12.4 Volume by Unit Cubes & Additive Volume of Composite Solids
Key Takeaways
- Volume is the count of unit cubes that fill a solid with no gaps and no overlaps, which is why volume is measured in cubic units.
- Filling a rectangular prism layer by layer shows why V = lwh and V = Bh describe the same computation.
- The volume of a solid made of two non-overlapping rectangular prisms is the sum of their volumes, which is how composite-solid items are solved.
- Volume scales by the cube of a linear scale factor, so doubling every dimension multiplies the volume by eight, not by two.
Volume by Unit Cubes & Additive Volume of Composite Solids
Section 12.1 supplied the volume formulas for prisms, cylinders, pyramids, cones, and spheres. This section covers the Level M standards underneath them: understanding volume as a count of unit cubes, deriving $V = lwh$ from that count, and finding the volume of solids composed of two rectangular prisms by adding.
Volume Is a Count of Unit Cubes
Volume is the number of unit cubes — cubes 1 unit on every edge — needed to fill a solid with no gaps and no overlaps.
A cube 1 centimeter on each edge has a volume of 1 cubic centimeter (1 cm³). Fill a box with 60 of them and its volume is 60 cubic centimeters.
Filling Layer by Layer
A 4 × 3 × 2 rectangular prism:
Layer 1 (bottom): Layer 2 (top):
┌───┬───┬───┬───┐ ┌───┬───┬───┬───┐
├───┼───┼───┼───┤ ├───┼───┼───┼───┤
├───┼───┼───┼───┤ ├───┼───┼───┼───┤
└───┴───┴───┴───┘ └───┴───┴───┴───┘
4 × 3 = 12 cubes 4 × 3 = 12 cubes
Total: 2 layers × 12 cubes = 24 cubic units
Two readings of the same count give the two formulas:
| Reading | Formula | Computation |
|---|---|---|
| length × width × height | $V = lwh$ | $4 \times 3 \times 2 = 24$ |
| area of base × height | $V = Bh$ | $12 \times 2 = 24$ |
$V = Bh$ is the more powerful form because it generalizes: any prism's volume is its base area times its height, whether the base is a triangle, a trapezoid, or a circle. A cylinder is just a prism whose base is a circle, which is why $V = \pi r^2 h$ — the $\pi r^2$ is $B$.
Why the unit is cubed. $\text{cm} \times \text{cm} \times \text{cm} = \text{cm}^3$. An answer whose unit is not cubed is not a volume. This is the fastest way to catch the classic error of reporting surface area when the question asked for volume.
Counting Cubes on TABE
Items show a stack of cubes and ask for the volume. Two habits keep you accurate:
- Count by layers, not by visible faces. Cubes hidden behind others still count.
- Check for missing cubes. If the drawing shows a notch, subtract the cubes that are absent.
A drawing shows a solid built as a 5 × 4 base, 3 layers tall, with a 2 × 2 × 1 notch removed from one top corner.
Full block: $5 \times 4 \times 3 = 60$ cubes. Notch: $2 \times 2 \times 1 = 4$ cubes. Volume: $60 - 4 = \mathbf{56}$ cubic units.
Additive Volume: Composite Solids
The Level M standard says it directly: find volumes of solids composed of two non-overlapping right rectangular prisms by adding the volumes of the non-overlapping parts.
The procedure:
- Slice the solid into rectangular prisms — one horizontal or vertical cut usually suffices.
- Find each prism's dimensions, deducing any that are not labeled.
- Compute each volume.
- Add.
Worked example. A loading dock is poured as an L-shaped concrete pad. The lower section is 20 ft × 12 ft × 1 ft. A raised section sits on part of it, 8 ft × 12 ft × 2 ft. What is the total concrete volume?
- Lower section: $20 \times 12 \times 1 = 240$ cu ft
- Raised section: $8 \times 12 \times 2 = 192$ cu ft
- Total: 432 cubic feet
Converting to the unit concrete is ordered in: $432 \div 27 = \mathbf{16}$ cubic yards.
Worked example with a deduced dimension. A storage unit is a 10 ft × 8 ft × 9 ft room with a 3 ft × 8 ft × 4 ft alcove added along one wall.
- Main room: $10 \times 8 \times 9 = 720$ cu ft
- Alcove: $3 \times 8 \times 4 = 96$ cu ft
- Total: 816 cubic feet
The overlap warning. "Non-overlapping" is in the standard for a reason. If you slice a solid so that a region belongs to both pieces, you will count it twice. Draw the cut line and confirm that every cubic inch belongs to exactly one piece.
Subtracting: Hollow Solids
Some items need the reverse operation.
A concrete pipe is 10 ft long with an outer diameter of 4 ft and an inner diameter of 3 ft. How much concrete? (Use $\pi \approx 3.14$.)
- Outer cylinder: $3.14 \times 2^2 \times 10 = 125.6$ cu ft
- Inner void: $3.14 \times 1.5^2 \times 10 = 70.65$ cu ft
- Concrete: $125.6 - 70.65 = 54.95$ cubic feet
Volume and Scaling
If every linear dimension is multiplied by $k$:
| Quantity | Scale factor |
|---|---|
| Length, width, height | $k$ |
| Surface area | $k^2$ |
| Volume | $k^3$ |
Doubling every dimension of a box multiplies its volume by 8, not by 2. A 2 × 3 × 4 box holds 24 cubic units; a 4 × 6 × 8 box holds 192, and $192 \div 24 = 8 = 2^3$.
This is why a container twice as tall, wide, and deep holds eight times as much — a result that regularly appears as a TABE reasoning item and that almost everyone underestimates on instinct.
Volume and Capacity
Volume in cubic units converts to liquid capacity:
| Conversion | Value |
|---|---|
| 1 cubic foot | about 7.48 gallons |
| 1 cubic yard | 27 cubic feet |
| 1 liter | 1,000 cubic centimeters |
| 1 milliliter | 1 cubic centimeter |
A tank measures 3 ft × 2 ft × 2 ft. Its volume is 12 cubic feet, which holds about $12 \times 7.48 \approx \mathbf{90}$ gallons.
A solid is built from unit cubes as a 6 × 5 base that is 4 layers tall, with a 2 × 3 × 2 block removed from one corner. What is its volume?
A concrete pad is poured as two non-overlapping rectangular sections: one measuring 18 ft × 10 ft × 1 ft and a raised section measuring 6 ft × 10 ft × 2 ft. How many cubic yards of concrete are required?
A shipping container is redesigned so that its length, width, and height are each tripled. How does the new volume compare to the original?