10.5 Postulates of Quantum Mechanics, Operators, Particle in a Box, and Harmonic Oscillator

Key Takeaways

  • Classical physics failed to describe atomic-scale phenomena (blackbody ultraviolet catastrophe, photoelectric effect, Compton scattering), necessitating Planck's energy quantization (E=nhνE = nh\nu) and de Broglie matter waves (λ=h/p\lambda = h/p).

  • The Heisenberg Uncertainty Principle (ΔxΔpx≥ℏ/2\Delta x \Delta p_x \ge \hbar / 2) formalizes quantum indeterminacy between non-commuting observable operators ([x^,p^x]=iℏ[\hat{x}, \hat{p}_x] = i\hbar).

  • The Five Postulates of Quantum Mechanics define the state wave function Ψ\Psi, Born probability interpretation (∣Ψ∣2dτ|\Psi|^2 d\tau), linear Hermitian operators with real eigenvalues (A^ψn=anψn\hat{A}\psi_n = a_n \psi_n), expectation values (⟨A⟩=∫Ψ∗A^Ψdτ\langle A \rangle = \int \Psi^* \hat{A}\Psi d\tau), and Schrödinger time evolution.

  • A particle in a 1D box reveals spatial quantization of energy (En=n2h28mL2E_n = \frac{n^2 h^2}{8 m L^2}), zero-point energy (E1>0E_1 > 0), and nodal topology (n−1n-1 nodes); in a 3D cubic box, spatial symmetry produces degenerate energy states.

  • The quantum harmonic oscillator exhibits parabolic potential V(x)=12kx2V(x) = \frac{1}{2}kx^2, equispaced vibrational levels (Ev=(v+1/2)hνE_v = (v + 1/2)h\nu), non-zero vibrational zero-point energy (E0=12hνE_0 = \frac{1}{2}h\nu), and quantum tunneling into classically forbidden zones.

Last updated: October 2026

Postulates of Quantum Mechanics, Operators, Particle in a Box, and Harmonic Oscillator

At the close of the nineteenth century, classical Newtonian mechanics and Maxwellian electrodynamics failed completely when applied to subatomic phenomena and radiation-matter interactions. The emergence of quantum mechanics introduced an entirely new physical paradigm where energy, angular momentum, and physical observables are quantized, matter exhibits wave-particle duality, and physical states are described probabilistically by wave functions operating under linear Hermitian operators.


1. Classical Failures and Early Quantum Milestones

1. Blackbody Radiation and Planck's Quantum Hypothesis (1900)

Classical Rayleigh-Jeans theory modeled cavity radiation as electromagnetic standing waves in thermal equilibrium, predicting that spectral energy density dρd\rho increases with the inverse fourth power of wavelength: dρ=8πkBTλ4dλd\rho = \frac{8\pi k_B T}{\lambda^4} d\lambda As λ→0\lambda \to 0 (ultraviolet region), this classical formula predicted that radiated energy density diverges to infinity—an absurd physical catastrophe known as the ultraviolet catastrophe.

Max Planck solved this by postulating that matter absorbs and emits radiation only in discrete packets or quanta of energy proportional to radiation frequency ν\nu: E=nhν(n=0,1,2,… )E = n h \nu \quad (n = 0, 1, 2, \dots) where h=6.62607×10−34 J⋅sh = 6.62607 \times 10^{-34}\text{ J}\cdot\text{s} is Planck's constant. Planck's radiation law reproduced experimental blackbody spectra across all wavelengths: ρ(ν,T)dν=8πhν3c31ehν/kBT−1dν\rho(\nu, T) d\nu = \frac{8\pi h \nu^3}{c^3} \frac{1}{e^{h\nu / k_B T} - 1} d\nu

2. The Photoelectric Effect (Einstein, 1905)

When monochromatic light strikes a clean metal surface in a vacuum, electrons are ejected immediately, but only if the light frequency exceeds a critical threshold frequency (ν0\nu_0):

  • Classical wave theory predicted that electron kinetic energy should increase with light intensity (wave amplitude), and that dim light would require an accumulation time delay.
  • Experimentally, light intensity alters only the number of ejected photoelectrons (photocurrent), while the maximum kinetic energy depends strictly on light frequency.

