100+ Free BEL Probationary Engineer Practice Questions

Pass your Bharat Electronics Limited Probationary Engineer (E-II Grade) Examination exam on the first try — instant access, no signup required.

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Sample BEL Probationary Engineer Practice Questions

Try these sample questions to test your BEL Probationary Engineer exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1In a forward-biased silicon PN junction diode, the dominant current mechanism is:

A.Minority-carrier injection across the depletion region

B.Thermionic emission in vacuum

C.Tunneling through the oxide layer

D.Photoelectric emission at the cathode

Explanation: Forward bias narrows the depletion width and injects minority carriers across the junction, producing diffusion current. Thermionic emission applies to vacuum tubes, not standard silicon diodes.

2An ideal op-amp in inverting configuration with input resistor Rin and feedback resistor Rf has voltage gain:

A.-Rin/Rf

B.-Rf/Rin

C.1 + Rf/Rin

D.Rin/Rf

Explanation: The inverting amplifier gain is Vout/Vin = -Rf/Rin because the inverting input is held at virtual ground. The non-inverting formula 1+Rf/Rin applies to the other topology.

3A Zener diode operated in breakdown region is primarily used for:

A.Light emission

B.Charge storage in DRAM

C.Voltage regulation

D.High-frequency amplification

Explanation: Zener (and avalanche) breakdown maintains an approximately constant voltage across the diode, making it a simple shunt regulator. It is not used for amplification or light emission.

4The -3 dB cutoff frequency of a simple RC low-pass filter with R and C is:

A.2πRC

B.1/(RC)

C.RC/2π

D.1/(2πRC)

Explanation: Magnitude falls to 1/√2 at ωc = 1/RC, so fc = 1/(2πRC). The other forms misplace 2π or invert the product.

5Compared with amplitude modulation (AM), frequency modulation (FM) generally provides:

A.Better noise immunity at the receiver

B.Lower bandwidth requirement

C.Constant envelope only in AM

D.No need for a discriminator detector

Explanation: FM trades bandwidth for improved noise performance because amplitude noise affects FM less when detected by frequency discrimination. FM typically needs wider bandwidth than AM.

6Which logic gate is functionally complete by itself?

A.XNOR

B.NAND

C.XOR

D.Buffer

Explanation: NAND (and NOR) alone can implement NOT, AND, and OR, so any Boolean function can be built from NAND gates. XOR and buffer gates cannot generate inversion by themselves.

7A synchronous counter built from edge-triggered flip-flops avoids the problem of:

A.Metastability in combinational logic only

B.Excess power in CMOS static logic

C.Ripple propagation delay limiting maximum clock rate

D.Need for an external clock entirely

Explanation: Ripple counters accumulate stage delays; synchronous designs clock all flip-flops together, enabling higher speed. They still require a clock and can have metastability on async inputs.

8In a BJT common-emitter amplifier, the output is taken from the:

A.Emitter while collector is open

B.Base directly without load

C.Base terminal with collector AC-grounded

D.Collector with emitter often AC-grounded

Explanation: Common-emitter configuration uses the collector as output and emitter as common reference (often bypassed to ground for AC). Base is the input, not the primary output node.

9According to the Nyquist sampling theorem, a band-limited signal with maximum frequency fm must be sampled at a rate:

A.Greater than 2fm

B.Equal to fm

C.Less than fm

D.Exactly fm/2

Explanation: Nyquist requires fs > 2fm (at least twice the highest frequency) to avoid aliasing. Sampling at fm or below folds spectra and loses information.

10CMOS logic draws significant dynamic power primarily because of:

A.Photovoltaic generation at the gate

B.Charging and discharging load capacitance during switching

C.Static short-circuit current when inputs are steady

D.Thermionic emission in the channel

Explanation: Dynamic power P ≈ α·C·Vdd²·f arises from toggling nodes. CMOS has negligible static current in ideal steady state compared with switching losses at high frequency.

About the BEL Probationary Engineer Exam

The BEL Probationary Engineer examination recruits engineering graduates into E-II Grade at Bharat Electronics Limited, a Navratna defence PSU manufacturing radar, communication, electronic warfare, and avionics systems. The CBT tests deep discipline knowledge plus aptitude, unlike GATE-only shortlisting in some earlier cycles. This free practice bank spans Electronics, Computer Science, Electrical, and Mechanical fundamentals plus the 25-mark aptitude mix so candidates from any BEL PE stream can drill core concepts and non-technical sections.

Assessment

BEL Probationary Engineer selection (2025 cycle): Stage 1 — Computer-Based Test, 125 objective MCQs, 125 marks, 120 minutes, bilingual (English/Hindi). Paper split: 100 questions from the candidate's engineering discipline (Electronics, Computer Science, Electrical, or Mechanical) and 25 questions on General Aptitude and Reasoning (logical reasoning, English, basic numeracy, general knowledge). Negative marking: 1/4 mark per wrong answer. Stage 2 — Personal interview (shortlisted from CBT). Final merit weightage: CBT 85 marks, interview 15 marks. Medical examination before appointment. Pay Level E-II (Rs. 40,000–1,40,000 with 3% annual increment per 2025 notification summaries).

