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3.2 Cost Price, Selling Price, Profit/Loss Percentage, Dishonest Dealer & Discount Schemes

Key Takeaways

  • Unless another base is specified, profit/loss percentages use cost price. The first discount uses marked price; each successive discount uses the remaining price.

  • The master unified bridge MP / CP = (100 + P%) / (100 - D%) directly relates markup and discount without evaluating intermediate selling prices.

  • Successive discounts compound on diminishing balances via D_eq = d_1 + d_2 - (d_1 * d_2 / 100), while 'Buy x, Get y Free' offers yield a discount percentage of [y / (x + y)] * 100.

  • Dishonest weighbridge yield and false-measure dealer gain follow Profit% = [Error / (True Value - Error)] * 100.

  • Selling two articles at identical selling prices, one at x% profit and the other at x% loss, always results in a net transaction loss of (x / 10)^2 percent.

Last updated: October 2026

Core Commercial Parameters & Accounting Foundations

Every commercial transaction revolves around three primary price thresholds:

  1. Cost Price (CP): The total capital outlay required to procure, manufacture, or transport an item. Any auxiliary transportation, installation, or refurbishment overheads must be added to the initial purchase price to establish the effective CP:
Effective CP=Purchase Price+Overhead Expenses\text{Effective CP} = \text{Purchase Price} + \text{Overhead Expenses}
  1. Selling Price (SP): The actual monetary value realized upon the transfer or sale of the asset.
  2. Marked Price (MP) / List Price: The catalogue price or base quoted tariff prior to concessions.

Foundational Mathematical Relationships

Profit=SP−CP(when SP>CP)\text{Profit} = SP - CP \quad (\text{when } SP > CP) Loss=CP−SP(when CP>SP)\text{Loss} = CP - SP \quad (\text{when } CP > SP) Profit%=(SP−CPCP)×100=(SPCP−1)×100\mathbf{\text{Profit}\% = \left(\frac{SP - CP}{CP}\right) \times 100 = \left(\frac{SP}{CP} - 1\right) \times 100} Loss%=(CP−SPCP)×100=(1−SPCP)×100\mathbf{\text{Loss}\% = \left(\frac{CP - SP}{CP}\right) \times 100 = \left(1 - \frac{SP}{CP}\right) \times 100} Markup%=(MP−CPCP)×100\text{Markup}\% = \left(\frac{MP - CP}{CP}\right) \times 100 Discount%=(MP−SPMP)×100\text{Discount}\% = \left(\frac{MP - SP}{MP}\right) \times 100
Pricing ParameterReference BaselineFundamental Expression
Profit PercentageCost Price (CP)SP=CP×(1+P100)SP = CP \times \left(1 + \frac{P}{100}\right)
Loss PercentageCost Price (CP)SP=CP×(1−L100)SP = CP \times \left(1 - \frac{L}{100}\right)
Discount PercentageMarked Price (MP)SP=MP×(1−D100)SP = MP \times \left(1 - \frac{D}{100}\right)
Markup PercentageCost Price (CP)MP=CP×(1+M100)MP = CP \times \left(1 + \frac{M}{100}\right)

Important

Profit and loss are evaluated strictly on Cost Price (CP) unless a question explicitly specifies profit as a percentage of selling price. The initial discount uses Marked Price (MP); each subsequent discount uses the remaining balance. Keep these different bases explicit in each calculation.


The Master Unified Bridge Formula (MP/CPMP / CP)

Selling price (SPSP) serves as the connecting link between Cost Price and Marked Price:

SP=CP×(100+P100)SP = CP \times \left(\frac{100 + P}{100}\right) SP=MP×(100−D100)SP = MP \times \left(\frac{100 - D}{100}\right)

Equating both expressions eliminates the selling price entirely:

CP×(100+P)=MP×(100−D)CP \times (100 + P) = MP \times (100 - D) MPCP=100+P100−D\mathbf{\frac{MP}{CP} = \frac{100 + P}{100 - D}}

If the transaction results in a net commercial loss, the formulation adapts directly:

MPCP=100−L100−D\mathbf{\frac{MP}{CP} = \frac{100 - L}{100 - D}}

This single ratio eliminates the need to calculate intermediate selling prices, cutting exam calculation steps in half.


