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10.1 The Normal Distribution, Empirical Rule, and Z-Scores

Key Takeaways

  • The normal distribution is a continuous, unimodal, symmetric bell-shaped distribution where the mean, median, and mode are all identical at the center (x = μ).

  • The Empirical Rule (68-95-99.7% rule) dictates that approximately 68.2% of values lie within μ ± 1σ, 95.4% within μ ± 2σ, and 99.7% within μ ± 3σ, with inflection points located at μ ± 1σ.

  • The standard score formula z = (x - μ) / σ expresses an observation's directed distance from the mean in standard deviation units; it is NOT printed on the Next Generation reference sheet and must be memorized.

  • Cumulative normal probabilities are computed using graphing calculator command normalcdf(lower, upper, μ, σ), using ±1E99 for extreme bounds.

  • Percentiles and cutoff scores are determined using invNorm(area, μ, σ), where the input area must always represent the cumulative area from the far left tail.

Last updated: September 2026

10.1 The Normal Distribution, Empirical Rule, and Z-Scores

Quick Answer: The normal distribution is a symmetric, unimodal, bell-shaped continuous probability distribution where mean=median=mode\text{mean} = \text{median} = \text{mode} at the center μ\mu. The total area under the density curve equals 11 (100%100\%). The Empirical Rule dictates that approximately 68.2%68.2\% of values fall within μ±1σ\mu \pm 1\sigma, 95.4%95.4\% within μ±2σ\mu \pm 2\sigma, and 99.7%99.7\% within μ±3σ\mu \pm 3\sigma. The zz-score formula z=x−μσz = \frac{x - \mu}{\sigma} standardizes raw scores into directed standard deviation units; memorize it, because it is not printed on the reference sheet. On graphing calculators, use normalcdf(lower,upper,μ,σ)\text{normalcdf}(\text{lower}, \text{upper}, \mu, \sigma) to calculate cumulative probabilities and invNorm(area,μ,σ)\text{invNorm}(\text{area}, \mu, \sigma) to calculate cutoff scores from left-tail percentiles.


1. Characteristics and Geometry of Normal Distributions (AII-S.ID.4a, AII-S.ID.4b)

Note

Standard note. NYSED split S-ID.4 into two assessed components for Algebra II: AII-S.ID.4a - recognize whether or not a normal curve is appropriate for a given data set - and AII-S.ID.4b - if appropriate, determine population percentages using a graphing calculator for an appropriate normal curve. Section 10.4 covers the 4a judgment call; this section covers the 4b machinery.

In statistics, quantitative data can follow many different distributions. Among continuous probability distributions, the normal distribution (often called the Gaussian distribution or bell curve) is the most fundamental model in Algebra II and inferential statistics.

A normal distribution is completely determined by two parameters:

  1. Population Mean (μ\mu): The center of the distribution, locating the line of symmetry.
  2. Population Standard Deviation (σ\sigma): The measure of spread, determining the dispersion and height of the curve.

Essential Geometric Properties

  • Unimodal and Symmetric: The curve exhibits a single central peak and is perfectly symmetric about the vertical line x=μx = \mu. If the curve is folded along x=μx = \mu, the two halves coincide.
  • Central Equivalence: Because of perfect symmetry, the mean, median, and mode are all identical and located at the exact center: μ=median=mode\mu = \text{median} = \text{mode}.
  • Total Area Under the Curve: The total area bounded between the normal curve and the horizontal axis equals exactly 11 (representing 100%100\% of the population).
  • Asymptotic Tails: As xx moves away from the mean in either direction (x→∞x \to \infty or x→−∞x \to -\infty), the tails approach the horizontal axis asymptotically, getting closer to 00 without ever touching or crossing it.
  • Inflection Points at μ±σ\mu \pm \sigma: The curve transitions from concave down (near the peak) to concave up (in the tails) at points of inflection located at exactly one standard deviation from the mean: x=μ−σx = \mu - \sigma and x=μ+σx = \mu + \sigma.

2. The Empirical Rule (68-95-99.7% Rule)

When a dataset is approximately normally distributed, the Empirical Rule provides precise percentage approximations for data falling within integer multiples of the standard deviation from the mean.

                           Mean
                            μ
                            |
                     34.1%  |  34.1%
                   +--------+--------+
            13.6%  |                 |  13.6%
          +--------+                 +--------+
   2.15%  |                                   |  2.15%
  +-------+                                   +-------+
  | 0.15% |                                   | 0.15% |
--+-------+--------+--------+--------+--------+-------+-->
 μ-3σ    μ-2σ     μ-1σ      μ       μ+1σ     μ+2σ    μ+3σ

Detailed Interval Breakdown

Because the normal distribution is symmetric about μ\mu, each symmetric interval can be partitioned into constituent sub-regions:

