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2.2 Series and Parallel LC Resonance and Q Factor

Key Takeaways

  • For ideal LL and CC, resonance occurs at XL=XCX_L=X_C and f0=1/(2πLC)f_0=1/(2\pi\sqrt{LC}). Series reactive voltages cancel; parallel reactive branch currents cancel.

  • A series resonant circuit exhibits minimum impedance (Z=RZ = R), maximum current flow, zero phase angle, and produces a voltage magnification across LL and CC equal to Q×VsourceQ \times V_{\text{source}}.

  • A parallel resonant circuit (tank) exhibits maximum dynamic resistance (Rp=L/(Crs)≈Q2rsR_p = L / (C r_s) \approx Q^2 r_s), draws minimum line current from the generator, and sustains a circulating current of Q×IlineQ \times I_{\text{line}}.

  • Circuit quality factor is Q=2π×Q=2\pi\times(maximum stored energy)/(energy dissipated per cycle). Loaded QLQ_L includes source and load losses and determines a simple resonator's half-power bandwidth, B=f0/QLB=f_0/Q_L.

  • In amateur radio equipment, resonant circuits provide preselection in receiver front ends, harmonic suppression and impedance matching in transmitter output stages, and frequency isolation in multiband antenna traps.

Last updated: November 2026

2.2 Series and Parallel LC Resonance and Q Factor

Resonance is the fundamental phenomenon underlying almost all frequency-selective radio frequency (RF) equipment. From antenna tuning units and transmitter power amplifiers to intermediate frequency (IF) filters and receiver preselectors, resonant LC circuits isolate desired signals from the electromagnetic spectrum while rejecting unwanted frequencies. A thorough mastery of series and parallel resonance, quality factor (QQ), and circuit bandwidth is vital for advanced amateur radio theory.


The Physical Condition for Resonance

At resonance, energy alternates between the inductor's magnetic field and the capacitor's electric field. In the ideal resonator their maximum stored energies are equal. Reactive voltages cancel in a series circuit; reactive branch currents cancel in a parallel circuit. For ideal LL and CC, both conditions give:

XL=XCX_L = X_C

Mathematical Derivation of the Thomson Resonant Frequency Formula

Substituting the definitions of inductive and capacitive reactance into the equilibrium condition:

2πf0L=12πf0C2\pi f_0 L = \frac{1}{2\pi f_0 C}

Multiplying both sides by f0f_0:

2πf02L=12πC2\pi f_0^2 L = \frac{1}{2\pi C}

Dividing both sides by 2πL2\pi L:

f02=14π2LCf_0^2 = \frac{1}{4\pi^2 LC}

Taking the square root of both sides yields the classical Thomson resonant frequency formula:

f0=12πLCf_0 = \frac{1}{2\pi \sqrt{LC}}

Expressed in terms of angular frequency (ω0=2πf0\omega_0 = 2\pi f_0):

ω0=1LC\omega_0 = \frac{1}{\sqrt{LC}}

At f0f_0, series LC reactances sum to zero, whereas parallel LC susceptances sum to zero. A series resonator therefore has low input impedance; a parallel resonator has high input impedance. Resistance limits these ideal responses.


Series Resonant Circuits: Low Impedance and Voltage Magnification

In a series resonant circuit, an alternating voltage source drives an inductor, capacitor, and equivalent series resistance (RR) connected in a single loop.

       Series Resonant Circuit
         +---[ L ]---[ C ]---[ R ]---+
         |                           |
         +----------( ~ )------------+
                    V_in

Impedance and Current Characteristics

The total impedance of the series circuit is:

Zs=R+j(XL−XC)Z_s = R + j(X_L - X_C)
  • At resonance (f=f0f = f_0): XL=XCX_L = X_C, so XL−XC=0X_L - X_C = 0. The impedance collapses to its theoretical minimum: Zs=RZ_s = R. The circuit is purely resistive, the phase angle between generator voltage and current is 0∘0^\circ, and circuit current reaches its absolute maximum:
Imax=VinRI_{\text{max}} = \frac{V_{\text{in}}}{R}
  • Below resonance (f<f0f < f_0): Capacitive reactance exceeds inductive reactance (XC>XLX_C > X_L). The circuit appears net capacitive; current leads applied voltage.
  • Above resonance (f>f0f > f_0): Inductive reactance exceeds capacitive reactance (XL>XCX_L > X_C). The circuit appears net inductive; current lags applied voltage.

