
Last updated: August 2026

13.2 Electromagnetic Waves & Transmission Line Fields

High-voltage power transmission lines, high-frequency communication cables, and industrial bus ducts behave not as lumped parameters, but as distributed field systems. In the PRC REE Licensure Examination, candidates are tested on uniform plane wave propagation, intrinsic wave impedance, Poynting power flow, transmission line equations, characteristic impedance $Z_0$, reflection coefficients, standing wave ratios ($VSWR$), and surge wave behavior.


1. Wave Equations & Propagation Parameters

Applying the curl operator to Maxwell's equations in a linear, isotropic, homogeneous medium with conductivity $\sigma$, permeability $\mu$, and permittivity $\epsilon$ yields the vector wave equation for time-harmonic electric fields:

2Esγ2Es=0\nabla^2 \mathbf{E}_s - \gamma^2 \mathbf{E}_s = 0

where $\mathbf{E}_s$ is the phasor electric field intensity, and $\gamma$ is the Complex Propagation Constant:

γ=α+jβ=jωμ(σ+jωϵ)(m1)\gamma = \alpha + j\beta = \sqrt{j\omega\mu (\sigma + j\omega\epsilon)} \quad (\text{m}^{-1})

Attenuation Constant (\alpha) & Phase Constant (\beta)

  • Attenuation Constant (\alpha): Measures wave amplitude reduction per unit distance due to dielectric and conduction losses, expressed in Nepers per meter (Np/m) or decibels per meter ($\text{dB/m}$, where $1\ \text{Np} = 8.686\ \text{dB}$).
  • Phase Constant (\beta): Measures phase shift per unit distance, expressed in radians per meter (rad/m): β=2πλ=ωvp\beta = \frac{2\pi}{\lambda} = \frac{\omega}{v_p}

Intrinsic Impedance (\eta) & Phase Velocity (v_p)

The ratio of the transverse electric field to transverse magnetic field for a forward-propagating wave is the Intrinsic Impedance $\eta$:

η=ExHy=jωμσ+jωϵ(Ω)\eta = \frac{E_x}{H_y} = \sqrt{\frac{j\omega\mu}{\sigma + j\omega\epsilon}} \quad (\Omega)

In Free Space (\sigma = 0, \mu_r = 1, \epsilon_r = 1):

η0=μ0ϵ0=4π×1078.854×1012120π377 Ω\eta_0 = \sqrt{\frac{\mu_0}{\epsilon_0}} = \sqrt{\frac{4\pi \times 10^{-7}}{8.854 \times 10^{-12}}} \approx 120\pi \approx 377\ \Omega

vp=c=1μ0ϵ03×108 m/sv_p = c = \frac{1}{\sqrt{\mu_0 \epsilon_0}} \approx 3 \times 10^8\ \text{m/s}

Low-Loss Dielectrics vs. Good Conductors

The ratio $\frac{\sigma}{\omega \epsilon}$ is known as the loss tangent ($\tan\delta$):

  1. Good Dielectrics (\frac{\sigma}{\omega \epsilon} \ll 1): ασ2μϵ(Np/m),βωμϵ(rad/m),ημϵ\alpha \approx \frac{\sigma}{2} \sqrt{\frac{\mu}{\epsilon}} \quad (\text{Np/m}), \quad \beta \approx \omega \sqrt{\mu \epsilon} \quad (\text{rad/m}), \quad \eta \approx \sqrt{\frac{\mu}{\epsilon}}

  2. Good Conductors (\frac{\sigma}{\omega \epsilon} \gg 1): α=β=πfμσ(m1),η=(1+j)πfμσ\alpha = \beta = \sqrt{\pi f \mu \sigma} \quad (\text{m}^{-1}), \quad \eta = (1 + j)\sqrt{\frac{\pi f \mu}{\sigma}}

