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100+ Free UPPCL JE Practice Questions

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2026 Statistics

Key Facts: UPPCL JE Exam

200

Total MCQ Questions

UPPCL Outline

3 hours

Exam Duration

CBT Limit

30%

Minimum Qualifying Marks

60/200 Score

₹1,180

Application Fee

General/OBC

-0.25

Negative Marking

Per Wrong Answer

Diploma

Educational Requirement

Electrical Engg

The UPPCL Junior Engineer (Electrical) recruitment CBT is a 3-hour exam consisting of 200 MCQ questions. 150 questions test Diploma-level Electrical Engineering, while 50 test GK, Reasoning, and Hindi. The exam has a 0.25 negative marking penalty. Candidates must score at least 30% (60/200) to qualify for merit ranking and document verification.

Sample UPPCL JE Practice Questions

Try these sample questions to test your UPPCL JE exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A DC shunt motor has an armature resistance of 0.25 ohms and runs at 1000 RPM when connected to a 220V supply, drawing an armature current of 40A. What will be the back EMF (Eb) of the motor under this condition?
A.230 V
B.210 V
C.220 V
D.200 V
Explanation: For a DC shunt motor, the back EMF is calculated as Eb = V - Ia * Ra. Given V = 220V, Ia = 40A, and Ra = 0.25 ohms, we have Eb = 220 - (40 * 0.25) = 220 - 10 = 210 V.
2In a 3-phase, 4-pole induction motor connected to a 50 Hz supply, the rotor is running at a speed of 1440 RPM. What is the percentage slip of the induction motor?
A.2%
B.4%
C.5%
D.6%
Explanation: First, calculate the synchronous speed (Ns) = 120 * f / P = 120 * 50 / 4 = 1500 RPM. Then, the slip (s) is calculated as (Ns - Nr) / Ns = (1500 - 1440) / 1500 = 60 / 1500 = 0.04 or 4%.
3Which of the following theorems states that any linear, bilateral, active two-terminal network can be replaced by a single equivalent voltage source in series with an equivalent resistance?
A.Norton's Theorem
B.Thevenin's Theorem
C.Superposition Theorem
D.Maximum Power Transfer Theorem
Explanation: Thevenin's Theorem states that a linear, bilateral, active network can be replaced by a single voltage source (Vth) in series with an equivalent resistance (Rth).
4A single-phase transformer has 400 primary turns and 1000 secondary turns. If the primary winding is connected to a 240 V, 50 Hz supply, what is the value of the secondary voltage on no-load?
A.96 V
B.600 V
C.400 V
D.500 V
Explanation: The voltage ratio of a transformer is given by V2/V1 = N2/N1. Therefore, V2 = V1 * (N2 / N1) = 240 * (1000 / 400) = 240 * 2.5 = 600 V.
5What is the primary function of a moderator in a nuclear power plant?
A.To accelerate the speed of fast-moving neutrons
B.To slow down fast-moving neutrons to thermal energy levels
C.To absorb excess neutrons to control the fission rate
D.To cool the reactor core and transfer heat to the boiler
Explanation: A moderator (like heavy water, light water, or graphite) is used in nuclear reactors to slow down fast-moving neutrons to thermal speeds, which increases the probability of sustaining the nuclear fission chain reaction.
6In a series R-L-C resonant circuit, the inductive reactance (XL) is 100 ohms, capacitive reactance (XC) is 100 ohms, and the resistance (R) is 10 ohms. What is the value of the Quality Factor (Q-factor) of this circuit?
A.1
B.10
C.100
D.0.1
Explanation: The Q-factor of a series resonant circuit is given by Q = XL / R = XC / R. Substituting the values, Q = 100 / 10 = 10.
7Which type of instrument uses a permanent magnet and a moving coil, and can only be used for measuring DC quantities?
A.Moving Iron Instrument
B.PMMC Instrument
C.Dynamometer Type Instrument
D.Electrostatic Instrument
Explanation: Permanent Magnet Moving Coil (PMMC) instruments work on the principle that a torque is exerted on a current-carrying coil placed in a magnetic field. Because the magnetic field direction is fixed, reversing current changes torque direction. Thus, it can only measure DC averages.
8A 100/5 A current transformer (CT) is connected to an ammeter that reads 4 A. What is the actual current flowing in the primary transmission line?
A.20 A
B.80 A
C.100 A
D.125 A
Explanation: The transformation ratio of the CT is 100/5 = 20. The primary current (Ip) is the secondary current (Is) multiplied by the CT ratio. Ip = 4 A * 20 = 80 A.
9What is the peak inverse voltage (PIV) rating of a diode in a center-tapped full-wave rectifier if the peak value of the AC input voltage across each half of the secondary winding is Vm?
A.Vm
B.2 Vm
C.3 Vm
D.0.5 Vm
Explanation: In a center-tapped full-wave rectifier, when one diode conducts it clamps the center tap to one end of the secondary. The non-conducting diode then sees the full secondary voltage from end to end across it. Since each half peaks at Vm, the reverse voltage across the off diode peaks at Vm + Vm = 2 Vm.
10Which of the following semiconductors is widely used in power electronic applications for high-power, high-voltage switching and has a three-terminal structure (Gate, Collector, Emitter)?
A.Power MOSFET
B.IGBT
C.GTO
D.TRIAC
Explanation: The Insulated Gate Bipolar Transistor (IGBT) combines the simple gate-drive characteristics of MOSFETs with the high-current and low-saturation-voltage capability of bipolar transistors. Its three terminals are Gate, Collector, and Emitter.

