4.3 Engineering Economics & Financial Analysis
Key Takeaways
Time value of money converts single future sums F = P(1+i)^n using the single payment compound amount factor (F/P, i, n).
Uniform series annual cash flows relate to present worth via using (P/A, i, n).
Depreciation reduces asset book value over recovery life: Straight-Line gives constant , whereas SYD accelerates early tax deductions.
Net Present Value (NPV) evaluation criteria accepts projects when NPV at the Minimum Attractive Rate of Return (MARR).
Capitalized cost represents the present worth of an asset maintained indefinitely through periodic replacement.
4.3 Engineering Economics & Financial Analysis
1. Principles of Engineering Economics & Interest Formulas
Engineering Economics combines engineering decision-making with financial evaluation to select the most cost-effective alternatives over a project's lifecycle.
Simple vs. Compound Interest
- Simple Interest: Interest is charged only on the principal amount :
- Compound Interest: Interest earned in each period is added to the principal to earn interest in subsequent periods: where is Present Worth, is Future Worth, is interest rate per period, and is number of compounding periods.
Nominal vs. Effective Interest Rates
When an annual nominal interest rate is compounded times per year:
- Period interest rate:
- Total periods in years:
- Effective Annual Rate ():
- Continuous Compounding: As , the future worth becomes , and .
2. Discrete Cash Flow Equivalence Factors
| Equivalence Factor Name | Standard Notation | Formula |
|---|---|---|
| Single Payment Compound Amount | ||
| Single Payment Present Worth | ||
| Uniform Series Sinking Fund | ||
| Uniform Series Compound Amount | ||
| Capital Recovery Factor | ||
| Uniform Series Present Worth | ||
| Arithmetic Gradient Present Worth |
3. Project Evaluation Methods
1. Present Worth (PW) Method
All cash inflows () and outflows () are discounted to using the Minimum Attractive Rate of Return (MARR):
Decision Criterion: Accept project if .
2. Annual Worth (AW) Method
Converts all project cash flows into an equivalent uniform annual cash flow over the service life:
Decision Criterion: Accept project if . Useful for comparing mutually exclusive projects with unequal service lives.
3. Internal Rate of Return (IRR / ROR)
The discount rate at which the Present Worth of cash inflows equals the Present Worth of cash outflows (i.e., ):
Decision Criterion: Accept project if .
4. Capitalized Cost ()
Capitalized cost is the present worth of an asset that is assumed to provide service perpetually (infinite life ):
where is initial cost, is annual operating cost, is replacement cost every years, and is interest rate.
4. Asset Depreciation & Tax Accounting
Depreciation is the systematic allocation of an asset's initial cost over its useful recovery life , leaving a salvage value .
Straight-Line Method (SL)
Constant annual depreciation charge :
Book value at end of year : .
Sum-of-the-Years-Digits Method (SYD)
Accelerated depreciation method where annual charge decreases linearly:
Declining Balance Method (DB / DDB)
Fixed percentage rate applied to the beginning book value :
- (150% Declining Balance) or (200% Double Declining Balance)
5. Break-Even Analysis & Inflation
Break-Even Analysis
Determines the production volume where Total Revenue equals Total Cost :
where is fixed costs, is variable cost per unit, and is selling price per unit.
Inflation Adjustment
If market interest rate is and annual inflation rate is , the real (inflation-free) interest rate is:
An electronics firm borrows $500,000 at a nominal annual interest rate of 12% compounded monthly. What is the effective annual interest rate (EAR)?
12.00%
12.36%
12.68%
13.04%
A telecommunications company plans to install a fiber network costing $1,200,000 that generates annual net savings of $250,000 for 8 years. If the MARR is 10%, what is the Present Worth (PW) of the project? (Given: (P/A, 10%, 8) = 5.3349)
-$133,725
$800,000
$333,725
$133,725
An industrial test bench costs $150,000 with an estimated salvage value of $30,000 after 5 years. Using the Sum-of-the-Years-Digits (SYD) method, what is the depreciation expense in Year 2?
$24,000
$40,000
$32,000
$48,000
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