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6.4 Comparing and Combining Functions Across Representations

Key Takeaways

  • Standard AII-F.IF.9 asks students to compare properties of two functions presented in different ways - algebraically, graphically, numerically in a table, or by a verbal description - and NYSED extends the families to include square root and cube root functions alongside polynomial, exponential, logarithmic, and trigonometric ones.

  • The reliable protocol is to name the property, extract that one property from each representation using the method appropriate to that representation, and only then compare; never convert every representation into an equation first.

  • A table of equally spaced inputs identifies its family through differences and ratios: constant first differences signal linear, constant second differences signal quadratic, and a constant ratio signals exponential.

  • Standard AII-F.BF.1b requires combining standard function types using arithmetic operations, so a profit model is a revenue function minus a cost function and inherits the domain restrictions of both.

  • When two functions are compared over an interval rather than at a point, the fair comparison statistic is the average rate of change [f(b) - f(a)]/(b - a) evaluated on the same interval for both.

Last updated: September 2026

6.4 Comparing and Combining Functions Across Representations

Note

Regents Standard Alignment: AII-F.IF.9 - compare properties of two functions each represented in a different way (algebraically, graphically, numerically in tables, or by verbal descriptions). NYSED's Algebra II note widens the families: "Tasks also involve square root and cube root functions, in addition to polynomial, exponential, logarithmic and trigonometric functions." AII-F.BF.1b - combine standard function types using arithmetic operations.

Every F-IF.9 item has the same shape. You are handed two functions in two different formats and asked which one has the greater something. The format asymmetry is the difficulty; the underlying comparison is usually easy once each property is extracted.


1. The Extraction Table

Do not convert everything into an equation. Pull the one property you need directly from whatever form you were given.

PropertyFrom an EquationFrom a GraphFrom a TableFrom a Verbal Description
yy-interceptEvaluate f(0)f(0)Read where the curve crosses the vertical axisRead the row where x=0x = 0The stated "initial", "starting", or "at time zero" value
ZerosSolve f(x)=0f(x) = 0Read the horizontal-axis crossingsFind rows where the output is 00 or where the sign changesStated "breaks even", "hits the ground", "runs out"
Maximum or minimumVertex x=−b2ax = -\frac{b}{2a} for a quadratic; otherwise 2nd TRACE -> max/minRead the peak or valleyFind the largest or smallest listed output, checking symmetry around itStated "peaks at", "the most it ever reaches"
Average rate of change on [a,b][a,b]f(b)−f(a)b−a\dfrac{f(b) - f(a)}{b - a}Slope of the segment joining the two pointsSame quotient using two table rowsStated "increases by ... per ..."
End behaviorLeading term for polynomials; base for exponentialsFollow the armsExtend the trend of the last rows with cautionStated "levels off", "grows without bound"
Period / amplitude / midlineP=2π∣B∣P = \frac{2\pi}{\vert B\vert}, ∣A∣\vert A\vert, y=Dy = DCrest-to-crest distance; half the crest-to-trough height; the average of the extremesDistance between repeated outputs; half the rangeStated "every 12 hours", "swings between"

Fingerprinting a Table

For equally spaced inputs:

  • Constant first differences ⇒\Rightarrow linear.
  • Constant second differences ⇒\Rightarrow quadratic.
  • Constant ratio between consecutive outputs ⇒\Rightarrow exponential.
  • Neither pattern, but a curve that flattens as xx grows and is defined only for x≥x \geq some value ⇒\Rightarrow suspect a square root; defined everywhere with an inflection ⇒\Rightarrow suspect a cube root.

2. Worked Comparison 1: Equation Versus Table

Problem: Function ff is defined by f(x)=2x2−8x+3f(x) = 2x^2 - 8x + 3. Function gg is given by the table below. Which function has the greater minimum value, and by how much?

xx01234
g(x)g(x)60−2-206
  • Confirm the family of gg. First differences: −6,−2,2,6-6, -2, 2, 6. Second differences: 4,4,44, 4, 4. Constant second differences confirm a quadratic.
  • Minimum of gg. The table is symmetric about x=2x = 2, where the output −2-2 is the smallest listed value and the outputs rise identically on both sides. The minimum value of gg is −2-2.
  • Minimum of ff. For a quadratic in standard form the vertex sits at x=−b2a=−−82(2)=2x = -\dfrac{b}{2a} = -\dfrac{-8}{2(2)} = 2. Then f(2)=2(4)−8(2)+3=8−16+3=−5f(2) = 2(4) - 8(2) + 3 = 8 - 16 + 3 = -5. Because a=2>0a = 2 > 0, this is a minimum.
  • Compare. −2>−5-2 > -5, so gg has the greater minimum, by 3 units.

Warning

Both functions bottom out at x=2x = 2, which makes it tempting to say they are "the same." The question asks about the minimum value - an output - not its location. Confusing the two is the classic F-IF.9 deduction.


3. Worked Comparison 2: Verbal Versus Graph, Using Average Rate of Change

Problem: A biologist describes colony AA verbally: it starts at 40 cells and triples every hour. Colony BB is shown on a graph that passes through (0,400)(0, 400), (1,600)(1, 600), (2,800)(2, 800), and (3,1000)(3, 1000). Over the interval from t=0t = 0 to t=3t = 3 hours, which colony has the greater average rate of change?

