1.8 Arithmetic & Geometric Sequences, Series & Word Patterns
Key Takeaways
- Differentiate arithmetic sequences (constant common difference d) from geometric sequences (constant common ratio r).
- Apply summation formulas for arithmetic series Sn = n/2 * (a1 + an) and geometric series Sn = a1*(1-r^n)/(1-r).
- Evaluate infinite geometric series using S_infinity = a1 / (1-r) when |r| < 1.
- Convert repeating decimals to exact rational fractions using infinite series summation rules.
Arithmetic & Geometric Sequences, Series & Word Patterns
Sequence and series problems on the ACET evaluate term calculation speed, summation formula usage, and pattern recognition.
1. Arithmetic Sequences & Series
An arithmetic sequence has a constant common difference $d = a_n - a_{n-1}$.
ACET Speed Tactic (Sum of Integers): The sum of the first $n$ positive integers is $S_n = \frac{n(n + 1)}{2}$.
2. Geometric Sequences & Series
A geometric sequence has a constant common ratio $r = \frac{a_n}{a_{n-1}}$.
3. Infinite Geometric Series & Convergent Applications
An infinite geometric series $a_1 + a_1 r + a_1 r^2 + \dots$ converges to a finite sum if and only if $|r| < 1$:
Converting Repeating Decimals to Fractions
To express $0.\overline{36} = 0.363636\dots$ as a fraction:
- First term $a_1 = 0.36 = \frac{36}{100}$.
- Common ratio $r = 0.01 = \frac{1}{100}$.
4. Special Sequences & Pattern Recognition
- Harmonic Sequence: A sequence whose reciprocals form an arithmetic sequence (e.g., $\frac{1}{2}, \frac{1}{5}, \frac{1}{8}, \frac{1}{11}$). Harmonic Mean: $H_M = \frac{2ab}{a+b}$.
- Fibonacci Sequence: Defined recursively as $F_1 = 1, F_2 = 1, F_n = F_{n-1} + F_{n-2}$. Sequence:
1, 1, 2, 3, 5, 8, 13, 21, 34, 55... - Triangular Numbers: $T_n = \frac{n(n+1)}{2}$. Sequence:
1, 3, 6, 10, 15, 21, 28...
Worked Step-by-Step ACET Exam Problems
Problem 1: Bouncing Ball Infinite Series Distance
A rubber ball is dropped from a height of 80 meters. Each time it hits the ground, it bounces back up to $3/4$ of its previous height. What is the total vertical distance traveled by the ball before coming to rest?
Step 1: Separate downward and upward distances.
- Initial drop distance: $80\text{ m}$.
- Subsequent bounces involve both an upward movement and an equal downward drop.
Step 2: Set up the geometric series for bounces.
- First bounce height $h_1 = 80 \times \frac{3}{4} = 60\text{ m}$.
- Ball travels $60\text{ m}$ up and $60\text{ m}$ down, total $120\text{ m}$.
- The bounce distance series starts with first term $a_1 = 2 \times 60 = 120\text{ m}$ and ratio $r = \frac{3}{4}$.
Step 3: Calculate the infinite sum of bounces.
Step 4: Add the initial drop height.
ACET Shortcut Formula: For drop height $H$ and bounce fraction $f = \frac{a}{b}$:
Problem 2: Arithmetic Series Sum of Multiples
Find the sum of all three-digit integers that are exactly divisible by 7.
Step 1: Identify first and last three-digit multiples of 7.
- Smallest 3-digit number is $100$. $100 \div 7 = 14.28 \implies 15 \times 7 = 105 = a_1$.
- Largest 3-digit number is $999$. $999 \div 7 = 142.71 \implies 142 \times 7 = 994 = a_n$.
Step 2: Find total number of terms $n$.
Step 3: Calculate total sum $S_{128}$.
ACET Speed Tactics & Traps Summary
| Problem Type | Common Student Trap | ACET Speed Tactic |
|---|---|---|
| Arithmetic Sum | Counting terms incorrectly ($n = \text{last} - \text{first}$) | Use $n = \frac{a_n - a_1}{d} + 1$ |
| Infinite Series | Applying $S_\infty = \frac{a_1}{1-r}$ when $ | r |
| Bouncing Ball | Forgetting that bounces travel both up and down | Use shortcut formula $H \cdot \frac{1+f}{1-f}$ |
| Repeating Decimal | Dividing repeating digits by 100 instead of 99 | $0.\overline{ab} = \frac{ab}{99}$ |
What is the sum of the first 20 terms of an arithmetic sequence whose first term is 5 and common difference is 4?
Find the sum of the infinite geometric series: 12 + 4 + 4/3 + 4/9 + ...
The 3rd term of a geometric sequence is 18 and the 6th term is 486. What is the first term of the sequence?