Successive Discounts & Promotional Schemes

Single Equivalent Discount Formula

When successive commercial discounts of d1%d_1\% and d2%d_2\% are granted sequentially on Marked Price, each subsequent discount applies to the diminished balance:

Deq=d1+d2−d1d2100\mathbf{D_{\text{eq}} = d_1 + d_2 - \frac{d_1 d_2}{100}}

For three successive discounts d1%d_1\%, d2%d_2\%, and d3%d_3\%:

SP=MP(1−d1100)(1−d2100)(1−d3100)SP = MP \left(1 - \frac{d_1}{100}\right) \left(1 - \frac{d_2}{100}\right) \left(1 - \frac{d_3}{100}\right) Deq=100×[1−(1−d1100)(1−d2100)(1−d3100)]D_{\text{eq}} = 100 \times \left[1 - \left(1 - \frac{d_1}{100}\right) \left(1 - \frac{d_2}{100}\right) \left(1 - \frac{d_3}{100}\right)\right]

Buy xx, Get yy Free Promotional Architecture

The effective-discount calculation assumes identical unit prices for the paid and free items. In commercial tenders and retail concessions, promotions often offer free items upon purchasing a specified batch. The true discount percentage represents the ratio of free goods to total goods delivered:

Discount%=Free QuantityTotal Quantity Delivered×100=yx+y×100\mathbf{\text{Discount}\% = \frac{\text{Free Quantity}}{\text{Total Quantity Delivered}} \times 100 = \frac{y}{x + y} \times 100}
Promotional OfferFree Units (yy)Total Units (x+yx + y)Effective Single Discount
Buy 1, Get 1 Free1212×100=50.0%\frac{1}{2} \times 100 = 50.0\%
Buy 2, Get 1 Free1313×100=33.33%\frac{1}{3} \times 100 = 33.33\%
Buy 3, Get 1 Free1414×100=25.0%\frac{1}{4} \times 100 = 25.0\%
Buy 4, Get 1 Free1515×100=20.0%\frac{1}{5} \times 100 = 20.0\%
Buy 5, Get 3 Free3838×100=37.5%\frac{3}{8} \times 100 = 37.5\%
Buy 7, Get 3 Free310310×100=30.0%\frac{3}{10} \times 100 = 30.0\%

Tip

If an offer states "Buy 4, Get 1 Free PLUS an additional 10%10\% cash discount", treat it as two successive discounts: d1=20%d_1 = 20\% and d2=10%d_2 = 10\%. The equivalent single discount is Deq=20+10−20×10100=28%D_{\text{eq}} = 20 + 10 - \frac{20 \times 10}{100} = 28\%.


Dishonest Dealers & Weighbridge Errors

In bulk freight loading yards, mineral sidings, and parcel hubs, weighbridge calibration directly determines billing accuracy. Dishonest dealer models analyze situations where a vendor claims to sell at cost price but dispenses a fraudulent weight or measure.

Core Formulation

When a seller claims to deliver a true measure WtrueW_{\text{true}} but dispenses only WfalseW_{\text{false}}:

  • Revenue collected corresponds to WtrueW_{\text{true}}.
  • Actual cost outlay incurred corresponds only to WfalseW_{\text{false}}.
Profit%=Wtrue−WfalseWfalse×100=ErrorTrue Value−Error×100\mathbf{\text{Profit}\% = \frac{W_{\text{true}} - W_{\text{false}}}{W_{\text{false}}} \times 100 = \frac{\text{Error}}{\text{True Value} - \text{Error}} \times 100}

Compound Fraud Architecture (Markup Combined with False Weight)

When a dealer marks up the price by m%m\%, grants an optional discount of d%d\%, and uses a false measure WfalseW_{\text{false}} for WtrueW_{\text{true}}:

Net Multiplier=(1+m100)×(1−d100)×(WtrueWfalse)\text{Net Multiplier} = \left(1 + \frac{m}{100}\right) \times \left(1 - \frac{d}{100}\right) \times \left(\frac{W_{\text{true}}}{W_{\text{false}}}\right) Net Profit%=(Net Multiplier−1)×100\mathbf{\text{Net Profit}\% = (\text{Net Multiplier} - 1) \times 100}

Twin Items at Equal Selling Price with Symmetrical Gain and Loss

A classic railway CBT question involves selling two distinct items at the exact same selling price (SP1=SP2=SP>0SP_1 = SP_2 = SP>0), where one item yields a profit of x%x\% and the other incurs a loss of x%x\%, with 0<x<1000<x<100.