Time Limit

120 minutes for the CBT (125 questions).

Passing Score

Minimum qualifying marks cited for 2025: 35% General/OBC/EWS and 30% SC/ST/PwBD on CBT and interview; shortlisting ~1:5 for interview. Final merit: CBT 85 + interview 15 against notified vacancies (340 in 2025).

Exam Fee

Rs. 1,180 (Rs. 1,000 + 18% GST) for General/EWS/OBC (NCL) in BEL PE Recruitment 2025; SC/ST/PwBD/Ex-Servicemen exempt. Paid online via SBI e-Pay Lite. (Bharat Electronics Limited (BEL), Ministry of Defence, Government of India)

BEL Probationary Engineer Exam Content Outline

20%

Electronics Engineering

Devices, analog/digital circuits, signals, communications, microprocessors (technical paper).

20%

Computer Science

OS, DBMS, algorithms, networking, programming, cyber-law basics (technical paper).

20%

Electrical Engineering

Machines, power systems, networks, measurements, protection (technical paper).

20%

Mechanical Engineering

Thermodynamics, SOM, fluids, manufacturing, machine design (technical paper).

20%

General Aptitude & Reasoning

Reasoning, English, numeracy, and GK matching the 25-question aptitude section.

How to Pass the BEL Probationary Engineer Exam

What You Need to Know

Passing score: Minimum qualifying marks cited for 2025: 35% General/OBC/EWS and 30% SC/ST/PwBD on CBT and interview; shortlisting ~1:5 for interview. Final merit: CBT 85 + interview 15 against notified vacancies (340 in 2025).
Assessment: BEL Probationary Engineer selection (2025 cycle): Stage 1 — Computer-Based Test, 125 objective MCQs, 125 marks, 120 minutes, bilingual (English/Hindi). Paper split: 100 questions from the candidate's engineering discipline (Electronics, Computer Science, Electrical, or Mechanical) and 25 questions on General Aptitude and Reasoning (logical reasoning, English, basic numeracy, general knowledge). Negative marking: 1/4 mark per wrong answer. Stage 2 — Personal interview (shortlisted from CBT). Final merit weightage: CBT 85 marks, interview 15 marks. Medical examination before appointment. Pay Level E-II (Rs. 40,000–1,40,000 with 3% annual increment per 2025 notification summaries).
Time limit: 120 minutes for the CBT (125 questions).
Exam fee: Rs. 1,180 (Rs. 1,000 + 18% GST) for General/EWS/OBC (NCL) in BEL PE Recruitment 2025; SC/ST/PwBD/Ex-Servicemen exempt. Paid online via SBI e-Pay Lite.

Keys to Passing

Complete 500+ practice questions
Score 80%+ consistently before scheduling
Focus on highest-weighted sections
Use our AI tutor for tough concepts

BEL Probationary Engineer Study Tips from Top Performers

1Revise your B.E./B.Tech branch syllabus end-to-end first — 100 of 125 official marks are discipline-specific, and BEL defence-electronics context favours solid analog/digital and communication fundamentals for Electronics candidates.

2Practise aptitude under a 120-minute full-paper clock with negative marking in mind: 0.25 per wrong answer means educated guesses on reasoning and GK should be selective.

3Prepare a concise interview folder on BEL products (radar, EW, naval systems), your final-year project, and Ministry of Defence PSU awareness — interview carries 15% of final merit after CBT shortlisting.

Frequently Asked Questions

What is the BEL Probationary Engineer CBT exam pattern?

The CBT has 125 objective MCQs in 120 minutes: 100 from your engineering discipline (Electronics, CS, Electrical, or Mechanical) and 25 on General Aptitude and Reasoning. Each question carries 1 mark; 0.25 mark is deducted for each wrong answer. The paper is bilingual (English and Hindi).

What is the BEL PE application fee?

For BEL Probationary Engineer Recruitment 2025, General/EWS/OBC (NCL) candidates paid Rs. 1,180 (Rs. 1,000 plus GST). SC/ST/PwBD/Ex-Servicemen categories were exempt. Payment was online through SBI e-Pay. Always confirm the fee table in the live notification.

Is GATE score required for BEL Probationary Engineer?

The 2025 BEL PE direct recruitment used its own CBT plus interview; a valid GATE score was not mandatory for that cycle. Eligibility rested on a full-time B.E./B.Tech in the relevant discipline with minimum percentage marks and age limits stated in the advertisement.

How does this 100-question practice bank relate to the real exam?

The official exam has 125 questions; this bank provides 100 MCQs weighted 80:20 to technical versus aptitude sections. Technical items sample all four BEL disciplines so any stream can practise fundamentals; revise your specific branch syllabus deeply for the 100-mark discipline portion.