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Key Facts: EGEL Plus Ingeniería Electrónica Exam

200

Total items on the official EGEL Plus IELECTRO (140 disciplinary + 60 transversal)

Ceneval, Guía para el sustentante EGEL Plus IELECTRO

9 hours

Two sessions of 4.5 hours each on the same day

Ceneval, Guía para el sustentante EGEL Plus IELECTRO

1000

Minimum Índice Ceneval for a Satisfactorio level in an area or section

Ceneval, Guía para el sustentante EGEL Plus IELECTRO

1150

Minimum Índice Ceneval for a Sobresaliente level

Ceneval, Guía para el sustentante EGEL Plus IELECTRO

MXN 1,885

Individual national Examen desde casa fee in 2026

Ceneval EGEL portal

Ceneval's EGEL Plus IELECTRO is a 200-item, nine-hour Spanish exit exam: 140 disciplinary items in three areas plus 60 transversal language and communication items.

Sample EGEL Plus Ingeniería Electrónica Practice Questions

Try these sample questions to review concepts for the EGEL Plus Ingeniería Electrónica exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A silicon NPN bipolar junction transistor (BJT) is configured in a voltage-divider common-emitter bias circuit with VCC = 12 V, R1 = 47 kΩ, R2 = 10 kΩ, RC = 2.2 kΩ, and RE = 1.0 kΩ. Assuming VBE = 0.7 V and base current is negligible (stiff divider), what are the approximate quiescent collector current ICQ and collector-emitter voltage VCEQ?
A.ICQ ≈ 1.40 mA, VCEQ ≈ 7.50 V
B.ICQ ≈ 2.10 mA, VCEQ ≈ 5.26 V
C.ICQ ≈ 0.64 mA, VCEQ ≈ 9.96 V
D.ICQ ≈ 1.40 mA, VCEQ ≈ 8.91 V
Explanation: The base voltage comes from the divider: VB = VCC × R2 / (R1 + R2) = 12 V × 10 / 57 ≈ 2.105 V. The emitter voltage is VE = VB − VBE = 1.405 V, so IE = VE / RE = 1.405 mA and ICQ ≈ 1.40 mA. Then VCEQ = VCC − IC × (RC + RE) = 12 V − 1.405 mA × 3.2 kΩ ≈ 12 V − 4.50 V ≈ 7.50 V.
2An N-channel enhancement MOSFET has a threshold voltage Vth = 1.2 V and conduction parameter k'n*(W/L) = 1.0 mA/V². If the device is biased with gate-to-source voltage VGS = 3.2 V and drain-to-source voltage VDS = 4.0 V, what is the drain current ID assuming channel-length modulation is negligible?
A.4.0 mA
B.2.0 mA
C.5.12 mA
D.8.0 mA
Explanation: First, determine the operating region: VGS - Vth = 3.2 V - 1.2 V = 2.0 V (the overdrive voltage VOV). Because VDS = 4.0 V >= VOV = 2.0 V, the MOSFET operates in the saturation (active) region. The saturation drain current is ID = (1/2) * k'n * (W/L) * (VGS - Vth)² = 0.5 * (1.0 mA/V²) * (2.0 V)² = 0.5 * 1.0 * 4.0 = 2.0 mA.
3An ideal operational amplifier is connected in an inverting configuration with input resistor Rin = 4.7 kΩ and feedback resistor Rf = 47 kΩ. If an input signal Vin = +0.5 V is applied, what is the output voltage Vout and the input impedance seen by the source?
A.Vout = -5.0 V, Zin = 4.7 kΩ
B.Vout = +5.0 V, Zin = 47 kΩ
C.Vout = -5.0 V, Zin = ∞
D.Vout = -0.05 V, Zin = 4.7 kΩ
Explanation: For an ideal inverting op-amp configuration, the closed-loop voltage gain is Av = -Rf / Rin = -47 kΩ / 4.7 kΩ = -10. Therefore, Vout = Av * Vin = -10 * (+0.5 V) = -5.0 V. Because the inverting terminal is held at virtual ground (0 V) by negative feedback, the input impedance seen by the signal source is simply Rin = 4.7 kΩ.
4A sensor provides an analog voltage of 1.20 V that must be scaled to 12.0 V using a non-inverting op-amp amplifier. If the feedback resistor between output and inverting terminal is Rf = 90 kΩ, what resistance R1 must be placed between the inverting terminal and ground?
A.10 kΩ
B.9.0 kΩ
C.100 kΩ
D.1.0 kΩ
Explanation: The required non-inverting voltage gain is Av = Vout / Vin = 12.0 V / 1.20 V = 10. The non-inverting gain equation is Av = 1 + (Rf / R1). Setting 1 + (90 kΩ / R1) = 10 gives 90 kΩ / R1 = 9, which yields R1 = 90 kΩ / 9 = 10 kΩ.
5A summing operational amplifier has three input resistors R1 = 10 kΩ, R2 = 20 kΩ, and R3 = 50 kΩ connected to input voltages V1 = +1.0 V, V2 = -2.0 V, and V3 = +5.0 V respectively. If the feedback resistor is Rf = 100 kΩ, what is the output voltage Vout?
