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100+ Free JSSC JE Practice Questions

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Key Facts: JSSC JE Exam

₹100

Exam Fee

JSSC Notification

40%

Min. Qualifying Mark

General Category

+3 / -1

Marking Scheme

Correct/Incorrect

2 Hours

Time per Paper

Official standard

120 Qs

Questions per Paper

Paper 1 & Paper 2

Diploma/B.Tech

Eligibility

Engineering Stream

The JSSC JE (Jharkhand Diploma Level Combined Competitive Examination - JDLCCE) is a highly competitive state-level recruitment test. The exam features two papers: Paper 1 with 120 questions (80 General Engineering, 40 GK) and Paper 2 with 120 technical questions, with 2 hours per paper. A correct answer scores +3 marks, and an incorrect one penalizes -1 mark. Minimum qualifying marks are 40% for General, with selection strictly based on final merit cut-offs.

Sample JSSC JE Practice Questions

Try these sample questions to test your JSSC JE exam readiness. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1Which test is most commonly used to measure the workability of medium to high workability concrete in the field?
A.Slump test
B.Compactor test
C.Vee-Bee consistometer
D.Flow table test
Explanation: The slump test is the most common field test for measuring the workability of medium to high workability concrete due to its simplicity.
2What is the primary cause of the bulking of sand?
A.Surface tension of moisture films
B.Presence of clay impurities
C.Chemical reaction with cement
D.Thermal expansion of sand grains
Explanation: Bulking of sand occurs due to the formation of a thin film of water around sand particles, which creates surface tension forces that push the particles apart.
3A 30m chain was found to be 10 cm too long after measuring a distance of 1500m. What is the true distance measured?
A.1505.0 m
B.1495.0 m
C.1501.0 m
D.1499.0 m
Explanation: True Distance = (Actual chain length / Nominal chain length) * Measured distance. Here, L' = 30.1 m, L = 30 m, and measured distance = 1500 m. True Distance = (30.1 / 30) * 1500 = 1505.0 m.
4If the porosity of a soil sample is 0.40, what is its void ratio?
A.0.67
B.0.25
C.0.40
D.1.50
Explanation: Void ratio (e) is related to porosity (n) by the formula: e = n / (1 - n). Thus, e = 0.40 / (1 - 0.40) = 0.40 / 0.60 = 2/3 ≈ 0.67.
5For Fe 415 grade steel, what is the limiting depth of the neutral axis (xu,max) in terms of effective depth (d) as per IS 456?
A.0.48 d
B.0.53 d
C.0.46 d
D.0.40 d
Explanation: As per IS 456, the limiting depth of the neutral axis is 0.53 d for Fe 250, 0.48 d for Fe 415, and 0.46 d for Fe 500.
6What is the shape factor of a standard rectangular steel beam cross-section?
A.1.50
B.1.15
C.1.70
D.2.00
Explanation: The shape factor is the ratio of plastic section modulus to elastic section modulus. For a rectangular section, Shape Factor = Zp / Ze = (b*d^2 / 4) / (b*d^2 / 6) = 1.50.
7Bernoulli's equation in fluid mechanics is a mathematical formulation of which conservation law?
A.Conservation of energy
B.Conservation of mass
C.Conservation of momentum
D.Conservation of angular momentum
Explanation: Bernoulli's equation is derived from Euler's equation of motion and represents the conservation of energy for a steady, incompressible, frictionless, and irrotational flow.
8What is the minimum initial setting time of Ordinary Portland Cement (OPC) as per IS 269?
A.30 minutes
B.10 hours
C.60 minutes
D.45 minutes
Explanation: According to Indian Standards, the initial setting time of Ordinary Portland Cement (OPC) should not be less than 30 minutes, and the final setting time should not exceed 10 hours.
9Calculate the stopping sight distance (SSD) for a design speed of 80 km/h on a flat road, assuming a reaction time of 2.5 seconds and longitudinal friction coefficient of 0.35.
A.127.3 m
B.80.5 m
C.150.2 m
D.105.6 m
Explanation: SSD = vt + v^2 / (2gf), where v = 80/3.6 = 22.22 m/s. Lag distance = 22.22 * 2.5 = 55.56 m. Braking distance = 22.22^2 / (2 * 9.81 * 0.35) = 71.89 m. SSD = 55.56 + 71.89 = 127.45 m ≈ 127.3 m.
10A sewage sample diluted 100 times has an initial dissolved oxygen (DO) of 9.0 mg/L and a 5-day DO of 3.0 mg/L. What is its 5-day Biochemical Oxygen Demand (BOD5)?
A.600 mg/L
B.60 mg/L
C.6 mg/L
D.1200 mg/L
Explanation: BOD5 = (Initial DO - Final DO) * Dilution Factor = (9.0 - 3.0) * 100 = 600 mg/L.

