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8.1 Arithmetic and Geometric Sequences

Key Takeaways

  • A sequence is formally defined as a function whose domain is a subset of integers (typically positive integers {1, 2, 3, ...}), generating an ordered progression of real-number outputs called terms.

  • Arithmetic sequences maintain a constant common difference d = a_n - a_(n-1), represented by explicit formula a_n = a_1 + (n - 1)d and recursive form a_1 = k, a_n = a_(n-1) + d, which models discrete points along a linear function with slope m = d.

  • Geometric sequences maintain a constant common ratio r = a_n / a_(n-1), represented by explicit formula a_n = a_1 · r^(n - 1) and recursive form a_1 = k, a_n = r · a_(n-1), which models discrete points along an exponential function with base b = r.

  • Recursive formulas define each term from preceding terms and strictly mandate a base case initial value (a_1), whereas explicit formulas permit immediate calculation of any n-th term without intermediate evaluations.

  • Unknown terms between two non-consecutive terms are resolved algebraically: for arithmetic sequences, by calculating d = (a_k - a_j) / (k - j); for geometric sequences, by solving r^(k - j) = a_k / a_j, evaluating both positive and negative roots when k - j is even.

Last updated: September 2026

8.1 Arithmetic and Geometric Sequences

Quick Answer: A sequence is a function whose domain consists of consecutive integers (typically n∈{1,2,3,… }n \in \{1, 2, 3, \dots\}). An arithmetic sequence adds a constant common difference dd to each term (an=a1+(n−1)da_n = a_1 + (n-1)d), exhibiting discrete linear growth with slope m=dm = d. A geometric sequence multiplies each term by a constant common ratio rr (an=a1rn−1a_n = a_1 r^{n-1}), exhibiting discrete exponential growth with base b=rb = r. Explicit formulas calculate any term directly from its index nn, while recursive formulas specify an initial term a1a_1 and define ana_n from an−1a_{n-1}.


1. Sequences as Functions on Discrete Integer Domains (F-BF.1a, F-BF.2)

In elementary algebra, functions are typically introduced over continuous real domains: a linear function f(x)=3x+2f(x) = 3x + 2 or an exponential function g(x)=5(2)xg(x) = 5(2)^x accepts any real input x∈Rx \in \mathbb{R}, yielding unbroken, continuous graphical curves. Under the New York State Next Generation Learning Standards, students transition to analyzing sequences through the formal lens of function theory.

The Formal Definition of a Sequence

A sequence is a function ff whose domain is a subset of the integers—almost universally the set of positive integers (natural numbers):

Domain: N={1,2,3,4,…,n,… }\text{Domain: } \mathbb{N} = \{1, 2, 3, 4, \dots, n, \dots\}

Rather than writing function notation f(n)f(n), mathematicians use subscript notation ana_n to designate the output value corresponding to the input integer nn:

f(1)=a1,f(2)=a2,f(3)=a3,…,f(n)=anf(1) = a_1, \quad f(2) = a_2, \quad f(3) = a_3, \quad \dots, \quad f(n) = a_n
  • The input integer nn is called the term index or position.
  • The output value ana_n is called the nn-th term or general term.
  • The first output a1a_1 is called the initial term.

Because the domain contains only isolated integers, the graph of a sequence in the coordinate plane consists strictly of discrete, disconnected points (1,a1),(2,a2),(3,a3),…(1, a_1), (2, a_2), (3, a_3), \dots. It is mathematically incorrect to connect the plotted points with a solid line or curve, because values such as a2.5a_{2.5} or a2a_{\sqrt{2}} do not exist.

Explicit vs. Recursive Representations

Every sequence can be described using two distinct mathematical frameworks:

  1. Explicit Formulas: Express the term value ana_n solely in terms of its position index nn. This allows direct computation of any arbitrary term without prior knowledge of earlier terms. For example, to find the 100th term, one simply evaluates a100a_{100}.
  2. Recursive Formulas: Express the term value ana_n as a function of the immediately preceding term an−1a_{n-1} (or multiple preceding terms). A complete recursive definition strictly requires two components: an initial condition (base case) defining a1a_1, and a recurrence relation governing ana_n for all integers n≥2n \ge 2.

2. Arithmetic Sequences: Differences, Formulas, and Linear Models

An arithmetic sequence is a sequence in which the difference between any two consecutive terms is constant. This constant value is designated the common difference, symbolized by dd.

Calculating the Common Difference

To determine whether a sequence is arithmetic, compute the difference between successive terms:

d=an−an−1=a2−a1=a3−a2=a4−a3d = a_n - a_{n-1} = a_2 - a_1 = a_3 - a_2 = a_4 - a_3
  • If d>0d > 0, the sequence is strictly increasing.
  • If d<0d < 0, the sequence is strictly decreasing.
  • If d=0d = 0, the sequence is constant.

