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8.4 Right-Triangle Trigonometry, the Unit Circle, and Radian Measure

Key Takeaways

  • Right triangle trigonometric ratios define sine, cosine, and tangent as ratios of side lengths via SOH CAH TOA (sin θ = opp/hyp, cos θ = adj/hyp, tan θ = opp/adj), complemented by reciprocal ratios cosecant (csc θ = 1/sin θ), secant (sec θ = 1/cos θ), and cotangent (cot θ = 1/tan θ).

  • Special right triangles provide exact trigonometric values without a calculator: 45°-45°-90° triangles exhibit side ratios 1 : 1 : √2, and 30°-60°-90° triangles exhibit side ratios 1 : √3 : 2.

  • Radian measure relates angle size to arc length on a unit circle (360° = 2π rad); conversions require multiplying degrees by π/180°, enabling arc length calculation s = r·θ and sector area calculation A = (1/2)r²·θ (where θ is strictly in radians).

  • On the unit circle (x² + y² = 1), any angle θ corresponds to coordinates (cos θ, sin θ); the ASTC rule (All Students Take Calculus) identifies positive function signs across quadrants, paired with reference angles θ' in [0, π/2].

  • The fundamental Pythagorean identity sin²θ + cos²θ = 1 and its variants (1 + tan²θ = sec²θ, 1 + cot²θ = csc²θ) allow algebraic simplification of trigonometric expressions; sinusoidal graphs y = A·sin(B(x - C)) + D possess amplitude |A|, period T = 2π/B, horizontal phase shift C, and vertical midline y = D.

Last updated: August 2026

Trigonometric Ratios, Unit Circle, Radian Measure & Circles

Core Advanced Mathematics: Trigonometry on the ACCUPLACER Advanced Algebra and Functions (AAF) assessment links geometric right triangle side ratios, circular radian dynamics, unit circle coordinates across all four quadrants, fundamental Pythagorean identities, and periodic sinusoidal wave models. Mastery requires computing exact trigonometric ratios, executing angle and sector conversions, applying identities, and analyzing wave parameters.


Right Triangle Trigonometry (SOH CAH TOA) & Reciprocal Functions

In a right triangle with an acute angle θ\theta, side lengths are classified relative to θ\theta as the Opposite leg (OO), the Adjacent leg (AA), and the Hypotenuse (HH) (the side opposite the 90∘90^\circ right angle).

                    Right Triangle Trigonometry Reference
                                  ▲
                                 ╱│
                                ╱ │
                Hypotenuse (H) ╱  │ Opposite (O)
                              ╱   │
                             ╱    │
                            ╱ θ   │
                           ───────┴─
                             Adjacent (A)

Primary Trigonometric Ratios (SOH CAH TOA)

sin⁡θ=OppositeHypotenuse=OHcos⁡θ=AdjacentHypotenuse=AHtan⁡θ=OppositeAdjacent=OA\sin\theta = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{O}{H} \qquad \cos\theta = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{A}{H} \qquad \tan\theta = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{O}{A}

Reciprocal Trigonometric Ratios

Each primary ratio has a corresponding reciprocal trigonometric function:

csc⁡θ=HypotenuseOpposite=1sin⁡θsec⁡θ=HypotenuseAdjacent=1cos⁡θcot⁡θ=AdjacentOpposite=1tan⁡θ\csc\theta = \frac{\text{Hypotenuse}}{\text{Opposite}} = \frac{1}{\sin\theta} \qquad \sec\theta = \frac{\text{Hypotenuse}}{\text{Adjacent}} = \frac{1}{\cos\theta} \qquad \cot\theta = \frac{\text{Adjacent}}{\text{Opposite}} = \frac{1}{\tan\theta}

Co-Function Identities (Complementary Angles)

Because the two acute angles in a right triangle sum to 90∘90^\circ (or π2\frac{\pi}{2} radians), co-functions of complementary angles are equal:

  • sin⁡(90∘−θ)=cos⁡θ\sin(90^\circ - \theta) = \cos\theta and cos⁡(90∘−θ)=sin⁡θ\cos(90^\circ - \theta) = \sin\theta
  • tan⁡(90∘−θ)=cot⁡θ\tan(90^\circ - \theta) = \cot\theta and cot⁡(90∘−θ)=tan⁡θ\cot(90^\circ - \theta) = \tan\theta
  • sec⁡(90∘−θ)=csc⁡θ\sec(90^\circ - \theta) = \csc\theta and csc⁡(90∘−θ)=sec⁡θ\csc(90^\circ - \theta) = \sec\theta

Special Right Triangles & Exact Trigonometric Values

Exact trigonometric values for benchmark angles (30∘,45∘,60∘30^\circ, 45^\circ, 60^\circ) derive directly from two geometric special right triangles.

