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7.2 Quadratic Equations, Nature of Roots, Discriminant Analysis & Maximum/Minimum Values

Key Takeaways

  • A quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 (a≠0a \neq 0) has roots given by the Sridharacharya quadratic formula x=−b±D2ax = \frac{-b \pm \sqrt{D}}{2a}, where D=b2−4acD = b^2 - 4ac is the discriminant.

  • Vieta's root-coefficient theorems establish α+β=−ba\alpha + \beta = -\frac{b}{a} and αβ=ca\alpha\beta = \frac{c}{a}; the original equation can always be reconstructed as x2−(α+β)x+αβ=0x^2 - (\alpha + \beta)x + \alpha\beta = 0.

  • For real coefficients, D>0D>0 gives distinct real roots, D=0D=0 gives equal real roots, and D<0D<0 gives nonreal conjugates. Rational coefficients are needed for the stated rational/surd classification; equal roots need not be rational for irrational coefficients.

  • For real roots, the difference ∣α−β∣=D∣a∣|\alpha - \beta| = \frac{\sqrt{D}}{|a|} and symmetrical powers (α2+β2\alpha^2 + \beta^2, α3+β3\alpha^3 + \beta^3) evaluate directly from sum and product without calculating explicit roots.

  • A quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c achieves its extreme value at the vertex x=−b2ax = -\frac{b}{2a}, yielding an absolute minimum of −D4a=4ac−b24a-\frac{D}{4a} = \frac{4ac - b^2}{4a} when a>0a > 0 and an absolute maximum of −D4a-\frac{D}{4a} when a<0a < 0.

Last updated: October 2026

Standard Form & The Quadratic Formula (Sridharacharya's Rule)

A second-degree polynomial equation in a single variable xx is termed a quadratic equation. Its standard form is:

ax2+bx+c=0,where a,b,c∈R and a≠0ax^2 + bx + c = 0, \quad \text{where } a, b, c \in \mathbb{R} \text{ and } a \neq 0

Derivation by Completing the Square

To understand the structural origin of the quadratic formula:

  1. Divide through by the leading coefficient aa:
x2+bax+ca=0x^2 + \frac{b}{a}x + \frac{c}{a} = 0
  1. Transpose the constant term to the right side:
x2+bax=−cax^2 + \frac{b}{a}x = -\frac{c}{a}
  1. Complete the square on the left side by adding (b2a)2=b24a2\left( \frac{b}{2a} \right)^2 = \frac{b^2}{4a^2} to both sides:
x2+2(b2a)x+b24a2=b24a2−ca=b2−4ac4a2x^2 + 2 \left( \frac{b}{2a} \right) x + \frac{b^2}{4a^2} = \frac{b^2}{4a^2} - \frac{c}{a} = \frac{b^2 - 4ac}{4a^2}
  1. Factor the left side as a perfect square binomial:
(x+b2a)2=b2−4ac4a2\left( x + \frac{b}{2a} \right)^2 = \frac{b^2 - 4ac}{4a^2}
  1. Take the square root of both sides:
x+b2a=±b2−4ac2ax + \frac{b}{2a} = \pm \frac{\sqrt{b^2 - 4ac}}{2a}
  1. Isolate xx to yield the classical Sridharacharya Quadratic Formula:
x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Vieta's Relations: Roots and Coefficients

Let α\alpha and β\beta be the two roots of the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0:

α=−b+b2−4ac2a,β=−b−b2−4ac2a\alpha = \frac{-b + \sqrt{b^2 - 4ac}}{2a}, \quad \beta = \frac{-b - \sqrt{b^2 - 4ac}}{2a}

