9.5 Learning Curves: Unit and Cumulative-Average Models, Learning Rates & Applications

Key Takeaways

  • With learning rate r, the time per unit (or cumulative average time) falls to r times its previous value each time cumulative output doubles.

  • The model is T_n = T_1 × n^b with b = ln r ÷ ln 2; for an 85% curve, b = −0.2345, and for an 80% curve, b = −0.3219.

  • The unit (Crawford) model applies the formula to the time of the n-th unit, while the cumulative-average (Wright) model applies it to the average of the first n units; problems must say which.

  • Total time for the first N units under the unit model is the sum of unit times, approximately T_1 × [(N + 0.5)^(b+1) − 0.5^(b+1)] ÷ (b + 1).

  • Time standards set during start-up should account for learning, and labor plans and cost estimates for new products should follow the expected curve rather than the steady-state standard.

Last updated: October 2026

9.5 Learning Curves

Workers and organizations get faster with repetition. T.P. Wright documented the pattern in airframe assembly in 1936: each time cumulative production doubled, labor hours per plane fell by a roughly constant percentage. The NCEES specification lists learning curves as a Work Design topic. They matter whenever a standard, a staffing plan, or a price must be set for a new product or process.


1. The Doubling Rule and the Learning Rate

If the learning rate is rr (for example 0.85, an "85% curve"):

T2n=r⋅TnT_{2n} = r \cdot T_n

  • Unit 2 takes 85% of unit 1's time, unit 4 takes 85% of unit 2's, unit 8 takes 85% of unit 4's, and so on.
  • A lower percentage means faster learning. An 80% curve improves faster than a 90% curve.
  • Typical rates are about 70% to 80% for heavily manual, complex work, and 90% to 95% for highly automated or machine-paced work, where people control little of the cycle.

2. The Mathematical Model

Tn=T1⋅n b,b=ln⁡rln⁡2=log⁡rlog⁡2T_n = T_1 \cdot n^{\,b}, \qquad b = \frac{\ln r}{\ln 2} = \frac{\log r}{\log 2}

Learning rate rrExponent bb
95%−0.0740
90%−0.1520
85%−0.2345
80%−0.3219
75%−0.4150
70%−0.5146

Two versions of the model:

  • Unit model (Crawford): TnT_n is the time for the nn-th unit. This is the more common convention in industrial engineering texts.
  • Cumulative-average model (Wright): TnT_n is the average time of the first nn units. Then total time for nn units is n⋅T1nb=T1nb+1n \cdot T_1 n^b = T_1 n^{b+1}.

The two give different numbers for the same rr. Read the problem carefully; if it says "the 8th unit," use the unit model.


3. Worked Examples (Unit Model)

First unit T1=100T_1 = 100 hours, 85% learning curve, so b=ln⁡0.85/ln⁡2=−0.2345b = \ln 0.85 / \ln 2 = -0.2345.

(a) Time for unit 8. Unit 8 is three doublings from unit 1:

T8=100×0.853=61.4 hr(or 100×8−0.2345=61.4)T_8 = 100 \times 0.85^3 = 61.4 \text{ hr} \quad \text{(or } 100 \times 8^{-0.2345} = 61.4\text{)}

(b) Time for unit 10 (not a power of 2, so use the formula):

T10=100×10−0.2345=58.3 hrT_{10} = 100 \times 10^{-0.2345} = 58.3 \text{ hr}

(c) Total hours for the first 10 units. Summing T1T_1 through T10T_{10} gives 711.6 hours. The continuous approximation is:

TotalN≈T1(N+0.5)b+1−0.5b+1b+1=100×10.50.7655−0.50.76550.7655≈713 hr\text{Total}_N \approx T_1 \frac{(N + 0.5)^{b+1} - 0.5^{b+1}}{b + 1} = 100 \times \frac{10.5^{0.7655} - 0.5^{0.7655}}{0.7655} \approx 713 \text{ hr}

which is close enough for planning.

(d) When does the time reach 40 hours? Solve 40=100×n−0.234540 = 100 \times n^{-0.2345}:

n=(0.40)1/b=0.40−4.265≈49.8n = (0.40)^{1/b} = 0.40^{-4.265} \approx 49.8

so about the 50th unit.

Finding the Learning Rate from Data

If unit 1 took 50 hours and unit 4 took 32 hours, two doublings separate them:

r2=3250=0.64⇒r=0.80r^2 = \frac{32}{50} = 0.64 \Rightarrow r = 0.80

For units that are not a power of 2 apart, use b=ln⁡(Tn/T1)/ln⁡nb = \ln(T_n/T_1)/\ln n and then r=2br = 2^b.

Unit vs. Cumulative-Average Model Compared

For T1=100T_1 = 100 hours on an 80% curve (b=−0.3219b = -0.3219):

Units built nnUnit model: time of unit nnCumulative-average model: average of first nnCumulative-average model: total for nn units
1100.0100.0100
280.080.0160
464.064.0256
851.251.2410

Under the cumulative-average model, unit 2 by itself takes 160−100=60160 - 100 = 60 hours, not 80. The same 80% rate therefore implies faster unit-level improvement under the Wright model than under the Crawford model. Mixing the two conventions in one problem is a common source of wrong answers.


4. Applications in Work Design and Operations

  1. Setting time standards. A stopwatch study during start-up captures workers who are still learning. Either wait until performance levels off, or set a temporary standard that follows the curve. A standard set too early is too loose and will be easy to beat later.
  2. Staffing and capacity planning. Early units need more labor hours, so the hours needed per week fall as cumulative output grows. Plan crews and overtime to the curve.
  3. Cost estimating and bidding. Defense and aerospace contracts often price production lots on a learning curve. The average cost of lot 2 is lower than lot 1.
  4. Make-or-buy and outsourcing. A supplier far down its curve may beat a new in-house line on cost.
  5. Incentive and training programs. Compare a trainee's actual times with the expected curve to spot those who need help.

Plateaus and limits. Learning slows when the process is machine paced, when operators are replaced (turnover resets part of the learning), or after long interruptions ("forgetting"). Many organizations treat the curve as leveling off at the engineered standard.

Warning

Common exam errors:

  • Using b=ln⁡rb = \ln r instead of ln⁡r/ln⁡2\ln r / \ln 2.
  • Applying the cumulative-average model when the unit model is intended.
  • Treating a 90% curve as faster learning than an 80% curve.
  • Assuming every unit falls by 15% on an 85% curve. The 15% reduction happens per doubling, not per unit.
Test Your Knowledge

The first unit of a new assembly takes 80 hours, and the process follows a 90% learning curve (unit model). How long should the 16th unit take?

A

52.5 hours

B

57.6 hours

C

64.8 hours

D

18.5 hours

Test Your Knowledge

Time-study records show the first unit of a cable harness took 50 minutes and the fourth unit took 32 minutes. What learning rate do these data imply?

A

64%

B

72%

C

80%

D

84%

Test Your Knowledge

A manager says, "We are on an 85% learning curve, so each unit takes 15% less time than the one before it." What is wrong with this statement?

A

An 85% curve means each unit takes 85% less time than the first unit

B

Learning curves apply only to machine-paced work

C

The 15% reduction applies to the cumulative cost, not to labor time

D

The 15% drop occurs per doubling of output, not per additional unit

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