1. The 45∘−45∘−90∘45^\circ-45^\circ-90^\circ (π4−π4−π2\frac{\pi}{4}-\frac{\pi}{4}-\frac{\pi}{2}) Isosceles Right Triangle

  • Side Ratio: 1:1:21 : 1 : \sqrt{2} (Leg : Leg : Hypotenuse)
  • sin⁡45∘=12=22\sin 45^\circ = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}
  • cos⁡45∘=12=22\cos 45^\circ = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}
  • tan⁡45∘=11=1\tan 45^\circ = \frac{1}{1} = 1

2. The 30∘−60∘−90∘30^\circ-60^\circ-90^\circ (π6−π3−π2\frac{\pi}{6}-\frac{\pi}{3}-\frac{\pi}{2}) Scalene Right Triangle

  • Side Ratio: 1:3:21 : \sqrt{3} : 2 (Short Leg opposite 30∘30^\circ : Long Leg opposite 60∘60^\circ : Hypotenuse)
  • sin⁡30∘=12cos⁡30∘=32tan⁡30∘=13=33\sin 30^\circ = \frac{1}{2} \qquad \cos 30^\circ = \frac{\sqrt{3}}{2} \qquad \tan 30^\circ = \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3}
  • sin⁡60∘=32cos⁡60∘=12tan⁡60∘=31=3\sin 60^\circ = \frac{\sqrt{3}}{2} \qquad \cos 60^\circ = \frac{1}{2} \qquad \tan 60^\circ = \frac{\sqrt{3}}{1} = \sqrt{3}

Radian Measure, Arc Length & Sector Area

A radian is the measure of a central angle θ\theta that subtends a circular arc equal in length to the radius rr of the circle.

1 full revolution=360∘=2π radians  ⟹  180∘=π radians1\text{ full revolution} = 360^\circ = 2\pi\text{ radians} \implies 180^\circ = \pi\text{ radians}

Angle Conversion Formulas

  • Degrees to Radians: Multiply by π180∘\frac{\pi}{180^\circ} (e.g., 135∘×π180∘=3π4 rad135^\circ \times \frac{\pi}{180^\circ} = \frac{3\pi}{4}\text{ rad})
  • Radians to Degrees: Multiply by 180∘π\frac{180^\circ}{\pi} (e.g., 2π3 rad×180∘π=120∘\frac{2\pi}{3}\text{ rad} \times \frac{180^\circ}{\pi} = 120^\circ)

Circle Geometry Formulas with Radians

For a circle of radius rr with central angle θ\theta strictly measured in radians:

+-----------------------------------------------------------------------------------------+
|                         CIRCULAR SECTOR & ARC FORMULAS                                  |
+-----------------------+---------------------------------+-------------------------------+
| Geometric Measure     | Formula (θ in Radians)          | Formula (θ in Degrees)        |
+-----------------------+---------------------------------+-------------------------------+
| Arc Length (s)        | s = r · θ                       | s = (θ / 360°) · 2πr          |
| Sector Area (A)       | A = (1/2) · r² · θ              | A = (θ / 360°) · πr²          |
+-----------------------+---------------------------------+-------------------------------+

Worked Example: Arc Length and Sector Area

A circular sector in a circle of radius r=6 cmr = 6\text{ cm} is subtended by a central angle of 120∘120^\circ. Find the arc length ss and sector area AA.