The Fundamental Relations

  • Sum of Roots (α+β\alpha + \beta):
α+β=−b+D2a+−b−D2a=−2b2a=−ba\alpha + \beta = \frac{-b + \sqrt{D}}{2a} + \frac{-b - \sqrt{D}}{2a} = \frac{-2b}{2a} = -\frac{b}{a}
  • Product of Roots (αβ\alpha \beta):
αβ=(−b+D2a)(−b−D2a)=(−b)2−(D)24a2=b2−(b2−4ac)4a2=4ac4a2=ca\alpha \beta = \left( \frac{-b + \sqrt{D}}{2a} \right) \left( \frac{-b - \sqrt{D}}{2a} \right) = \frac{(-b)^2 - (\sqrt{D})^2}{4a^2} = \frac{b^2 - (b^2 - 4ac)}{4a^2} = \frac{4ac}{4a^2} = \frac{c}{a}

Reconstructing the Quadratic Equation

Any quadratic equation can be directly assembled from its roots α\alpha and β\beta:

x2−(α+β)x+αβ=0  ⟺  x2−(Sum of Roots)x+(Product of Roots)=0x^2 - (\alpha + \beta)x + \alpha \beta = 0 \iff x^2 - (\text{Sum of Roots})x + (\text{Product of Roots}) = 0
+-----------------------------------------------------------------------------------------+
|                         SYMMETRIC FUNCTIONS OF ROOTS DIRECTORY                          |
+-----------------------------------------------------------------------------------------+
| Sum of Squares:              alpha^2 + beta^2 = (alpha + beta)^2 - 2*alpha*beta         |
|                                               = (b^2 - 2ac) / a^2                       |
| Difference of Roots:         |alpha - beta|   = sqrt((alpha + beta)^2 - 4*alpha*beta)   |
|                                               = sqrt(D) / |a|                           |
| Sum of Cubes:                alpha^3 + beta^3 = (alpha + beta)^3 - 3*alpha*beta(alpha + beta)  |
|                                               = -b(b^2 - 3ac) / a^3                     |
| Reciprocal Sum:              1/alpha + 1/beta = (alpha + beta) / (alpha*beta) = -b / c  |
| Reciprocal Square Sum:       1/alpha^2 + 1/beta^2 = (alpha^2 + beta^2) / (alpha*beta)^2 |
| Ratio Sum:                   alpha/beta + beta/alpha = (alpha^2 + beta^2) / (alpha*beta)|
|                                                      = (b^2 - 2ac) / (ac)               |
+-----------------------------------------------------------------------------------------+

For the absolute real-root difference, require D≥0D\ge0. Reciprocal-root expressions require c≠0c\ne0, so neither root is zero. Multiplying roots by kk via substitution requires k≠0k\ne0.

Useful Root Transformation Shortcuts

When a question requests an equation with transformed roots, direct polynomial substitution is faster than finding roots:

  • Reciprocal Roots (1α,1β\frac{1}{\alpha}, \frac{1}{\beta}): Replace xx with 1x  ⟹  cx2+bx+a=0\frac{1}{x} \implies cx^2 + bx + a = 0 (swap aa and cc).
  • Roots with Opposite Signs (−α,−β-\alpha, -\beta): Replace xx with −x  ⟹  ax2−bx+c=0-x \implies ax^2 - bx + c = 0 (negate bb).
  • Roots Multiplied by Constant (kα,kβk\alpha, k\beta): Replace xx with xk  ⟹  ax2+kbx+k2c=0\frac{x}{k} \implies ax^2 + kbx + k^2c = 0.

Tip

The Instant Factor Inspection Test:

  1. If a+b+c=0a + b + c = 0, then x=1x = 1 is guaranteed to be a root, and the second root is x=cax = \frac{c}{a}.
  2. If a−b+c=0a - b + c = 0 (i.e., a+c=ba + c = b), then x=−1x = -1 is guaranteed to be a root, and the second root is x=−cax = -\frac{c}{a}. For example, in 137x2−219x+82=0137x^2 - 219x + 82 = 0, 137−219+82=0137 - 219 + 82 = 0, so the roots are immediately 11 and 82137\frac{82}{137} without applying the quadratic formula.