Albert Einstein resolved this by proposing that electromagnetic radiation consists of localized energy packets called photons, each bearing energy E=hνE = h\nu. Energy conservation requires:

Ek=hν−Φ=hν−hν0E_k = h\nu - \Phi = h\nu - h\nu_0 where Φ=hν0\Phi = h\nu_0 is the work function of the metal (the minimum binding energy required to liberate an electron from the Fermi level into the vacuum).

3. Compton Scattering (1923)

Arthur Compton bombarded graphite targets with monochromatic X-rays and observed that scattered X-rays had a longer wavelength (λ′>λ\lambda' > \lambda) than incident rays. Treating the collision as a relativistic elastic impact between a photon carrying momentum p=h/λp = h/\lambda and a stationary electron yields the Compton wavelength shift:

Δλ=λ′−λ=hmec(1−cos⁡θ)\Delta \lambda = \lambda' - \lambda = \frac{h}{m_e c}(1 - \cos\theta) where hmec=2.4263×10−12 m=0.02426 A˚\frac{h}{m_e c} = 2.4263 \times 10^{-12}\text{ m} = 0.02426\text{ \AA} is the Compton wavelength of an electron, and θ\theta is the scattering angle.

4. De Broglie Matter Waves (1924)

Louis de Broglie hypothesized that if light waves possess particle characteristics (momentum pp), then material particles must possess wave characteristics. The de Broglie wavelength of any particle with linear momentum p=mvp = mv is:

λ=hp=hmv\lambda = \frac{h}{p} = \frac{h}{mv} Electron wave properties were confirmed experimentally in 1927 by Clinton Davisson and Lester Germer (observing electron diffraction from nickel crystals) and George Thomson (thin gold foil transmission).

5. Heisenberg Uncertainty Principle (1927)

Werner Heisenberg proved that due to wave-particle duality, it is physically impossible to measure simultaneously both the position and conjugate linear momentum of a quantum entity with arbitrary precision:

ΔxΔpx≥ℏ2\Delta x \Delta p_x \ge \frac{\hbar}{2} where ℏ≡h2π=1.05457×10−34 J⋅s\hbar \equiv \frac{h}{2\pi} = 1.05457 \times 10^{-34}\text{ J}\cdot\text{s}. A parallel uncertainty relation links energy and time: ΔEΔt≥ℏ2\Delta E \Delta t \ge \frac{\hbar}{2}.


2. The Five Postulates of Quantum Mechanics

Modern quantum theory is constructed axiomatically upon five foundational postulates:

Postulate 1: The State and the Wave Function

The physical state of a system of particles is completely specified by a continuous, single-valued complex wave function Ψ(r1,r2,…,t)\Psi(\mathbf{r}_1, \mathbf{r}_2, \dots, t).

  • Born Interpretation (Max Born, 1926): The wave function itself carries no direct classical physical dimension, but the product of Ψ\Psi with its complex conjugate Ψ∗\Psi^*—the squared modulus ∣Ψ∣2|\Psi|^2—represents the probability density: P(x,y,z)dτ=∣Ψ∣2dτ=Ψ∗Ψ dτP(x, y, z) d\tau = |\Psi|^2 d\tau = \Psi^* \Psi\,d\tau representing the probability of locating the particle within spatial volume element dτ=dx dy dzd\tau = dx\,dy\,dz.
  • Well-Behaved Criteria: For Ψ\Psi to represent a physically realizable state, it must satisfy three conditions everywhere:
    1. Ψ\Psi must be single-valued (f(x)f(x) has only one value at each point).
    2. Ψ\Psi and its first spatial derivatives (dΨdx\frac{d\Psi}{dx}) must be continuous.
    3. Ψ\Psi must be quadratically integrable (normalizable), so the total probability over all space equals unity: ∫−∞+∞∣Ψ∣2dτ=1\int_{-\infty}^{+\infty} |\Psi|^2 d\tau = 1

Postulate 2: Physical Observables and Operators

To every physically observable quantity in classical mechanics (position, momentum, kinetic energy, angular momentum) corresponds a linear Hermitian operator in quantum mechanics.