  • Step 1 (Convert to radians): θ=120∘×π180∘=2π3 radians\theta = 120^\circ \times \frac{\pi}{180^\circ} = \frac{2\pi}{3}\text{ radians}.
  • Step 2 (Calculate arc length): s=r⋅θ=6×2π3=4π cm≈12.57 cms = r \cdot \theta = 6 \times \frac{2\pi}{3} = 4\pi\text{ cm} \approx 12.57\text{ cm}.
  • Step 3 (Calculate sector area): A=12r2θ=12(6)2(2π3)=12(36)(2π3)=18×2π3=12π cm2≈37.70 cm2A = \frac{1}{2} r^2 \theta = \frac{1}{2} (6)^2 \left(\frac{2\pi}{3}\right) = \frac{1}{2} (36) \left(\frac{2\pi}{3}\right) = 18 \times \frac{2\pi}{3} = 12\pi\text{ cm}^2 \approx 37.70\text{ cm}^2.

The Unit Circle & Quadrant Trigonometry

The Unit Circle is a circle centered at the origin (0,0)(0, 0) with a radius of exactly r=1r = 1, governed by the algebraic equation:

x2+y2=1x^2 + y^2 = 1

For any angle θ\theta drawn in standard position (vertex at origin, initial ray along positive xx-axis), the terminal ray intersects the unit circle at coordinates:

(x,y)=(cos⁡θ,sin⁡θ)andtan⁡θ=yx=sin⁡θcos⁡θ  (x≠0)(x, y) = (\cos\theta, \sin\theta) \quad \text{and} \quad \tan\theta = \frac{y}{x} = \frac{\sin\theta}{\cos\theta} \; (x \neq 0)
                                  The Unit Circle Quadrants
                                           y ▲ (0, 1) [90°, π/2]
                                             │
                         QUADRANT II         │         QUADRANT I
                         (-x, +y)            │         (+x, +y)
                         Sine & Csc (+)      │         ALL Functions (+)
                   [180°, π]                 │                 [0°, 0 rad]
             (-1, 0) ────────────────────────┼────────────────────────► (1, 0) x
                                             │                 [360°, 2π]
                         QUADRANT III        │         QUADRANT IV
                         (-x, -y)            │         (+x, -y)
                         Tan & Cot (+)       │         Cosine & Sec (+)
                                             │
                                           ▼ (0, -1) [270°, 3π/2]

Quadrant Signs Rule (ASTC: "All Students Take Calculus")

  • Quadrant I (0<θ<π20 < \theta < \frac{\pi}{2}): All trigonometric functions are positive.
  • Quadrant II (π2<θ<π\frac{\pi}{2} < \theta < \pi): Sine (and cosecant) are positive; cosine and tangent are negative.
  • Quadrant III (π<θ<3π2\pi < \theta < \frac{3\pi}{2}): Tangent (and cotangent) are positive; sine and cosine are negative.
  • Quadrant IV (3π2<θ<2π\frac{3\pi}{2} < \theta < 2\pi): Cosine (and secant) are positive; sine and tangent are negative.

Reference Angles (θ′\theta')

The reference angle θ′\theta' is the positive acute angle formed between the terminal side of θ\theta and the xx-axis:

Quadrant of θ\thetaReference Angle Formula (Degrees)Reference Angle Formula (Radians)
Quadrant Iθ′=θ\theta' = \thetaθ′=θ\theta' = \theta
Quadrant IIθ′=180∘−θ\theta' = 180^\circ - \thetaθ′=π−θ\theta' = \pi - \theta
Quadrant IIIθ′=θ−180∘\theta' = \theta - 180^\circθ′=θ−π\theta' = \theta - \pi
Quadrant IVθ′=360∘−θ\theta' = 360^\circ - \thetaθ′=2π−θ\theta' = 2\pi - \theta

