PracticeVideosBlogFlashcards

3.2 Bipolar Junction Transistors, FETs, and Operational Amplifiers

Key Takeaways

  • BJTs are current-controlled bipolar devices stabilized against thermal runaway (-2 mV/°C V_BE shift) via voltage divider bias with emitter degeneration; FETs are unipolar, voltage-controlled devices with near-infinite input impedance.

  • Monolithic integrated circuits fabricate active and passive components on a shared silicon substrate, providing thermal tracking, high component density, and reduced parasitic reactances.

  • An ideal op-amp has infinite open-loop gain and input impedance, and zero output impedance. In linear negative-feedback operation its input voltages are equal; the inverting input is a virtual ground when the non-inverting input is grounded.

  • Closed-loop op-amp topologies include the inverting amplifier (V_out = -(R_f / R_in) * V_in), non-inverting amplifier (V_out = (1 + R_f / R_1) * V_in), buffer (V_out = V_in), and summing amplifier for audio mixing.

  • Op-amp small-signal bandwidth is approximately GBWP divided by noise gain: 1 + R_f/R_in for an inverting stage. Slew rate limits sine-wave output to f_max = SR / (2πV_p).

Last updated: November 2026

3.2 Bipolar Junction Transistors, FETs, and Operational Amplifiers

Key Focus: Active semiconductor devices and integrated circuits provide signal amplification, mixing, buffering, and filtering across amateur equipment. Mastering current-controlled BJTs, voltage-controlled FETs, monolithic planar fabrication, and operational amplifier feedback topologies is vital for the ACMA Advanced Examination.


Bipolar Junction Transistors (BJTs) and Biasing Stability

A BJT has emitter (EE), base (BB) and collector (CC) regions. In forward-active operation, the base-emitter junction is forward biased and the collector-base junction reverse biased. For silicon, the forward junction voltage is commonly about 0.7 V at an illustrative operating current:

  • NPN: Base is positive relative to emitter; collector is normally above base. Conventional base/collector currents enter the device and emitter current leaves it. The emitter arrow points outward.
  • PNP: Bias polarities and conventional-current directions reverse: base is below emitter and collector below base. Current enters the emitter and leaves the collector/base. The emitter arrow points inward.

Using current magnitudes, IE=IB+ICI_E=I_B+I_C, β=IC/IB\beta=I_C/I_B and α=β/(β+1)\alpha=\beta/(\beta+1). A small base-current change controls a larger collector-current change; the actual gain depends on device and operating conditions.

Fundamental BJT Configurations and Thermal Stabilization

  • Common Emitter (CE): Input at base, output at collector. Provides high voltage and current gain with 180∘180^\circ phase inversion. At RF, collector-base capacitance (CcbC_{cb}) causes capacitive feedback (the Miller effect), limiting high-frequency bandwidth.
  • Common Collector (CC / Emitter Follower): Input at base, output at emitter. Delivers near-unity voltage gain (Av≈1A_v \approx 1), high input impedance, low output impedance, and zero phase shift, acting as an isolation buffer.
  • Common Base (CB): Input at emitter, output at collector. Provides unity current gain (α\alpha), high voltage gain, and low input impedance (20 Ω−50 Ω20\ \Omega - 50\ \Omega). Grounding the base shields the input from the output, eliminating the Miller effect in VHF/UHF preamplifiers.
  • Thermal Runaway Prevention: Base-emitter forward voltage possesses a negative temperature coefficient: ΔVBE/ΔT≈−2.0 mV/∘C\Delta V_{BE} / \Delta T \approx -2.0\text{ mV}/^\circ\text{C}. Rising temperatures decrease VBEV_{BE}, exponentially increasing IBI_B and ICI_C and risking destructive thermal runaway. Bias stability is achieved via voltage divider bias with an emitter degeneration resistor (RER_E). The divider holds VBV_B constant; as temperature increases IEI_E, the larger drop across RER_E forces VBE=VB−IEREV_{BE} = V_B - I_E R_E down, throttling base drive and stabilizing the QQ-point. An AC bypass capacitor (CEC_E) across RER_E prevents AC gain reduction.

Field Effect Transistors (FETs) and CMOS Architecture

Field Effect Transistors are voltage-controlled, unipolar devices: conduction occurs strictly via majority carriers flowing from Source (SS) to Drain (DD) through a channel modulated by the Gate (GG).

