PracticeVideosBlogFlashcards

8.4 Operational Amplifiers & Active Filter Design

Key Takeaways

  • An ideal operational amplifier possesses infinite open-loop voltage gain (AOL=∞A_{OL} = \infty), infinite input impedance (Zin=∞Z_{in} = \infty), zero output impedance (Zout=0Z_{out} = 0), infinite bandwidth, and zero offset voltage.

  • The negative feedback Golden Rules dictate: 1) No current flows into either input terminal (I^+ = I^- = 0), and 2) Feedback forces input terminal voltages equal (V^+ = V^-), creating a virtual ground/short.

  • Essential linear op-amp circuits include Inverting (Av=−RfRiA_v = -\frac{R_f}{R_i}), Non-Inverting (Av=1+RfRiA_v = 1 + \frac{R_f}{R_i}), Unity Buffer (Av=1A_v = 1), Summing, Difference, and Instrumentation Amplifiers (Av=(1+2R1Rg)R3R2A_v = \left(1 + \frac{2R_1}{R_g}\right)\frac{R_3}{R_2}).

  • Key non-ideal parameters are Common-Mode Rejection Ratio (CMRR=20log⁡10∣Ad/Ac∣CMRR = 20\log_{10}|A_d/A_c|), Slew Rate (SR=dVodt∣max=2πfmaxVpSR = \left.\frac{dV_o}{dt}\right|_{max} = 2\pi f_{max} V_p), input offset current/voltage, and GBW product.

  • Active filters (Sallen-Key topology) eliminate bulky inductors; Butterworth filters yield maximally flat passbands, Chebyshev filters provide sharp roll-off with passband ripple, and Bessel filters preserve linear phase delay.

Last updated: July 2026

8.4 Operational Amplifiers & Active Filter Design

1. Ideal vs. Practical Op-Amp Characteristics

An Operational Amplifier (Op-Amp) is a high-gain DC-coupled differential amplifier. Under negative feedback, op-amp circuit operation is simplified by the Golden Rules of Op-Amps.

The Golden Rules of Ideal Op-Amps (with Negative Feedback)

  1. Rule 1 (Infinite Input Resistance): No current enters either input terminal (I+=I−=0 AI^+ = I^- = 0\text{ A}).
  2. Rule 2 (Virtual Short Circuit): Negative feedback forces the differential input voltage to zero (V+−V−=0  ⟹  V+=V−V^+ - V^- = 0 \implies V^+ = V^-).

Ideal vs. Practical (741 BJT) Parameter Comparison

ParameterSymbolIdeal Op-AmpPractical Op-Amp (LM741)Practical FET Op-Amp (TL081)
Open-Loop Voltage GainAOLA_{OL}∞\infty200,000200,000 (106 dB106\text{ dB})200,000200,000 (106 dB106\text{ dB})
Input ResistanceRinR_{in}∞\infty2 MΩ2\text{ M}\Omega1012 Ω10^{12}\ \Omega (1 TΩ1\text{ T}\Omega)
Output ResistanceRoutR_{out}0 Ω0\ \Omega75 Ω75\ \Omega50 Ω50\ \Omega
BandwidthBWBW∞\infty1 MHz1\text{ MHz} (Unity Gain fTf_T)3 MHz3\text{ MHz}
Common-Mode Rejection RatioCMRRCMRR∞\infty90 dB90\text{ dB}100 dB100\text{ dB}
Slew RateSRSR∞\infty0.5 V/μs0.5\text{ V/}\mu\text{s}13 V/μs13\text{ V/}\mu\text{s}
Input Offset VoltageVOSV_{OS}0 V0\text{ V}1−5 mV1-5\text{ mV}3 mV3\text{ mV}

Key Non-Ideal Parameters

  • Common-Mode Rejection Ratio (CMRRCMRR): Ability to reject common noise signals present at both input terminals.
CMRR=20log⁡10∣AdAc∣CMRR = 20 \log_{10} \left| \frac{A_d}{A_c} \right|
  • Slew Rate (SRSR): Maximum rate of output voltage change per unit time:
SR=dVodt∣max[V/μs]SR = \left. \frac{dV_o}{dt} \right|_{max} \quad [\text{V/}\mu\text{s}]
  • Full-Power Bandwidth (fmaxf_{max}): Maximum undistorted frequency for a peak output voltage amplitude VpV_p:
fmax=SR2πVpf_{max} = \frac{SR}{2\pi V_p}

2. Linear Op-Amp Configurations

A. Inverting Amplifier

  • Voltage Gain: Av=−RfRiA_v = -\frac{R_f}{R_i}
  • Input Impedance: Zin=RiZ_{in} = R_i
  • Virtual Ground: Non-inverting input is grounded (V+=0 V  ⟹  V−=0 VV^+ = 0\text{ V} \implies V^- = 0\text{ V}).

B. Non-Inverting Amplifier

  • Voltage Gain: Av=1+RfRiA_v = 1 + \frac{R_f}{R_i}
  • Input Impedance: Zin≈∞Z_{in} \approx \infty
  • Phase: In-phase output (0∘0^\circ phase shift).

C. Voltage Follower (Unity-Gain Buffer)

  • Rf=0 Ω,Ri=∞  ⟹  Av=+1R_f = 0\ \Omega, R_i = \infty \implies A_v = +1.
  • Ideal buffer: Zin=∞,Zout=0Z_{in} = \infty, Z_{out} = 0.