    The depth at which the wave amplitude decays to $1/e$ ($36.8%$) of its surface value is the Skin Depth (\delta): δ=1α=1πfμσ(m)\delta = \frac{1}{\alpha} = \frac{1}{\sqrt{\pi f \mu \sigma}} \quad (\text{m})


2. Poynting Vector & Electromagnetic Power Flow

Electromagnetic fields transport energy through space. The instantaneous rate of energy flow per unit area is defined by the Poynting Vector $\mathbf{S}$:

S=E×H(W/m2)\mathbf{S} = \mathbf{E} \times \mathbf{H} \quad (\text{W/m}^2)

For time-harmonic fields, the Time-Average Poynting Vector $\mathbf{P}_{\text{avg}}$ represents true real power density:

Pavg=12Re{Es×Hs}=E022ηe2αzcos(θn)az(W/m2)\mathbf{P}_{\text{avg}} = \frac{1}{2} \text{Re} \left\{ \mathbf{E}_s \times \mathbf{H}_s^* \right\} = \frac{|E_0|^2}{2 |\eta|} e^{-2\alpha z} \cos(\theta_n) \mathbf{a}_z \quad (\text{W/m}^2)

where $\theta_n$ is the phase angle of the intrinsic impedance $\eta$. Total power crossing a surface $S$ is obtained by integrating over the area:

Ptotal=SPavgdA(Watts)P_{\text{total}} = \iint_S \mathbf{P}_{\text{avg}} \cdot d\mathbf{A} \quad (\text{Watts})


3. Distributed Transmission Line Parameters & Telegrapher's Equations

A uniform transmission line is modeled using per-unit-length distributed parameters:

  • $R$: Series resistance per unit length ($\Omega/\text{m}$)
  • $L$: Series inductance per unit length ($\text{H/m}$)
  • $G$: Shunt conductance per unit length ($\text{S/m}$)
  • $C$: Shunt capacitance per unit length ($\text{F/m}$)

Telegrapher's Equations

Applying Kirchhoff's laws to an incremental line section $dz$ yields the time-domain Telegrapher's Equations:

v(z,t)z=Ri(z,t)Li(z,t)t\frac{\partial v(z,t)}{\partial z} = -R i(z,t) - L \frac{\partial i(z,t)}{\partial t}

i(z,t)z=Gv(z,t)Cv(z,t)t\frac{\partial i(z,t)}{\partial z} = -G v(z,t) - C \frac{\partial v(z,t)}{\partial t}

In the frequency domain (phasor form):

d2Vs(z)dz2=γ2Vs(z),d2Is(z)dz2=γ2Is(z)\frac{d^2 V_s(z)}{dz^2} = \gamma^2 V_s(z), \quad \frac{d^2 I_s(z)}{dz^2} = \gamma^2 I_s(z)

where the line propagation constant is $\gamma = \sqrt{(R + j\omega L)(G + j\omega C)} = \alpha + j\beta$.

Characteristic Impedance (Z_0)

The ratio of forward voltage wave to forward current wave is the Characteristic Impedance $Z_0$:

Z0=R+jωLG+jωC(Ω)Z_0 = \sqrt{\frac{R + j\omega L}{G + j\omega C}} \quad (\Omega)

  • Lossless Line ($R = 0, G = 0$): Z0=LC(Purely real resistance),α=0,β=ωLCZ_0 = \sqrt{\frac{L}{C}} \quad (\text{Purely real resistance}), \quad \alpha = 0, \quad \beta = \omega \sqrt{LC}

  • Distortionless Line (Condition: $\frac{R}{L} = \frac{G}{C}$): Z0=LC,α=RG,β=ωLCZ_0 = \sqrt{\frac{L}{C}}, \quad \alpha = \sqrt{RG}, \quad \beta = \omega \sqrt{LC}

    A distortionless line transmits signals without amplitude distortion across frequency components because $\alpha$ is independent of frequency $\omega$.


4. Line Reflections, VSWR & Impedance Matching

When a transmission line with characteristic impedance $Z_0$ is terminated by a load impedance $Z_L \neq Z_0$, a portion of the incident wave reflects back toward the source.