  • Junction FET (JFET): Employs a reverse-biased gate junction. For an N-channel JFET, normal gate bias has VGS≤0V_{GS}\le0; a P-channel device uses the opposite polarity. Above pinch-off (∣Vp∣|V_p|), drain current saturates at ID=IDSS(1−VGS/Vp)2I_D = I_{DSS}(1 - V_{GS}/V_p)^2.
  • MOSFETs: An ultra-thin silicon dioxide (SiO2\text{SiO}_2) layer insulates the gate (Zin>1014 ΩZ_{in} > 10^{14}\ \Omega), requiring ESD precautions. In depletion-mode, a channel exists at VGS=0 VV_{GS} = 0\text{ V}; An N-channel enhancement-mode device requires positive gate-to-source voltage above its threshold; a P-channel device requires the opposite polarity.
  • Dual-Gate MOSFETs: Feature two gates in series; Gate 1 receives RF while Gate 2 receives AGC bias or LO injection. Gate 2 acts as an electrostatic shield (Cgd<0.02 pFC_{gd} < 0.02\text{ pF}), allowing gain control without detuning tuned circuits.
  • CMOS Technology: Pairs complementary P-channel and N-channel MOSFETs. With one transistor always off in any static state, CMOS draws near-zero static DC power, consuming energy only during switching transitions (P=CV2fP = C V^2 f).
  • RF Power Devices: LDMOS devices operate at 50 V50\text{ V} rails with high gain and extreme mismatch tolerance (SWR >65:1> 65:1) for HF/VHF power amplifiers. GaN HEMTs exploit a wide bandgap (3.4 eV3.4\text{ eV}) for high efficiency into microwave bands.

FET Amplifier Configurations

“Common” identifies the terminal held at signal reference, which need not be DC ground. For ordinary voltage-amplifier arrangements:

FET stageSignal input/outputVoltage phaseInput impedanceOutput impedance
Common sourceGate / drainInvertingHighRelatively high
Common gateSource / drainNon-invertingLow, roughly 1/gm1/g_mRelatively high
Common drain (source follower)Gate / sourceNon-inverting, gain near but below 1HighLow, roughly 1/gm1/g_m

These correspond to common-emitter, common-base and emitter-follower BJT arrangements. Bias networks, loading, feedback and frequency alter the actual impedances; gate capacitance matters at RF.

Simple Integrated Circuits (ICs)

Monolithic integrated circuits fabricate active transistors, diodes, and resistors on a single monocrystalline silicon die using planar photolithography, diffusion, and metallization.

  • Key Advantages:
    1. Matched Thermal Characteristics: Nearby components on one die track temperature closely. Matched differential-pair transistors reduce input offset and its temperature drift; real ICs retain finite offset and drift.
    2. Miniaturization & Density: Concentrates complex circuits into compact packages with minimal weight.
    3. Reduced Parasitics: Microscopic interconnects minimize stray lead inductances and capacitances.
  • Linear vs Digital ICs:
    • Linear / Analogue ICs: Process continuous signals with proportional fidelity (e.g., op-amps, voltage regulators, RF mixers).
    • Digital ICs: Switch between discrete binary states (0 and 1) between saturation and cutoff (e.g., CMOS logic, microcontrollers, DDS chips).

Operational Amplifiers and the Golden Rules

An operational amplifier (op-amp) is a high-gain direct-coupled differential amplifier.

  • Ideal Characteristics: Infinite open-loop voltage gain (AOL→∞A_{OL} \to \infty), infinite input impedance (Zin→∞Z_{in} \to \infty), zero output impedance (Zout→0Z_{out} \to 0), infinite bandwidth, and zero input offset voltage/drift (Vos→0V_{os} \to 0, ΔVos/ΔT→0\Delta V_{os}/\Delta T \to 0).
  • The Two Golden Rules of Negative Feedback:
    1. Rule 1: Zero current flows into either input terminal (I+=I−=0I_+ = I_- = 0).
    2. Rule 2: Negative feedback drives differential input voltage to zero (V+=V−V_+ = V_-). Grounding the non-inverting input (V+=0 VV_+ = 0\text{ V}) forces the inverting terminal to become a virtual ground (V−=0 VV_- = 0\text{ V}).