D. Summing Amplifier

  • Output Voltage:
Vo=−Rf(V1R1+V2R2+V3R3+⋯+VnRn)V_o = -R_f \left( \frac{V_1}{R_1} + \frac{V_2}{R_2} + \frac{V_3}{R_3} + \dots + \frac{V_n}{R_n} \right)

E. Difference (Differential) Amplifier

  • When matched resistors are used (R4/R3=R2/R1R_4/R_3 = R_2/R_1):
Vo=R2R1(V2−V1)V_o = \frac{R_2}{R_1} (V_2 - V_1)

F. Three Op-Amp Instrumentation Amplifier

  • Consists of two non-inverting input buffer stages driving a differential amplifier stage.
  • Overall Voltage Gain:
Av=(1+2R1Rg)(R3R2)A_v = \left( 1 + \frac{2 R_1}{R_g} \right) \left( \frac{R_3}{R_2} \right)
  • Advantages: Single resistor (RgR_g) gain control, ultra-high input impedance on both inputs, superior CMRR.

G. Op-Amp Integrator & Differentiator

  • Integrator: vo(t)=−1RC∫0tvi(τ)dτ+vo(0)v_o(t) = -\frac{1}{R C} \int_{0}^{t} v_i(\tau) d\tau + v_o(0). Practical circuits include parallel RfR_f across CC to limit DC gain.
  • Differentiator: vo(t)=−RCdvi(t)dtv_o(t) = -R C \frac{dv_i(t)}{dt}. Practical circuits add series RsR_s with CC to suppress high-frequency noise amplification.

3. Non-Linear Op-Amp Circuits & Comparators

A. Schmitt Trigger (Inverting with Positive Feedback)

Provides positive feedback to introduce hysteresis, eliminating output noise chattering.

  • Upper Threshold Point (VUTPV_{UTP}):
VUTP=+Vsat⋅R1R1+R2V_{UTP} = +V_{sat} \cdot \frac{R_1}{R_1 + R_2}
  • Lower Threshold Point (VLTPV_{LTP}):
VLTP=−Vsat⋅R1R1+R2V_{LTP} = -V_{sat} \cdot \frac{R_1}{R_1 + R_2}
  • Hysteresis Voltage (VHV_H):
VH=VUTP−VLTP=2Vsat(R1R1+R2)V_H = V_{UTP} - V_{LTP} = 2 V_{sat} \left(\frac{R_1}{R_1 + R_2}\right)

4. Active Filter Design & Approximation Responses

Active filters utilize op-amps, resistors, and capacitors (no inductors) to shape frequency response.

Filter Approximation Characteristics

  1. Butterworth: Maximally flat passband response; smooth monotonic attenuation (−20 dB/dec-20\text{ dB/dec} per order nn).
  2. Chebyshev: Steep initial roll-off rate; exhibits equal-ripple passband variations.
  3. Bessel: Linear phase shift (constant group delay); gradual amplitude roll-off; preserves pulse shapes.

Second-Order Sallen-Key Low-Pass Filter (LPF)

  • Cutoff Frequency (fcf_c):
fc=12πR1R2C1C2f_c = \frac{1}{2\pi \sqrt{R_1 R_2 C_1 C_2}}
  • Equal-Component Design (R1=R2=R,C1=C2=CR_1 = R_2 = R, C_1 = C_2 = C):
fc=12πRCf_c = \frac{1}{2\pi R C}
  • Passband Voltage Gain (AvA_v) & Quality Factor (QQ):
Av=1+RfRi,Q=13−AvA_v = 1 + \frac{R_f}{R_i}, \quad Q = \frac{1}{3 - A_v}
  • For Second-Order Butterworth Response (Q=0.707=12Q = 0.707 = \frac{1}{\sqrt{2}}):
3−Av=2≈1.414  ⟹  Av=1.586  ⟹  RfRi=0.5863 - A_v = \sqrt{2} \approx 1.414 \implies A_v = 1.586 \implies \frac{R_f}{R_i} = 0.586
  • Roll-off Rate: −40 dB/decade-40\text{ dB/decade} (−12 dB/octave-12\text{ dB/octave}).
Loading diagram...
Three Op-Amp Instrumentation Amplifier Architecture
Roll-Off Rate Comparison by Active Filter Order
Test Your Knowledge

An op-amp with a slew rate of SR = 2.5 V/μs is used in an amplifier with a desired output peak voltage of V_p = 10 V. What is the maximum distortion-free operating frequency (full-power bandwidth f_max)?

A

12.8 kHz

B

39.8 kHz

C

79.6 kHz

D

159.2 kHz

Test Your Knowledge

In a three-op-amp instrumentation amplifier, R1 = 25 kΩ, R2 = 10 kΩ, R3 = 50 kΩ, and the gain resistor is set to Rg = 2.0 kΩ. What is the total closed-loop differential voltage gain A_v?

A

65

B

130

C

260

D

325

Test Your Knowledge

To achieve a second-order Butterworth low-pass filter response using equal-component Sallen-Key topology with R = 10 kΩ and C = 0.01 μF, what should be the required feedback resistor ratio R_f / R_i and cutoff frequency f_c?

A

Rf/Ri = 0.586, fc = 1.59 kHz

B

Rf/Ri = 1.414, fc = 3.18 kHz

C

Rf/Ri = 1.586, fc = 1.59 kHz

D

Rf/Ri = 2.000, fc = 3.18 kHz

Sections you finish are checked off in the contents.