ObservableClassical SymbolQuantum Operator SymbolCoordinate-Space Representation
Positionxxx^\hat{x}xx (multiplication by xx)
Linear Momentumpxp_xp^x\hat{p}_x−iℏ∂∂x-i\hbar \frac{\partial}{\partial x}
Kinetic EnergyT=px22mT = \frac{p_x^2}{2m}T^x\hat{T}_x−ℏ22m∂2∂x2-\frac{\hbar^2}{2m} \frac{\partial^2}{\partial x^2}
Potential EnergyV(x)V(x)V^(x)\hat{V}(x)V(x)V(x)
Total Energy (Hamiltonian)H=T+VH = T + VH^\hat{H}−ℏ22m∇2+V(r)-\frac{\hbar^2}{2m} \nabla^2 + V(\mathbf{r})

Here, ∇2=∂2∂x2+∂2∂y2+∂2∂z2\nabla^2 = \frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial y^2} + \frac{\partial^2}{\partial z^2} is the Laplacian operator.

Postulate 3: Eigenvalues and Measurement

If a physical observable represented by operator A^\hat{A} is measured on a system, the only possible numerical outcome of the measurement is one of the eigenvalues (ana_n) that satisfy the eigenvalue equation:

A^ψn=anψn\hat{A} \psi_n = a_n \psi_n where ψn\psi_n is the corresponding eigenfunction.

  • If the system is already in an eigenstate ψn\psi_n, measuring observable AA yields eigenvalue ana_n with 100% certainty.
  • If the system is in an arbitrary state Ψ\Psi (a linear combination Ψ=∑cnψn\Psi = \sum c_n \psi_n), measuring AA yields eigenvalue ana_n with probability ∣cn∣2|c_n|^2, and the measurement instantly collapses the wave function to eigenstate ψn\psi_n.

Postulate 4: Expectation Values

When an observable AA is measured repeatedly on an ensemble of identically prepared quantum systems described by normalized wave function Ψ\Psi, the statistical average or expectation value (⟨A⟩\langle A \rangle) is:

⟨A⟩=∫−∞+∞Ψ∗A^Ψ dτ\langle A \rangle = \int_{-\infty}^{+\infty} \Psi^* \hat{A} \Psi\,d\tau

Postulate 5: Time Evolution of the State

The time-dependent evolution of a wave function is governed by the Time-Dependent Schrödinger Equation (TDSE):

iℏ∂Ψ∂t=H^Ψi\hbar \frac{\partial \Psi}{\partial t} = \hat{H}\Psi When the potential energy V(r)V(\mathbf{r}) is independent of time, separation of variables Ψ(r,t)=ψ(r)e−iEt/ℏ\Psi(\mathbf{r}, t) = \psi(\mathbf{r}) e^{-iEt / \hbar} yields the stationary Time-Independent Schrödinger Equation (TISE):

H^ψ=Eψ  ⟺  −ℏ22m∇2ψ+V(r)ψ=Eψ\hat{H} \psi = E \psi \iff -\frac{\hbar^2}{2m}\nabla^2 \psi + V(\mathbf{r})\psi = E\psi


3. Mathematical Properties of Operators: Hermitian and Commutator Algebra

Hermitian Operators

An operator A^\hat{A} is defined as Hermitian if it satisfies the integral equality for all well-behaved wave functions ff and gg: ∫f∗(A^g) dτ=∫(A^f)∗g dτ\int f^* (\hat{A} g)\,d\tau = \int (\hat{A} f)^* g\,d\tau

Two Essential Theorems:

