9.2 Graphs of Sine and Cosine & Sinusoidal Modeling

Key Takeaways

  • The parent functions y = sin(x) and y = cos(x) have domain (-∞, ∞), range [-1, 1], and a fundamental period of 2π radians, differing only by a horizontal shift of π/2 radians.
  • In the general sinusoidal equation y = A·sin(B(x - C)) + D or y = A·cos(B(x - C)) + D, the amplitude is |A| = (max - min)/2, and the horizontal midline is y = D = (max + min)/2.
  • The frequency coefficient B determines the period via P = 2π / |B|, and conversely B = 2π / P, representing the angular frequency in radians per unit time.
  • The phase shift C indicates horizontal translation; unshifted cosine curves begin at an extreme value (crest or trough) at x = 0, whereas unshifted sine curves begin at the midline.
  • Periodic real-world phenomena—including tides, temperatures, ferris wheels, and ecological cycles—are modeled by calculating midline D, amplitude |A|, period P, frequency B, and aligning the phase shift C with initial conditions.
Last updated: September 2026

9.2 Graphs of Sine and Cosine & Sinusoidal Modeling

Quick Answer: Transformed sinusoidal functions follow $y = A\sin(B(x - C)) + D$ or $y = A\cos(B(x - C)) + D$. The amplitude is $|A| = \frac{\text{max} - \text{min}}{2}$, the midline is $y = D = \frac{\text{max} + \text{min}}{2}$, the period is $P = \frac{2\pi}{|B|}$ (so $B = \frac{2\pi}{P}$), and the phase shift is $C$. Modeling cyclic real-world scenarios requires identifying maximum and minimum values, calculating $A, D,$ and $B$, and selecting cosine if the cycle begins at a peak/trough or sine if it begins at the midline.


1. Parent Graphs of Sine and Cosine (F-IF.7e)

The graphs of the parent trigonometric functions $f(x) = \sin(x)$ and $g(x) = \cos(x)$ are continuous, smooth, undulating waves called sinusoids. Their wave shape reflects the cyclical variation of $y$ and $x$ coordinates as a point rotates around the unit circle.

   y ^
   1 +       * (π/2, 1)                  * (5π/2, 1)
     |      / \                         / \
   0 +----*----+----*---------*-------*----+----*---> x
     |  (0,0)   \  (π,0)     /     (2π,0)   \  (3π,0)
  -1 +           * (3π/2, -1)                * (7π/2, -1)
       Graph of y = sin(x): Zeros at integer multiples of π; Peak at π/2; Trough at 3π/2

The Five-Point Method for One Full Cycle ($[0, 2\pi]$)

Graphing one complete period of a sinusoid requires plotting five critical points: the start point, quarter-cycle, half-cycle, three-quarter cycle, and end point.

Cycle FractionAngle ($x$)$y = \sin(x)$ Landmark$y = \sin(x)$ Point$y = \cos(x)$ Landmark$y = \cos(x)$ Point
$0$$0$Midline (rising)$(0, 0)$Maximum (crest)$(0, 1)$
$\frac{1}{4}$$\frac{\pi}{2}$Maximum (crest)$\left(\frac{\pi}{2}, 1\right)$Midline (falling)$\left(\frac{\pi}{2}, 0\right)$
$\frac{1}{2}$$\pi$Midline (falling)$(\pi, 0)$Minimum (trough)$(\pi, -1)$
$\frac{3}{4}$$\frac{3\pi}{2}$Minimum (trough)$\left(\frac{3\pi}{2}, -1\right)$Midline (rising)$\left(\frac{3\pi}{2}, 0\right)$
$1$$2\pi$Midline (completion)$(2\pi, 0)$Maximum (completion)$(2\pi, 1)$