Equal-Selling-Price Loss Rule (0<x<1000<x<100)

Because the base cost prices (CP1CP_1 and CP2CP_2) are unequal, the percentage loss operates on a larger base than the percentage profit. Therefore, the overall transaction always results in a net loss:

Net Loss%=(x10)2%=x2100%\mathbf{\text{Net Loss}\% = \left(\frac{x}{10}\right)^2\% = \frac{x^2}{100}\%}

Absolute Monetary Net Loss Formula

To compute the absolute rupee loss directly from the common selling price SPSP:

Absolute Net Loss=2×x2×SP1002−x2\mathbf{\text{Absolute Net Loss} = \frac{2 \times x^2 \times SP}{100^2 - x^2}}

Equal SP vs. Equal CP Comparison

Transaction StructureFirst ArticleSecond ArticleOverall Transaction Outcome
Equal Selling Price (SP1=SP2SP_1 = SP_2)+x%+x\% Profit−x%-x\% LossAlways a Net Loss of x2100%\frac{x^2}{100}\%
Equal Cost Price (CP1=CP2CP_1 = CP_2)+x%+x\% Profit−x%-x\% LossZero Net Gain / Zero Net Loss (0%0\%)
Equal Selling Price (SP1=SP2SP_1 = SP_2)+a%+a\% Profit−b%-b\% LossOverall%=100(a−b)−2ab(100+a)+(100−b)\text{Overall}\% = \frac{100(a - b) - 2ab}{(100 + a) + (100 - b)}

Comprehensive Worked Operational Problems

Worked Problem 1: Railway Catering Menu Pricing via Master Bridge

Scenario: A zonal railway catering licensee intends to realize a net profit of 20%20\% on premium thali meal boxes after granting an advertised promotional discount of 10%10\% on the printed menu price. If the actual cost price (CPCP) of preparing each meal box is ₹180180, calculate:

  1. The marked menu price (MPMP).
  2. The percentage markup over cost price.

Step-by-Step Mathematical Resolution:

  1. Apply the Master Unified Bridge:
MPCP=100+P100−D\frac{MP}{CP} = \frac{100 + P}{100 - D} MP180=100+20100−10=12090=43\frac{MP}{180} = \frac{100 + 20}{100 - 10} = \frac{120}{90} = \frac{4}{3}
  1. Solve for Marked Price (MPMP):
MP=180×43=INR 240MP = 180 \times \frac{4}{3} = \text{INR } 240
  1. Compute the Percentage Markup:
Markup%=MP−CPCP×100=240−180180×100=60180×100=33.33%\text{Markup}\% = \frac{MP - CP}{CP} \times 100 = \frac{240 - 180}{180} \times 100 = \frac{60}{180} \times 100 = 33.33\%
  1. Verification via Intermediate Selling Price:
SP=MP×(1−0.10)=240×0.90=INR 216SP = MP \times (1 - 0.10) = 240 \times 0.90 = \text{INR } 216 Profit=216−180=INR 36\text{Profit} = 216 - 180 = \text{INR } 36 Profit%=36180×100=20.0%\text{Profit}\% = \frac{36}{180} \times 100 = 20.0\%

Worked Problem 2: Symmetrical Gain/Loss on Equal Selling Price Locomotives

Scenario: A divisional railway administration auctions two retired diesel shunting tractors for ₹1,98,0001,98,000 each. On the first tractor, the administration realizes a profit of 10%10\%, while on the second tractor, it incurs a loss of 10%10\%. Calculate the overall net gain or loss percentage and the total absolute monetary loss on the dual sale.

Step-by-Step Mathematical Resolution:

  1. Apply the Symmetrical Loss Theorem:
Overall Loss%=x2100%=102100%=1.0%\text{Overall Loss}\% = \frac{x^2}{100}\% = \frac{10^2}{100}\% = 1.0\%
  1. Evaluate Individual Cost Prices:
CP1=SP1+0.10=1980001.10=INR 1,80,000CP_1 = \frac{SP}{1 + 0.10} = \frac{198000}{1.10} = \text{INR } 1,80,000 CP2=SP1−0.10=1980000.90=INR 2,20,000CP_2 = \frac{SP}{1 - 0.10} = \frac{198000}{0.90} = \text{INR } 2,20,000
  1. Calculate Aggregate Financials:
Total CP=1,80,000+2,20,000=INR 4,00,000\text{Total CP} = 1,80,000 + 2,20,000 = \text{INR } 4,00,000 Total SP=1,98,000+1,98,000=INR 3,96,000\text{Total SP} = 1,98,000 + 1,98,000 = \text{INR } 3,96,000 Absolute Net Loss=4,00,000−3,96,000=INR 4,000\text{Absolute Net Loss} = 4,00,000 - 3,96,000 = \text{INR } 4,000
  1. Verify via the Direct Formula:
Absolute Loss=2×102×1980001002−102=200×1980009900=200×20=INR 4,000\text{Absolute Loss} = \frac{2 \times 10^2 \times 198000}{100^2 - 10^2} = \frac{200 \times 198000}{9900} = 200 \times 20 = \text{INR } 4,000

