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Sample PEC EPE Mechatronics Practice Questions

Try these sample questions to review concepts for the PEC EPE Mechatronics exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1An ideal operational amplifier is connected in an inverting configuration with an input resistor R_in = 10 kΩ and a feedback resistor R_f = 100 kΩ. If a DC input voltage of +0.40 V is applied to the input terminal, what is the output voltage V_out?
A.+4.00 V
B.-4.00 V
C.-0.40 V
D.+0.04 V
Explanation: For an ideal inverting operational amplifier, the closed-loop voltage gain is given by Av = -R_f / R_in = -100 kΩ / 10 kΩ = -10. Multiplying this gain by the input voltage yields V_out = Av * V_in = (-10) * (+0.40 V) = -4.00 V. The virtual ground at the inverting input terminal enforces zero volts at that summing junction.
2A non-inverting op-amp has R_f = 39 kΩ, R_1 = 1 kΩ, and gain-bandwidth product 4 MHz. Assuming a dominant single-pole response and negligible loading, what is its approximate closed-loop -3 dB bandwidth?
A.25 kHz
B.50 kHz
C.100 kHz
D.400 kHz
Explanation: The closed-loop voltage gain of a non-inverting op-amp is Av = 1 + (R_f / R_1) = 1 + (39 kΩ / 1 kΩ) = 40. Because the gain-bandwidth product is constant for internally compensated op-amps, the -3 dB bandwidth is BW = GBWP / Av = 4.0 MHz / 40 = 100 kHz. Higher closed-loop gain directly trades off against operational bandwidth.
3A second-order Sallen-Key low-pass section has equal resistors 10 kΩ and equal capacitors 15.9 nF. What is its pole natural frequency f0 = 1/(2πRC), which need not equal its -3 dB frequency?
A.1.0 kHz
B.6.28 kHz
C.15.9 kHz
D.100 Hz
Explanation: The pole natural frequency is f0=1/(2πRC)=1/(2π × 10000 × 15.9 × 10^-9) ≈ 1001 Hz, or 1.0 kHz. The -3 dB frequency also depends on Q. An ideal second-order low-pass section approaches a -40 dB/decade high-frequency slope.
4A complementary push-pull stage uses ±15 V supplies and an 8 Ω resistive load. Neglect bias current and use the ideal Class-B power model. At 12 V peak sinusoidal output, what is the combined output-transistor dissipation?
A.14.32 W
B.9.00 W
C.7.16 W
D.5.32 W
Explanation: The average AC load power is P_load = V_p^2 / (2 * R_L) = (12.0)^2 / (2 * 8.0) = 144 / 16 = 9.00 W. The total DC power drawn from both ±V_cc supplies is P_dc = (2 / π) * (V_cc * V_p / R_L) = (2 / 3.1416) * (15 * 12 / 8) = 0.6366 * 22.5 = 14.32 W. Transistor power dissipation is the difference: P_diss = P_dc - P_load = 14.32 W - 9.00 W = 5.32 W (shared equally at 2.66 W each).
5To determine the Thévenin equivalent resistance R_th looking into a linear resistive network with independent sources only, how should the independent voltage and current sources be deactivated?
A.Open-circuit all independent voltage sources and short-circuit all independent current sources
B.Short-circuit all independent voltage sources and open-circuit all independent current sources
C.Replace all independent voltage and current sources with 1 Ω precision resistors
D.Ground both terminals of all independent voltage and current sources simultaneously
Explanation: To deactivate independent sources, their source values are set to zero. Setting an independent voltage source to zero volts (V = 0) creates an ideal short circuit, while setting an independent current source to zero amperes (I = 0) creates an ideal open circuit. The remaining passive resistor network is then simplified to find R_th.
6What is the steady-state phase shift introduced by a passive first-order RC low-pass filter at its half-power corner frequency f_c = 1 / (2πRC)?
A.0°
B.-90°
C.-45°
D.+45°
Explanation: The frequency response transfer function of a first-order RC low-pass filter is H(jω) = 1 / (1 + j(ω/ω_c)). The phase angle is θ(ω) = -arctan(ω / ω_c). At the corner frequency ω = ω_c, θ(ω_c) = -arctan(1) = -45° (-π/4 rad). The output sinusoid lags the input sinusoid by exactly 45 degrees.
7An n-channel enhancement-mode MOSFET has a threshold voltage V_th = 1.0 V and transconductance parameter k'*(W/L) = 2.0 mA/V^2. If the gate-to-source voltage is V_gs = 3.0 V and the drain-to-source voltage is V_ds = 5.0 V, what is the drain current I_d (neglecting channel length modulation)?
A.4.0 mA
B.8.0 mA
C.2.0 mA
D.16.0 mA
Explanation: First, evaluate the operating region: V_gs - V_th = 3.0 V - 1.0 V = 2.0 V. Since V_ds (5.0 V) ≥ V_gs - V_th (2.0 V) and V_gs > V_th, the transistor operates in the saturation (active) region. The saturation drain current is I_d = 0.5 * k'*(W/L) * (V_gs - V_th)^2 = 0.5 * 2.0 mA/V^2 * (2.0 V)^2 = 1.0 * 4.0 = 4.0 mA.
8A small-signal common-emitter BJT amplifier has a quiescent collector current I_c = 2.6 mA and a collector load resistor R_c = 2.0 kΩ connected in parallel with an AC load resistor R_L = 2.0 kΩ. If the emitter resistor is completely bypassed by a large capacitor and thermal voltage V_t = 26 mV, what is the small-signal voltage gain A_v?
A.-200
B.-50
C.-10
D.-100
Explanation: Transconductance is g_m = I_c / V_t = 2.6 mA / 26 mV = 0.10 A/V (100 mS). The total AC collector resistance is r_out = R_c || R_L = (2.0 kΩ * 2.0 kΩ) / (2.0 kΩ + 2.0 kΩ) = 1.0 kΩ = 1000 Ω. The small-signal voltage gain with a bypassed emitter is A_v = -g_m * (R_c || R_L) = -0.10 S * 1000 Ω = -100.
9A single-phase full-wave bridge rectifier is supplied by a 230 V_rms, 50 Hz AC utility mains. What is the fundamental ripple frequency present at the output of the rectifier prior to filtering?
A.50 Hz
B.100 Hz
C.25 Hz
D.200 Hz
Explanation: In a full-wave rectifier, both the positive and negative half-cycles of the AC input waveform are converted into positive output pulses across the load. Therefore, there are two conduction pulses per cycle of input mains, producing a fundamental ripple frequency f_ripple = 2 * f_in = 2 * 50 Hz = 100 Hz.
10A Zener diode voltage regulator uses a 5.1 V Zener diode and a current-limiting series resistor R_s = 200 Ω. If the unregulated input voltage varies between 9.0 V and 12.0 V while the load draws a constant current of 15.0 mA, what is the minimum current I_z,min flowing through the Zener diode?
A.19.5 mA
B.15.0 mA
C.4.5 mA
D.1.5 mA
Explanation: The minimum Zener current occurs at the minimum unregulated input voltage V_in,min = 9.0 V. The total current supplied through the series resistor is I_s = (V_in,min - V_z) / R_s = (9.0 V - 5.1 V) / 200 Ω = 3.9 V / 200 Ω = 19.5 mA. By Kirchhoff's Current Law, I_z,min = I_s - I_load = 19.5 mA - 15.0 mA = 4.5 mA, ensuring the Zener remains safely in breakdown regulation.

