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Key Facts: EGEL Plus Ingeniería Eléctrica Exam

200

Total items on the official EGEL Plus IELEC (140 disciplinary + 60 transversal)

Ceneval, Guía para el sustentante EGEL Plus IELEC

9 hours

Two sessions of 4.5 hours each on the same day

Ceneval, Guía para el sustentante EGEL Plus IELEC

1000

Minimum Índice Ceneval for a Satisfactorio level in an area or section

Ceneval, Guía para el sustentante EGEL Plus IELEC

1150

Minimum Índice Ceneval for a Sobresaliente level

Ceneval, Guía para el sustentante EGEL Plus IELEC

MXN 1,885

Individual national Examen desde casa fee in 2026

Ceneval EGEL portal

Ceneval's EGEL Plus IELEC is a 200-item, nine-hour Spanish exit exam: 140 disciplinary items in four areas plus 60 transversal language and communication items.

Sample EGEL Plus Ingeniería Eléctrica Practice Questions

Try these sample questions to review concepts for the EGEL Plus Ingeniería Eléctrica exam. Each question includes a detailed explanation. Start the interactive quiz above for the full 100+ question experience with AI tutoring.

1A three-phase power transformer has a nameplate rating of 50 MVA, 115 kV / 13.8 kV, with a leakage reactance of X = 0.10 pu on its own base. If the power system base is chosen as S_base,new = 100 MVA and V_base,new = 110 kV on the high-voltage side, what is the new per-unit reactance of the transformer?
A.0.2186 pu
B.0.1830 pu
C.0.0457 pu
D.0.0547 pu
Explanation: The formula for changing per-unit impedance base is Z_pu,new = Z_pu,old * (V_base,old / V_base,new)^2 * (S_base,new / S_base,old). Substituting the given values: X_new = 0.10 * (115 / 110)^2 * (100 / 50) = 0.10 * (1.04545)^2 * 2 = 0.10 * 1.0930 * 2 = 0.2186 pu. The impedance scales proportionally with MVA base and inversely with the square of the voltage base.
2In an unbalanced three-phase power circuit, the phase currents measured at a bus are Ia = 120∠0° A, Ib = 90∠-100° A, and Ic = 80∠110° A. What is the zero-sequence current component (Ia0) of this set of currents?
A.26.06∠-9.9° A
B.78.17∠-9.9° A
C.96.67∠0° A
D.0.0∠0° A
Explanation: The zero-sequence component is Ia0 = (1/3)(Ia + Ib + Ic). In rectangular form: Ia = 120 + j0 A; Ib = 90∠−100° = −15.63 − j88.63 A; Ic = 80∠110° = −27.36 + j75.18 A. The sum is 77.01 − j13.45 A = 78.17∠−9.9° A, so Ia0 = 78.17 / 3 ∠−9.9° ≈ 26.06∠−9.9° A. A non-zero zero-sequence current shows the unbalance produces a residual (neutral or ground) current of 3·Ia0.
3Before closing the breaker to synchronize a generator to an energized grid, which set of conditions must be satisfied between the generator and the bus?
A.Equal voltage magnitude, equal frequency, the same phase sequence, and voltages in phase (angle difference close to zero)
B.Generator voltage at least 10% above bus voltage and generator frequency exactly 2 Hz above grid frequency
C.Opposite phase sequence and a 180° phase difference so that the machines lock together
D.Only the frequency must match; voltage and phase angle are corrected automatically after closing
Explanation: Synchronizing requires the incoming machine's voltage magnitude, frequency, phase sequence, and phase angle to match the bus within tight limits; a synchroscope or synch-check relay (ANSI 25) supervises the closing. Closing with large voltage, frequency, or angle differences causes high circulating currents and mechanical torque shocks to the shaft and couplings.
4A 115 kV substation bus has a positive-sequence Thevenin impedance of Z1 = j0.05 pu on a 100 MVA, 115 kV base. Assuming a prefault voltage of Vf = 1.0 pu, what is the three-phase bolted short-circuit current (Isc) in symmetrical kiloamperes (kA)?
A.10.04 kA
B.17.39 kA
C.5.80 kA
D.20.00 kA
