5.2 Linear Equations in One Variable
Key Takeaways
- A linear equation in one variable can be written as ax + b = c (a not zero); solve by isolating the variable through inverse operations in reverse order.
- When an equation has variables on both sides, move all variable terms to one side and constants to the other before dividing.
- Clearing fractions by multiplying every term by the LCD eliminates rational coefficients before isolating the variable.
- If variable terms cancel and leave a true statement, there are infinitely many solutions; a false statement means no solution.
- When solving a linear inequality, reverse the inequality symbol whenever multiplying or dividing both sides by a negative number.
Linear Equations in One Variable
Quick Answer: A linear equation in one variable can be written as
ax + b = c, wherea != 0. On the Florida Algebra 1 EOC, MA.912.AR.2.1 and AR.2.2 test your ability to write a linear equation from a real-world context, solve multi-step equations with variables on both sides and rational coefficients, and solve and graph one-variable linear inequalities.
Anatomy of a Linear Equation
A linear equation in one variable has a single variable raised only to the first power. The solution is the value of the variable that makes the equation true. Standard form: ax + b = c (or ax + b = cx + d when the variable appears on both sides).
| Form | Example | Solution Path |
|---|---|---|
| One-step | x + 7 = 12 | Subtract 7 |
| Two-step | 3x - 5 = 16 | Add 5, divide by 3 |
| Variables on both sides | 5x + 2 = 2x + 14 | Subtract 2x, subtract 2, divide by 3 |
| Rational coefficients | (1/2)x + (2/3) = (5/6)x | Multiply by LCD = 6 |
Solving Strategy: Undo in Reverse Order of Operations
The reliable strategy is to isolate the variable by performing inverse operations in reverse order:
- Clear parentheses using the distributive property.
- Clear fractions by multiplying both sides by the least common denominator (LCD).
- Combine like terms on each side.
- Move variable terms to one side.
- Move constants to the other side.
- Divide by the coefficient of the variable.
Worked example (rational coefficients): (1/2)x + (2/3) = (5/6)x.
- LCD of 2, 3, 6 is 6. Multiply each term by 6:
3x + 4 = 5x. Subtract 3x:4 = 2x. Divide by 2:x = 2.
Worked example (variables on both sides with distribution): 3(x - 4) = 2x + 5 - x.
- Distribute and combine on the right:
3x - 12 = x + 5. - Subtract x:
2x - 12 = 5. Add 12:2x = 17. Divide by 2:x = 8.5.
Writing Equations from Context
Florida items commonly present a word problem and ask students to write the equation before solving it. Translate phrases carefully:
| Phrase | Algebra |
|---|---|
| "Twice a number, decreased by 5" | 2x - 5 |
| "Three more than half a number" | (1/2)x + 3 |
| "Five less than twice a number equals the number plus 7" | 2x - 5 = x + 7 |
Worked example: A rental company charges a flat fee of $25 plus $0.40 per mile. A customer's total bill was $73. Write and solve an equation for miles driven.
- Equation:
25 + 0.40m = 73. Subtract 25:0.40m = 48. Divide by 0.40:m = 120miles.
Types of Solutions: One, None, Infinite
When the variable cancels out entirely, the equation has either no solution (contradiction) or infinitely many solutions (identity). Florida EOC items use these special cases as distractors.
- One solution: The variable has a unique value. Example:
2x + 3 = 11givesx = 4. - No solution: The equation reduces to a false statement. Example:
3(x + 2) = 3x + 7simplifies to6 = 7. Solution set is empty. - Infinite solutions: The equation reduces to a true statement. Example:
4x + 8 = 2(2x + 4)simplifies to8 = 8. Any real value of x works.
Exam trap: If your variable terms cancel and you get a numerical statement, do not write "x = 0." A true statement means infinite solutions; a false statement means no solution.
One-Variable Linear Inequalities
Solving a linear inequality follows the same procedure as solving an equation with one critical exception: when you multiply or divide both sides by a negative number, reverse the inequality symbol.
| Equation form | Inequality equivalent |
|---|---|
x + 4 > 10 | x > 6 |
-2x < 8 | x > -4 (divide by -2, flip sign) |
-(1/3)x >= 2 | x <= -6 (multiply by -3, flip sign) |
Worked example: -3(x - 2) >= 9 - 3x.
- Distribute:
-3x + 6 >= 9 - 3x. Add 3x:6 >= 9. This is false, so the inequality has no solution.
Graphing on a number line: Use an open circle for < or > (endpoint not included) and a closed circle for <= or >= (endpoint included). Shade the direction of the solution set.
Common Exam Traps
- Forgetting to flip the inequality sign when dividing by a negative. This is the single most tested inequality error.
- Distributing a negative coefficient incorrectly:
-2(x - 5) = -2x + 10, not-2x - 10. - Combining unlike terms when clearing parentheses:
3(x + 4) = 3x + 12, not3x + 4. - Treating "no solution" as
x = 0. Verify by substituting back into the original equation. - Misreading the question: "Write an equation" items ask for the equation itself, not the solution.
Real-World Inequality Context
Florida items often phrase inequalities as minimum or maximum thresholds. Example: A student needs at least 75 points on a final test to pass. The test has 20 questions worth 5 points each, and the student already earned 35 points. Let x = number of correct answers on the final:
- Inequality:
5x + 35 >= 75. Subtract 35:5x >= 40. Divide:x >= 8.
This pattern applies to minimum GPA requirements, spending limits, and speed thresholds — common EOC items.
Solve: 3(x - 4) = 2x + 5 - x.
Solve the inequality: -2x + 7 < 15.
A rental company charges a flat fee of $25 plus $0.40 per mile. A customer's total bill was $73. Which equation correctly represents the situation and gives the number of miles driven?