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100+ Free SSC JE Mechanical Practice Questions

Pass your SSC Junior Engineer Paper I — Mechanical Engineering exam on the first try — instant access, no signup required.

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Key Facts: SSC JE Mechanical Exam

200 Qs

Total Exam Questions

SSC

120 mins

Time Limit

SSC

₹100

Application Fee

SSC

0.25

Negative Mark

Per Wrong Q

30%

Min Pass (UR)

60/200 marks

Level-7

Starting Pay Grade

7th CPC

The SSC JE Mechanical Paper I is a computer-based recruitment test with a highly competitive 5-10% pass rate. The exam consists of 200 multiple-choice questions (100 Technical Mechanical, 50 Reasoning, 50 General Awareness) to be completed in 2 hours. Candidates must achieve minimum qualifying marks (30% for UR) and meet specific category-wise cut-offs to advance to Paper II. The exam fee is ₹100, and it offers recruitment into prestigious departments like CPWD, MES, and BRO with starting salaries around ₹44,900 (Level 7).

Sample SSC JE Mechanical Practice Questions

Try these sample questions to test your SSC JE Mechanical exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1In a certain code language, 'ROSE' is written as 'TQUG'. How is 'BISCUIT' written in that code language?
A.DKUEWKV
B.DKVEXKV
C.DKUEUKV
D.DKVEWKV
Explanation: The coding pattern is a simple letter shift where each character is moved forward by 2 positions in the alphabetical order (R+2=T, O+2=Q, S+2=U, E+2=G). Applying this same pattern to the word 'BISCUIT', we get: B+2=D, I+2=K, S+2=U, C+2=E, U+2=W, I+2=K, T+2=V, resulting in 'DKUEWKV'.
2Select the option that is related to the third number in the same way as the second number is related to the first number: 7 : 56 :: 9 : ?
A.81
B.90
C.72
D.99
Explanation: The relationship pattern follows the rule n : n * (n + 1). For the first pair, 7 : 7 * (7 + 1) = 7 * 8 = 56. Applying this same rule to the number 9, we get 9 * (9 + 1) = 9 * 10 = 90. Therefore, 90 is the correct related number.
3Select the related letter-pair from the given options: BCD : GHI :: LMN : ?
A.OPQ
B.QRS
C.RST
D.PQR
Explanation: The pattern is a constant forward shift of 5 letters for each character in the alphabet. B (+5) = G, C (+5) = H, D (+5) = I. Applying this same +5 shift to 'LMN', we get L (+5) = Q, M (+5) = R, N (+5) = S. Hence, LMN is related to QRS.
4Choose the word from the given options that is different from the rest of the group.
A.Copper
B.Iron
C.Silicon
D.Aluminum
Explanation: Copper, Iron, and Aluminum are all metallic elements and good conductors of electricity. Silicon, on the other hand, is a metalloid (semimetal) and behaves as a semiconductor, which distinguishes it from the other three pure metals.
5Choose the number from the given options that is different from the rest.
A.27
B.64
C.125
D.144
Explanation: The numbers 27, 64, and 125 are all perfect cubes (27 = 3³, 64 = 4³, 125 = 5³). In contrast, 144 is a perfect square (12²) but not a perfect cube. This makes 144 the odd number out in this group.
6Find the missing term in the following number series: 3, 7, 15, 31, 63, ?
A.95
B.111
C.127
D.128
Explanation: The series follows the mathematical rule that each term is twice the previous term plus one (next_term = 2 * prev_term + 1). Applying this: 3 * 2 + 1 = 7; 7 * 2 + 1 = 15; 15 * 2 + 1 = 31; 31 * 2 + 1 = 63; and finally 63 * 2 + 1 = 127. Alternatively, the differences between consecutive terms are powers of 2 (4, 8, 16, 32, 64), giving 63 + 64 = 127.
7Identify the next number in the given mathematical series: 2, 6, 12, 20, 30, ?
A.38
B.40
C.42
D.44
Explanation: The differences between successive terms are consecutive even numbers starting from 4: 6 - 2 = 4; 12 - 6 = 6; 20 - 12 = 8; 30 - 20 = 10. The next difference in the sequence must be 12. Therefore, the next term is 30 + 12 = 42. Alternatively, the series is represented by the formula n² + n (or n*(n+1)) for n = 1, 2, 3, 4, 5, 6, which gives 6 * 7 = 42.
8Find the next letter in the following alphabetical series: Y, V, S, P, M, ?
A.K
B.J
C.I
D.H
Explanation: The series progresses in reverse alphabetical order, skipping two letters each time (a constant backward step of -3 in letter position). Under this rule: Y (25) -> V (22) -> S (19) -> P (16) -> M (13). Subtracting 3 from M (13) gives the 10th letter of the alphabet, which is J.
9In a certain code, 'CABLE' is written as 'ECDNG'. How is the word 'LIGHT' written in that code?
A.NKJKV
B.NKIJV
C.NKJJV
D.NKIIU
Explanation: In this coding scheme, each letter is shifted forward by 2 positions in the alphabet: C (+2) = E, A (+2) = C, B (+2) = D, L (+2) = N, E (+2) = G. Applying this pattern to 'LIGHT': L (+2) = N, I (+2) = K, G (+2) = I, H (+2) = J, T (+2) = V, which gives 'NKIJV'.
10If 'A' is coded as 1, and 'CAT' is coded as 24, then what is the code value for the word 'POLICE'?
A.58
B.60
C.62
D.64
Explanation: The code value of a word is the sum of the numerical positions of its constituent letters in the standard English alphabet. For 'CAT': C(3) + A(1) + T(20) = 24. For 'POLICE': P(16) + O(15) + L(12) + I(9) + C(3) + E(5) = 60. Therefore, the code value is 60.