A.-10.0 V
B.+10.0 V
C.-20.0 V
D.0.0 V
Explanation: The output of an inverting summing amplifier is given by Vout = -Rf * (V1/R1 + V2/R2 + V3/R3). Calculating each term: V1/R1 = 1.0 V / 10 kΩ = 0.10 mA; V2/R2 = -2.0 V / 20 kΩ = -0.10 mA; V3/R3 = 5.0 V / 50 kΩ = 0.10 mA. The sum of input currents is 0.10 mA - 0.10 mA + 0.10 mA = 0.10 mA. Multiplying by -Rf = -100 kΩ gives Vout = -100 kΩ * 0.10 mA = -10.0 V.
6In a standard four-resistor operational amplifier difference amplifier (subtractor) with inputs V1 (to inverting branch via R1) and V2 (to non-inverting branch via R3), what exact resistor matching relationship must be satisfied to achieve an ideal common-mode rejection ratio (CMRR = ∞)?
A.Rf / R1 = R4 / R3
B.Rf + R1 = R4 + R3
C.Rf * R1 = R4 * R3
D.Rf - R1 = R4 - R3
Explanation: In a difference amplifier, the common-mode gain Acm becomes exactly zero when the voltage division ratio at the non-inverting terminal matches the feedback ratio at the inverting terminal, which requires Rf / R1 = R4 / R3 (where Rf is the feedback resistor and R4 is the resistor from the non-inverting terminal to ground). When this condition is met, Vout = (Rf / R1) * (V2 - V1), completely rejecting common-mode noise.
7An operational amplifier has a slew rate SR = 0.50 V/μs. What is the maximum frequency (full-power bandwidth fmax) of a sinusoidal output signal with a peak amplitude of Vp = 5.0 V that can be reproduced without slew-rate distortion?
A.15.9 kHz
B.31.8 kHz
C.100.0 kHz
D.7.95 kHz
Explanation: For a sinusoidal voltage v(t) = Vp * sin(2*pi*f*t), the maximum rate of change occurs at the zero crossings: (dv/dt)_max = 2*pi*f*Vp. To prevent distortion, this maximum derivative must not exceed the slew rate: SR >= 2*pi*f*Vp. Solving for maximum frequency gives fmax = SR / (2*pi*Vp) = (0.50 * 10^6 V/s) / (2 * pi * 5.0 V) = 500,000 / (31.4159) ≈ 15,915 Hz ≈ 15.9 kHz.
8An active first-order low-pass filter is implemented using an operational amplifier with an input resistor R = 10.0 kΩ and a feedback capacitor C = 15.9 nF connected in parallel with a feedback resistor Rf = 10.0 kΩ. What is the cutoff frequency (-3 dB frequency fc) of this filter?
A.1.0 kHz
B.6.28 kHz
C.15.9 kHz
D.100 Hz
Explanation: The cutoff frequency fc of a first-order active low-pass filter is determined by the feedback RC network: fc = 1 / (2 * pi * Rf * C). Substituting the given values: fc = 1 / (2 * pi * 10,000 Ω * 15.9 * 10^-9 F) = 1 / (9.99 * 10^-4) ≈ 1,000 Hz = 1.0 kHz.
9A second-order Sallen-Key low-pass filter is designed with a maximally flat passband response (Butterworth approximation). What are the damping ratio zeta, quality factor Q, and high-frequency stopband attenuation roll-off rate of this filter?
A.zeta = 0.707, Q = 0.707, roll-off = -40 dB/decade
B.zeta = 1.000, Q = 0.500, roll-off = -20 dB/decade
C.zeta = 0.500, Q = 1.000, roll-off = -60 dB/decade
D.zeta = 0.000, Q = ∞, roll-off = -40 dB/decade
Explanation: A second-order Butterworth filter provides maximally flat passband magnitude response without ripple. This condition requires a damping ratio zeta = 1 / sqrt(2) ≈ 0.707, which corresponds to a quality factor Q = 1 / (2 * zeta) = 1 / sqrt(2) ≈ 0.707. Because it has two conjugate poles, the high-frequency attenuation rolls off at -20 dB/decade per pole, giving -40 dB/decade (-12 dB/octave).
10A through-hole resistor on a prototype board has the four color bands yellow, violet, red, gold. What are its nominal resistance and tolerance?
A.4.7 kΩ ± 5%
B.47 kΩ ± 5%
C.472 Ω ± 10%
D.4.7 kΩ ± 10%
Explanation: In the four-band code, the first two bands are significant digits (yellow = 4, violet = 7), the third band is the multiplier (red = × 10² = 100), and the fourth is the tolerance (gold = ±5%). The value is 47 × 100 = 4,700 Ω = 4.7 kΩ ± 5%.