About the PEC EPE Mechatronics Exam

Mechatronics Engineering is a named PEC EPE discipline for Registered Engineers progressing toward Professional Engineer registration. OpenExamPrep provides independent English-language MCQ study on circuits, mechanics, instrumentation, controls, robotics, machine vision, and embedded systems. This collection is topic practice and does not reproduce every official syllabus outcome or a full examination paper.

Exam sponsor: Pakistan Engineering Council (PEC). The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

Part-I closed-book MCQs, 2 hours; 90-minute break; Part-II open-book MCQs, 3 hours. The syllabus lists one Mechatronics Depth area, not separate sensor, robotics, or embedded Depth choices. No additional mandatory EPE assignment, oral, practical, or case-study component is listed.

Time Limit

3 hours (Part-II); 2 hours (Part-I), with a 90-minute break

Passing Score

60% in each part independently

Exam / Certification Fees

Rs. 5,000 new candidate; Rs. 2,500 single-part reappearance, plus bank charges

Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Official sources

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

10% of official Breadth

Mathematics

Calculus, linear algebra, transforms, and differential equations.

30% of official Breadth

Electrical/electronics and instrumentation

Circuit analysis, electronic circuits, instrumentation, and measurements.

30% of official Breadth

Computing and embedded systems

Digital logic, programming, data structures, object-oriented programming, and microcontrollers.

30% of official Breadth

Mechanics and design

Statics, dynamics, and strength of materials. Breadth totals 25 MCQs.

35 of 60 official Part-II MCQs

Mechatronics Depth

Power electronics, control, robotics, machine vision, actuation, modeling/simulation, system design, and machine design.

Preparing for the PEC EPE Mechatronics Exam

What You Need to Know

  • Passing score: 60% in each part independently
  • Assessment: Part-I closed-book MCQs, 2 hours; 90-minute break; Part-II open-book MCQs, 3 hours. The syllabus lists one Mechatronics Depth area, not separate sensor, robotics, or embedded Depth choices. No additional mandatory EPE assignment, oral, practical, or case-study component is listed.
  • Time limit: 3 hours (Part-II); 2 hours (Part-I), with a 90-minute break
  • Exam / certification fees: Rs. 5,000 new candidate; Rs. 2,500 single-part reappearance, plus bank charges Official sources

Using Our Practice Resources

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

PEC EPE Mechatronics: Suggested Study Strategy

1Review the full Breadth and single Mechatronics Depth outline rather than treating robotics as a separate paper.
2State model assumptions before applying stability, scheduling, and sensor formulas.
3Use the applicable edition and device documentation for PLC languages, safety categories, and communication interfaces.

Frequently Asked Questions

How is this practice inventory distributed?

The 100 items contain 42 Breadth/foundation and 58 Depth items, approximating the general 25/35 split. Categories are 15 circuits, 15 mechanics/fluids, 10 foundational computing/embedded, 2 mathematics, 20 sensors/actuators, 18 control, 15 robotics/automation, 3 applied embedded, and 2 vision items. Overlapping topics are assigned editorially. These are study counts, not official subdomain percentages; use the full syllabus to address remaining mathematics, programming, power electronics, vision, and design outcomes.

What is the official assessment language?

The official materials reviewed are in English, but current sources do not separately confirm assessment-language options. This bank is English-language independent study material, not an official translation.

Is there an additional mandatory robotics practical or oral exam?

The published EPE assessment has two MCQ parts and does not list a separate mandatory practical, oral, assignment, or case-study component. Relevant practice and CPD are eligibility requirements.

What resources may I bring to Part-II?

Bound textbooks, reference books, and standards are permitted under PEC's guidelines. Loose notes, laptops, and prohibited electronic devices are not permitted. Follow the current candidate instructions for identification and calculator requirements.