Voltage Reflection Coefficient (\Gamma_L)

The ratio of the reflected voltage wave $V_0^-$ to the incident voltage wave $V_0^+$ at the load is:

ΓL=ZLZ0ZL+Z0=ΓLejθr\Gamma_L = \frac{Z_L - Z_0}{Z_L + Z_0} = |\Gamma_L| e^{j\theta_r}

Key Load Termination Cases:

  1. Matched Load ($Z_L = Z_0$): $\Gamma_L = 0$ (No reflected wave; maximum power transfer).
  2. Open-Circuit Load ($Z_L = \infty$): $\Gamma_L = +1$ (Total voltage reflection in-phase; $V_{\text{load}} = 2 V_0^+$).
  3. Short-Circuit Load ($Z_L = 0$): $\Gamma_L = -1$ (Total voltage reflection $180^\circ$ out-of-phase; $V_{\text{load}} = 0$).
  4. Purely Reactive Load ($Z_L = jX$): $|\Gamma_L| = 1$ (Total power reflection).

Voltage Standing Wave Ratio (VSWR)

The superposition of incident and reflected waves creates a standing wave pattern. The ratio of peak voltage to minimum voltage along the line is:

VSWR=VmaxVmin=1+ΓL1ΓLVSWR = \frac{V_{\text{max}}}{V_{\text{min}}} = \frac{1 + |\Gamma_L|}{1 - |\Gamma_L|}

  • Bounds: $1 \le VSWR \le \infty$.
  • $VSWR = 1.0$ indicates a perfectly matched line ($|\Gamma_L| = 0$).

Input Impedance at Distance l from Load

The input impedance $Z_{\text{in}}(l)$ looking into a lossless transmission line of length $l$ terminated by load $Z_L$ is:

Zin(l)=Z0[ZL+jZ0tan(βl)Z0+jZLtan(βl)]Z_{\text{in}}(l) = Z_0 \left[ \frac{Z_L + j Z_0 \tan(\beta l)}{Z_0 + j Z_L \tan(\beta l)} \right]

  • Quarter-Wave Line ($l = \lambda/4$, $\beta l = \pi/2$): Zin=Z02ZL(Quarter-wave impedance transformer)Z_{\text{in}} = \frac{Z_0^2}{Z_L} \quad (\text{Quarter-wave impedance transformer})
  • Half-Wave Line ($l = \lambda/2$, $\beta l = \pi$): Zin=ZL(Impedance repeats every half-wavelength)Z_{\text{in}} = Z_L \quad (\text{Impedance repeats every half-wavelength})

5. Transient Surge Propagation on Power Lines (Bounce Diagrams)

When a circuit breaker closes or lightning strikes an overhead transmission line, a high-voltage step wave $V_1$ travels along the line at the surge velocity $v = \frac{1}{\sqrt{LC}}$.

  • Surge Impedance: $Z_c = \sqrt{\frac{L}{C}}$
  • Sending-End Reflection Coefficient: $\Gamma_S = \frac{Z_S - Z_0}{Z_S + Z_0}$
  • Receiving-End Reflection Coefficient: $\Gamma_R = \frac{Z_R - Z_0}{Z_R + Z_0}$

A Bewley Lattice Diagram (Bounce Diagram) tracks successive position-time reflections ($t_1 = l/v, 2t_1, 3t_1$) to compute transient voltage profiles at any line position.


Solved Board Exam Numerical Problems

Problem 1: Intrinsic Impedance & Power Density of an EM Wave

Question: An electromagnetic wave operating at $f = 100\ \text{MHz}$ propagates through a lossless, non-magnetic medium ($\mu_r = 1.0$) with a relative permittivity $\epsilon_r = 9.0$. The electric field amplitude is $E_0 = 120\ \text{V/m}$. Calculate: (a) the phase velocity $v_p$, (b) the wavelength $\lambda$, (c) the intrinsic impedance $\eta$, and (d) the average power density $P_{\text{avg}}$.

