PracticeVideosBlogFlashcardsEspañol
All Practice Exams

Free Practice Questions for EGEL Plus Ingeniería Química

Exam-style questions and explanations by OpenExamPrep.

✓ No registration✓ No credit card
100+ Questions
100% Free

Loading practice questions...

Same family resources

Explore More Ceneval EGEL Plus Licenciatura Exit Examinations (Mexico)

Continue into nearby exams from the same family. Each card keeps practice questions, study guides, flashcards, videos, and articles in one place.

CENEVAL EGEL Plus Administración (EGEL Plus ADMON)

Practice Questions

CENEVAL EGEL Plus Comercio/Negocios Internacionales (EGEL Plus CNI)

Practice Questions

CENEVAL EGEL Plus Arquitectura (EGEL Plus ARQUI)

Practice Questions

CENEVAL EGEL Plus Mercadotecnia (EGEL Plus MERCA)

Practice Questions

CENEVAL EGEL Plus Turismo (EGEL Plus TUR)

Practice Questions

CENEVAL EGEL Plus Contaduría (EGEL Plus CONTA)

Practice Questions
Exam Review

Key Facts: EGEL Plus Ingeniería Química Exam

190

Total items on the official EGEL Plus IQUIM (130 disciplinary + 60 transversal)

Ceneval, Guía para el sustentante EGEL Plus IQUIM

9 hours

Two sessions of 4.5 hours each on the same day

Ceneval, Guía para el sustentante EGEL Plus IQUIM

1000

Minimum Índice Ceneval for a Satisfactorio level in an area or section

Ceneval, Guía para el sustentante EGEL Plus IQUIM

1150

Minimum Índice Ceneval for a Sobresaliente level

Ceneval, Guía para el sustentante EGEL Plus IQUIM

MXN 1,885

Individual national Examen desde casa fee in 2026

Ceneval EGEL portal

Ceneval's EGEL Plus IQUIM is a 190-item, nine-hour Spanish exit exam: 130 disciplinary items in three areas plus 60 transversal language and communication items.