Discriminant Analysis & The Nature of Roots

The quantity under the square root in Sridharacharya's formula is termed the Discriminant (DD):

D=b2−4acD = b^2 - 4ac

The algebraic value of DD, relative to zero and the field of rational numbers, completely determines the nature and geometric orientation of the roots.

+-----------------------------------------------------------------------------------------+
|                              DISCRIMINANT DECISION TREE                                 |
+-----------------------------------------------------------------------------------------+
|                                    D = b^2 - 4ac                                        |
|                                          │                                              |
|             ┌────────────────────────────┼────────────────────────────┐                 |
|             ▼                            ▼                            ▼                 |
|          D > 0                         D = 0                        D < 0               |
|      Real & Distinct                Real & Equal                  Imaginary             |
|             │                     (Coincident Roots)         (Complex Conjugates)       |
|      ┌──────┴──────┐                   x = -b/(2a)                 p +- i*q             |
|      ▼             ▼               (Tangent to X-axis)      (No X-axis intersection)    |
|  D is Perfect   D is NOT                                                                |
|    Square     Perfect Square                                                            |
| Rational Roots  Irrational Conjugates                                                   |
|   p, q in Q        p +- sqrt(q)                                                         |
+-----------------------------------------------------------------------------------------+
Condition on Discriminant (DD)Nature of RootsParabola y=f(x)y = f(x) Geometric Behavior
D>0D > 0 and DD is a perfect square (with a,b,c∈Qa, b, c \in \mathbb{Q})Real, Rational, and UnequalCrosses the x-axis at two distinct rational points
D>0D > 0 and DD is not a perfect square (with a,b,c∈Qa, b, c \in \mathbb{Q})Real, Irrational, and Unequal (Roots form conjugate surds p±qp \pm \sqrt{q})Crosses the x-axis at two distinct irrational coordinates
D=0D = 0 (with a,b,c∈Ra, b, c \in \mathbb{R})Real and Equal; rational when the coefficients are rational (x1=x2=−b2ax_1 = x_2 = -\frac{b}{2a})Vertex touches (is tangent to) the x-axis at a single point
D<0D < 0 (with a,b,c∈Ra, b, c \in \mathbb{R})Non-Real / Imaginary (Complex conjugates p±iqp \pm iq, where i=−1i = \sqrt{-1})Entire parabola lies strictly above (a>0a > 0) or below (a<0a < 0) the x-axis

Warning

The Rational Coefficient Prerequisite: The theorem stating that irrational roots occur in conjugate pairs (p+qp + \sqrt{q} and p−qp - \sqrt{q}) holds only when the coefficients a,b,ca, b, c are rational. If the quadratic itself contains irrational coefficients (e.g., x2−(2+3)x+23=0x^2 - (2 + \sqrt{3})x + 2\sqrt{3} = 0), roots are 22 and 3\sqrt{3}, which are not conjugate pairs.


Graphical Properties & Extreme Values of Quadratic Functions

The graph of any quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c is a symmetric vertical parabola.

Vertex Coordinates & Axis of Symmetry

By completing the square on the function:

f(x)=a(x+b2a)2+(c−b24a)=a(x+b2a)2−D4af(x) = a \left( x + \frac{b}{2a} \right)^2 + \left( c - \frac{b^2}{4a} \right) = a \left( x + \frac{b}{2a} \right)^2 - \frac{D}{4a}
  • The Axis of Symmetry is the vertical line x=−b2ax = -\frac{b}{2a}.
  • The Vertex of the parabola is located at the point:
Vertex (V)=(−b2a,−D4a)=(−b2a,4ac−b24a)\text{Vertex } (V) = \left( -\frac{b}{2a}, -\frac{D}{4a} \right) = \left( -\frac{b}{2a}, \frac{4ac - b^2}{4a} \right)
   a > 0 (Opens Upwards - Minimum)              a < 0 (Opens Downwards - Maximum)
               y                                            y
               |       /                                    |      Vertex (-b/(2a), -D/(4a))
               |      /                                     |         .---.
        \     |     /                                      |        /     \
         \    |    /                                 ------|-------/-------\-------> x
          \   |   /                                        |      /         \
           '--+--'  Vertex (-b/(2a), -D/(4a))              |     /           \
        ------+------------------> x                       |    /             \
              |                                            |