Fundamental Properties Comparison

PropertyParent Sine: $y = \sin(x)$Parent Cosine: $y = \cos(x)$
Domain$(-\infty, \infty)$$(-\infty, \infty)$
Range$[-1, 1]$$[-1, 1]$
Amplitude$1$$1$
Midline$y = 0$ ($x$-axis)$y = 0$ ($x$-axis)
Fundamental Period$2\pi$ radians ($360^\circ$)$2\pi$ radians ($360^\circ$)
SymmetryOdd function: $\sin(-x) = -\sin(x)$ (origin symmetry)Even function: $\cos(-x) = \cos(x)$ ($y$-axis symmetry)
Phase RelationshipLags cosine by $\frac{\pi}{2}$: $\sin(x) = \cos\left(x - \frac{\pi}{2}\right)$Leads sine by $\frac{\pi}{2}$: $\cos(x) = \sin\left(x + \frac{\pi}{2}\right)$

2. The General Transformed Sinusoidal Equation (F-TF.5)

Every periodic wave in Algebra II can be represented by the transformed sinusoidal function:

y=Asin(B(xC))+Dory=Acos(B(xC))+Dy = A\sin(B(x - C)) + D \quad \text{or} \quad y = A\cos(B(x - C)) + D

Each parameter controls a specific geometric transformation of the parent curve:

1. Amplitude ($|A|$): Vertical Stretch / Reflection

  • The amplitude measures the vertical distance from the horizontal midline to the maximum peak (or to the minimum trough): Amplitude=A=Maximum ValueMinimum Value2\text{Amplitude} = |A| = \frac{\text{Maximum Value} - \text{Minimum Value}}{2}
  • Range: The range of the function is $[D - |A|, D + |A|]$.
  • Sign of $A$: Amplitude is strictly a non-negative distance ($|A| > 0$). If $A < 0$, the wave is vertically reflected across the midline $y = D$.

2. Midline ($y = D$): Vertical Shift

  • The midline is the horizontal line running halfway between the maximum and minimum values: Midline: y=D=Maximum Value+Minimum Value2\text{Midline: } y = D = \frac{\text{Maximum Value} + \text{Minimum Value}}{2}
  • It represents the equilibrium or baseline state in physical modeling.

3. Frequency Parameter ($B$) & Period ($P$): Horizontal Stretch / Compression

  • The period ($P$) is the horizontal distance required for the function to complete one full cycle: P=2πBP = \frac{2\pi}{|B|}
  • Conversely, when given the period $P$ from data or a graph, the frequency coefficient $B$ is found using: B=2πPB = \frac{2\pi}{P}
  • Frequency ($f$): The number of complete cycles executed per unit of $x$: $f = \frac{1}{P} = \frac{|B|}{2\pi}$.

4. Phase Shift ($C$): Horizontal Translation

  • The parameter $C$ represents the horizontal shift of the wave.
  • In the standard factored form $B(x - C)$, a value of $C > 0$ shifts the wave right by $C$ units, while $C < 0$ (written as $(x + |C|)$) shifts the wave left by $|C|$ units.

[!CAUTION] The Unfactored Phase Shift Trap: When an equation is written in the unfactored form $y = A\cos(Bx - k) + D$, the horizontal shift is not $k$. You must factor out $B$: $B\left(x - \frac{k}{B}\right)$. Thus, the true phase shift is $C = \frac{k}{B}$.


3. Selecting Sine vs. Cosine for Periodic Real-World Scenarios

Because sine and cosine are horizontal translations of each other, any periodic sinusoid can be written using either function. However, strategic selection simplifies model construction based on the initial condition at $t = 0$:

Behavior at $t = 0$ (Initial State)Optimal Function SelectionSign of $A$Phase Shift ($C$)
Starts at Maximum (Crest)Cosine: $y = A\cos(Bt) + D$$A > 0$$C = 0$
Starts at Minimum (Trough)Cosine: $y = A\cos(Bt) + D$$A < 0$ (or $-A
Starts at Midline & risesSine: $y = A\sin(Bt) + D$$A > 0$$C = 0$
Starts at Midline & fallsSine: $y = A\sin(Bt) + D$$A < 0$ (or $-A
Starts at an intermediate pointCosine with shift to peak$A > 0$$C = t_{\text{peak}}$