About the EGEL Plus Ingeniería Electrónica Exam

Independent EGEL Plus Ingeniería Electrónica practice by OpenExamPrep. The official Ceneval examination is in Spanish and has 200 three-option items: 140 disciplinary items in Diseño de equipos y sistemas electrónicos, Construcción de equipos y sistemas electrónicos, and Operación de equipos y sistemas electrónicos, and 60 transversal Lenguaje y Comunicación items. This bank is an English-language study adaptation with four-option multiple-choice questions, not an official translation or format simulation. Disciplinary stems and explanations are in English. Language and communication items keep their Spanish passages and answer options, because Spanish usage is the skill being tested, and give their instructions and explanations in English.

Exam sponsor: Centro Nacional de Evaluación para la Educación Superior (Ceneval). The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

200 three-option items: 140 disciplinary items (Diseño de equipos y sistemas electrónicos 50, Construcción de equipos y sistemas electrónicos 43, Operación de equipos y sistemas electrónicos 47) and 60 transversal items in Comprensión Lectora and Redacción Indirecta.

Time Limit

Two sessions of 4.5 hours each on the same day (9 hours in total)

Passing Score

Each area and each section is reported on the Índice Ceneval (700-1300): 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio, 1150-1300 Sobresaliente. The global result is weighted toward the disciplinary section: Satisfactorio or better there earns at least a Testimonio de Desempeño Satisfactorio, and a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación

Exam / Certification Fees

MXN 1,885 for the 2026 national Examen desde casa; institutional administrations may charge a different amount

Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Official sources

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

50 of 140 disciplinary items

Diseño de equipos y sistemas electrónicos

Needs, requirements and technical specifications (8), design alternatives (14), modeling and simulation (15), and design feasibility (13)

43 of 140 disciplinary items

Construcción de equipos y sistemas electrónicos

Technical specifications (10), implementation procedures and resources (11), experimental prototypes (11), and assembly (11)

47 of 140 disciplinary items

Operación de equipos y sistemas electrónicos

Use (14), operation (22) and maintenance (11) of electronic equipment and systems

60 of 200 total items

Lenguaje y Comunicación

Reading comprehension of academic, literary and public-interest texts (30 items) and indirect writing, which asks candidates to choose the version of a text that is correct, coherent and well punctuated (30 items)