Standard Op-Amp Topologies and Dynamic Limitations

  • Inverting Amplifier: Input connects through RinR_{in} to the inverting input with feedback resistor RfR_f. With the inverting terminal at virtual ground:
Vout=−(RfRin)VinandZin=RinV_{out} = -\left(\frac{R_f}{R_{in}}\right) V_{in} \quad \text{and} \quad Z_{in} = R_{in}
  • Non-Inverting Amplifier: Signal enters the non-inverting terminal (++) directly; R1R_1 and RfR_f form a feedback divider to (−-). With Zin→∞Z_{in} \to \infty:
Vout=(1+RfR1)VinV_{out} = \left(1 + \frac{R_f}{R_1}\right) V_{in}
  • Voltage Follower (Buffer): Direct output-to-inverting feedback (Rf=0R_f = 0): Vout=VinV_{out} = V_{in} (Av=1A_v = 1, high ZinZ_{in}, low ZoutZ_{out}).
  • Summing Amplifier: Multiple inputs sum into the inverting virtual ground node without crosstalk: Vout=−(Rf/R1⋅V1+Rf/R2⋅V2)V_{out} = -(R_f/R_1 \cdot V_1 + R_f/R_2 \cdot V_2), used in audio mixers and CTCSS encoders.
  • Difference Amplifier: Rejects common-mode hum and RF pickup across balanced lines: Vout=(Rf/R1)(V2−V1)V_{out} = (R_f/R_1)(V_2 - V_1), characterized by its Common-Mode Rejection Ratio (CMRR).
  • Active Filters: A second-order Sallen-Key low-pass stage rolls off at −12 dB/octave-12\text{ dB/octave}. Op-amp band-pass filters select SSB speech (300 Hz−2.8 kHz300\text{ Hz} - 2.8\text{ kHz}) or narrower CW audio bands without bulky inductors.
  • Comparator and Schmitt Trigger: Open-loop operation compares inputs, saturating to supply rails (±Vsat\pm V_{sat}). Adding positive feedback introduces hysteresis (VH=UTP−LTPV_H = \text{UTP} - \text{LTP}), eliminating chatter when squaring noisy signals.
  • Dynamic Limits:
    • Gain-Bandwidth Product (GBWP): For a dominant-pole voltage-feedback op-amp, fc≈GBWP/GNf_c \approx \text{GBWP}/G_N, where GNG_N is noise gain. An inverting stage has GN=1+Rf/RinG_N=1+R_f/R_{in}; a non-inverting stage has noise gain equal to its signal gain.
    • Slew Rate (SR): Maximum rate of output change (V/μs\text{V}/\mu\text{s}), restricting full-power bandwidth to fmax=SR/(2πVp)f_{\text{max}} = \text{SR} / (2 \pi V_p).

Circuit Topologies Comparison

TopologyVoltage Gain (AvA_v)Input Impedance (ZinZ_{in})Output Impedance (ZoutZ_{out})Key Amateur Application
Common EmitterHigh (inverted)Moderate (1−5 kΩ1 - 5\text{ k}\Omega)Moderate-HighAudio and IF amplification
Emitter Follower≈1\approx 1 (in-phase)High (20−500 kΩ20 - 500\text{ k}\Omega)Very Low (10−50 Ω10 - 50\ \Omega)VFO buffer, impedance matching
Inverting Op-Amp−Rf/Rin-R_f / R_{in}RinR_{in}Very Low (<1 Ω< 1\ \Omega)Audio preamplifiers
Non-Inverting Op-Amp1+Rf/R11 + R_f / R_1High (>109 Ω> 10^9\ \Omega)Very Low (<1 Ω< 1\ \Omega)Sensor interfaces
Op-Amp BufferUnity (11)High (>109 Ω> 10^9\ \Omega)Extremely Low (<0.1 Ω< 0.1\ \Omega)Filter and VFO isolation
Summing Op-Amp−∑(Rf/Rn)Vn-\sum (R_f/R_n) V_nRnR_n per channelVery Low (<1 Ω< 1\ \Omega)Audio mixers, CTCSS injection
Difference Op-Amp(Rf/R1)(V2−V1)(R_f/R_1)(V_2 - V_1)R1R_1Very Low (<1 Ω< 1\ \Omega)Balanced lines, noise rejection

Worked Engineering Calculations

Example 1: Op-Amp Audio Stage Gain and Bandwidth

Problem: An inverting op-amp stage has Rin=10 kΩR_{in} = 10\text{ k}\Omega and Rf=100 kΩR_f = 100\text{ k}\Omega, using an op-amp with GBWP=3.0 MHz\text{GBWP} = 3.0\text{ MHz} and SR=1.5 V/μs\text{SR} = 1.5\text{ V}/\mu\text{s}. Calculate the closed-loop gain (AvA_v), input impedance (ZinZ_{in}), −3 dB-3\text{ dB} bandwidth (fcf_c), and maximum peak voltage (VpV_p) at f=2.5 kHzf = 2.5\text{ kHz} without slew distortion.