Sample EGEL Plus Ingeniería Química Practice Questions

Try these sample questions to review concepts for the EGEL Plus Ingeniería Química exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A continuous chemical process receives a fresh feed of 100 mol/h of compound A containing 2.0 mol% of an inert gaseous impurity I. The reactor achieves a single-pass conversion of 20% of A. Unreacted A and inert I from the reactor separator are recycled, but a purge stream containing 10.0 mol% of inert I is withdrawn to prevent accumulation. What is the required molar flow rate of the purge stream at steady state?
A.10.0 mol/h
B.20.0 mol/h
C.50.0 mol/h
D.2.0 mol/h
Explanation: At steady state, inerts cannot accumulate within the recycle loop, meaning the rate of inerts entering in the fresh feed must equal the rate of inerts leaving in the purge stream. The entering rate of inerts is 100 mol/h × 0.02 = 2.0 mol/h of I. Setting this equal to the purge flow rate multiplied by the purge mole fraction: F_purge × 0.10 = 2.0 mol/h, which yields F_purge = 2.0 / 0.10 = 20.0 mol/h.
2A fresh fruit juice stream of 1,000 kg/h containing 10.0 wt% soluble solids is concentrated using an evaporator. To preserve volatile aroma compounds, a bypass stream is split from the fresh juice before the evaporator and blended downstream with the evaporator discharge (which leaves at 58.0 wt% solids). If the final blended product must contain exactly 42.0 wt% solids, what is the required bypass flow rate?
A.761.9 kg/h
B.42.0 kg/h
C.79.4 kg/h
D.158.8 kg/h
Explanation: An overall solids balance gives: 1,000 kg/h × 0.10 = P × 0.42, yielding product flow rate P = 238.10 kg/h. At the mixing point, let B be the bypass flow rate (at 10 wt% solids) and C be the concentrated stream (at 58 wt% solids). The total mass balance is B + C = 238.10 kg/h, and the solids balance is 0.10·B + 0.58·C = 238.10 × 0.42 = 100 kg/h. Substituting C = 238.10 - B gives 0.10·B + 0.58·(238.10 - B) = 100, which simplifies to 138.10 - 0.48·B = 100, leading to B = 38.10 / 0.48 = 79.38 kg/h (approx. 79.4 kg/h).
3Propane (C3H8) is burned completely with 20.0% excess dry air in a process furnace according to the stoichiometry C3H8 + 5 O2 -> 3 CO2 + 4 H2O. Air consists of 21.0 mol% O2 and 79.0 mol% N2. What is the mole fraction of O2 in the dry flue gas leaving the stack?
A.3.76%
B.3.27%
C.2.07%
D.25.0%
Explanation: On a basis of 1.0 mol of C3H8 burned, stoichiometric O2 required is 5.0 mol. With 20% excess air, O2 fed = 5.0 × 1.20 = 6.0 mol, and N2 fed = 6.0 × (79/21) = 22.57 mol. Complete combustion consumes 5.0 mol O2 and produces 3.0 mol CO2 and 4.0 mol H2O. Excess unreacted O2 = 6.0 - 5.0 = 1.0 mol. The dry flue gas contains only CO2, unreacted O2, and inert N2 (water vapor is excluded): total dry moles = 3.0 (CO2) + 1.0 (O2) + 22.57 (N2) = 26.57 mol. The dry mole fraction of O2 is 1.0 / 26.57 = 0.0376 or 3.76%.
4A perfectly mixed holding tank initially contains 500 L of pure water. At time t = 0, a saline stream containing 0.20 kg/L of NaCl is fed to the tank at a volumetric flow rate of 10.0 L/min. Solution is simultaneously withdrawn from the tank at 10.0 L/min to maintain a constant liquid volume. Assuming constant liquid density, what is the salt concentration in the effluent stream after 50.0 minutes?
A.0.200 kg/L
B.0.074 kg/L
C.0.100 kg/L
D.0.126 kg/L
Explanation: The transient solute mass balance on the constant volume tank is V·(dC/dt) = Q·(C_in - C). Rearranging gives dC/dt + (Q/V)·C = (Q/V)·C_in, where the space time tau = V/Q = 500 L / 10 L/min = 50 min. The analytical solution for C(0) = 0 is C(t) = C_in·[1 - exp(-t/tau)]. At t = 50 min, t/tau = 1.0, so C(50) = 0.20·[1 - exp(-1.0)] = 0.20·[1 - 0.3679] = 0.20 × 0.6321 = 0.1264 kg/L (approx. 0.126 kg/L).
5A process heat exchanger heats 2,000 kg/h of liquid water (specific heat capacity Cp = 4.184 kJ/kg·K) from 20.0 °C to 80.0 °C using saturated steam at 150 °C. The steam condenses isothermally with a latent heat of condensation lambda = 2,114 kJ/kg without subcooling. Assuming negligible heat loss to the environment, what is the required steam consumption rate?
A.118.8 kg/h
B.237.5 kg/h
C.475.0 kg/h
D.222.5 kg/h
Explanation: The heat duty absorbed by the liquid water is Q_dot = m_water · Cp · (T_out - T_in) = 2,000 kg/h × 4.184 kJ/kg·K × (80.0 - 20.0) K = 502,080 kJ/h. Under adiabatic operation with saturated steam condensing completely without subcooling, Q_dot = m_steam · lambda. Therefore, m_steam = Q_dot / lambda = 502,080 kJ/h / 2,114 kJ/kg = 237.50 kg/h.
6Given the standard enthalpies of formation at 298 K: Delta_H_f°[CH4(g)] = -74.8 kJ/mol, Delta_H_f°[CO2(g)] = -393.5 kJ/mol, and Delta_H_f°[H2O(l)] = -285.8 kJ/mol, what is the standard higher heat of combustion (Delta_H_c°) for methane at 298 K?
A.-890.3 kJ/mol
B.-604.5 kJ/mol
C.-965.1 kJ/mol
D.-802.3 kJ/mol
Explanation: The combustion reaction is CH4(g) + 2 O2(g) -> CO2(g) + 2 H2O(l). By Hess's law, Delta_H_rxn° = sum(nu_p·Delta_H_f,products°) - sum(nu_r·Delta_H_f,reactants°). Because O2 is in its standard elemental state, its Delta_H_f° = 0. Therefore, Delta_H_c° = [(-393.5) + 2·(-285.8)] - [(-74.8)] = [-393.5 - 571.6] + 74.8 = -965.1 + 74.8 = -890.3 kJ/mol.
7A liquid mixture containing 40.0 mol% benzene (1) and 60.0 mol% toluene (2) is maintained in vapor-liquid equilibrium at 80.0 °C. At this temperature, the pure component vapor pressures are P1_sat = 101.3 kPa and P2_sat = 39.0 kPa. Assuming ideal solution behavior in both phases (Raoult's law), what is the total bubble point pressure and the equilibrium vapor mole fraction of benzene (y1)?
A.P = 70.15 kPa, y1 = 0.578
B.P = 140.3 kPa, y1 = 0.722
C.P = 63.92 kPa, y1 = 0.634
D.P = 63.92 kPa, y1 = 0.400
Explanation: According to Raoult's law, the bubble point pressure is P = x1·P1_sat + x2·P2_sat = (0.40 × 101.3 kPa) + (0.60 × 39.0 kPa) = 40.52 + 23.40 = 63.92 kPa. The vapor phase mole fraction of the more volatile component is y1 = (x1·P1_sat) / P = 40.52 / 63.92 = 0.6339 (approx. 0.634).
8In a non-ideal binary liquid mixture at 65 °C, component 1 has a liquid mole fraction x1 = 0.15 and a pure vapor pressure P1_sat = 60.0 kPa. Due to positive deviations from Raoult's law, its activity coefficient is gamma1 = 1.80. What is the equilibrium partial pressure of component 1 in the vapor phase, assuming ideal gas behavior for the vapor?
A.9.00 kPa
B.16.20 kPa
C.108.0 kPa
D.5.00 kPa
Explanation: According to the modified Raoult's law for real solutions at moderate pressures: P1 = y1·P = x1·gamma1·P1_sat. Substituting the values: P1 = 0.15 × 1.80 × 60.0 kPa = 16.20 kPa. The activity coefficient of 1.80 increases the volatility and partial pressure compared to an ideal solution (which would have yielded 9.00 kPa).
9In cubic equations of state such as van der Waals, Redlich-Kwong, and Peng-Robinson, what physical phenomena do the parameters 'a' and 'b' represent in the pressure explicit expression P = RT/(v - b) - a/(v^2 + ...)?
A.Parameter 'a' accounts for attractive intermolecular forces, while 'b' represents the co-volume of the molecules due to repulsive forces
B.Parameter 'a' represents molecular kinetic energy, while 'b' accounts for dipole orientation effects
C.Parameter 'a' is the critical compressibility factor, while 'b' is the acentric factor of Pitzer
D.Parameter 'a' accounts for molecular size (co-volume), while 'b' accounts for attractive London dispersion forces
Explanation: In cubic equations of state derived from van der Waals' hard-sphere perturbation theory, 'b' is the co-volume (effective volume occupied by molecules due to short-range repulsive steric forces, reducing free space to v - b), and 'a' quantifies the reduction in pressure caused by attractive long-range intermolecular forces (van der Waals attractions). In modern equations like Peng-Robinson, 'a' is temperature-dependent via the acentric factor.
10For the gas-phase chemical equilibrium reaction A(g) <=> 2 B(g) at 500 K, the standard Gibbs free energy change of reaction is Delta_G° = +5,762 J/mol. Taking the universal gas constant R = 8.314 J/mol·K, what is the thermodynamic equilibrium constant K_p at 500 K?
A.4.00
B.1.38
C.0.041
D.0.25
Explanation: The fundamental thermodynamic relation between standard Gibbs energy and equilibrium constant is Delta_G° = -R·T·ln(K_p). Rearranging: ln(K_p) = -Delta_G° / (R·T) = -5,762 J/mol / (8.314 J/mol·K × 500 K) = -5,762 / 4,157 = -1.3861. Taking the exponential: K_p = exp(-1.3861) = 0.250.