  • Model AA from the description. Tripling per hour is exponential: A(t)=40(3)tA(t) = 40(3)^t. Then A(0)=40A(0) = 40 and A(3)=40(27)=1080A(3) = 40(27) = 1080. AROCA=1080−403−0=10403≈346.7 cells per hour\text{AROC}_A = \frac{1080 - 40}{3 - 0} = \frac{1040}{3} \approx 346.7 \text{ cells per hour}
  • Read BB from the graph. The listed points rise by a constant 200 per hour, so BB is linear with B(0)=400B(0) = 400 and B(3)=1000B(3) = 1000. AROCB=1000−4003−0=6003=200 cells per hour\text{AROC}_B = \frac{1000 - 400}{3 - 0} = \frac{600}{3} = 200 \text{ cells per hour}
  • Compare. 346.7>200346.7 > 200, so colony AA has the greater average rate of change over [0,3][0, 3].
  • Interpret honestly. Colony BB is far larger for the first two hours - A(1)=120A(1) = 120 against B(1)=600B(1) = 600 - and only overtakes BB between t=2t = 2 (A=360A = 360, B=800B = 800) and t=3t = 3 (A=1080A = 1080, B=1000B = 1000). "Greater average rate of change on an interval" is not the same claim as "larger throughout."

4. Combining Functions with Arithmetic Operations (AII-F.BF.1b)

Standard AII-F.BF.1b asks you to build a new function from two standard types using ++, −-, ×\times, or ÷\div. The workhorse example in context is profit.

P(x)=R(x)−C(x)P(x) = R(x) - C(x)

Worked Combination

Problem: A small manufacturer's weekly revenue in dollars from selling xx units is R(x)=120x−2x2R(x) = 120x - 2x^2, and weekly cost is C(x)=300+20xC(x) = 300 + 20x. Write the profit function, determine the profit at 10 units, and find the production level that maximizes profit.

  • Combine. P(x)=(120x−2x2)−(300+20x)=−2x2+100x−300P(x) = (120x - 2x^2) - (300 + 20x) = -2x^2 + 100x - 300 Distribute the subtraction across both terms of C(x)C(x) - dropping the sign on +20x+20x is the single most common error here.
  • Evaluate at 10 units. P(10)=−2(100)+100(10)−300=−200+1000−300=500P(10) = -2(100) + 100(10) - 300 = -200 + 1000 - 300 = 500 Weekly profit at 10 units is $500\text{\textdollar}500.
  • Maximize. The profit function is a downward-opening parabola, so its maximum is at the vertex: x=−b2a=−1002(−2)=25 unitsx = -\frac{b}{2a} = -\frac{100}{2(-2)} = 25 \text{ units} P(25)=−2(625)+100(25)−300=−1250+2500−300=950P(25) = -2(625) + 100(25) - 300 = -1250 + 2500 - 300 = 950 Maximum weekly profit is $950\text{\textdollar}950 at 25 units.

Rules a Combined Function Inherits

OperationResulting DomainWatch For
(f+g)(x)(f + g)(x), (f−g)(x)(f - g)(x), (f⋅g)(x)(f \cdot g)(x)The intersection of the domains of ff and ggA radical or logarithmic piece narrows the whole combined domain
(fg)(x)\left(\dfrac{f}{g}\right)(x)The intersection, minus every xx with g(x)=0g(x) = 0Zeros of the denominator function are excluded even if ff is fine there

For example, if f(x)=x−1f(x) = \sqrt{x - 1} and g(x)=x−4g(x) = x - 4, then (f+g)(x)=x−1+x−4(f + g)(x) = \sqrt{x - 1} + x - 4 has domain [1,∞)[1, \infty), while (fg)(x)\left(\frac{f}{g}\right)(x) has domain [1,4)∪(4,∞)[1, 4) \cup (4, \infty).

Test Your Knowledge

Function p is defined by p(x) = 3x² - 12x + 4. Function q is given by the table with q(0) = 7, q(1) = 4, q(2) = 3, q(3) = 4, and q(4) = 7. Which statement correctly compares the minimum values of the two functions?

A

Both functions have a minimum value of 2, because both are minimized at x = 2

B

The minimum value of q is 3, which is greater than the minimum value of p, which is -8

C

The minimum value of p is 4, which is greater than the minimum value of q, which is 3

D

Neither function has a minimum value, because both are quadratic functions with unbounded range

Test Your Knowledge

Colony A starts with 40 cells and triples every hour. Colony B is graphed through the points (0, 400), (1, 600), (2, 800), and (3, 1000). Which statement about the interval from t = 0 to t = 3 hours is correct?

A

Colony B has the greater average rate of change, because its graph passes above colony A at every time in the interval

B

The two colonies have equal average rates of change, because both start and end the interval at different values

C

Colony A has the greater average rate of change, approximately 346.7 cells per hour compared with 200 cells per hour for colony B

D

Average rate of change cannot be compared, because colony A is exponential and colony B is linear

Test Your Knowledge

A shop has revenue R(x) = 120x - 2x² dollars and cost C(x) = 300 + 20x dollars for x units sold per week. Which expression gives the weekly profit, and what is the profit at 10 units?

A

P(x) = -2x² + 140x + 300, with a profit of $1,500 at 10 units

B

P(x) = -2x² + 100x + 300, with a profit of $1,100 at 10 units

C

P(x) = 2x² - 100x + 300, with a profit of $-500 at 10 units

D

P(x) = -2x² + 100x - 300, with a profit of $500 at 10 units

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