Master Unit Circle Exact Values Reference Table

Angle (Degrees)Angle (Radians)QuadrantPoint Coordinates (x,y)=(cos⁡θ,sin⁡θ)(x, y) = (\cos\theta, \sin\theta)tan⁡θ=sin⁡θcos⁡θ\tan\theta = \frac{\sin\theta}{\cos\theta}
0∘0^\circ00Positive xx-axis(1,0)(1, 0)00
30∘30^\circπ6\frac{\pi}{6}Quadrant I(32,12)\left(\frac{\sqrt{3}}{2}, \frac{1}{2}\right)33\frac{\sqrt{3}}{3}
45∘45^\circπ4\frac{\pi}{4}Quadrant I(22,22)\left(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)11
60∘60^\circπ3\frac{\pi}{3}Quadrant I(12,32)\left(\frac{1}{2}, \frac{\sqrt{3}}{2}\right)3\sqrt{3}
90∘90^\circπ2\frac{\pi}{2}Positive yy-axis(0,1)(0, 1)Undefined
120∘120^\circ2π3\frac{2\pi}{3}Quadrant II(−12,32)\left(-\frac{1}{2}, \frac{\sqrt{3}}{2}\right)−3-\sqrt{3}
135∘135^\circ3π4\frac{3\pi}{4}Quadrant II(−22,22)\left(-\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)−1-1
150∘150^\circ5π6\frac{5\pi}{6}Quadrant II(−32,12)\left(-\frac{\sqrt{3}}{2}, \frac{1}{2}\right)−33-\frac{\sqrt{3}}{3}
180∘180^\circπ\piNegative xx-axis(−1,0)(-1, 0)00
210∘210^\circ7π6\frac{7\pi}{6}Quadrant III(−32,−12)\left(-\frac{\sqrt{3}}{2}, -\frac{1}{2}\right)33\frac{\sqrt{3}}{3}
225∘225^\circ5π4\frac{5\pi}{4}Quadrant III(−22,−22)\left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2}\right)11
240∘240^\circ4π3\frac{4\pi}{3}Quadrant III(−12,−32)\left(-\frac{1}{2}, -\frac{\sqrt{3}}{2}\right)3\sqrt{3}
270∘270^\circ3π2\frac{3\pi}{2}Negative yy-axis(0,−1)(0, -1)Undefined
300∘300^\circ5π3\frac{5\pi}{3}Quadrant IV(12,−32)\left(\frac{1}{2}, -\frac{\sqrt{3}}{2}\right)−3-\sqrt{3}
315∘315^\circ7π4\frac{7\pi}{4}Quadrant IV(22,−22)\left(\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2}\right)−1-1
330∘330^\circ11π6\frac{11\pi}{6}Quadrant IV(32,−12)\left(\frac{\sqrt{3}}{2}, -\frac{1}{2}\right)−33-\frac{\sqrt{3}}{3}

Fundamental Trigonometric Identities

Quotient & Reciprocal Identities

tan⁡θ=sin⁡θcos⁡θcot⁡θ=cos⁡θsin⁡θsec⁡θ=1cos⁡θcsc⁡θ=1sin⁡θ\tan\theta = \frac{\sin\theta}{\cos\theta} \qquad \cot\theta = \frac{\cos\theta}{\sin\theta} \qquad \sec\theta = \frac{1}{\cos\theta} \qquad \csc\theta = \frac{1}{\sin\theta}

The Three Pythagorean Identities

Substituting x=cos⁡θx = \cos\theta and y=sin⁡θy = \sin\theta into the unit circle equation x2+y2=1x^2 + y^2 = 1 establishes the primary Pythagorean Identity:

sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1

Dividing this equation by cos⁡2θ\cos^2\theta and sin⁡2θ\sin^2\theta respectively yields two secondary Pythagorean identities:

1+tan⁡2θ=sec⁡2θ1+cot⁡2θ=csc⁡2θ1 + \tan^2\theta = \sec^2\theta \qquad 1 + \cot^2\theta = \csc^2\theta

Worked Example: Simplifying an Identity Expression

Simplify the trigonometric expression: 1−cos⁡2θsin⁡θcos⁡θ\frac{1 - \cos^2\theta}{\sin\theta \cos\theta}.