About the EGEL Plus Ingeniería Química Exam

Independent EGEL Plus Ingeniería Química practice by OpenExamPrep. The official Ceneval examination is in Spanish and has 190 three-option items: 130 disciplinary items in Análisis elemental y fenomenológico de procesos, Análisis y diseño de procesos de transformación básicos, and Diseño, optimización y control de procesos, and 60 transversal Lenguaje y Comunicación items. This bank is an English-language study adaptation with four-option multiple-choice questions, not an official translation or format simulation. Disciplinary stems and explanations are in English. Language and communication items keep their Spanish passages and answer options, because Spanish usage is the skill being tested, and give their instructions and explanations in English.

Exam sponsor: Centro Nacional de Evaluación para la Educación Superior (Ceneval). The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

190 three-option items: 130 disciplinary items (Análisis elemental y fenomenológico de procesos 50, Análisis y diseño de procesos de transformación básicos 50, Diseño, optimización y control de procesos 30) and 60 transversal items in Comprensión Lectora and Redacción Indirecta.

Time Limit

Two sessions of 4.5 hours each on the same day (9 hours in total)

Passing Score

Each area and each section is reported on the Índice Ceneval (700-1300): 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio, 1150-1300 Sobresaliente. The global result is weighted toward the disciplinary section: Satisfactorio or better there earns at least a Testimonio de Desempeño Satisfactorio, and a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación

Exam / Certification Fees

MXN 1,885 for the 2026 national Examen desde casa; institutional administrations may charge a different amount

Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Official sources

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

50 of 130 disciplinary items

Análisis elemental y fenomenológico de procesos

Thermodynamics, physical and chemical equilibrium, mass and energy balances, transfer mechanisms, and chemical kinetics and catalysis (10 items each)