IntervalBoundary NotationStandard Deviation RangePercentage of Data
Central 1 SD[μ−1σ,μ+1σ][\mu - 1\sigma, \mu + 1\sigma]−1≤z≤+1-1 \le z \le +1≈68.2%\approx 68.2\% (34.1%34.1\% each side)
Central 2 SD[μ−2σ,μ+2σ][\mu - 2\sigma, \mu + 2\sigma]−2≤z≤+2-2 \le z \le +2≈95.4%\approx 95.4\% (47.7%47.7\% each side)
Central 3 SD[μ−3σ,μ+3σ][\mu - 3\sigma, \mu + 3\sigma]−3≤z≤+3-3 \le z \le +3≈99.7%\approx 99.7\% (49.85%49.85\% each side)
Second SD Slice[μ+1σ,μ+2σ][\mu + 1\sigma, \mu + 2\sigma] or [μ−2σ,μ−1σ][\mu - 2\sigma, \mu - 1\sigma]1<z≤21 < z \le 2 or −2≤z<−1-2 \le z < -1≈13.6%\approx 13.6\%
Third SD Slice[μ+2σ,μ+3σ][\mu + 2\sigma, \mu + 3\sigma] or [μ−3σ,μ−2σ][\mu - 3\sigma, \mu - 2\sigma]2<z≤32 < z \le 3 or −3≤z<−2-3 \le z < -2≈2.15%\approx 2.15\%
Extreme TailsAbove μ+3σ\mu + 3\sigma or Below μ−3σ\mu - 3\sigmaz>3z > 3 or z<−3z < -3≈0.15%\approx 0.15\% (0.3%0.3\% combined)

Note

Summing Percentages on Regents Problems: To find the percentage between asymmetric boundaries such as μ−2σ\mu - 2\sigma and μ+1σ\mu + 1\sigma, sum the specific partitions: Area=13.6%+34.1%+34.1%=81.8%\text{Area} = 13.6\% + 34.1\% + 34.1\% = 81.8\%


3. Standardization and the Z-Score Formula

When comparing values from different distributions or evaluating values not located at integer standard deviations, data must be standardized.

The Formula

Caution

This formula is not on the reference sheet. The Next Generation Algebra II reference sheet prints the quadratic formula, trigonometric identities, cubic factorizations, probability rules, sequence and series formulas, and exponential growth/decay models - and nothing statistical. The zz-score formula and the Empirical Rule percentages must both be memorized.

z=x−μσz = \frac{x - \mu}{\sigma}

Where:

  • xx is the raw data value.
  • μ\mu is the population mean.
  • σ\sigma is the population standard deviation (σ>0\sigma > 0).
  • zz is the standard score (zz-score).

Mathematical Interpretation of the Z-Score

A zz-score represents the directed distance between a raw score xx and the mean μ\mu, measured in units of standard deviation:

  • If z>0z > 0, the raw score lies above the mean.
  • If z<0z < 0, the raw score lies below the mean.
  • If z=0z = 0, the raw score is equal to the mean.
  • For example, z=−1.75z = -1.75 indicates that the observation lies 1.751.75 standard deviations below the distribution mean.

Converting from Z-Score Back to Raw Score

Multiplying both sides by σ\sigma and adding μ\mu yields the inverse algebraic formula:

x=μ+zσx = \mu + z\sigma

The transformation maps any normal distribution X∼N(μ,σ)X \sim N(\mu, \sigma) onto the Standard Normal Distribution Z∼N(0,1)Z \sim N(0, 1), which has a mean of 00 and a standard deviation of 11.


4. Graphing Calculator Technology: normalcdf & invNorm

The graphing calculator is required on the Regents examination for computing non-integer cumulative probabilities and inverse percentiles.

Calculator CommandInput SyntaxPurpose
normalcdfnormalcdf(lower, upper, [μ, σ])Calculates the probability / area under the normal curve between lower and upper bounds.
invNorminvNorm(area, [μ, σ])Finds the data value or zz-score corresponding to a given cumulative area strictly from the left (−∞-\infty to xx).

Practical Execution Details

  1. Accessing Distribution Functions: Press 2nd →\to VARS (DISTR).
  2. Infinite Tail Approximations:
    • For left-tail probabilities (P(X<b)P(X < b)), set lower to −1E99-1\text{E}99 (entered as (-) 1 [2nd] [,] 99).
    • For right-tail probabilities (P(X>a)P(X > a)), set upper to 1E991\text{E}99 (entered as 1 [2nd] [,] 99).
  3. Left-Area Rule for invNorm: The area argument in invNorm must always represent the cumulative area from the far left tail. If an exam question asks for the "top 15%15\%," the area to the left is 1−0.15=0.851 - 0.15 = 0.85.

5. Worked Examples

Worked Problem 1: Empirical Rule Interval Calculation

Problem: The packaging weights of organic flour bags are normally distributed with a mean of 5.00 lb5.00\text{ lb} and a standard deviation of 0.08 lb0.08\text{ lb}. Determine the percentage of bags weighing between 4.84 lb4.84\text{ lb} and 5.08 lb5.08\text{ lb}.

