9.3 Solutions: Raoult's and Henry's Laws, Colligative Properties, and Electrolytes

Key Takeaways

  • Ideal solutions obey Raoult's Law (Pi=xiPi∗P_i = x_i P_i^*) across all compositions, characterized by zero enthalpy of mixing (ΔmixH=0\Delta_{\text{mix}} H = 0), zero volume change (ΔmixV=0\Delta_{\text{mix}} V = 0), and an entirely entropy-driven spontaneity (ΔmixG=nRT∑xiln⁡xi<0\Delta_{\text{mix}} G = nRT \sum x_i \ln x_i < 0).

  • In dilute real solutions, the solvent approaches Raoult's Law (P1=x1P1∗P_1 = x_1 P_1^*) while the volatile solute obeys Henry's Law (P2=KH,2x2P_2 = K_{H, 2} x_2), reflecting constant solvated microscopic environments.

  • Colligative properties—vapor pressure lowering (ΔP=x2P1∗\Delta P = x_2 P_1^*), boiling point elevation (ΔTb=iKbm\Delta T_b = i K_b m), freezing point depression (ΔTf=iKfm\Delta T_f = i K_f m), and osmotic pressure (Π=icRT\Pi = i c R T)—depend strictly on the number ratio of dissolved solute particles to solvent molecules, not on solute chemical identity.

  • For electrolyte solutions, the van 't Hoff factor ii accounts for ion dissociation and ion pairing, correlating with the degree of dissociation via α=i−1ν−1\alpha = \frac{i - 1}{\nu - 1}.

  • Long-range electrostatic interactions in electrolyte solutions are quantified by the ionic strength I=12∑cizi2I = \frac{1}{2}\sum c_i z_i^2 and mean activity coefficients via the Debye-Hückel Limiting Law: log⁡10γ±=−A∣z+z−∣I\log_{10} \gamma_\pm = -A |z_+ z_-| \sqrt{I} (where A=0.509A = 0.509 in water at 25°C).

Last updated: October 2026

Solutions: Raoult's and Henry's Laws, Colligative Properties, and Electrolytes

A solution is a homogeneous mixture of two or more substances down to the molecular scale. In physical chemistry and on the PRC Chemist Licensure Examination, solution theory spans ideal solutions, volatile and non-volatile solute behaviors, colligative phenomena, macromolecular characterization by osmometry, and the non-ideality of electrolyte solutions treated by Debye-Hückel theory.


1. Ideal Solutions, Raoult's Law, and Thermodynamics of Mixing

An ideal solution is defined at the molecular level as a mixture in which the intermolecular forces between unlike molecules (A−BA-B) are identical in magnitude to those between like molecules (A−AA-A and B−BB-B).

Raoult's Law

For an ideal solution in equilibrium with its vapor, the partial vapor pressure of each volatile component ii is proportional to its mole fraction in the liquid phase (xix_i):

Pi=xiPi∗P_i = x_i P_i^*

where Pi∗P_i^* is the saturation vapor pressure of pure component ii at the specified temperature.

For a binary mixture of volatile components AA and BB, the total vapor pressure is:

Ptot=PA+PB=xAPA∗+xBPB∗=xAPA∗+(1−xA)PB∗=PB∗+xA(PA∗−PB∗)P_{tot} = P_A + P_B = x_A P_A^* + x_B P_B^* = x_A P_A^* + (1 - x_A) P_B^* = P_B^* + x_A (P_A^* - P_B^*)

The mole fraction of component AA in the coexisting vapor phase (yAy_A) is given by Dalton's law:

yA=PAPtot=xAPA∗xAPA∗+xBPB∗y_A = \frac{P_A}{P_{tot}} = \frac{x_A P_A^*}{x_A P_A^* + x_B P_B^*}

If component AA is more volatile than BB (PA∗>PB∗P_A^* > P_B^*), then yA>xAy_A > x_A, meaning the vapor is enriched in the more volatile component.

