2.3 Factors, Multiples, Divisibility Rules, & Prime Factorization
Key Takeaways
- Primes are integers greater than 1 with exactly two positive factors, while 0 and 1 are neither prime nor composite; every composite number has a unique prime factorization.
- Divisibility tests allow rapid factoring: 3 and 9 evaluate digit sums, 4 and 8 evaluate terminal digit blocks, and 6 requires passing tests for both 2 and 3.
- GCF takes the lowest powers of shared prime factors for partitioning problems, whereas LCM takes the highest powers of all prime factors for repeating cycle problems.
- The fundamental product relationship GCF(a, b) × LCM(a, b) = a × b links factors and multiples across all pairs of positive integers.
2.3 Factors, Multiples, Divisibility Rules, & Prime Factorization
Number theory concepts—including prime factorization, divisibility rules, Greatest Common Factor (GCF), and Least Common Multiple (LCM)—are heavily tested on TABE Mathematics Levels M, D, and A. These principles are vital for simplifying algebraic fractions, finding common denominators, and solving real-world scheduling and resource distribution problems.
Factors, Multiples, & Number Classification
Definitions
- Factor (Divisor): An integer that divides evenly into another integer without leaving a remainder. For example, the factors of $24$ are ${1, 2, 3, 4, 6, 8, 12, 24}$.
- Multiple: The product of a given number and any integer. The positive multiples of $6$ are ${6, 12, 18, 24, 30, 36, \dots}$.
Prime vs. Composite Numbers
- Prime Number: A positive integer strictly greater than $1$ that has exactly two distinct positive divisors: $1$ and itself.
- The first ten prime numbers are: $2, 3, 5, 7, 11, 13, 17, 19, 23, 29$.
- The number $2$ is the smallest prime and the only even prime number.
- Composite Number: A positive integer strictly greater than $1$ that has more than two distinct positive divisors (e.g., $4, 6, 8, 9, 10, 12$).
[!CAUTION] The Special Status of 0 and 1:
- The number $1$ is NEITHER prime NOR composite because it has only one positive factor ($1$).
- The number $0$ is NEITHER prime NOR composite because it has infinitely many divisors, but division by zero is undefined.
Master Divisibility Rules (2 through 10)
Divisibility rules allow you to test whether large numbers can be divided evenly without carrying out full long division.
| Divisor | Divisibility Condition | Example Test ($7,812$) | Pass/Fail |
|---|---|---|---|
| $2$ | The last digit is even ($0, 2, 4, 6, 8$). | Last digit is $2$ (even). | Pass ($7,812 \div 2 = 3,906$) |
| $3$ | The sum of all digits is divisible by $3$. | $7 + 8 + 1 + 2 = 18$; $18 \div 3 = 6$. | Pass ($7,812 \div 3 = 2,604$) |
| $4$ | The number formed by the last two digits is divisible by $4$. | Last two digits: $12$; $12 \div 4 = 3$. | Pass ($7,812 \div 4 = 1,953$) |
| $5$ | The last digit is $0$ or $5$. | Last digit is $2$ (not $0$ or $5$). | Fail |
| $6$ | The number passes the rules for BOTH $2$ and $3$. | Passes test for $2$ and test for $3$. | Pass ($7,812 \div 6 = 1,302$) |
| $8$ | The number formed by the last three digits is divisible by $8$. | Last three digits: $812$; $812 \div 8 = 101.5$. | Fail |
| $9$ | The sum of all digits is divisible by $9$. | $7 + 8 + 1 + 2 = 18$; $18 \div 9 = 2$. | Pass ($7,812 \div 9 = 868$) |
| $10$ | The last digit is $0$. | Last digit is $2$. | Fail |
Prime Factorization Algorithms
The Fundamental Theorem of Arithmetic states that every composite integer greater than $1$ can be expressed as a unique product of prime numbers (up to the order of the factors).
Method 1: Factor Tree
Continually split composite factors into factor pairs until every branch ends in a prime number.
180
/ \
18 10
/ \ / \
2 9 2 5
/ \
3 3
Collecting prime terminal nodes: $180 = 2 \times 2 \times 3 \times 3 \times 5 = \mathbf{2^2 \times 3^2 \times 5^1}$.