  1. Real Eigenvalues: All eigenvalues of a Hermitian operator are strictly real numbers (an∈Ra_n \in \mathbb{R}). Because physical measurements in the laboratory yield real quantities, all quantum operators representing observables must be Hermitian.
  2. Orthogonality of Eigenfunctions: Eigenfunctions of a Hermitian operator corresponding to distinct eigenvalues are mutually orthogonal: ∫ψm∗ψn dτ=0(for am≠an)\int \psi_m^* \psi_n\,d\tau = 0 \quad (\text{for } a_m \ne a_n) Combining normalization with orthogonality yields the orthonormality condition: ∫ψm∗ψn dτ=δmn={1if m=n0if m≠n\int \psi_m^* \psi_n\,d\tau = \delta_{mn} = \begin{cases} 1 & \text{if } m = n \\ 0 & \text{if } m \ne n \end{cases}

Commutator Algebra and Compatible Observables

The commutator of two operators A^\hat{A} and B^\hat{B} is defined as: [A^,B^]≡A^B^−B^A^[\hat{A}, \hat{B}] \equiv \hat{A}\hat{B} - \hat{B}\hat{A}

  • If [A^,B^]=0[\hat{A}, \hat{B}] = 0: The operators commute. The observables can be measured simultaneously with infinite precision, and share a common set of simultaneous eigenfunctions.
  • If [A^,B^]≠0[\hat{A}, \hat{B}] \ne 0: The operators do not commute. The observables cannot be known simultaneously with arbitrary precision, obeying generalized uncertainty ΔAΔB≥12∣⟨[A^,B^]⟩∣\Delta A \Delta B \ge \frac{1}{2} |\langle [\hat{A}, \hat{B}] \rangle|.

Fundamental Commutator Evaluation: [x^,p^x]f(x)=x(−iℏdfdx)−(−iℏddx(xf))=−iℏxdfdx+iℏ(f+xdfdx)=iℏf(x)[\hat{x}, \hat{p}_x] f(x) = x\left(-i\hbar \frac{df}{dx}\right) - \left(-i\hbar \frac{d}{dx}(x f)\right) = -i\hbar x \frac{df}{dx} + i\hbar\left(f + x\frac{df}{dx}\right) = i\hbar f(x) [x^,p^x]=iℏ≠0[\hat{x}, \hat{p}_x] = i\hbar \ne 0 This non-zero commutator is the mathematical origin of the Heisenberg Uncertainty Principle.


4. The Particle in a One-Dimensional Box

The particle in a 1D box (infinite potential well) is the simplest quantum model exhibiting spatial quantization of energy. Consider a particle of mass mm confined along the xx-axis between impenetrable rigid boundaries: V(x)={00<x<L∞x≤0 and x≥LV(x) = \begin{cases} 0 & 0 < x < L \\ \infty & x \le 0 \text{ and } x \ge L \end{cases}

Derivation of Energy and Wave Functions

Inside the box (0<x<L0 < x < L), V(x)=0V(x) = 0, so the TISE is: −ℏ22md2ψdx2=Eψ  ⟹  d2ψdx2+k2ψ=0where k=2mEℏ-\frac{\hbar^2}{2m} \frac{d^2\psi}{dx^2} = E\psi \implies \frac{d^2\psi}{dx^2} + k^2 \psi = 0 \quad \text{where } k = \frac{\sqrt{2mE}}{\hbar} General solution: ψ(x)=Csin⁡(kx)+Dcos⁡(kx)\psi(x) = C \sin(kx) + D \cos(kx).