Thermodynamic Functions of Mixing for Ideal Solutions

When nAn_A moles of pure AA and nBn_B moles of pure BB mix to form an ideal solution at constant TT and PP:

  1. Enthalpy of Mixing: No net bond breaking or making energetics occurs: ΔmixH=0\Delta_{mix} H = 0
  2. Volume of Mixing: Molecules pack identically to their pure states: ΔmixV=0\Delta_{mix} V = 0
  3. Entropy of Mixing: Driven entirely by configurational disorder (xi<1  ⟹  ln⁡xi<0x_i < 1 \implies \ln x_i < 0): ΔmixS=−nR∑ixiln⁡xi>0\Delta_{mix} S = -nR \sum_{i} x_i \ln x_i > 0
  4. Gibbs Free Energy of Mixing: ΔmixG=ΔmixH−TΔmixS=nRT∑ixiln⁡xi<0\Delta_{mix} G = \Delta_{mix} H - T\Delta_{mix} S = nRT \sum_{i} x_i \ln x_i < 0 Because ΔmixG<0\Delta_{mix} G < 0 for all compositions, ideal mixing is spontaneous at all temperatures.

2. Dilute Real Solutions and Henry's Law

In real solutions, A−AA-A, B−BB-B, and A−BA-B intermolecular potentials differ. However, in the limit of high dilution (where solute mole fraction x2→0x_2 \rightarrow 0 and solvent mole fraction x1→1x_1 \rightarrow 1):

  • Solvent Behavior (Raoult's Law): Every solvent molecule is surrounded virtually exclusively by other solvent molecules. Thus, the solvent behaves ideally and obeys Raoult's Law: P1=x1P1∗(as x1→1)P_1 = x_1 P_1^* \quad (\text{as } x_1 \rightarrow 1)

  • Solute Behavior (Henry's Law): Every solute molecule is completely surrounded by solvent molecules, experiencing a constant solvated environment. The partial pressure of the solute is directly proportional to its mole fraction, but governed by Henry's Law constant (KH,2K_{H, 2}): P2=KH,2x2(as x2→0)P_2 = K_{H, 2} x_2 \quad (\text{as } x_2 \rightarrow 0)

Alternatively, expressing solute concentration in molarity (cc): c=kHPc = k_H P

Because the dissolution of gases in liquids is generally an exothermic process (ΔHsoln<0\Delta H_{soln} < 0), the solubility of gases in water decreases with increasing temperature, as predicted by Le Chatelier's principle.


3. Colligative Properties of Non-Electrolyte Solutions

Colligative properties are properties of solutions that depend solely on the number of solute particles dissolved per unit volume or mass of solvent, and are independent of the chemical identity, size, or charge of the solute particles.

Thermodynamically, all colligative properties originate from a single phenomenon: the lowering of the solvent's chemical potential in solution compared to pure liquid solvent:

μ1(soln)=μ1∗(l)+RTln⁡x1<μ1∗(l)(since x1<1)\mu_1(soln) = \mu_1^*(l) + RT \ln x_1 < \mu_1^*(l) \quad (\text{since } x_1 < 1)

This stabilization of the liquid phase expands the liquid temperature range, lowering both the vapor pressure and the freezing point, while elevating the boiling point.

The Four Colligative Properties

PropertyGoverning EquationPhysical Constants & Definitions
1. Vapor Pressure LoweringΔP=P1∗−P1=x2P1∗\Delta P = P_1^* - P_1 = x_2 P_1^*ΔPP1∗=x2\frac{\Delta P}{P_1^*} = x_2 (Relative vapor pressure lowering equals solute mole fraction)
2. Boiling Point ElevationΔTb=Tb−Tb∗=Kbm\Delta T_b = T_b - T_b^* = K_b mKb=R(Tb∗)2M1ΔHvapK_b = \frac{R (T_b^*)^2 M_1}{\Delta H_{vap}} (Ebullioscopic constant; for H2OH_2O, Kb=0.512∘C⋅kg/molK_b = 0.512^\circ\text{C}\cdot\text{kg/mol})
3. Freezing Point DepressionΔTf=Tf∗−Tf=Kfm\Delta T_f = T_f^* - T_f = K_f mKf=R(Tf∗)2M1ΔHfusK_f = \frac{R (T_f^*)^2 M_1}{\Delta H_{fus}} (Cryoscopic constant; for H2OH_2O, Kf=1.86∘C⋅kg/molK_f = 1.86^\circ\text{C}\cdot\text{kg/mol})
4. Osmotic PressureΠ=cRT=(nV)RT\Pi = c R T = \left(\frac{n}{V}\right) R TΠ\Pi is hydrostatic pressure preventing solvent influx across a semipermeable membrane

Exam Application: Macromolecular Molar Mass by Osmometry For polymers and proteins (M>10000 g/molM > 10000\text{ g/mol}), freezing point depression produces temperature changes of less than 0.001∘C0.001^\circ\text{C}, which cannot be measured accurately. In contrast, osmotic pressure produces hydrostatic column heights of several centimeters, making osmometry the primary colligative method for determining macromolecular weights: M=wRTΠVM = \frac{w R T}{\Pi V} where ww is the mass of dissolved solute in grams.