Deriving the Explicit Formula

Tracing the sequence term-by-term reveals a clear structural pattern:

a1=a1a2=a1+da3=a2+d=(a1+d)+d=a1+2da4=a3+d=(a1+2d)+d=a1+3d    ⋮an=a1+(n−1)d\begin{aligned} a_1 &= a_1 \\ a_2 &= a_1 + d \\ a_3 &= a_2 + d = (a_1 + d) + d = a_1 + 2d \\ a_4 &= a_3 + d = (a_1 + 2d) + d = a_1 + 3d \\ &\;\;\vdots \\ a_n &= a_1 + (n - 1)d \end{aligned}

Notice that to advance from the first term a1a_1 to the nn-th term ana_n, exactly (n−1)(n - 1) additions of the common difference dd are executed. This explicit formula is explicitly provided on the NYSED Next Generation Mathematics Reference Sheet.

The Recursive Definition

The recursive formula translates the stepwise addition of dd directly into mathematical notation:

{a1=kan=an−1+d,for n≥2\begin{cases} a_1 = k \\ a_n = a_{n-1} + d, & \text{for } n \ge 2 \end{cases}

Important

The Base Case Rule on Regents Exams: When asked to write a recursive formula on Part II or Part III constructed-response items, failing to state a1=ka_1 = k results in an automatic 1-credit penalty. A recurrence relation an=an−1+da_n = a_{n-1} + d alone is incomplete because an infinite number of sequences share the same common difference but start at different initial values.

The Connection Between Arithmetic Sequences and Linear Functions

Expanding the explicit formula highlights its underlying algebraic identity with linear functions:

an=a1+(n−1)d=a1+dn−d=dn+(a1−d)a_n = a_1 + (n - 1)d = a_1 + dn - d = dn + (a_1 - d)

Comparing this structure to slope-intercept form f(x)=mx+bf(x) = mx + b:

  • The common difference dd corresponds exactly to the constant rate of change (slope mm).
  • The constant term (a1−d)(a_1 - d) corresponds to the vertical intercept (the hypothetical 0th term a0a_0).
Mathematical AttributeContinuous Linear Function f(x)=mx+bf(x) = mx + bDiscrete Arithmetic Sequence an=dn+(a1−d)a_n = dn + (a_1 - d)
DomainAll real numbers: x∈Rx \in \mathbb{R}Positive integers: n∈{1,2,3,… }n \in \{1, 2, 3, \dots\}
Rate of ChangeConstant slope: m=ΔyΔxm = \frac{\Delta y}{\Delta x}Common difference: d=an−an−1d = a_n - a_{n-1}
Vertical InterceptValue at x=0x = 0: f(0)=bf(0) = bHypothetical 0th term: a0=a1−da_0 = a_1 - d
Graphical AppearanceUnbroken continuous lineCollinear set of isolated points

3. Geometric Sequences: Ratios, Formulas, and Exponential Models

A geometric sequence is a sequence in which the ratio between any two consecutive terms is constant. This multiplier is designated the common ratio, symbolized by rr.

Calculating the Common Ratio

To determine whether a sequence is geometric, divide each term by its immediate predecessor:

r=anan−1=a2a1=a3a2=a4a3(an−1≠0)r = \frac{a_n}{a_{n-1}} = \frac{a_2}{a_1} = \frac{a_3}{a_2} = \frac{a_4}{a_3} \quad (a_{n-1} \neq 0)
  • If r>1r > 1 and a1>0a_1 > 0, terms grow exponentially without bound.
  • If 0<r<10 < r < 1 and a1>0a_1 > 0, terms decay exponentially toward 0.
  • If r<0r < 0, terms alternate in sign between positive and negative values (an oscillating sequence).

Deriving the Explicit Formula

Tracing the multiplication term-by-term reveals the exponential progression:

a1=a1a2=a1⋅ra3=a2⋅r=(a1⋅r)⋅r=a1r2a4=a3⋅r=(a1r2)⋅r=a1r3    ⋮an=a1rn−1\begin{aligned} a_1 &= a_1 \\ a_2 &= a_1 \cdot r \\ a_3 &= a_2 \cdot r = (a_1 \cdot r) \cdot r = a_1 r^2 \\ a_4 &= a_3 \cdot r = (a_1 r^2) \cdot r = a_1 r^3 \\ &\;\;\vdots \\ a_n &= a_1 r^{n - 1} \end{aligned}

To advance from a1a_1 to ana_n, the initial value is multiplied by rr exactly (n−1)(n - 1) times. This explicit formula is provided on the official NYSED Reference Sheet.