Applying Boundary Conditions (particle cannot penetrate infinite potential, so ψ=0\psi = 0 at boundaries):

  1. At x=0x = 0: ψ(0)=Csin⁡(0)+Dcos⁡(0)=0  ⟹  D=0\psi(0) = C \sin(0) + D \cos(0) = 0 \implies D = 0.
  2. At x=Lx = L: ψ(L)=Csin⁡(kL)=0\psi(L) = C \sin(kL) = 0. Because C≠0C \ne 0 (otherwise ψ=0\psi = 0 everywhere), sin⁡(kL)=0  ⟹  kL=nπ\sin(kL) = 0 \implies kL = n\pi, where n=1,2,3,…n = 1, 2, 3, \dots

Quantized energy values follow directly by equating kk expressions: k=nπL=2mEℏ  ⟹  n2π2L2=2mEℏ2=2mE(h/2π)2=8π2mEh2k = \frac{n\pi}{L} = \frac{\sqrt{2mE}}{\hbar} \implies \frac{n^2 \pi^2}{L^2} = \frac{2mE}{\hbar^2} = \frac{2mE}{(h/2\pi)^2} = \frac{8\pi^2 mE}{h^2}

En=n2h28mL2(n=1,2,3,… )E_n = \frac{n^2 h^2}{8 m L^2} \quad (n = 1, 2, 3, \dots)

Normalizing ∫0L∣ψn(x)∣2dx=1\int_0^L |\psi_n(x)|^2 dx = 1 yields the normalized wave functions:

ψn(x)=2Lsin⁡(nπxL)\psi_n(x) = \sqrt{\frac{2}{L}} \sin\left( \frac{n\pi x}{L} \right)

Vital Physical Deductions

  1. Quantum Number nn: nn must be a non-zero positive integer (1,2,3,…1, 2, 3, \dots). The value n=0n = 0 is physically forbidden because ψ0(x)=0\psi_0(x) = 0 everywhere, meaning no particle exists.
  2. Zero-Point Energy (ZPE): The lowest possible energy state (n=1n = 1) has non-zero energy: E1=h28mL2>0E_1 = \frac{h^2}{8 m L^2} > 0 A confined quantum particle can never be completely motionless. If E=0E = 0, linear momentum would be zero with zero uncertainty (Δp=0\Delta p = 0), forcing position uncertainty Δx→∞\Delta x \to \infty, which violates confinement in box length LL.
  3. Nodes: An interior node is a point inside the box where ψn(x)=0\psi_n(x) = 0 (excluding walls). A state with quantum number nn possesses exactly n−1n - 1 interior nodes.
  4. Energy Level Spacing: Energy increases with n2n^2, meaning energy level spacing widens as nn increases: ΔEn→n+1=En+1−En=(2n+1)h28mL2\Delta E_{n \to n+1} = E_{n+1} - E_n = (2n + 1) \frac{h^2}{8mL^2}.

5. Particle in a Three-Dimensional Box and Degeneracy

For a particle confined in a 3D rectangular box of side lengths Lx,Ly,LzL_x, L_y, L_z:

Enx,ny,nz=h28m(nx2Lx2+ny2Ly2+nz2Lz2)(nx,ny,nz=1,2,3,… )E_{n_x, n_y, n_z} = \frac{h^2}{8m} \left( \frac{n_x^2}{L_x^2} + \frac{n_y^2}{L_y^2} + \frac{n_z^2}{L_z^2} \right) \quad (n_x, n_y, n_z = 1, 2, 3, \dots)

For a cubic box where Lx=Ly=Lz=LL_x = L_y = L_z = L: E=h28mL2(nx2+ny2+nz2)E = \frac{h^2}{8 m L^2} (n_x^2 + n_y^2 + n_z^2)

Concept of Degeneracy (gg)

Degeneracy refers to multiple distinct quantum states (different sets of quantum numbers) that share the exact same energy eigenvalue.