Resonant Voltage Magnification

Because the series current at resonance is limited only by resistance RR, very large alternating currents can circulate through the inductor and capacitor. The voltage drops across LL and CC are:

VL=ImaxXL=(VinR)XL=(XLR)Vin=Q×VinV_L = I_{\text{max}} X_L = \left(\frac{V_{\text{in}}}{R}\right) X_L = \left(\frac{X_L}{R}\right) V_{\text{in}} = Q \times V_{\text{in}} VC=ImaxXC=(VinR)XC=(XCR)Vin=Q×VinV_C = I_{\text{max}} X_C = \left(\frac{V_{\text{in}}}{R}\right) X_C = \left(\frac{X_C}{R}\right) V_{\text{in}} = Q \times V_{\text{in}}

where Q=XL/RQ = X_L / R is the quality factor.

Warning

In high-Q circuits, VLV_L and VCV_C can reach dozens or hundreds of times the source voltage. If an amateur transmitter applies 50 V RMS50\text{ V RMS} across a series resonant circuit with Q=80Q = 80, the reactive voltage across the capacitor reaches VC=80×50 V=4000 V RMSV_C = 80 \times 50\text{ V} = 4000\text{ V RMS} (5.65 kV peak5.65\text{ kV peak}). This voltage magnification easily causes dielectric puncture and arc-over in capacitors unless properly rated components are used.

Although VLV_L and VCV_C are individually enormous, they are 180∘180^\circ out of phase with each other (+jVL+j V_L and −jVC-j V_C), cancelling at any instant across the combined LC pair: VL+VC=0V_L + V_C = 0.


Parallel Resonant Circuits (Tank Circuits): High Impedance and Circulating Current

A practical parallel resonant circuit, commonly termed a tank circuit, consists of an inductor with internal winding resistance rsr_s placed in parallel with a low-loss capacitor CC.

          I_line -->
    +---------------+------------+
    |               |            |
  ( ~ )           [ r_s ]       [ C ]
 V_line             |            |
    |             [ L ]          |
    |               |            |
    +---------------+------------+

Dynamic Resistance (RpR_p)

The total admittance of the practical parallel circuit is the sum of the inductive branch admittance and capacitive branch admittance:

Y=1rs+jωL+jωC=rs−jωLrs2+ω2L2+jωCY = \frac{1}{r_s + j\omega L} + j\omega C = \frac{r_s - j\omega L}{r_s^2 + \omega^2 L^2} + j\omega C

Grouping real and imaginary parts:

Y=rsrs2+ω2L2+j(ωC−ωLrs2+ω2L2)Y = \frac{r_s}{r_s^2 + \omega^2 L^2} + j\left(\omega C - \frac{\omega L}{r_s^2 + \omega^2 L^2}\right)

Resonance occurs when the imaginary susceptance term equals zero:

ω0C=ω0Lrs2+ω02L2  ⟹  rs2+ω02L2=LC\omega_0 C = \frac{\omega_0 L}{r_s^2 + \omega_0^2 L^2} \implies r_s^2 + \omega_0^2 L^2 = \frac{L}{C}

At this resonant frequency, the admittance is purely real: Y0=rs/(rs2+ω02L2)=rs/(L/C)=Crs/LY_0 = r_s / (r_s^2 + \omega_0^2 L^2) = r_s / (L/C) = C r_s / L. The equivalent parallel impedance, called the dynamic resistance (RpR_p or ZdynamicZ_{\text{dynamic}}), is the reciprocal of Y0Y_0:

Rp=LCrsR_p = \frac{L}{C r_s}

Recalling that Q≈ω0L/rsQ \approx \omega_0 L / r_s and ω02=1/(LC)\omega_0^2 = 1/(LC), dynamic resistance can be expressed directly in terms of quality factor:

Rp=Q2rs=QXL=QXCR_p = Q^2 r_s = Q X_L = Q X_C

Line Current vs. Circulating Tank Current

  • Impedance: At resonance, the parallel tank exhibits maximum impedance (Zp=RpZ_p = R_p). Below resonance it is inductive; above resonance it is capacitive (the exact inverse of the series resonant circuit).
  • Line Current (IlineI_{\text{line}}): The current drawn from the external generator reaches its minimum:
Iline=VlineRpI_{\text{line}} = \frac{V_{\text{line}}}{R_p}
  • Circulating Current (IcircI_{\text{circ}}): Energy bounces continuously between the magnetic field of LL and the electric field of CC. The internal circulating current is magnified by QQ:
Icirc=VlineXL=IlineRpXL=Iline(QXLXL)=Q×IlineI_{\text{circ}} = \frac{V_{\text{line}}}{X_L} = \frac{I_{\text{line}} R_p}{X_L} = I_{\text{line}} \left(\frac{Q X_L}{X_L}\right) = Q \times I_{\text{line}}

In a high-power transmitter delivering 1000 W1000\text{ W} into an antenna matching tank where Q=15Q = 15, circulating tank currents often reach 20 to 30 amperes RMS20\text{ to }30\text{ amperes RMS}. Tank coils must therefore be wound with heavy copper tubing or silver-plated wire to prevent destructive I2rsI^2 r_s heating.


Circuit Quality Factor (QQ)

The Quality Factor (QQ) is a dimensionless parameter quantifying the efficiency of an energy-storage element or resonant system:

Q=2π×Maximum Energy Stored per CycleEnergy Dissipated per CycleQ = 2\pi \times \frac{\text{Maximum Energy Stored per Cycle}}{\text{Energy Dissipated per Cycle}}

Formulas for Q in Idealized and Practical Configurations

Circuit TypeFormula for QQIn terms of Component Values
Series LC CircuitQ=XLR=XCRQ = \frac{X_L}{R} = \frac{X_C}{R}Q=ω0LR=1ω0CR=1RLCQ = \frac{\omega_0 L}{R} = \frac{1}{\omega_0 C R} = \frac{1}{R}\sqrt{\frac{L}{C}}
Parallel LC CircuitQ=RpXp=RpXLQ = \frac{R_p}{X_p} = \frac{R_p}{X_L}Q=Rpω0L=ω0CRp=RpCLQ = \frac{R_p}{\omega_0 L} = \omega_0 C R_p = R_p \sqrt{\frac{C}{L}}

Unloaded Q (Q0Q_0) vs. Loaded Q (QLQ_L)

In real RF hardware, we must distinguish between two operating conditions:

  1. Unloaded Q (Q0Q_0): The intrinsic quality factor of the isolated resonant components, governed almost exclusively by the AC resistance of the inductor (skin effect, core eddy currents, dielectric loss in coil formers):
Q0=ω0LrinternalQ_0 = \frac{\omega_0 L}{r_{\text{internal}}}

Typical unloaded Q0Q_0 values for well-constructed air-wound or toroidal RF inductors range from 150150 to 400400. 2. Loaded Q (QLQ_L): When the resonant circuit is connected to an external source resistance (RsR_s) and load resistance (RLR_L), these external resistances dissipate stored energy, shunting the tank and reducing the effective parallel resistance:

Rtotal=Rp∥Rs∥RLR_{\text{total}} = R_p \parallel R_s \parallel R_L QL=RtotalXLQ_L = \frac{R_{\text{total}}}{X_L}

Finite source and load resistances reduce RtotalR_{\text{total}} below RpR_p, so QL<Q0Q_L<Q_0. Choose loaded Q for the required bandwidth and matching conditions; there is no general 1010–2020 range for both transmitters and receivers. For example, a 455 kHz455\text{ kHz} resonator with 10 kHz10\text{ kHz} bandwidth needs QL=45.5Q_L=45.5.


Bandwidth and Selectivity: Half-Power (-3 dB) Points

The bandwidth (BB or Δf\Delta f) of a tuned circuit describes the frequency span across which the circuit delivers at least half its maximum power (or 1/2≈70.7%1/\sqrt{2} \approx 70.7\% of its peak voltage):

B=f2−f1=f0QLB = f_2 - f_1 = \frac{f_0}{Q_L}

where f1f_1 and f2f_2 are the lower and upper half-power (−3 dB-3\text{ dB}) cutoff frequencies:

f1≈f0−B2,f2≈f0+B2f_1 \approx f_0 - \frac{B}{2}, \quad f_2 \approx f_0 + \frac{B}{2}
Relative voltage
1.000 |                 * (f0)
      |              /     \
0.707 |-----------*-----------*---------  -3 dB
      |          /|           |\
      |         / |           | \
0     +-----------+-----+-----+--------> Frequency
                  f1    f0    f2
                  |<--- B --->|

