6.2 Exponents, Radicals, and Scientific Notation

Key Takeaways

  • Exponents accounts for 2 to 3 of the 20 QAS questions, roughly 10 to 15 percent of the test.
  • Multiplying like bases adds exponents and dividing subtracts them; raising a power to a power multiplies them.
  • A negative exponent means the reciprocal, so x to the negative n equals 1 over x to the n.
  • A fractional exponent is a radical: x to the m over n is the nth root of x to the m.
  • Any nonzero base raised to the zero power equals 1, which is the most commonly missed single fact in this area.
Last updated: August 2026

A Named QAS Content Area

The Quantitative Reasoning, Algebra, and Statistics test lists ten content areas. Exponents is one of them, carrying 2 to 3 of the 20 questions:

Exponents: Calculating with exponents, radicals, fractional exponents, and applying scientific notation.

Four distinct competencies in one line. Each is treated below.

The Exponent Laws

LawRuleExample
Product$x^a \cdot x^b = x^{a+b}$$x^3 \cdot x^5 = x^8$
Quotient$x^a \div x^b = x^{a-b}$$x^7 \div x^2 = x^5$
Power of a power$(x^a)^b = x^{ab}$$(x^3)^4 = x^{12}$
Power of a product$(xy)^a = x^a y^a$$(2x)^3 = 8x^3$
Power of a quotient$(x/y)^a = x^a / y^a$$(x/3)^2 = x^2/9$
Zero exponent$x^0 = 1$, $x \neq 0$$47^0 = 1$
Negative exponent$x^{-a} = 1/x^a$$2^{-3} = 1/8$

The Two Most Common Errors

Adding exponents when multiplying bases, not powers. The product rule applies only to like bases:

$x^3 \cdot y^4$ does not simplify. Different bases. $2^3 \cdot 2^4 = 2^7 = 128$. ✓

Assuming $x^0 = 0$. It equals 1. This follows from the quotient rule: $x^3 \div x^3 = x^0$, and any nonzero quantity divided by itself is 1.

Power of a Product Includes the Coefficient

$(3x^2)^3 = 3^3 \cdot x^{2 \cdot 3} = 27x^6$

Students routinely produce $3x^6$, forgetting that the exponent applies to the coefficient too.

Negative Exponents

A negative exponent signals a reciprocal, not a negative value:

$2^{-3} = \dfrac{1}{2^3} = \dfrac{1}{8}$

$2^{-3}$ is positive. It is small, not negative.

Moving a factor across the fraction bar flips the sign of its exponent:

$\dfrac{x^{-2}}{y^{-3}} = \dfrac{y^3}{x^2}$

Fractional Exponents and Radicals

The bridge between exponents and roots:

$x^{1/n} = \sqrt[n]{x}$ and $x^{m/n} = \sqrt[n]{x^m} = \left(\sqrt[n]{x}\right)^m$

The denominator is the root; the numerator is the power.

$8^{2/3} = \left(\sqrt[3]{8}\right)^2 = 2^2 = 4$

Taking the root first keeps the numbers small — always preferable to computing $8^2 = 64$ and then finding $\sqrt[3]{64}$.

$16^{3/4} = \left(\sqrt[4]{16}\right)^3 = 2^3 = 8$

Simplifying Radicals

Extract perfect-square factors:

$\sqrt{72} = \sqrt{36 \cdot 2} = 6\sqrt{2}$

Find the largest perfect square that divides the radicand. Using $\sqrt{4 \cdot 18} = 2\sqrt{18}$ is correct but not fully simplified, since 18 still contains a factor of 9.

Perfect squares to recognize on sight: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144.

Radical Arithmetic

  • Multiply: $\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$, so $\sqrt{6} \cdot \sqrt{10} = \sqrt{60} = 2\sqrt{15}$
  • Add/subtract: only like radicals combine, exactly as with like terms. $3\sqrt{5} + 2\sqrt{5} = 5\sqrt{5}$, but $\sqrt{2} + \sqrt{3}$ does not simplify.

A frequent error: $\sqrt{a + b} \neq \sqrt{a} + \sqrt{b}$. Check with numbers: $\sqrt{9 + 16} = \sqrt{25} = 5$, but $\sqrt{9} + \sqrt{16} = 3 + 4 = 7$. Not equal.

Rationalizing a Denominator

$\dfrac{6}{\sqrt{3}} = \dfrac{6}{\sqrt{3}} \cdot \dfrac{\sqrt{3}}{\sqrt{3}} = \dfrac{6\sqrt{3}}{3} = 2\sqrt{3}$

Order of Operations With Exponents

Exponents sit above multiplication and division in the order of operations, which produces results that surprise students working quickly.

$3 \cdot 2^4 = 3 \cdot 16 = 48$, not $6^4$.

The exponent binds only to the 2. To raise the whole product, parentheses are required: $(3 \cdot 2)^4 = 6^4 = 1296$.

The same principle governs signs:

ExpressionValueWhy
$(-4)^2$16The parentheses include the sign in the base
$-4^2$−16The exponent binds to 4; the negative applies afterward
$(-2)^3$−8An odd power preserves a negative base
$-2^3$−8Same value here, but for a different reason

That third and fourth row coincide by accident. With an even exponent they diverge sharply, which is exactly where test items are built.

Negative bases follow a parity rule: a negative base raised to an even power is positive; raised to an odd power it stays negative.

(3)4=81qquad(3)5=243(-3)^4 = 81 \\qquad (-3)^5 = -243

Exponents Inside Fractions

When a quotient of like bases has the larger exponent in the denominator, the result is a negative exponent — that is, a fraction:

fracx2x6=x26=x4=frac1x4\\frac{x^2}{x^6} = x^{2-6} = x^{-4} = \\frac{1}{x^4}

Both forms are correct, but answer choices usually prefer the form with no negative exponents, so convert before matching.

Scientific Notation

A number in scientific notation is written $a \times 10^n$ where $1 \le |a| < 10$ and $n$ is an integer.

$4{,}730{,}000 = 4.73 \times 10^6$ $0.000082 = 8.2 \times 10^{-5}$

The exponent counts decimal-point moves: right-to-left moves give a positive exponent; left-to-right moves give a negative one.

Arithmetic in Scientific Notation

Multiplication — multiply the coefficients, add the exponents:

$(3.0 \times 10^4)(2.0 \times 10^3) = 6.0 \times 10^7$

Division — divide the coefficients, subtract the exponents:

$\dfrac{8.4 \times 10^9}{2.1 \times 10^4} = 4.0 \times 10^5$

Renormalizing. If the coefficient falls outside $[1, 10)$, adjust:

$(5.0 \times 10^3)(4.0 \times 10^6) = 20.0 \times 10^9 = 2.0 \times 10^{10}$

Addition and subtraction require matching exponents first:

$3.2 \times 10^5 + 4.0 \times 10^4 = 3.2 \times 10^5 + 0.4 \times 10^5 = 3.6 \times 10^5$

This is the step most often skipped, and it produces answers off by an order of magnitude — which is exactly what the distractors are built to catch.

Test Your Knowledge

Simplify $(2x^3)^4$.

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Test Your Knowledge

Evaluate $27^{2/3}$.

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Test Your Knowledge

Compute $2.4 \times 10^6 + 3.0 \times 10^5$ and express the result in scientific notation.

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