4. Electrolyte Solutions and the van 't Hoff Factor (ii)

When ionic salts or ionizable acids dissolve, each formula unit dissociates into ν\nu ions, producing a greater number of colligative particles than expected from stoichiometry.

The van 't Hoff factor (ii) is defined as:

i=Actual number of particles in solutionNumber of formula units dissolved=Measured colligative propertyCalculated property for non-electrolytei = \frac{\text{Actual number of particles in solution}}{\text{Number of formula units dissolved}} = \frac{\text{Measured colligative property}}{\text{Calculated property for non-electrolyte}}

Incorporating ii into the colligative formulas: ΔTb=iKbm,ΔTf=iKfm,Π=icRT\Delta T_b = i K_b m, \quad \Delta T_f = i K_f m, \quad \Pi = i c R T

Degree of Dissociation (α\alpha)

For a weak electrolyte where each formula unit dissociates into ν\nu ions with a fractional degree of dissociation α\alpha:

Aν⇌ν ionsInitial:10Equilibrium:1−ανα\begin{matrix} & A_\nu & \rightleftharpoons & \nu \text{ ions} \\ \text{Initial:} & 1 & & 0 \\ \text{Equilibrium:} & 1 - \alpha & & \nu\alpha \end{matrix}

Total particles at equilibrium =(1−α)+να=1+α(ν−1)= (1 - \alpha) + \nu\alpha = 1 + \alpha(\nu - 1). Therefore:

i=1+α(ν−1)  ⟹  α=i−1ν−1i = 1 + \alpha(\nu - 1) \implies \alpha = \frac{i - 1}{\nu - 1}

  • Ideal vs. Real Electrolytes: For strong electrolytes like NaClNaCl (ν=2\nu = 2), ii approaches 2.002.00 at infinite dilution. However, in real solutions (0.05 M0.05\text{ M}), i≈1.90i \approx 1.90 due to electrostatic attraction and the formation of transient ion pairs ([Na+Cl−]0[Na^+ Cl^-]^0).

5. Non-Ideal Electrolytes: Ionic Strength and Debye-Hückel Theory

In electrolyte solutions, long-range Coulombic forces (V(r)∝1/rV(r) \propto 1/r) prevent ions from behaving independently even at concentrations below 0.01 M0.01\text{ M}. Peter Debye and Erich Hückel developed the ionic atmosphere model, where every central cation is statistically surrounded by a net excess of anions, and vice versa.

Ionic Strength (II)

The electrostatic field strength of an electrolyte solution depends on both ion concentrations and their charges, quantified by the ionic strength:

I=12∑icizi2[or I=12∑imizi2]I = \frac{1}{2} \sum_{i} c_i z_i^2 \quad \left[ \text{or } I = \frac{1}{2} \sum_{i} m_i z_i^2 \right]

where cic_i is molar concentration and ziz_i is ionic valence.

  • 1:11:1 Salt (NaClNaCl, cc): I=12[c(1)2+c(−1)2]=cI = \frac{1}{2} [c(1)^2 + c(-1)^2] = c
  • 2:12:1 Salt (CaCl2CaCl_2, cc): I=12[c(2)2+2c(−1)2]=12[4c+2c]=3cI = \frac{1}{2} [c(2)^2 + 2c(-1)^2] = \frac{1}{2} [4c + 2c] = 3c
  • 2:22:2 Salt (MgSO4MgSO_4, cc): I=12[c(2)2+c(−2)2]=12[4c+4c]=4cI = \frac{1}{2} [c(2)^2 + c(-2)^2] = \frac{1}{2} [4c + 4c] = 4c
  • 3:13:1 Salt (FeCl3FeCl_3, cc): I=12[c(3)2+3c(−1)2]=12[9c+3c]=6cI = \frac{1}{2} [c(3)^2 + 3c(-1)^2] = \frac{1}{2} [9c + 3c] = 6c
  • 3:23:2 Salt (Al2(SO4)3Al_2(SO_4)_3, cc): I=12[2c(3)2+3c(−2)2]=12[18c+12c]=15cI = \frac{1}{2} [2c(3)^2 + 3c(-2)^2] = \frac{1}{2} [18c + 12c] = 15c