Shape Factor

Selectivity describes a circuit's ability to discriminate between closely spaced frequencies. While −3 dB-3\text{ dB} bandwidth defines the passband width, the shape factor describes the steepness ("skirts") of the response curve:

Shape Factor=Bandwidth at −60 dBBandwidth at −6 dB\text{Shape Factor} = \frac{\text{Bandwidth at } -60\text{ dB}}{\text{Bandwidth at } -6\text{ dB}}

An ideal "brick-wall" filter exhibits a shape factor of 1.01.0. A single tuned LC tank has a poor shape factor (frequently exceeding 1515 to 2020), whereas multi-pole crystal or mechanical ladder filters achieve shape factors of 1.51.5 to 2.02.0.


Step-by-Step Worked Numerical Example: High-Frequency Tank Circuit

An amateur radio transmitter power amplifier uses an output tank circuit resonant on the 80-meter band at f0=3.65 MHzf_0 = 3.65\text{ MHz}. The tank uses an inductance of L=10.0 μHL = 10.0\ \mu\text{H} with a winding RF resistance of rs=2.50 Ωr_s = 2.50\ \Omega.

Step 1: Calculate the Required Resonating Capacitance (CC):

C=14π2f02L=14π2×(3.65×106)2×(10.0×10−6)≈1.901×10−10 F≈190.1 pFC = \frac{1}{4\pi^2 f_0^2 L} = \frac{1}{4\pi^2 \times (3.65 \times 10^6)^2 \times (10.0 \times 10^{-6})} \approx 1.901 \times 10^{-10}\text{ F} \approx 190.1\text{ pF}

Step 2: Calculate Inductive Reactance (XLX_L):

XL=2πf0L=2π×(3.65×106 Hz)×(10.0×10−6 H)≈229.3 ΩX_L = 2\pi f_0 L = 2\pi \times (3.65 \times 10^6\text{ Hz}) \times (10.0 \times 10^{-6}\text{ H}) \approx 229.3\ \Omega

Step 3: Determine the Unloaded Quality Factor (Q0Q_0) and Dynamic Resistance (RpR_p):

Q0=XLrs=229.3 Ω2.50 Ω≈91.72Q_0 = \frac{X_L}{r_s} = \frac{229.3\ \Omega}{2.50\ \Omega} \approx 91.72 Rp=Q02rs=(91.72)2×2.50 Ω≈21,031 Ω≈21.03 kΩR_p = Q_0^2 r_s = (91.72)^2 \times 2.50\ \Omega \approx 21,031\ \Omega \approx 21.03\text{ k}\Omega

Alternatively, verifying with L/(Crs)L / (C r_s):

Rp=10.0×10−6(1.901×10−10)×2.50≈21,041 Ω≈21.04 kΩR_p = \frac{10.0 \times 10^{-6}}{(1.901 \times 10^{-10}) \times 2.50} \approx 21,041\ \Omega \approx 21.04\text{ k}\Omega

Step 4: Calculate the Unloaded Bandwidth (B0B_0):

B0=f0Q0=3650 kHz91.72≈39.80 kHzB_0 = \frac{f_0}{Q_0} = \frac{3650\text{ kHz}}{91.72} \approx 39.80\text{ kHz}

Step 5: Determine Loaded Q (QLQ_L) and Loaded Bandwidth (BLB_L) when driving a 2500 Ω2500\ \Omega load:

Connecting a load of RL=2500 ΩR_L = 2500\ \Omega across the tank places RLR_L in parallel with RpR_p:

Rtotal=Rp∥RL=21,031×250021,031+2500=52,577,50023,531≈2234.4 ΩR_{\text{total}} = R_p \parallel R_L = \frac{21,031 \times 2500}{21,031 + 2500} = \frac{52,577,500}{23,531} \approx 2234.4\ \Omega QL=RtotalXL=2234.4 Ω229.3 Ω≈9.74Q_L = \frac{R_{\text{total}}}{X_L} = \frac{2234.4\ \Omega}{229.3\ \Omega} \approx 9.74 BL=f0QL=3650 kHz9.74≈374.7 kHzB_L = \frac{f_0}{Q_L} = \frac{3650\text{ kHz}}{9.74} \approx 374.7\text{ kHz}

External resistive loading broadens the bandwidth from 39.8 kHz39.8\text{ kHz} to 374.7 kHz374.7\text{ kHz}, illustrating how circuit loading directly governs operational selectivity.