About the UPPCL JE Exam

Highly competitive computer-based recruitment exam for Junior Engineer positions in Uttar Pradesh Power Corporation Limited. Selection is based purely on written CBT merit.

Questions

200 scored questions

Time Limit

3 hours

Passing Score

30%

Exam Fee

₹1,180 (UPPCL)

UPPCL JE Exam Content Outline

75%

Electrical Engineering

Core technical concepts from Diploma in Electrical Engineering curriculum

10%

General Knowledge/Awareness

Current events, history, geography, and polity, with a focus on UP

10%

Reasoning Ability

Logical reasoning, series, analogies, coding-decoding, and puzzles

5%

General Hindi

Basic Hindi grammar, vocabulary, idioms, and comprehension

How to Pass the UPPCL JE Exam

What You Need to Know

  • Passing score: 30%
  • Exam length: 200 questions
  • Time limit: 3 hours
  • Exam fee: ₹1,180

Keys to Passing

  • Complete 500+ practice questions
  • Score 80%+ consistently before scheduling
  • Focus on highest-weighted sections
  • Use our AI tutor for tough concepts

UPPCL JE Study Tips from Top Performers

1Dedicate at least 75% of your study time to core Electrical Engineering topics, especially Machines, Power Systems, and Network Theory.
2Practice solving numerical calculations quickly, as the technical section includes direct quantitative formula applications.
3Be careful of the 0.25 negative marking; skip questions where you cannot narrow down options rather than guessing blindly.
4Review basic Hindi grammar rules (Sandhi, Upasarg, Pratyay) to secure high accuracy on the 10 Hindi questions.
5Solve previous years' UPPCL JE papers under timed conditions to improve speed and question selection strategy.

Frequently Asked Questions

What is the exam pattern for UPPCL JE Electrical?

The UPPCL JE Electrical exam is a 3-hour Computer Based Test (CBT) consisting of 200 multiple-choice questions. It includes 150 questions on core Electrical Engineering (Diploma level), 20 on General Knowledge/Awareness, 20 on Reasoning, and 10 on General Hindi. Each correct answer carries 1 mark, with a 0.25 mark penalty for wrong answers.

What is the qualification required for UPPCL JE Electrical?

Candidates must possess a 3-year Diploma in Electrical Engineering from a board/institute recognized by the Uttar Pradesh government or a central government equivalent. Distance learning diplomas are not eligible. Candidates must also have working knowledge of Hindi in the Devnagri script.

Is there an interview in UPPCL JE recruitment?

No. In compliance with the state policy to abolish interviews for Group C posts, selection for UPPCL Junior Engineer is based entirely on the marks secured in the written Computer-Based Test (CBT), followed by Document Verification (DV) of qualifying candidates.

What is the minimum passing score for UPPCL JE?

Candidates must score a minimum of 30% marks (60 marks out of 200) in the written test to qualify. However, because recruitment is highly competitive, the actual cutoff marks for document verification are much higher depending on the number of vacancies and candidate performance.

What is the application fee for UPPCL JE?

The application fee is ₹1,180 for General, OBC, and EWS candidates, and ₹826 for SC and ST candidates of Uttar Pradesh domicile. The fee must be paid online via net banking, debit card, or credit card.