Preparing for the EGEL Plus Ingeniería Electrónica Exam

What You Need to Know

  • Passing score: Each area and each section is reported on the Índice Ceneval (700-1300): 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio, 1150-1300 Sobresaliente. The global result is weighted toward the disciplinary section: Satisfactorio or better there earns at least a Testimonio de Desempeño Satisfactorio, and a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación
  • Assessment: 200 three-option items: 140 disciplinary items (Diseño de equipos y sistemas electrónicos 50, Construcción de equipos y sistemas electrónicos 43, Operación de equipos y sistemas electrónicos 47) and 60 transversal items in Comprensión Lectora and Redacción Indirecta.
  • Time limit: Two sessions of 4.5 hours each on the same day (9 hours in total)
  • Exam / certification fees: MXN 1,885 for the 2026 national Examen desde casa; institutional administrations may charge a different amount Official sources

Using Our Practice Resources

  • Work through all 100 available questions
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EGEL Plus Ingeniería Electrónica: Suggested Study Strategy

1Practice circuit design calculations: op-amp gains and bandwidth, active filter cutoffs, converter duty cycles, and transistor biasing.
2Review modeling and simulation: second-order responses, damping ratio and natural frequency, stability margins and Routh-Hurwitz.
3Study construction topics: PCB stack-up and decoupling, thermal design with heat sinks, soldering and assembly sequences, and ESD control.
4Operation (22 items) is the largest subarea: review instrument use, troubleshooting and maintenance of electronic equipment.
5Prepare for Lenguaje y Comunicación by reading academic articles, essays and public notices in Spanish, and by reviewing agreement, punctuation, accentuation and connectors.

Frequently Asked Questions

What is the EGEL Plus Ingeniería Electrónica?

The EGEL Plus Ingeniería Electrónica (EGEL Plus IELECTRO) is Ceneval's national exit examination for graduates of the Licenciatura en Ingeniería Electrónica and related programs. It measures the knowledge and skills considered indispensable at the end of the degree, plus Spanish reading comprehension and indirect writing. Institutions may use the result as a graduation requirement, a titulación option or part of a course grade, under their own rules; a Testimonio does not by itself determine the award of the degree or the cédula profesional.

How many questions are on the official EGEL Plus IELECTRO and how long is it?

The official exam has 200 items: 140 disciplinary items (Diseño de equipos y sistemas electrónicos 50, Construcción de equipos y sistemas electrónicos 43, Operación de equipos y sistemas electrónicos 47) and 60 Lenguaje y Comunicación items (30 reading comprehension and 30 indirect writing). It is given on one day in two sessions of 4.5 hours each (9 hours). About 15% of the items are pilot items that do not count toward the result.

How is the EGEL Plus IELECTRO scored?

Each area and section is reported on the Índice Ceneval from 700 to 1300: 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio and 1150-1300 Sobresaliente. The global result follows a conjunctive rule weighted toward the disciplinary section: Satisfactorio or better in the disciplinary section earns at least a Testimonio de Desempeño Satisfactorio, while a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación. Candidates with a global Sobresaliente who take the exam for the first time within one year of finishing the degree are eligible for the Premio Ceneval al Desempeño de Excelencia-EGEL.

Can I use a calculator or formula sheet on the EGEL Plus IELECTRO?

Yes. The official guide allows a non-programmable scientific calculator, which may not be shared between candidates. Ceneval also provides a formulario (formula sheet), handed out on paper or shown on the exam platform depending on the modality, and publishes it on its EGEL portal so you can study with it in advance.

Why is this practice bank in English if the official exam is in Spanish?

The official Ceneval exam is in Spanish. This bank is an independent English-language study adaptation with four-option questions, not an official translation or format simulation. Disciplinary questions and explanations are in English so you can review the engineering content. Language and communication items keep their Spanish passages and options because they test Spanish usage, and their instructions and explanations are in English.

Can candidates earn the Premio Ceneval al Desempeño de Excelencia-EGEL?

Yes. Candidates with a global Sobresaliente result (Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación) are eligible if they take the EGEL Plus for the first time and have been graduates for no more than one year.