Quantum Numbers (nx,ny,nz)(n_x, n_y, n_z)nx2+ny2+nz2n_x^2 + n_y^2 + n_z^2Energy (EE)Degeneracy (gg)Degeneracy Classification
(1,1,1)(1, 1, 1)1+1+1=31 + 1 + 1 = 33h28mL23 \frac{h^2}{8mL^2}1Non-degenerate (Ground State)
(2,1,1),(1,2,1),(1,1,2)(2, 1, 1), (1, 2, 1), (1, 1, 2)4+1+1=64 + 1 + 1 = 66h28mL26 \frac{h^2}{8mL^2}3Triply degenerate (1st Excited Level)
(2,2,1),(2,1,2),(1,2,2)(2, 2, 1), (2, 1, 2), (1, 2, 2)4+4+1=94 + 4 + 1 = 99h28mL29 \frac{h^2}{8mL^2}3Triply degenerate (2nd Excited Level)
(3,1,1),(1,3,1),(1,1,3)(3, 1, 1), (1, 3, 1), (1, 1, 3)9+1+1=119 + 1 + 1 = 1111h28mL211 \frac{h^2}{8mL^2}3Triply degenerate (3rd Excited Level)
(2,2,2)(2, 2, 2)4+4+4=124 + 4 + 4 = 1212h28mL212 \frac{h^2}{8mL^2}1Non-degenerate (4th Excited Level)
Permutations of (3,2,1)(3, 2, 1)9+4+1=149 + 4 + 1 = 1414h28mL214 \frac{h^2}{8mL^2}6Six-fold degenerate

6. The Quantum Harmonic Oscillator

The harmonic oscillator models molecular vibrations (such as bond stretching in diatomic molecules). The classical restoring force obeys Hooke's Law: F=−kforcexF = -k_{force} x, corresponding to a parabolic potential energy well:

V(x)=12kforcex2V(x) = \frac{1}{2} k_{force} x^2

Schrödinger Equation and Eigenvalues

−ℏ22μd2ψdx2+12kforcex2ψ=Eψ-\frac{\hbar^2}{2\mu} \frac{d^2\psi}{dx^2} + \frac{1}{2} k_{force} x^2 \psi = E\psi where μ\mu is the reduced mass of the vibrating diatomic system.

The allowed quantized vibrational energy levels are:

Ev=(v+12)hν=(v+12)ℏω(v=0,1,2,3,… )E_v = \left( v + \frac{1}{2} \right) h \nu = \left( v + \frac{1}{2} \right) \hbar \omega \quad (v = 0, 1, 2, 3, \dots) where vv is the vibrational quantum number, and the fundamental classical frequency is: ν=12πkforceμ\nu = \frac{1}{2\pi} \sqrt{\frac{k_{force}}{\mu}}

Fundamental Properties of the Quantum Harmonic Oscillator

  1. Zero-Point Vibrational Energy (ZPVE): In the ground vibrational state (v=0v = 0): E0=12hν=12ℏω>0E_0 = \frac{1}{2} h \nu = \frac{1}{2} \hbar \omega > 0 Molecules never cease vibrating, even at absolute zero (0 K0\text{ K}).
  2. Equidistant Energy Spacing: Unlike the particle in a box (whose spacing widens with nn), all adjacent harmonic oscillator levels are separated by the exact same constant quantum of energy: ΔE=Ev+1−Ev=hν\Delta E = E_{v+1} - E_v = h \nu
  3. Hermite Wave Functions: Wave functions are formulated as Hermite polynomials (HvH_v) modulated by a Gaussian decay envelope: ψv(x)=NvHv(α1/2x)e−αx2/2where α=μkforceℏ\psi_v(x) = N_v H_v(\alpha^{1/2} x) e^{-\alpha x^2 / 2} \quad \text{where } \alpha = \frac{\sqrt{\mu k_{force}}}{\hbar}
    • Ground state (v=0v = 0): H0=1H_0 = 1, wave function is a pure Gaussian curve centered at x=0x = 0 with zero nodes.
    • State vv possesses exactly vv nodes.
  4. Quantum Tunneling: In classical physics, an oscillating particle can never venture beyond the "classical turning points" where E=V(x)E = V(x). In quantum mechanics, the wave function decays exponentially into the classically forbidden region, yielding a finite probability of finding the particle where potential energy exceeds total energy (V(x)>EV(x) > E).