About the SSC JE Mechanical Exam

Competitive recruitment exam for Junior Engineer (Mechanical) posts in central government departments. The exam consists of 200 objective questions covering Technical, Reasoning, and General Awareness, with a negative marking of 0.25 marks.

Questions

200 scored questions

Time Limit

2 hours

Passing Score

30% (60/200 marks)

Exam Fee

₹100 (Staff Selection Commission (SSC))

SSC JE Mechanical Exam Content Outline

50%

General Engineering (Mechanical)

Thermodynamics, Fluid Mechanics, Theory of Machines, Strength of Materials, and Production

25%

General Intelligence & Reasoning

Analytical reasoning, analogical patterns, spatial visualization, coding, and logical series

25%

General Awareness

Static GK, current events, Indian history, geography, economy, polity, and everyday science

How to Pass the SSC JE Mechanical Exam

What You Need to Know

  • Passing score: 30% (60/200 marks)
  • Exam length: 200 questions
  • Time limit: 2 hours
  • Exam fee: ₹100

Keys to Passing

  • Complete 500+ practice questions
  • Score 80%+ consistently before scheduling
  • Focus on highest-weighted sections
  • Use our AI tutor for tough concepts

SSC JE Mechanical Study Tips from Top Performers

1Prioritize high-weightage technical subjects: Fluid Mechanics, Thermodynamics, and Strength of Materials represent over 70% of the engineering section.
2Work on speed: Since you need to solve 200 questions in 120 minutes, you have less than 40 seconds per question. Quick decision-making is essential.
3Aim for high accuracy in Reasoning: This section is scoring; practice regularly to achieve 45+ marks out of 50.
4Do not ignore General Science: In the General Awareness section, physics, chemistry, and biology questions make up nearly 15-20 marks and are direct.
5Practice previous year papers (PYQs): Solve at least 10 full-length mock tests to build endurance and time-management skills.

Frequently Asked Questions

What is the exam pattern for SSC JE Mechanical Paper I?

SSC JE Paper I is a Computer-Based Test (CBT) consisting of 200 multiple-choice questions. It is divided into three sections: General Engineering - Mechanical (100 questions), General Intelligence & Reasoning (50 questions), and General Awareness (50 questions). The total marks are 200, and the duration is 2 hours (120 minutes). There is a negative marking of 0.25 marks for each incorrect answer.

What are the eligibility criteria for the SSC JE Mechanical exam?

Candidates must hold either a Degree (B.E. / B.Tech) or a 3-year Diploma in Mechanical Engineering from a recognized university or institute. For certain departments (like BRO and MES), Diploma holders are required to have two years of work experience in planning, execution, or maintenance of mechanical works. The age limit is typically 18 to 30 years (up to 32 years for CPWD) with age relaxations for reserved categories.

What are the minimum qualifying marks for SSC JE Paper I?

The Staff Selection Commission sets the minimum qualifying marks for Paper I at 30% (60 marks) for the Unreserved (UR) category, 25% (50 marks) for OBC/EWS, and 20% (40 marks) for all other categories. However, to qualify for Paper II, candidates must score at or above the competitive category-wise cut-off marks, which are usually much higher.

Is there negative marking in the SSC JE Paper I exam?

Yes, there is negative marking in SSC JE Paper I. For every incorrect response, 0.25 marks are deducted from the candidate's total score. No marks are deducted for unattempted questions.

What is the salary structure for an SSC Junior Engineer (Mechanical)?

Candidates selected as Junior Engineers (Mechanical) through the SSC JE exam are appointed as Group 'B' Non-Gazetted officers. The post is in Level-7 of the Pay Matrix (7th Pay Commission) with a pay scale of Rs. 35,400 to Rs. 1,12,400. The starting basic pay is Rs. 35,400, and the total gross salary (including HRA, DA, and TA) ranges from Rs. 55,000 to Rs. 65,000 depending on the city of posting.