About the JSSC JE Exam

Competitive recruitment exam for Junior Engineers (Civil, Electrical, Mechanical) in Jharkhand. Paper 1 tests General Engineering and General GK, while Paper 2 is subject-specific.

Questions

120 scored questions

Time Limit

2 hours per paper

Passing Score

40% for General

Exam Fee

₹100 (JSSC)

JSSC JE Exam Content Outline

66.6%

General Engineering

Foundational topics covering Civil, Electrical, and Mechanical engineering concepts

20%

General Knowledge & Jharkhand GK

Jharkhand geography, history, culture, and national general awareness

13.4%

General Science & Mathematics

Basic concepts of physical sciences and elementary mathematics

How to Pass the JSSC JE Exam

What You Need to Know

  • Passing score: 40% for General
  • Exam length: 120 questions
  • Time limit: 2 hours per paper
  • Exam fee: ₹100

Keys to Passing

  • Complete 500+ practice questions
  • Score 80%+ consistently before scheduling
  • Focus on highest-weighted sections
  • Use our AI tutor for tough concepts

JSSC JE Study Tips from Top Performers

1Dedicate balanced time to all three engineering disciplines (Civil, Electrical, Mechanical) for Paper 1 General Engineering.
2Thoroughly study Jharkhand GK (geography, history, key projects, minerals, and tourist spots) as it is highly scoring.
3Practice numerical problems in fluid mechanics, thermodynamics, circuit theory, and structural mechanics to master Paper 1 engineering topics.
4Take mock tests simulating the 2-hour limit per paper to manage speed and accuracy under negative marking.
5Understand the basic principles of physics, chemistry, and biology up to class 10th level for the General Science section.

Frequently Asked Questions

What is the pattern of the JSSC JE Exam?

The exam consists of two papers, both multiple-choice (MCQs) and conducted online/CBT. Paper 1 has 120 questions (80 General Engineering, 40 General Knowledge) with a duration of 2 hours. Paper 2 has 120 questions from the candidate's chosen engineering branch (Civil, Electrical, or Mechanical) with a duration of 2 hours. Each correct answer carries +3 marks, and -1 mark is deducted for wrong answers.

What is the application fee for JSSC JE?

The application fee is ₹100 for General, OBC (BC-I/BC-II), and EWS candidates. For SC and ST candidates who are local residents of Jharkhand state, the application fee is reduced to ₹50.

Are B.Tech / BE degree holders eligible to apply for JSSC JE?

Yes, candidates holding a higher qualification such as a Bachelor of Technology (B.Tech) or Bachelor of Engineering (BE) in the respective branch are also eligible to apply, provided they meet all other criteria.

What are the minimum qualifying marks for the JSSC JE Exam?

The minimum qualifying marks are 40% for Unreserved/General category, 36.5% for BC-II, 34% for BC-I, 32% for SC/ST and Female candidates, and 30% for Primitive Tribes. However, actual selection requires scoring much higher due to competitive merit cut-offs.

How should I prepare for the General Engineering section of JSSC JE Paper 1?

The General Engineering section contributes 80 questions (240 marks) and contains basic concepts from Civil, Electrical, and Mechanical engineering. Candidates must study basic civil engineering (materials, surveying, concrete, structures), electrical engineering (AC circuits, machines, network theorems), and mechanical engineering (fluid mechanics, thermodynamics, power plants).