Solution:

  1. Gain and Input Impedance:
Av=−RfRin=−100 kΩ10 kΩ=−10(∣Av∣=10)andZin=Rin=10 kΩA_v = -\frac{R_f}{R_{in}} = -\frac{100\text{ k}\Omega}{10\text{ k}\Omega} = -10 \quad (|A_v| = 10) \quad \text{and} \quad Z_{in} = R_{in} = 10\text{ k}\Omega
  1. Closed-Loop Bandwidth and Slew Limit:
GN=1+10010=11,fc≈GBWPGN=3,000,000 Hz11≈273 kHzG_N=1+\frac{100}{10}=11, \qquad f_c \approx \frac{\text{GBWP}}{G_N}=\frac{3,000,000\text{ Hz}}{11}\approx273\text{ kHz} Vp=SR2πf=1.5×106 V/s2×π×2,500 Hz≈95.5 VV_p = \frac{\text{SR}}{2 \pi f} = \frac{1.5 \times 10^6\text{ V/s}}{2 \times \pi \times 2,500\text{ Hz}} \approx 95.5\text{ V}

(Output swing is limited by the power rails rather than slew rate).


Example 2: BJT Voltage Divider Bias Operating Point (QQ-Point)

Problem: An NPN BJT (β=100\beta = 100, VBE=0.7 VV_{BE} = 0.7\text{ V}) is biased with VCC=12 VV_{CC} = 12\text{ V}, R1=33 kΩR_1 = 33\text{ k}\Omega, R2=10 kΩR_2 = 10\text{ k}\Omega, RC=2.2 kΩR_C = 2.2\text{ k}\Omega, and RE=680 ΩR_E = 680\ \Omega. Calculate VBV_B, ICI_C, and VCEV_{CE}.

Solution:

  1. Include Divider Loading: Replace the bias divider by its Thevenin equivalent:
VTH=121033+10=2.791 V,RTH=33×1033+10=7.674 kΩV_{TH}=12\frac{10}{33+10}=2.791\text{ V}, \qquad R_{TH}=\frac{33\times10}{33+10}=7.674\text{ k}\Omega

The base current causes a voltage drop across RTHR_{TH}. With IE=(β+1)IBI_E=(\beta+1)I_B:

IB=VTH−VBERTH+(β+1)RE=2.791−0.7007674+101×680≈27.38 μAI_B=\frac{V_{TH}-V_{BE}}{R_{TH}+(\beta+1)R_E}=\frac{2.791-0.700}{7674+101\times680}\approx27.38\ \mu\text{A} IC=βIB≈2.738 mA,VE=(β+1)IBRE≈1.881 V,VB=VE+0.700≈2.581 VI_C=\beta I_B\approx2.738\text{ mA}, \quad V_E=(\beta+1)I_BR_E\approx1.881\text{ V}, \quad V_B=V_E+0.700\approx2.581\text{ V}
  1. Collector-Emitter Voltage:
VC=12−(2.738 mA)(2.2 kΩ)≈5.976 VV_C=12-(2.738\text{ mA})(2.2\text{ k}\Omega)\approx5.976\text{ V} VCE=VC−VE≈5.976−1.881=4.096 VV_{CE}=V_C-V_E\approx5.976-1.881=4.096\text{ V}

The collector is above the base, consistent with forward-active NPN operation. Ignoring base current would be an approximation; here it substantially changes the calculated operating point.

Test Your Knowledge

An operational amplifier is connected in an inverting amplifier circuit with its non-inverting terminal tied to ground. Which condition explains why the inverting terminal is treated as a virtual ground?

A

Negative feedback forces the differential input voltage to zero while infinite input impedance prevents current from entering the input terminals

B

The internal compensation capacitor creates a physical low-impedance short circuit to ground at all frequencies

C

The inverting input conducts all signal current directly into the negative power supply rail

D

Positive feedback drives the open-loop gain to unity, clamping both input terminals to ground

Test Your Knowledge

What primary engineering advantage does monolithic planar IC fabrication provide for differential pairs in operational amplifiers compared to discrete transistor designs?

A

It eliminates the need for negative feedback by providing unconditional infinite bandwidth

B

It lowers the gate threshold voltage of all transistors to exactly zero volts

C

Nearby transistors on the same semiconductor die have closely matched characteristics and temperature tracking, reducing differential input offset and its drift

D

It replaces all passive resistors and capacitors with high-Q inductors directly on the silicon die

Test Your Knowledge

An operational amplifier has a Gain-Bandwidth Product (GBWP) of 4.0 MHz and a slew rate of 2.0 V/microsecond. If it is configured as a non-inverting amplifier with a closed-loop voltage gain of 20 (26 dB), what is the maximum small-signal bandwidth and what causes high-frequency large-signal distortion?

A

The bandwidth is 4.0 MHz, and distortion occurs when input impedance drops to zero

B

The bandwidth is 200 kHz, and distortion occurs when the output rate of change exceeds 2.0 V/microsecond

C

The bandwidth is 80 MHz, and distortion occurs due to avalanche breakdown in the feedback divider

D

The bandwidth is 20 kHz, and distortion occurs because the virtual ground disconnects under AC drive

Sections you finish are checked off in the contents.