6.6 Linear Applications, Functions, and Graphs
Key Takeaways
- Linear applications and graphs carries 2 to 4 of the 20 QAS questions.
- In slope-intercept form the slope is the rate of change and the y-intercept is the starting or fixed value.
- Parallel lines share a slope; perpendicular lines have slopes that are negative reciprocals multiplying to negative one.
- A strict inequality graphs as a dashed boundary line and an inclusive one as a solid line.
- In context, interpreting the slope means naming its units, such as dollars per hour rather than simply the number.
From Algebra to Interpretation
Linear applications and graphs: Applying linear equations to real-life contexts, using elementary linear functions to describe relationships, and graphing linear equations in two variables, linear inequalities, parallel and perpendicular lines, and systems of equations.
This area carries 2 to 4 of the 20 QAS questions — tied for the largest single allocation on the test. The same content area appears again on the AAF test, so time invested here pays twice.
Forms of a Linear Equation
| Form | Equation | Best For |
|---|---|---|
| Slope-intercept | $y = mx + b$ | Graphing; reading rate and starting value |
| Point-slope | $y - y_1 = m(x - x_1)$ | Building an equation from a point and slope |
| Standard | $Ax + By = C$ | Intercepts; systems |
In $y = mx + b$: $m$ is the slope (rate of change) and $b$ is the $y$-intercept (value when $x = 0$).
Slope
| Slope | Line |
|---|---|
| Positive | rises left to right |
| Negative | falls left to right |
| Zero | horizontal ($y = c$) |
| Undefined | vertical ($x = c$) |
The ordering trap: subtract the coordinates in the same order in numerator and denominator. Using $y_2 - y_1$ over $x_1 - x_2$ produces the wrong sign.
Slope through $(2, -3)$ and $(6, 5)$: $m = \dfrac{5 - (-3)}{6 - 2} = \dfrac{8}{4} = 2$
Interpreting Slope in Context
This is what distinguishes an applications question from a pure algebra question. The answer is not a number — it is a number with units and meaning.
A plumber's charge is modeled by $C = 85 + 60h$, where $h$ is hours.
- Slope 60: the cost increases by $60 per additional hour.
- Intercept 85: the fixed call-out fee, charged even at zero hours.
A tank's volume is $V = 500 - 8t$, where $t$ is minutes.
- Slope −8: the tank loses 8 gallons per minute. The negative sign means decrease.
- Intercept 500: the initial volume.
A question asking "what does 8 represent" wants "the rate at which the tank drains, in gallons per minute" — not "the slope."
Writing an Equation From Context
A car rental costs $45 per day plus a flat $20 insurance charge. Write the cost C for d days.
Fixed value → intercept; per-unit value → slope:
$C = 45d + 20$
A membership costs $310 for 5 months and $490 for 9 months. Write the linear model.
Slope first:
$m = \dfrac{490 - 310}{9 - 5} = \dfrac{180}{4} = 45$ dollars per month
Then use point-slope with $(5, 310)$:
$y - 310 = 45(x - 5) \Rightarrow y = 45x + 85$
The $85$ is a one-time initiation fee. Check with the second point: $45(9) + 85 = 405 + 85 = 490$ ✓
Parallel and Perpendicular Lines
- Parallel: equal slopes, $m_1 = m_2$.
- Perpendicular: slopes are negative reciprocals, $m_1 \cdot m_2 = -1$.
A line perpendicular to $y = \tfrac{3}{4}x + 2$ has slope $-\tfrac{4}{3}$.
Flip the fraction and change the sign. Doing only one of the two is the standard error.
Special case: a horizontal line ($m = 0$) is perpendicular to a vertical line (undefined slope), even though their slopes cannot multiply to $-1$.
Find the line through $(4, 1)$ parallel to $y = -2x + 7$.
Parallel → $m = -2$. Point-slope: $y - 1 = -2(x - 4) \Rightarrow y = -2x + 9$.
Graphing Linear Inequalities
Three steps:
- Graph the boundary line as though the inequality were an equation.
- Dashed line for $<$ or $>$ (boundary excluded); solid for $\le$ or $\ge$ (boundary included).
- Shade the half-plane containing solutions — test $(0,0)$ when it is not on the line.
Graph $y > 2x - 3$.
Boundary $y = 2x - 3$, dashed. Test $(0,0)$: is $0 > 2(0) - 3 = -3$? Yes. Shade the side containing the origin — above the line.
When $y$ is isolated, $>$ shades above and $<$ shades below. But if you multiply or divide an inequality by a negative number, reverse the symbol — then re-check.
Systems of Linear Equations Graphically
The solution is the intersection point.
| Configuration | Solutions | Algebraic Sign |
|---|---|---|
| Lines cross once | Exactly one | Different slopes |
| Lines are parallel | None | Same slope, different intercepts |
| Lines coincide | Infinitely many | Same slope, same intercept |
How many solutions does this system have? $y = 3x - 4$ $6x - 2y = 8$
Rewrite the second: $-2y = -6x + 8 \Rightarrow y = 3x - 4$. Identical lines — infinitely many solutions.
The fast diagnostic is to put both equations in slope-intercept form and compare $m$ and $b$. Same $m$ and same $b$ means one line; same $m$ and different $b$ means no solution; different $m$ means exactly one.
Reading Graphs in Applied Items
Applied graph questions typically ask for one of four things:
- A value at a point — read the coordinate.
- A rate — compute the slope over an interval.
- An intercept meaning — the starting or break-even value.
- A comparison — which relationship grows faster (steeper slope).
Always read the axis labels and units first. A graph plotting thousands of dollars against months means a slope of 2 is $2,000 per month, and distractors are built from exactly that unit confusion.
A delivery service charges according to $C = 12 + 1.75m$, where m is miles. What does 1.75 represent?
Which line is perpendicular to $y = -\frac{2}{5}x + 4$?
How many solutions does this system have? $y = 4x + 1$ and $8x - 2y = 6$