Method 2: Upside-Down Division Ladder
Repeatedly divide the number by the smallest possible prime divisor until the quotient is $1$.
2 & 180 \\ \hline 2 & 90 \\ \hline 3 & 45 \\ \hline 3 & 15 \\ \hline 5 & 5 \\ \hline & 1 \end{array} \implies 180 = \mathbf{2^2 \times 3^2 \times 5^1}$$ --- ## Greatest Common Factor (GCF) vs. Least Common Multiple (LCM) | Attribute | Greatest Common Factor (GCF) | Least Common Multiple (LCM) | | :--- | :--- | :--- | | **Definition** | Largest factor dividing all given numbers evenly. | Smallest positive multiple shared by all given numbers. | | **Prime Factor Rule** | Take the **lowest exponent** of only the **shared** prime factors. | Take the **highest exponent** of **every** prime factor present. | | **Magnitude** | $\text{GCF} \le \text{smallest number}$ | $\text{LCM} \ge \text{largest number}$ | | **Formula** | $\text{GCF}(a,b) = \frac{a \times b}{\text{LCM}(a,b)}$ | $\text{LCM}(a,b) = \frac{a \times b}{\text{GCF}(a,b)}$ | ### Step-by-Step Calculation: GCF and LCM of $72$ and $108$ 1. Find prime factorizations: - $72 = 2^3 \times 3^2$ - $108 = 2^2 \times 3^3$ 2. **Compute GCF (Lowest Shared Exponents):** $$\text{GCF} = 2^{\min(3,2)} \times 3^{\min(2,3)} = 2^2 \times 3^2 = 4 \times 9 = \mathbf{36}$$ 3. **Compute LCM (Highest All Exponents):** $$\text{LCM} = 2^{\max(3,2)} \times 3^{\max(2,3)} = 2^3 \times 3^3 = 8 \times 27 = \mathbf{216}$$ 4. **Verify Fundamental Product Relationship:** $$\text{GCF} \times \text{LCM} = 36 \times 216 = 7,776$$ $$a \times b = 72 \times 108 = 7,776 \quad \checkmark$$ --- ## Word Problem Discrimination: GCF vs. LCM Scenarios A critical skill on the TABE exam is recognizing whether a word problem requires finding the GCF or the LCM. ### GCF Clues & Scenarios (Dividing / Partitioning) - **Keywords:** *"Greatest number of identical kits"*, *"divided equally without leftovers"*, *"maximum length of equal strips"*, *"arranged in equal rows"*. - **Problem Structure:** You have fixed quantities of multiple items and want to split or group them into the largest possible identical sets. - **Example:** A teacher has $48$ pencils and $64$ erasers. What is the greatest number of identical prize packs she can create with no supplies left over? $$\text{GCF}(48, 64) = 16 \text{ prize packs (each with } 3 \text{ pencils and } 4 \text{ erasers)}$$ ### LCM Clues & Scenarios (Repeating Cycles / Synchronization) - **Keywords:** *"When will they next happen at the same time?"*, *"smallest number of packages to have equal items"*, *"beeps every X minutes and Y minutes"*, *"revolving cycles"*. - **Problem Structure:** Two or more repeating intervals start together, and you must find when they coincide again. - **Example:** Bus Route A arrives every $15$ minutes; Bus Route B arrives every $20$ minutes. If both buses depart at 8:00 AM, at what time will they next depart simultaneously? $$\text{LCM}(15, 20) = 60 \text{ minutes} \implies 60 \text{ minutes after 8:00 AM} = \mathbf{\text{9:00 AM}}$$Which of the following numbers is divisible by both 3 and 4?
A community center coordinator has 84 granola bars, 126 juice boxes, and 210 fruit snacks. She wants to assemble identical snack bags with no items left over. What is the greatest number of identical snack bags she can assemble?
Hot dog buns come in packages of 8, and hot dog wieners come in packages of 12. What is the minimum number of bun packages and wiener packages a cook must purchase so that every hot dog has a bun with none left over?