50 of 130 disciplinary items

Análisis y diseño de procesos de transformación básicos

Momentum transfer processes (16), heat transfer processes (10), mass transfer processes (8), combined heat and mass transfer processes (9) and chemical reactors (7)

30 of 130 disciplinary items

Diseño, optimización y control de procesos

Process synthesis and optimization (17), and control and automation systems (13)

60 of 190 total items

Lenguaje y Comunicación

Reading comprehension of academic, literary and public-interest texts (30 items) and indirect writing, which asks candidates to choose the version of a text that is correct, coherent and well punctuated (30 items)

Preparing for the EGEL Plus Ingeniería Química Exam

What You Need to Know

  • Passing score: Each area and each section is reported on the Índice Ceneval (700-1300): 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio, 1150-1300 Sobresaliente. The global result is weighted toward the disciplinary section: Satisfactorio or better there earns at least a Testimonio de Desempeño Satisfactorio, and a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación
  • Assessment: 190 three-option items: 130 disciplinary items (Análisis elemental y fenomenológico de procesos 50, Análisis y diseño de procesos de transformación básicos 50, Diseño, optimización y control de procesos 30) and 60 transversal items in Comprensión Lectora and Redacción Indirecta.
  • Time limit: Two sessions of 4.5 hours each on the same day (9 hours in total)
  • Exam / certification fees: MXN 1,885 for the 2026 national Examen desde casa; institutional administrations may charge a different amount Official sources

Using Our Practice Resources

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

EGEL Plus Ingeniería Química: Suggested Study Strategy

1Practice material and energy balances with recycle, bypass and purge, and transient mixing; review phase and reaction equilibrium, fugacity and activity coefficients, and Arrhenius kinetics.
2Momentum transfer processes are the largest subarea (16 items): drill friction losses, pump power, NPSH and affinity laws.
3Review separation and heat transfer design: McCabe-Thiele, absorption NTU/HTU, extraction balances, drying times, evaporator economy, LMTD and fouling.
4Study process synthesis and control: pinch analysis targets and rules, P&ID symbols, FOPDT responses, PID tuning and feedforward control.
5Prepare for Lenguaje y Comunicación by reading academic articles, essays and public notices in Spanish, and by reviewing agreement, punctuation, accentuation and connectors.

Frequently Asked Questions

What is the EGEL Plus Ingeniería Química?

The EGEL Plus Ingeniería Química (EGEL Plus IQUIM) is Ceneval's national exit examination for graduates of the Licenciatura en Ingeniería Química and related programs. It measures the knowledge and skills considered indispensable at the end of the degree, plus Spanish reading comprehension and indirect writing. Institutions may use the result as a graduation requirement, a titulación option or part of a course grade, under their own rules; a Testimonio does not by itself determine the award of the degree or the cédula profesional.

How many questions are on the official EGEL Plus IQUIM and how long is it?

The official exam has 190 items: 130 disciplinary items (Análisis elemental y fenomenológico de procesos 50, Análisis y diseño de procesos de transformación básicos 50, Diseño, optimización y control de procesos 30) and 60 Lenguaje y Comunicación items (30 reading comprehension and 30 indirect writing). It is given on one day in two sessions of 4.5 hours each (9 hours). About 15% of the items are pilot items that do not count toward the result.

How is the EGEL Plus IQUIM scored?

Each area and section is reported on the Índice Ceneval from 700 to 1300: 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio and 1150-1300 Sobresaliente. The global result follows a conjunctive rule weighted toward the disciplinary section: Satisfactorio or better in the disciplinary section earns at least a Testimonio de Desempeño Satisfactorio, while a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación. Candidates with a global Sobresaliente who take the exam for the first time within one year of finishing the degree are eligible for the Premio Ceneval al Desempeño de Excelencia-EGEL.

Can I use a calculator or formula sheet on the EGEL Plus IQUIM?

Yes. The official guide allows a non-programmable scientific calculator, which may not be shared between candidates. Ceneval also provides a formulario (formula sheet), handed out on paper or shown on the exam platform depending on the modality, and publishes it on its EGEL portal so you can study with it in advance.

Why is this practice bank in English if the official exam is in Spanish?

The official Ceneval exam is in Spanish. This bank is an independent English-language study adaptation with four-option questions, not an official translation or format simulation. Disciplinary questions and explanations are in English so you can review the engineering content. Language and communication items keep their Spanish passages and options because they test Spanish usage, and their instructions and explanations are in English.

How does EGEL Plus Ingeniería Química differ from EGEL Plus Química?

They are separate Ceneval exams. Ingeniería Química is organized around process engineering: fundamentals and balances (50 items), the analysis and design of basic transformation processes such as fluid flow, heat and mass transfer and reactors (50 items), and process design, optimization and control (30 items).