Mean Ionic Activity and the Debye-Hückel Limiting Law (DHLL)

Because individual ion activities cannot be measured independently due to electroneutrality, we use the mean ionic activity coefficient γ±\gamma_\pm:

γ±=(γ+ν+γ−ν−)1/νwhere ν=ν++ν−\gamma_\pm = \left( \gamma_+^{\nu_+} \gamma_-^{\nu_-} \right)^{1/\nu} \quad \text{where } \nu = \nu_+ + \nu_-

For very dilute solutions (I<0.01 MI < 0.01\text{ M}), the Debye-Hückel Limiting Law states:

log⁡10γ±=−A∣z+z−∣I\log_{10} \gamma_\pm = -A |z_+ z_-| \sqrt{I}

In aqueous solution at 25.0∘C25.0^\circ\text{C} (298.15 K298.15\text{ K}), the solvent constant is A=0.509 kg1/2mol−1/2A = 0.509\text{ kg}^{1/2}\text{mol}^{-1/2} (or L1/2mol−1/2\text{L}^{1/2}\text{mol}^{-1/2}).

For higher concentrations (0.01 M<I<0.1 M0.01\text{ M} < I < 0.1\text{ M}), the Extended Debye-Hückel equation accounts for finite ion diameter (a∘a^\circ):

log⁡10γ±=−A∣z+z−∣I1+Ba∘I\log_{10} \gamma_\pm = -\frac{A |z_+ z_-| \sqrt{I}}{1 + B a^\circ \sqrt{I}}


6. Worked Examination Calculations

Problem A: Molar Mass of a Protein via Membrane Osmometry

Task: A 1.250 g1.250\text{ g} sample of a purified enzyme is dissolved in sufficient isotonic buffer to yield 100.0 mL100.0\text{ mL} of solution. At 25.0∘C25.0^\circ\text{C}, the osmotic pressure is measured as 4.350 mmHg4.350\text{ mmHg}. Determine the molar mass of the enzyme.

Solution: Π=4.350 mmHg760.0 mmHg/atm=5.7237×10−3 atm\Pi = \frac{4.350\text{ mmHg}}{760.0\text{ mmHg/atm}} = 5.7237 \times 10^{-3}\text{ atm} Using the van 't Hoff osmotic pressure equation Π=nVRT=wMVRT\Pi = \frac{n}{V} R T = \frac{w}{M V} R T: M=wRTΠV=(1.250 g)(0.082057 L⋅atm/(mol⋅K))(298.15 K)(5.7237×10−3 atm)(0.1000 L)M = \frac{w R T}{\Pi V} = \frac{(1.250\text{ g})(0.082057\text{ L}\cdot\text{atm}/(\text{mol}\cdot\text{K}))(298.15\text{ K})}{(5.7237 \times 10^{-3}\text{ atm})(0.1000\text{ L})} M=30.5825.7237×10−4=53430 g/mol=5.34×104 g/molM = \frac{30.582}{5.7237 \times 10^{-4}} = 53430\text{ g/mol} = 5.34 \times 10^4\text{ g/mol}

Comparison: What would the freezing point depression be for this same solution in water (Kf=1.86∘C⋅kg/molK_f = 1.86^\circ\text{C}\cdot\text{kg/mol})? m≈n0.100 kg=1.250/534300.100=2.34×10−4 mol/kgm \approx \frac{n}{0.100\text{ kg}} = \frac{1.250 / 53430}{0.100} = 2.34 \times 10^{-4}\text{ mol/kg} ΔTf=(1.86)(2.34×10−4)=0.000435∘C\Delta T_f = (1.86)(2.34 \times 10^{-4}) = 0.000435^\circ\text{C} A ΔTf\Delta T_f of 0.0004∘C0.0004^\circ\text{C} is indistinguishable from thermal noise on a standard lab thermometer, whereas Π=4.35 mmHg\Pi = 4.35\text{ mmHg} corresponds to a column height of 5.9 cm5.9\text{ cm} of water (h=Pρgh = \frac{P}{\rho g}), proving why osmometry is the definitive colligative tool for biochemistry.