Solution:

  1. Calculate phase velocity $v_p$: vp=cϵr=3.0×108 m/s9.0=1.0×108 m/sv_p = \frac{c}{\sqrt{\epsilon_r}} = \frac{3.0 \times 10^8\ \text{m/s}}{\sqrt{9.0}} = 1.0 \times 10^8\ \text{m/s}

  2. Calculate wavelength $\lambda$: λ=vpf=1.0×108 m/s100×106 Hz=1.0 meter\lambda = \frac{v_p}{f} = \frac{1.0 \times 10^8\ \text{m/s}}{100 \times 10^6\ \text{Hz}} = 1.0\ \text{meter}

  3. Calculate intrinsic impedance $\eta$: η=η0ϵr=377 Ω9.0=3773=125.67 Ω\eta = \frac{\eta_0}{\sqrt{\epsilon_r}} = \frac{377\ \Omega}{\sqrt{9.0}} = \frac{377}{3} = 125.67\ \Omega

  4. Calculate average power density $P_{\text{avg}}$: Pavg=E022η=(120)22×125.67=14,400251.34=57.28 W/m2P_{\text{avg}} = \frac{E_0^2}{2\eta} = \frac{(120)^2}{2 \times 125.67} = \frac{14,400}{251.34} = 57.28\ \text{W/m}^2


Problem 2: Transmission Line Reflection & VSWR Calculation

Question: A $50\ \Omega$ lossless transmission line is terminated by an antenna load impedance $Z_L = 75 + j50\ \Omega$. Determine: (a) the load reflection coefficient $\Gamma_L$ in polar form, (b) the reflection coefficient magnitude $|\Gamma_L|$, and (c) the Voltage Standing Wave Ratio ($VSWR$).

Solution:

  1. Compute load reflection coefficient $\Gamma_L$: ΓL=ZLZ0ZL+Z0=(75+j50)50(75+j50)+50=25+j50125+j50\Gamma_L = \frac{Z_L - Z_0}{Z_L + Z_0} = \frac{(75 + j50) - 50}{(75 + j50) + 50} = \frac{25 + j50}{125 + j50}

  2. Convert numerator and denominator to polar coordinates: Numerator: 25+j50=252+502arctan(50/25)=55.9063.43\text{Numerator: } 25 + j50 = \sqrt{25^2 + 50^2} \angle \arctan(50/25) = 55.90 \angle 63.43^\circ Denominator: 125+j50=1252+502arctan(50/125)=134.6321.80\text{Denominator: } 125 + j50 = \sqrt{125^2 + 50^2} \angle \arctan(50/125) = 134.63 \angle 21.80^\circ ΓL=55.9063.43134.6321.80=0.415241.63\Gamma_L = \frac{55.90 \angle 63.43^\circ}{134.63 \angle 21.80^\circ} = 0.4152 \angle 41.63^\circ

  3. Extract magnitude $|\Gamma_L|$: ΓL=0.4152|\Gamma_L| = 0.4152

  4. Calculate $VSWR$: VSWR=1+ΓL1ΓL=1+0.415210.4152=1.41520.5848=2.42VSWR = \frac{1 + |\Gamma_L|}{1 - |\Gamma_L|} = \frac{1 + 0.4152}{1 - 0.4152} = \frac{1.4152}{0.5848} = 2.42

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Transmission Line Wave Reflection and Standing Wave Metrics
Voltage Standing Wave Ratio (VSWR) vs. Reflection Coefficient Magnitude
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What is the intrinsic impedance of a non-magnetic dielectric medium having a relative permittivity εr = 4.0?

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A 50 Ω lossless transmission line is terminated by an open circuit (ZL = ∞). What are the values of the voltage reflection coefficient ΓL and the Voltage Standing Wave Ratio (VSWR)?

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Which specific condition must be satisfied for a lossy transmission line to operate as a distortionless line?

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