The Recursive Definition

{a1=kan=r⋅an−1,for n≥2\begin{cases} a_1 = k \\ a_n = r \cdot a_{n-1}, & \text{for } n \ge 2 \end{cases}

The Connection Between Geometric Sequences and Exponential Functions

Rewriting the explicit formula using exponent rules demonstrates its structural identity with exponential models:

an=a1rn−1=a1⋅rn⋅r−1=(a1r)rna_n = a_1 r^{n - 1} = a_1 \cdot r^n \cdot r^{-1} = \left(\frac{a_1}{r}\right) r^n

Comparing this to standard exponential form f(x)=a⋅bxf(x) = a \cdot b^x:

  • The common ratio rr corresponds to the growth/decay factor (base bb).
  • The leading coefficient a1r\frac{a_1}{r} represents the initial value f(0)=a0f(0) = a_0.

Note

Alternating Sequences vs. Real Exponential Curves: Continuous exponential functions f(x)=a⋅bxf(x) = a \cdot b^x require the base b>0b > 0 because negative bases raised to fractional powers (such as (−4)1/2=2i(-4)^{1/2} = 2i) produce non-real complex numbers. In contrast, geometric sequences restrict their domain to integer powers n∈Z+n \in \mathbb{Z}^+. Therefore, geometric sequences permit negative common ratios r<0r < 0, which generate alternating sign sequences such as 3,−6,12,−24,48,…3, -6, 12, -24, 48, \dots.


4. Comprehensive Structural Comparison

Sequence PropertyArithmetic SequenceGeometric Sequence
Defining OperationSuccessive addition of constant ddSuccessive multiplication by constant rr
Identifying Testa2−a1=a3−a2=da_2 - a_1 = a_3 - a_2 = da2a1=a3a2=r\frac{a_2}{a_1} = \frac{a_3}{a_2} = r
Explicit Formula (Ref. Sheet)an=a1+(n−1)da_n = a_1 + (n - 1)dan=a1rn−1a_n = a_1 r^{n - 1}
Recursive Definitiona1=k,  an=an−1+da_1 = k, \; a_n = a_{n-1} + da1=k,  an=r⋅an−1a_1 = k, \; a_n = r \cdot a_{n-1}
Underlying Function FamilyLinear: f(x)=mx+bf(x) = mx + bExponential: f(x)=a⋅bxf(x) = a \cdot b^x
Growth ParameterSlope: m=dm = dBase multiplier: b=rb = r
Hypothetical 0th Terma0=a1−da_0 = a_1 - da0=a1ra_0 = \frac{a_1}{r}
Behavior when d<0d < 0 or 0<r<10 < r < 1Decreases linearly toward −∞-\inftyDecays exponentially toward 0

5. Worked Problem 1: Converting Between Recursive and Explicit Forms

Problem: A sequence is defined recursively by a1=19a_1 = 19 and an=an−1−3.5a_n = a_{n-1} - 3.5 for n≥2n \ge 2. Write an explicit formula for the sequence, calculate the value of a32a_{32}, and determine the linear function f(n)f(n) that models this sequence.

  • Step 1: Identify the sequence type and parameters. The recurrence relation subtracts a constant 3.53.5 from each term, indicating an arithmetic sequence with:

    a1=19,d=−3.5a_1 = 19, \quad d = -3.5
  • Step 2: Construct the explicit formula. Using the reference sheet formula an=a1+(n−1)da_n = a_1 + (n - 1)d:

    an=19+(n−1)(−3.5)a_n = 19 + (n - 1)(-3.5)
  • Step 3: Simplify into slope-intercept form.

    an=19−3.5n+3.5=−3.5n+22.5a_n = 19 - 3.5n + 3.5 = -3.5n + 22.5

    The corresponding linear function is f(n)=−3.5n+22.5f(n) = -3.5n + 22.5 for n∈Nn \in \mathbb{N}.

  • Step 4: Compute the 32nd term. Substitute n=32n = 32 into the explicit formula:

    a32=−3.5(32)+22.5=−112+22.5=−89.5a_{32} = -3.5(32) + 22.5 = -112 + 22.5 = -89.5

6. Worked Problem 2: Finding Missing Terms Between Non-Consecutive Geometric Terms

Problem: In a geometric sequence of positive real numbers, the third term is a3=24a_3 = 24 and the seventh term is a7=384a_7 = 384. Algebraically determine the common ratio rr, the initial term a1a_1, write the explicit formula, and state the values of the intermediate missing terms a4,a5,a_4, a_5, and a6a_6.