Problem B: Degree of Dissociation of a Weak Acid

Task: A 0.0500 m0.0500\text{ m} aqueous solution of monochloroacetic acid (CH2ClCOOHCH_2ClCOOH, ν=2\nu = 2) freezes at −0.1080∘C-0.1080^\circ\text{C}. For water, Kf=1.860∘C⋅kg/molK_f = 1.860^\circ\text{C}\cdot\text{kg/mol}. Calculate the van 't Hoff factor ii and the percent dissociation α\alpha.

Solution: ΔTf=0.1080∘C\Delta T_f = 0.1080^\circ\text{C} i=ΔTfKfm=0.1080∘C(1.860∘C⋅kg/mol)(0.0500 mol/kg)=0.10800.09300=1.1613i = \frac{\Delta T_f}{K_f m} = \frac{0.1080^\circ\text{C}}{(1.860^\circ\text{C}\cdot\text{kg/mol})(0.0500\text{ mol/kg})} = \frac{0.1080}{0.09300} = 1.1613

For a monoprotic acid (CH2ClCOOH⇌H++CH2ClCOO−CH_2ClCOOH \rightleftharpoons H^+ + CH_2ClCOO^-), ν=2\nu = 2: α=i−1ν−1=1.1613−12−1=0.1613  ⟹  16.13%\alpha = \frac{i - 1}{\nu - 1} = \frac{1.1613 - 1}{2 - 1} = 0.1613 \implies 16.13\%

Problem C: Ionic Strength and Mean Activity Coefficient

Task: Calculate the ionic strength and mean ionic activity coefficient γ±\gamma_\pm of a 0.0050 M0.0050\text{ M} aqueous solution of Ca(NO3)2Ca(NO_3)_2 at 25∘C25^\circ\text{C}.

Solution: Ca(NO3)2(aq)→Ca2+(aq)+2NO3−(aq)Ca(NO_3)_2(aq) \rightarrow Ca^{2+}(aq) + 2NO_3^-(aq).

  • [Ca2+]=0.0050 M[Ca^{2+}] = 0.0050\text{ M}, z+=+2z_+ = +2
  • [NO3−]=2×0.0050=0.0100 M[NO_3^-] = 2 \times 0.0050 = 0.0100\text{ M}, z−=−1z_- = -1

I=12[(0.0050)(+2)2+(0.0100)(−1)2]=12[0.0200+0.0100]=0.0150 MI = \frac{1}{2} \left[ (0.0050)(+2)^2 + (0.0100)(-1)^2 \right] = \frac{1}{2} [ 0.0200 + 0.0100 ] = 0.0150\text{ M}

Using the Debye-Hückel Limiting Law (A=0.509A = 0.509): log⁡10γ±=−A∣z+z−∣I=−(0.509)∣(+2)(−1)∣0.0150=−(0.509)(2)(0.12247)\log_{10} \gamma_\pm = -A |z_+ z_-| \sqrt{I} = -(0.509) |(+2)(-1)| \sqrt{0.0150} = -(0.509)(2)(0.12247) log⁡10γ±=−0.12468\log_{10} \gamma_\pm = -0.12468 γ±=10−0.12468=0.7504≈0.750\gamma_\pm = 10^{-0.12468} = 0.7504 \approx 0.750

Loading diagram...
Colligative Properties and Debye-Hückel Ionic Cloud
Test Your Knowledge

Why is membrane osmometry preferred over freezing point depression or boiling point elevation for determining the molecular weights of synthetic polymers and proteins?

A

The ebullioscopic constant of water is zero for non-volatile organic polymers

B

High molecular weight polymers decompose spontaneously at the normal freezing point of water

C

Membrane osmometers require no calibration against standard reference materials

D

Molar concentrations are tiny, and only osmotic pressure gives a readily measurable effect

Test Your Knowledge

A 0.0200 m aqueous solution of a weak binary electrolyte MX (which dissociates into M+ and X-) exhibits a freezing point of -0.0446°C. Given that the cryoscopic constant of water is Kf = 1.86°C kg/mol, what is the degree of dissociation (α) of the electrolyte?

A

0.20

B

0.05

C

0.10

D

0.40

Test Your Knowledge

What is the calculated ionic strength (I) of an aqueous solution containing 0.0020 M Al2(SO4)3?

A

0.015 M

B

0.0020 M

C

0.030 M

D

0.010 M

Sections you finish are checked off in the contents.