  • Step 1: Express the interval boundaries in terms of standard deviations from the mean.
    • Lower boundary: 4.84=5.00−0.16=5.00−2(0.08)=μ−2σ4.84 = 5.00 - 0.16 = 5.00 - 2(0.08) = \mu - 2\sigma.
    • Upper boundary: 5.08=5.00+0.08=5.00+1(0.08)=μ+1σ5.08 = 5.00 + 0.08 = 5.00 + 1(0.08) = \mu + 1\sigma.
  • Step 2: Partition the interval into Empirical Rule sections.
    • From μ−2σ\mu - 2\sigma to μ−1σ\mu - 1\sigma: 13.6%13.6\%
    • From μ−1σ\mu - 1\sigma to μ\mu: 34.1%34.1\%
    • From μ\mu to μ+1σ\mu + 1\sigma: 34.1%34.1\%
  • Step 3: Sum the individual percentages. Percentage=13.6%+34.1%+34.1%=81.8%\text{Percentage} = 13.6\% + 34.1\% + 34.1\% = 81.8\% Approximately 81.8%81.8\% (or 81.85%81.85\% with unrounded decimals) of flour bags fall within this range.

Worked Problem 2: Comparing Relative Standing via Z-Scores

Problem: Sofia scored 8686 on a chemistry midterm with μ=74\mu = 74 and σ=8\sigma = 8. On her history midterm, she scored 8888 where μ=79\mu = 79 and σ=6\sigma = 6. On which exam did Sofia perform better relative to her peers?

  • Step 1: Calculate the zz-score for chemistry. zchem=x−μσ=86−748=128=1.50z_{\text{chem}} = \frac{x - \mu}{\sigma} = \frac{86 - 74}{8} = \frac{12}{8} = 1.50
  • Step 2: Calculate the zz-score for history. zhist=x−μσ=88−796=96=1.50z_{\text{hist}} = \frac{x - \mu}{\sigma} = \frac{88 - 79}{6} = \frac{9}{6} = 1.50
  • Step 3: Compare standard scores. Both zz-scores are equal (1.501.50), meaning Sofia scored exactly 1.51.5 standard deviations above the class mean on both examinations. Relative to her peers, her performance was identical.

Worked Problem 3: Finding Percentiles and Cutoff Scores with Calculator Functions

Problem: A manufacturing plant produces metal rods whose lengths are normally distributed with μ=120.0 cm\mu = 120.0\text{ cm} and σ=2.5 cm\sigma = 2.5\text{ cm}. Rods in the longest 8%8\% must be trimmed. Determine the minimum cutoff length for a rod to require trimming, rounded to the nearest tenth of a centimeter.

  • Step 1: Identify the cumulative left-tail area. Because trimming applies to the top 8%8\% (the right tail), the proportion of rods below this cutoff is: Cumulative Left Area=1−0.08=0.92\text{Cumulative Left Area} = 1 - 0.08 = 0.92
  • Step 2: Apply the inverse normal function. Using the calculator syntax invNorm(area, μ, σ): Cutoff=invNorm(0.92,120.0,2.5)\text{Cutoff} = \text{invNorm}(0.92, 120.0, 2.5)
  • Step 3: Compute the raw score.
    • Standard normal critical value: z=invNorm(0.92,0,1)≈1.40507z = \text{invNorm}(0.92, 0, 1) \approx 1.40507
    • Raw score: x=120.0+1.40507(2.5)=120.0+3.5127≈123.51 cmx = 120.0 + 1.40507(2.5) = 120.0 + 3.5127 \approx 123.51\text{ cm} Rounded to the nearest tenth, the cutoff length is 123.5 cm123.5\text{ cm}.

6. Common Regents Pitfalls & Exam Strategies

  • Pitfall 1: Inverting the Z-Score Numerator. Students often write z=μ−xσz = \frac{\mu - x}{\sigma}, which reverses the algebraic sign and misplaces the score on the opposite side of the mean.
  • Pitfall 2: Inputting Right-Tail Area into invNorm. When a problem specifies the "highest 10%10\%" or "top 5%5\%," entering 0.100.10 or 0.050.05 computes the bottom cutoff instead. Always enter 1−right-tail area1 - \text{right-tail area}.
  • Pitfall 3: Conflating Z-Scores with Probabilities. A zz-score is a coordinate position along the horizontal axis, not a probability. A zz-score of −1.5-1.5 is valid; a negative probability is mathematically impossible.
Test Your Knowledge

The weights of adult golden retrievers are normally distributed with a mean of 65 pounds and a standard deviation of 5 pounds. Using the Empirical Rule, what percentage of golden retrievers weigh between 55 pounds and 70 pounds?

A

81.85%

B

68.20%

C

84.00%

D

95.40%

Test Your Knowledge

On a statewide mathematics assessment, student scores are normally distributed with a mean of μ = 480 and a standard deviation of σ = 40. A selective STEM honors program admits students who score in the top 15% of all test-takers. What is the minimum score a student must achieve to qualify, rounded to the nearest integer?

A

438

B

512

C

521

D

546

Test Your Knowledge

A beverage company fills containers with an automated dispensing machine. The volume of juice per bottle is normally distributed with a mean of 502 mL and a standard deviation of 1.6 mL. What is the probability that a randomly chosen bottle contains less than 499 mL, rounded to the nearest thousandth?

A

0.054

B

0.030

C

0.970

D

0.003

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