7. The Rigid Rotor and Rotational Quantization

A diatomic molecule rotating in three dimensions with fixed bond length r0r_0 and moment of inertia I=μr02I = \mu r_0^2 is modeled as a rigid rotor:

EJ=ℏ22IJ(J+1)=BJ(J+1)(J=0,1,2,… )E_J = \frac{\hbar^2}{2I} J(J + 1) = B J(J + 1) \quad (J = 0, 1, 2, \dots) where JJ is the rotational quantum number, and BB is the rotational constant: B=ℏ22I=h28π2I(in Joules)B = \frac{\hbar^2}{2I} = \frac{h^2}{8\pi^2 I} \quad \text{(in Joules)} In spectroscopic wavenumber units (cm−1\text{cm}^{-1}): B~=h8π2cI\tilde{B} = \frac{h}{8\pi^2 c I}

  • Spatial Degeneracy (gJg_J): Each rotational energy level JJ possesses a (2J+1)(2J + 1)-fold spatial degeneracy (gJ=2J+1g_J = 2J + 1), arising from the allowed magnetic projection quantum numbers MJ∈{−J,−J+1,…,+J}M_J \in \{-J, -J+1, \dots, +J\}.
  • Rotational Transition Spacings: Under electric dipole selection rules (ΔJ=±1\Delta J = \pm 1): ΔEJ→J+1=EJ+1−EJ=B(J+1)(J+2)−BJ(J+1)=2B(J+1)\Delta E_{J \to J+1} = E_{J+1} - E_J = B(J+1)(J+2) - BJ(J+1) = 2B(J+1) Adjacent absorption lines in pure rotational spectra appear at frequencies ν~=2B~,4B~,6B~,8B~,…\tilde{\nu} = 2\tilde{B}, 4\tilde{B}, 6\tilde{B}, 8\tilde{B}, \dots, separated by a constant spacing of 2B~2\tilde{B}.
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Quantum Model Energy Level Topologies
Test Your Knowledge

An electron (mass m_e = 9.109 x 10^-31 kg) is confined in a one-dimensional box of length L = 1.000 nm (1.000 x 10^-9 m). If this box models a conjugated polyene containing 4 pi-electrons that fill the lowest energy levels in pairs according to the Pauli exclusion principle, what is the energy of the highest occupied molecular orbital (HOMO) and the wavelength of the photon absorbed during the HOMO-to-LUMO electronic transition?

A

E_HOMO = 5.43 x 10^-19 J and lambda = 441 nm

B

E_HOMO = 2.41 x 10^-19 J and lambda = 659 nm

C

E_HOMO = 9.65 x 10^-19 J and lambda = 330 nm

D

E_HOMO = 6.02 x 10^-20 J and lambda = 825 nm

Test Your Knowledge

The fundamental vibrational absorption band of the diatomic molecule 1H-35Cl occurs at wavenumber nu_tilde = 2886 cm^-1 (2.886 x 10^5 m^-1). Given the atomic masses m(1H) = 1.0078 u and m(35Cl) = 34.9688 u (where 1 u = 1.66054 x 10^-27 kg), what is the effective bond force constant (k_force) and the zero-point vibrational energy (ZPVE) of the molecule?

A

k_force = 780 N/m and ZPVE = 5.74 x 10^-20 J

B

k_force = 516 N/m and ZPVE = 3.82 x 10^-20 J

C

k_force = 481 N/m and ZPVE = 2.87 x 10^-20 J

D

k_force = 245 N/m and ZPVE = 1.43 x 10^-20 J

Test Your Knowledge

Consider (i) a quantum particle confined in a three-dimensional cubic box of side length L in the energy level corresponding to n_x^2 + n_y^2 + n_z^2 = 14, and (ii) a rigid diatomic rotor in the rotational state with rotational quantum number J = 3. What are the degeneracy degrees (g) for these two quantum systems?

A

Part (i) Degeneracy g = 3, and Part (ii) Degeneracy g = 3

B

Part (i) Degeneracy g = 1, and Part (ii) Degeneracy g = 6

C

Part (i) Degeneracy g = 6, and Part (ii) Degeneracy g = 7

D

Part (i) Degeneracy g = 8, and Part (ii) Degeneracy g = 5

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