4. Step-by-Step Protocol for Constructing Sinusoidal Models

When given a table of values, a graph, or a contextual description of a cyclic process:

+--------------------------------------------------------------------------------+
|                      Sinusoidal Modeling Workflow                              |
+--------------------------------------------------------------------------------+
| 1. Identify Extrema    --> Determine Maximum and Minimum values.               |
| 2. Calculate Midline   --> D = (Max + Min) / 2.                                |
| 3. Calculate Amplitude --> |A| = (Max - Min) / 2.                              |
| 4. Determine Period    --> P = Time for 1 full cycle (or 2 × time from min to max)|
| 5. Solve for B         --> B = 2\pi / P.                                         |
| 6. Choose Sine/Cosine  --> Align start condition at t = 0 to establish C and sign.|
+--------------------------------------------------------------------------------+

5. Worked Examples

Worked Problem 1: Ferris Wheel Height Over Time

Problem: A passenger boards a ferris wheel from a platform $6 \text{ feet}$ above the ground. The ferris wheel has a radius of $40 \text{ feet}$ and rotates continuously, completing one full revolution every $80 \text{ seconds}$. Construct a sinusoidal function $h(t)$ modeling the passenger's height in feet above the ground as a function of time $t$ in seconds after boarding.

  • Step 1: Identify maximum and minimum heights.

    • Minimum height (boarding platform): $\text{Min} = 6 \text{ ft}$.
    • Maximum height: $\text{Max} = \text{Min} + 2(\text{radius}) = 6 + 2(40) = 86 \text{ ft}$.
  • Step 2: Calculate the vertical midline $D$. D=Max+Min2=86+62=922=46 ftD = \frac{\text{Max} + \text{Min}}{2} = \frac{86 + 6}{2} = \frac{92}{2} = 46 \text{ ft}

  • Step 3: Calculate the amplitude $|A|$. A=MaxMin2=8662=802=40 ft|A| = \frac{\text{Max} - \text{Min}}{2} = \frac{86 - 6}{2} = \frac{80}{2} = 40 \text{ ft} (Note: For a circular wheel, amplitude always equals the wheel's radius).

  • Step 4: Calculate the period $P$ and frequency parameter $B$. The wheel completes one revolution in $80 \text{ seconds}$, so $P = 80$. B=2πP=2π80=π40B = \frac{2\pi}{P} = \frac{2\pi}{80} = \frac{\pi}{40}

  • Step 5: Determine function type and sign based on $t = 0$. At time $t = 0$, the passenger is at the minimum height ($6 \text{ ft}$). An unshifted inverted cosine function ($-\cos$) begins at the minimum value: h(t)=40cos(π40t)+46h(t) = -40\cos\left(\frac{\pi}{40}t\right) + 46

Worked Problem 2: Tidal Water Depth Prediction

Problem: The water depth in a coastal harbor oscillates sinusoidally with the tide. On a particular day, high tide occurs at 2:00 AM with a depth of $18 \text{ feet}$, and low tide occurs $6.2 \text{ hours}$ later at 8:12 AM with a depth of $6 \text{ feet}$. Let $t$ represent elapsed hours since midnight ($t = 0$ at 12:00 AM).

  1. Write a sinusoidal equation $D(t)$ modeling the water depth.
  2. Determine the predicted water depth at 11:00 AM ($t = 11$).
  • Step 1: Calculate amplitude and midline.