Maximum and Minimum Rules

  1. Case 1: Leading Coefficient a>0a > 0 (Parabola opens upwards):

    • Because (x+b2a)2≥0\left( x + \frac{b}{2a} \right)^2 \ge 0, the minimum value occurs when that squared term vanishes.
    • Absolute Minimum Value: fmin⁡=−D4a=4ac−b24af_{\min} = -\frac{D}{4a} = \frac{4ac - b^2}{4a}, occurring at x=−b2ax = -\frac{b}{2a}.
    • Maximum Value: No finite maximum over all real xx; the function is unbounded above.
    • Range: [−D4a,∞)\left[ -\frac{D}{4a}, \infty \right).
  2. Case 2: Leading Coefficient a<0a < 0 (Parabola opens downwards):

    • Because a<0a < 0, a(x+b2a)2≤0a \left( x + \frac{b}{2a} \right)^2 \le 0. The maximum value occurs when the negative term is zero.
    • Absolute Maximum Value: fmax⁡=−D4a=4ac−b24af_{\max} = -\frac{D}{4a} = \frac{4ac - b^2}{4a}, occurring at x=−b2ax = -\frac{b}{2a}.
    • Minimum Value: No finite minimum over all real xx; the function is unbounded below.
    • Range: (−∞,−D4a]\left( -\infty, -\frac{D}{4a} \right].

Definiteness of Quadratic Forms

  • Strictly Positive Definite: ax2+bx+c>0ax^2 + bx + c > 0 for all real xx if and only if a>0a > 0 and D<0D < 0.
  • Strictly Negative Definite: ax2+bx+c<0ax^2 + bx + c < 0 for all real xx if and only if a<0a < 0 and D<0D < 0.

Worked Examples

Worked Example 1: Constructing Quadratic Equations with Transformed Roots

Problem: If α\alpha and β\beta are the roots of the quadratic equation 2x2−7x+4=02x^2 - 7x + 4 = 0, construct the quadratic equation whose roots are αβ\frac{\alpha}{\beta} and βα\frac{\beta}{\alpha}.

  • Step 1: Compute the basic root relations via Vieta's formulas:
α+β=−−72=72\alpha + \beta = -\frac{-7}{2} = \frac{7}{2} αβ=42=2\alpha \beta = \frac{4}{2} = 2
  • Step 2: Find the sum of the new roots (SS):
S=αβ+βα=α2+β2αβ=(α+β)2−2αβαβS = \frac{\alpha}{\beta} + \frac{\beta}{\alpha} = \frac{\alpha^2 + \beta^2}{\alpha \beta} = \frac{(\alpha + \beta)^2 - 2\alpha \beta}{\alpha \beta}

Substitute the computed values:

S=(72)2−2(2)2=494−42=49−1642=3342=338S = \frac{\left(\frac{7}{2}\right)^2 - 2(2)}{2} = \frac{\frac{49}{4} - 4}{2} = \frac{\frac{49 - 16}{4}}{2} = \frac{\frac{33}{4}}{2} = \frac{33}{8}
  • Step 3: Find the product of the new roots (PP):
P=(αβ)(βα)=1P = \left(\frac{\alpha}{\beta}\right) \left(\frac{\beta}{\alpha}\right) = 1
  • Step 4: Form the quadratic equation:
x2−Sx+P=0  ⟹  x2−338x+1=0x^2 - Sx + P = 0 \implies x^2 - \frac{33}{8}x + 1 = 0

Multiply through by 8 to express in integer coefficients:

8x2−33x+8=08x^2 - 33x + 8 = 0

Worked Example 2: Condition for Equal Roots

Problem: Determine the value of mm for which the quadratic equation (m−2)x2−(2m−1)x+(m+2)=0(m - 2)x^2 - (2m - 1)x + (m + 2) = 0 has real and equal roots.