Comparison Table: Series Resonance vs. Parallel Resonance

Feature / MetricSeries LC Resonant CircuitParallel LC (Tank) Circuit
Impedance at f0f_0Minimum (Zs=RZ_s = R, purely resistive)Maximum (Zp=Rp≈Q2rsZ_p = R_p \approx Q^2 r_s)
Circuit Current at f0f_0Maximum (I=Vsource/RI = V_{\text{source}} / R)Minimum from source (Iline=V/RpI_{\text{line}} = V / R_p)
Reactive QuantitiesXL=XC  ⟹  Xnet=0X_L = X_C \implies X_{\text{net}} = 0BL=BC  ⟹  Bnet=0B_L = B_C \implies B_{\text{net}} = 0
Phase Angle at f0f_00∘0^\circ (Voltage and current in phase)0∘0^\circ (Voltage and current in phase)
Frequency <f0< f_0Net capacitive (XC>XLX_C > X_L); current leadsNet inductive (IL>ICI_L > I_C); line current lags
Frequency >f0> f_0Net inductive (XL>XCX_L > X_C); current lagsNet capacitive (IC>ILI_C > I_L); line current leads
Magnification PhenomenonVoltage magnification: VL=VC=Q×VinV_L = V_C = Q \times V_{\text{in}}Current magnification: Icirc=Q×IlineI_{\text{circ}} = Q \times I_{\text{line}}
Quality Factor (QQ)Q=ω0LR=XLRQ = \frac{\omega_0 L}{R} = \frac{X_L}{R}Q=Rpω0L=RpXLQ = \frac{R_p}{\omega_0 L} = \frac{R_p}{X_L}
Primary HF ApplicationsNotch/wave traps, antenna loading coilsAmplifier plate/drain tanks, preselectors, VFOs

Practical Amateur Radio Applications

  1. Receiver Front-End Preselectors: Tuned parallel LC circuits installed between the antenna and the RF amplifier attenuate strong out-of-band signals (such as local AM broadcast stations), preventing front-end overload and intermodulation distortion.
  2. Transmitter Output Pi-Networks: Resonant tank circuits match the high output impedance of power amplifier devices (tubes or transistors) to standard 50 Ω50\ \Omega coaxial feedlines while attenuating second and higher harmonic emissions.
  3. Multiband Antenna Traps: Parallel LC traps embedded along a wire dipole or vertical element present a high impedance at higher band frequencies, effectively isolating the outer antenna sections, while acting as an inductive loading coil on lower frequencies.
  4. Variable Frequency Oscillators (VFO): High-QQ inductors combined with temperature-stable capacitors establish precise, low-phase-noise reference signals essential for stable radio reception and transmission.
Test Your Knowledge

A parallel resonant LC tank circuit operating at 7.05 MHz consists of a 5.0 μH inductor with an internal series winding resistance of 2.2 Ω and a resonating capacitor. What is the dynamic parallel resistance (R_p) of this tank circuit at resonance, and if the generator supplies a line current of 20 mA, what is the approximate circulating current within the tank?

A

R_p ≈ 2.2 Ω and circulating current is 20 mA

B

R_p ≈ 221 Ω and circulating current is 200 mA

C

R_p ≈ 4.88 kΩ and circulating current is 500 mA

D

R_p ≈ 22.3 kΩ and circulating current is 2.01 A

Test Your Knowledge

A series resonant circuit is connected to an RF generator supplying 12 V RMS at 10.1 MHz. The circuit has a total series resistance of 4.0 Ω and an inductive reactance of 240 Ω at resonance. What is the RMS RF voltage developed across the inductor at resonance?

A

720 V RMS

B

12 V RMS

C

48 V RMS

D

240 V RMS

Test Your Knowledge

An intermediate frequency (IF) band-pass filter LC tank in a superheterodyne receiver operates at a center frequency of 455 kHz. If the loaded quality factor (Q_L) of the stage is measured as 45.5, what is the half-power (-3 dB) bandwidth of the tuned circuit?

A

1.0 kHz

B

4.55 kHz

C

10.0 kHz

D

45.5 kHz

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