Worked Problem 3: Multi-Factor Tampered Weighbridge Siding

Scenario: A siding contractor supplying locomotive coal advertises a price markup of 20%20\% above base procurement cost price and offers a nominal concession discount of 10%10\% on billing. However, inspection reveals that the electronic weighbridge sensor is calibrated so that when 800 kg of coal is loaded into a wagon hopper, the digital terminal records 1,000 kg. Calculate the contractor's actual net profit percentage.

Step-by-Step Mathematical Resolution:

  1. Identify the Operational Multipliers:

    • Markup factor: 1+20100=65=1.201 + \frac{20}{100} = \frac{6}{5} = 1.20
    • Concession discount factor: 1−10100=910=0.901 - \frac{10}{100} = \frac{9}{10} = 0.90
    • False weight multiplier: WtrueWfalse=1000800=54=1.25\frac{W_{\text{true}}}{W_{\text{false}}} = \frac{1000}{800} = \frac{5}{4} = 1.25
  2. Compute Composite Net Transaction Multiplier:

Net Multiplier=65×910×54=6×9×55×10×4=5440=2720=1.35\text{Net Multiplier} = \frac{6}{5} \times \frac{9}{10} \times \frac{5}{4} = \frac{6 \times 9 \times 5}{5 \times 10 \times 4} = \frac{54}{40} = \frac{27}{20} = 1.35
  1. Extract Actual Net Profit Percentage:
Net Profit%=(1.35−1)×100=35.0%\text{Net Profit}\% = (1.35 - 1) \times 100 = 35.0\%

The contractor realizes an actual net gain of 35.0%35.0\%.


Common Exam Traps & Conceptual Pitfalls

Trap DescriptionErroneous ApproachCorrect Examination Protocol
Using an unstated selling-price baseCalculating SP−CPSP×100\frac{SP - CP}{SP} \times 100For the usual profit-on-cost convention, divide by Cost Price: SP−CPCP×100\frac{SP - CP}{CP} \times 100. Profit is return on capital outlay.
Summing Successive DiscountsTreating 20%+10%20\% + 10\% successive discounts as 30%30\%Apply d1+d2−d1d2100=20+10−2=28%d_1 + d_2 - \frac{d_1 d_2}{100} = 20 + 10 - 2 = 28\%. Each discount applies to the remaining balance.
Assuming Zero Gain on Equal SPBelieving +20%+20\% and −20%-20\% at equal SP cancel out to 0%0\%Equal SP always yields a net loss of x2100%=4%\frac{x^2}{100}\% = 4\%. Zero net result occurs ONLY under equal CP.
False Weighbridge Base InversionDividing error by True Weight: 2001000=20%\frac{200}{1000} = 20\%Divide error by the actual weight parted with: 200800=25%\frac{200}{800} = 25\%. Cost is tied to physical inventory outlay.

In these shortcuts, P,D,x,a,bP,D,x,a,b are numerical percentage rates, such as 2020 for 20%20\%. The equal-selling-price loss shortcut assumes 0<x<1000<x<100; at x=0x=0 there is no loss. For false-weight problems the multiplier is billed quantity divided by delivered quantity; the delivered quantity determines the actual cost.

Test Your Knowledge

Two track inspection trolleys are auctioned by a railway division at an identical selling price of ₹48,000 each. On the first trolley, the division realizes a profit of 20%, while on the second trolley, it suffers a loss of 20%. What is the net financial outcome of the entire transaction?

A

Overall loss of ₹4,000

B

Overall loss of ₹2,000

C

No profit, no loss

D

Overall gain of ₹4,000

Test Your Knowledge

A railway staff cooperative store offers a promotional scheme: 'Buy 4 shirts, Get 1 free', and additionally grants a cash discount of 10% on the invoice total for railway employees presenting their identity cards. What is the effective single discount percentage enjoyed by an employee?

A

30.0%

B

25.0%

C

28.0%

D

32.5%

Test Your Knowledge

A scrap merchant marks up copper signalling wire by 20% above cost price and allows a nominal discount of 10% on the marked price. When dispensing the wire on a tampered mechanical scale, a weight of only 800 grams is delivered for every 1,000 grams billed on the receipt. What is the merchant's net profit percentage?

A

30.0%

B

35.0%

C

40.0%

D

42.5%

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