  • Step 1: Express both terms using the explicit geometric formula. Using an=a1rn−1a_n = a_1 r^{n-1}:

    a3=a1r3−1=a1r2=24a_3 = a_1 r^{3 - 1} = a_1 r^2 = 24 a7=a1r7−1=a1r6=384a_7 = a_1 r^{7 - 1} = a_1 r^6 = 384
  • Step 2: Solve for rr by forming the quotient of the equations.

    a7a3=a1r6a1r2=38424\frac{a_7}{a_3} = \frac{a_1 r^6}{a_1 r^2} = \frac{384}{24} r6−2=r4=16r^{6 - 2} = r^4 = 16
  • Step 3: Extract the fourth root.

    r=±164=±2r = \pm \sqrt[4]{16} = \pm 2

    Because the problem prompt explicitly specifies that the sequence consists of positive real numbers, reject the negative root:

    r=2r = 2
  • Step 4: Calculate the first term a1a_1. Substitute r=2r = 2 back into the equation for a3a_3:

    a1(2)2=24  ⟹  4a1=24  ⟹  a1=6a_1 (2)^2 = 24 \implies 4a_1 = 24 \implies a_1 = 6
  • Step 5: State the explicit formula and calculate missing terms.

    an=6(2)n−1a_n = 6(2)^{n - 1}

    Evaluating consecutive terms:

    a4=6(2)3=48,a5=6(2)4=96,a6=6(2)5=192a_4 = 6(2)^3 = 48, \quad a_5 = 6(2)^4 = 96, \quad a_6 = 6(2)^5 = 192

7. Worked Problem 3: Resolving Non-Consecutive Arithmetic Terms

Problem: An arithmetic sequence has a 4th term of a4=−7a_4 = -7 and an 11th term of a11=35a_{11} = 35. Determine the common difference dd, the first term a1a_1, and the term index nn for which an=101a_n = 101.

  • Step 1: Set up equations for both terms.

    a4=a1+3d=−7a_4 = a_1 + 3d = -7 a11=a1+10d=35a_{11} = a_1 + 10d = 35
  • Step 2: Subtract the equations to eliminate a1a_1.

    (a1+10d)−(a1+3d)=35−(−7)(a_1 + 10d) - (a_1 + 3d) = 35 - (-7) 7d=42  ⟹  d=67d = 42 \implies d = 6
  • Step 3: Solve for a1a_1.

    a1+3(6)=−7  ⟹  a1+18=−7  ⟹  a1=−25a_1 + 3(6) = -7 \implies a_1 + 18 = -7 \implies a_1 = -25
  • Step 4: Determine the index nn where an=101a_n = 101.

    101=−25+(n−1)6101 = -25 + (n - 1)6 126=6(n−1)  ⟹  21=n−1  ⟹  n=22126 = 6(n - 1) \implies 21 = n - 1 \implies n = 22

    The 22nd term of the sequence is 101101.


8. Common Regents Pitfalls and Exam Strategies

  • Pitfall 1: Index Off-by-One Exponent Error: A frequent error on Part I items is confusing rn−1r^{n-1} with rnr^n. In an=a1rn−1a_n = a_1 r^{n-1}, the exponent is n−1n - 1 because the first term already has zero factors of rr (a1=a1r0a_1 = a_1 r^0). Writing an=a1rna_n = a_1 r^n shifts the entire sequence by one index, making a1a_1 equal to a1ra_1 r, which is incorrect.
  • Pitfall 2: Forgetting the Base Case in Recursive Definitions: When writing a recursive formula on Regents constructed-response items, you must explicitly state a1=ka_1 = k. Omitting a1a_1 forfeits 1 credit out of 2.
  • Pitfall 3: Reversing the Subtraction or Division Order: When computing common difference dd or common ratio rr, always take the later term minus (or divided by) the earlier term: d=a2−a1d = a_2 - a_1, never a1−a2a_1 - a_2.
  • Pitfall 4: Overlooking Dual Signs on Even Roots: When solving rk−j=Cr^{k-j} = C where k−jk - j is even, r=±Ck−jr = \pm \sqrt[k-j]{C}. Unless the prompt restricts terms to positive real numbers, both positive and negative values for rr are mathematically valid.
Test Your Knowledge

An arithmetic sequence has a third term of 17 and an eighth term of 47. Which explicit formula defines the n-th term of this sequence?

A

a_n = 6n - 1

B

a_n = 6n + 5

C

a_n = 5n + 2

D

a_n = 5 + (n - 1)8

Test Your Knowledge

A sequence is recursively defined by a_1 = 12 and a_n = -0.5 · a_(n-1) for n ≥ 2. What is the exact value of the sixth term, a_6?

A

0.375

B

-0.375

C

-0.75

D

0.1875

Test Your Knowledge

Which statement correctly explains why any arithmetic or geometric sequence qualifies as a function under New York State Next Generation standards?

A

Every sequence can be graphed as a continuous, unbroken curve passing through all real coordinates in the plane.

B

Any term index can produce multiple distinct output values depending on whether an explicit or recursive formula is chosen.

C

Each input value from the sequence's domain—a subset of consecutive integers—is paired with exactly one unique output value called a term.

D

A sequence is classified as a function only when its common difference is positive, because alternating sequences violate the vertical line test.

Sections you finish are checked off in the contents.