  • Step 1 (Apply Pythagorean identity): Since sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1, we have 1−cos⁡2θ=sin⁡2θ1 - \cos^2\theta = \sin^2\theta.
  • Step 2 (Substitute and reduce): sin⁡2θsin⁡θcos⁡θ=sin⁡θcos⁡θ=tan⁡θ\frac{\sin^2\theta}{\sin\theta \cos\theta} = \frac{\sin\theta}{\cos\theta} = \tan\theta

Sinusoidal Functions & Their Graphs (Sine & Cosine)

Sinusoidal functions model periodic, oscillating phenomena (e.g., sound waves, tides, alternating current):

y=Asin⁡(B(x−C))+Dory=Acos⁡(B(x−C))+Dy = A \sin(B(x - C)) + D \quad \text{or} \quad y = A \cos(B(x - C)) + D

Sinusoidal Parameters Explained

  1. Amplitude (∣A∣|A|): Half the distance between the maximum and minimum values: Amplitude=∣A∣=ymax⁡−ymin⁡2\text{Amplitude} = |A| = \frac{y_{\max} - y_{\min}}{2} (If A<0A < 0, the graph is reflected vertically across its midline).
  2. Period (TT): The horizontal distance required to complete one full cycle: T=2πB  ⟺  B=2πTT = \frac{2\pi}{B} \iff B = \frac{2\pi}{T}
  3. Frequency (ff): Number of cycles completed per unit of xx: f=1T=B2πf = \frac{1}{T} = \frac{B}{2\pi}
  4. Phase Shift (CC): Horizontal translation (shifts right if C>0C > 0, left if C<0C < 0).
  5. Vertical Shift / Midline (y=Dy = D): The horizontal centerline of oscillation: Midline y=D=ymax⁡+ymin⁡2\text{Midline } y = D = \frac{y_{\max} + y_{\min}}{2}

Parent Graphs Comparison: sin⁡(x)\sin(x) vs. cos⁡(x)\cos(x)

Featurey=sin⁡(x)y = \sin(x)y=cos⁡(x)y = \cos(x)
yy-Intercept(0,0)(0, 0) (starts on midline)(0,1)(0, 1) (starts at maximum peak)
Period2π2\pi2π2\pi
Amplitude1111
Domain / Range(−∞,∞)(-\infty, \infty) / [−1,1][-1, 1](−∞,∞)(-\infty, \infty) / [−1,1][-1, 1]
Five Key Points(0,0)→(π2,1)→(π,0)→(3π2,−1)→(2π,0)(0,0) \to (\frac{\pi}{2},1) \to (\pi,0) \to (\frac{3\pi}{2},-1) \to (2\pi,0)(0,1)→(π2,0)→(π,−1)→(3π2,0)→(2π,1)(0,1) \to (\frac{\pi}{2},0) \to (\pi,-1) \to (\frac{3\pi}{2},0) \to (2\pi,1)
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Unit Circle Quadrant Signs & Reference Angles Guide
Test Your Knowledge

What is the exact value of cos⁡(5π6)\cos\left(\frac{5\pi}{6}\right)?

A

−32-\frac{\sqrt{3}}{2}

B

−12-\frac{1}{2}

C

32\frac{\sqrt{3}}{2}

D

−22-\frac{\sqrt{2}}{2}

Test Your Knowledge

A circle has a radius of 8 cm8\text{ cm}. A central angle intercepts an arc of length 12π cm12\pi\text{ cm}. What is the area of the circular sector bounded by this central angle?

A

24π cm224\pi\text{ cm}^2

B

96π cm296\pi\text{ cm}^2

C

36π cm236\pi\text{ cm}^2

D

48π cm248\pi\text{ cm}^2

Test Your Knowledge

A sinusoidal wave is modeled by the function y=−4cos⁡(3x−π)+2y = -4\cos(3x - \pi) + 2. What are the amplitude, period, and midline equation of this function?

A

Amplitude=4,  Period=3π,  Midline: y=−2\text{Amplitude} = 4, \; \text{Period} = 3\pi, \; \text{Midline: } y = -2

B

Amplitude=−4,  Period=2π3,  Midline: y=2\text{Amplitude} = -4, \; \text{Period} = \frac{2\pi}{3}, \; \text{Midline: } y = 2

C

Amplitude=4,  Period=2π3,  Midline: y=2\text{Amplitude} = 4, \; \text{Period} = \frac{2\pi}{3}, \; \text{Midline: } y = 2

D

Amplitude=8,  Period=2π3,  Midline: y=2\text{Amplitude} = 8, \; \text{Period} = \frac{2\pi}{3}, \; \text{Midline: } y = 2

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