    • $\text{Max} = 18 \text{ ft}$, $\text{Min} = 6 \text{ ft}$.
    • Midline: $D = \frac{18 + 6}{2} = 12 \text{ ft}$.
    • Amplitude: $A = \frac{18 - 6}{2} = 6 \text{ ft}$.
  • Step 2: Determine period and frequency parameter $B$. The time from a maximum to the consecutive minimum represents half a period: 12P=6.2    P=12.4 hours\frac{1}{2}P = 6.2 \implies P = 12.4 \text{ hours} B=2π12.4=2π625=10π62=5π31B = \frac{2\pi}{12.4} = \frac{2\pi}{\frac{62}{5}} = \frac{10\pi}{62} = \frac{5\pi}{31}

  • Step 3: Identify the phase shift $C$. High tide occurs at 2:00 AM, so a crest occurs at $t = 2$. Using a positive cosine model, shift right by $C = 2$: D(t)=6cos(5π31(t2))+12D(t) = 6\cos\left(\frac{5\pi}{31}(t - 2)\right) + 12

  • Step 4: Evaluate depth at 11:00 AM ($t = 11$). D(11)=6cos(5π31(112))+12=6cos(45π31)+12D(11) = 6\cos\left(\frac{5\pi}{31}(11 - 2)\right) + 12 = 6\cos\left(\frac{45\pi}{31}\right) + 12 Using a calculator in Radian mode: cos(45π31)0.1514\cos\left(\frac{45\pi}{31}\right) \approx -0.1514 D(11)=6(0.1514)+12=0.908+1211.09 feetD(11) = 6(-0.1514) + 12 = -0.908 + 12 \approx 11.09 \text{ feet}

Worked Problem 3: Analyzing an Algebraic Sinusoidal Function

Problem: Given the function $f(x) = -5\cos\left(\frac{\pi}{6}(x - 2)\right) + 11$, state the amplitude, midline, period, range, and horizontal phase shift.

  • Step 1: Amplitude ($|A|$). A=5=5|A| = |-5| = 5

  • Step 2: Midline ($y = D$). y=11y = 11

  • Step 3: Period ($P$). P=2πB=2ππ6=2π×6π=12P = \frac{2\pi}{|B|} = \frac{2\pi}{\frac{\pi}{6}} = 2\pi \times \frac{6}{\pi} = 12

  • Step 4: Range. Min=DA=115=6andMax=D+A=11+5=16\text{Min} = D - |A| = 11 - 5 = 6 \quad \text{and} \quad \text{Max} = D + |A| = 11 + 5 = 16 Range: [6,16]\text{Range: } [6, 16]

  • Step 5: Phase shift ($C$). The factor inside is $(x - 2)$, corresponding to a phase shift of $2$ units to the right.


6. Common Regents Pitfalls & Exam Strategies

  • Pitfall 1: Reporting negative amplitude. Amplitude is defined as a distance, meaning it must always be expressed as a positive number. If $A = -5$, the amplitude is $5$, not $-5$.
  • Pitfall 2: Equating frequency parameter $B$ directly to period. Writing $P = B$ or $P = \frac{\pi}{6}$ is a common rubric violation. Remember: $P = \frac{2\pi}{B}$ and $B = \frac{2\pi}{P}$.
  • Pitfall 3: Failing to double the half-period. When given the time from minimum to maximum, students often mistake this for the full period. The time from low to high is only half of the complete wave cycle ($P = 2 \times \Delta t$).
Test Your Knowledge

What are the amplitude, period, and range of the sinusoidal function y = -5·cos((π / 6)(x - 2)) + 11?

A
B
C
D
Test Your Knowledge

A ferris wheel with a radius of 40 feet rotates at a constant speed, completing one full revolution every 80 seconds. Passengers board at the bottom of the wheel from a platform 6 feet above the ground. If t represents elapsed seconds since boarding, which equation correctly models the passenger's height h(t) in feet?

A
B
C
D
Test Your Knowledge

The water depth in a tidal harbor oscillates between a high tide of 18 feet and a low tide of 6 feet. High tide occurs at t = 0 hours and low tide occurs 6 hours later at t = 6 hours. Based on a sinusoidal model, what is the depth of the water at t = 4 hours?

A
B
C
D