  • Step 1: Identify coefficients and state the condition: Here a=m−2a = m - 2, b=−(2m−1)b = -(2m - 1), and c=m+2c = m + 2. For real and equal roots, the discriminant must vanish: D=b2−4ac=0D = b^2 - 4ac = 0.
  • Step 2: Set up and expand the discriminant equation:
[−(2m−1)]2−4(m−2)(m+2)=0[-(2m - 1)]^2 - 4(m - 2)(m + 2) = 0 (4m2−4m+1)−4(m2−4)=0(4m^2 - 4m + 1) - 4(m^2 - 4) = 0
  • Step 3: Simplify and solve for mm:
4m2−4m+1−4m2+16=04m^2 - 4m + 1 - 4m^2 + 16 = 0

Notice the quadratic terms 4m24m^2 cancel out:

−4m+17=0  ⟹  4m=17  ⟹  m=174-4m + 17 = 0 \implies 4m = 17 \implies m = \frac{17}{4}
  • Step 4: Verify non-zero leading coefficient: a=m−2=174−2=94≠0a = m - 2 = \frac{17}{4} - 2 = \frac{9}{4} \neq 0. The condition is satisfied.
  • Conclusion: The required value of mm is 174\frac{17}{4} (or 4.254.25).

Worked Example 3: Operational Optimization via Parabolic Extrema

Problem: In a fictional quadratic model, the hourly expenditure C(v)C(v) (in ₹) of hauling a freight rake over a 200 km railway sector varies with sectional speed vv (in km/h) according to the quadratic relation:

C(v)=2v2−160v+4500C(v) = 2v^2 - 160v + 4500

Find: (a) The optimal operational speed vv that minimizes hourly running costs, and (b) The minimum cost per hour.

  • Step 1: Identify the quadratic parameters: In C(v)=av2+bv+cC(v) = av^2 + bv + c, a=2a = 2, b=−160b = -160, and c=4500c = 4500. Since a=2>0a = 2 > 0, the parabola opens upward, confirming that the vertex represents an absolute minimum.
  • Step 2: Calculate the minimizing speed vv:
voptimal=−b2a=−−1602(2)=1604=40 km/hv_{\text{optimal}} = -\frac{b}{2a} = -\frac{-160}{2(2)} = \frac{160}{4} = 40 \text{ km/h}
  • Step 3: Compute the minimum hourly expenditure: Substitute v=40v = 40 into the cost function:
C(40)=2(40)2−160(40)+4500=2(1600)−6400+4500C(40) = 2(40)^2 - 160(40) + 4500 = 2(1600) - 6400 + 4500 C(40)=3200−6400+4500=−3200+4500=1300 INR/hourC(40) = 3200 - 6400 + 4500 = -3200 + 4500 = 1300 \text{ INR/hour}

Alternatively, use the vertex ordinate formula:

Cmin⁡=4ac−b24a=4(2)(4500)−(−160)24(2)=36000−256008=104008=1300 INR/hourC_{\min} = \frac{4ac - b^2}{4a} = \frac{4(2)(4500) - (-160)^2}{4(2)} = \frac{36000 - 25600}{8} = \frac{10400}{8} = 1300 \text{ INR/hour}
  • Conclusion: The optimal operating speed is 40 km/h with a minimum cost of ₹1,300 per hour.
Test Your Knowledge

For what value of the constant k does the quadratic equation 3x^2 - 12x + k = 0 possess real, rational, and equal roots?

A

8

B

10

C

12

D

16

Test Your Knowledge

What is the absolute maximum value attained by the quadratic function f(x) = -3x^2 + 18x - 15 across all real values of x?

A

12

B

15

C

9

D

18

Test Your Knowledge

If one real root of the quadratic equation x^2 - px + 8 = 0 is the square of the other root, and p is a real number, what is the value of p?

A

4

B

5

C

8

D

6

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