Explanation: First calculate the base current: I_base = S_base / (sqrt(3) * V_base) = 100 MVA / (sqrt(3) * 115 kV) = 100,000 / (1.73205 * 115) = 502.04 A = 0.502 kA. The per-unit fault current for a bolted three-phase fault is Isc,pu = Vf / Z1 = 1.0 / 0.05 = 20.0 pu. Multiplying by base current gives Isc = 20.0 * 0.50204 kA = 10.04 kA.
5For a single line-to-ground (SLG) fault on phase A through a fault impedance Zf, how are the positive-, negative-, and zero-sequence networks connected in the symmetrical component equivalent circuit?
A.All three sequence networks are connected in series with an impedance of 3*Zf
B.All three sequence networks are connected in parallel with an impedance of Zf
C.The positive and negative sequence networks are in parallel, and the zero sequence is open-circuited
D.The positive and negative sequence networks are in series, and the zero sequence is in parallel
Explanation: In a single line-to-ground (SLG) fault on phase A, boundary conditions dictate Ib = 0, Ic = 0, and Va = Ia * Zf. Because Ib = Ic = 0, the sequence currents are equal: Ia0 = Ia1 = Ia2 = (1/3)*Ia. Since the same current flows through all three sequence networks, they must be connected in series. The voltage sum is Va = Va0 + Va1 + Va2 = Ia * Zf = (3*Ia1)*Zf, which introduces the term 3*Zf in series with the loop.
6A line-to-line (L-L) bolted fault occurs between phases B and C of an unloaded synchronous generator. If Z1 = j0.15 pu, Z2 = j0.15 pu, Z0 = j0.08 pu, and prefault voltage is Vf = 1.0 pu, what is the magnitude of the subtransient fault current in phase B?
A.5.77 pu
B.3.33 pu
C.6.67 pu
D.2.63 pu
Explanation: For a bolted line-to-line fault between phases B and C, Ia1 = -Ia2 = Vf / (Z1 + Z2) = 1.0 / (j0.15 + j0.15) = 1.0 / j0.30 = -j3.333 pu, and Ia0 = 0. The phase B current is Ib = Ia0 + a^2*Ia1 + a*Ia2 = (a^2 - a)*Ia1 = -j*sqrt(3)*Ia1. Therefore, |Ib| = sqrt(3) * |Ia1| = 1.73205 * 3.333 pu = 5.77 pu.
7For an unloaded power system with sequence impedances Z1 = j0.20 pu, Z2 = j0.20 pu, and Z0 = j0.10 pu, a bolted double line-to-ground (DLG) fault occurs on phases B and C. What is the total fault current entering the ground (If = 3*Ia0)?
A.5.73 pu
B.3.75 pu
C.2.50 pu
D.7.50 pu
Explanation: For a DLG fault the three sequence networks are connected in parallel at the fault point. Z2 ∥ Z0 = (0.20 × 0.10) / 0.30 = 0.0667 pu, so Ia1 = 1.0 / (0.20 + 0.0667) = 3.75 pu. The positive-sequence voltage at the fault is Va1 = 1.0 − 3.75 × 0.20 = 0.25 pu, and Va0 = Va1, so |Ia0| = 0.25 / 0.10 = 2.50 pu. The current into ground is If = 3·|Ia0| = 7.50 pu.
8What is the zero-sequence equivalent circuit representation for a three-phase Delta-Wye transformer bank whose Wye winding has a solidly grounded neutral?
A.The secondary (Wye) terminal is connected to the reference bus through the leakage impedance, while the primary (Delta) terminal is open-circuited from the transmission line but shorted to reference on the transformer side
B.Both primary and secondary terminals are connected directly through the leakage impedance to the external network
C.Both primary and secondary terminals are completely open-circuited, blocking all zero-sequence currents
D.The Delta winding permits zero-sequence current to pass into the external line, but the grounded Wye winding blocks it
Explanation: In a Delta-Wye transformer with a solidly grounded neutral, zero-sequence current can flow into the grounded Wye winding from the secondary system and returns through ground. This induces circulating currents inside the closed Delta winding, which traps the zero sequence inside the Delta and prevents it from exiting into the primary external system. Therefore, the zero-sequence network shows the secondary connected to ground through the leakage impedance, while the line side of the Delta is open.
9A 1,000 kVA distribution transformer has a core (no-load) loss of 1.8 kW and a full-load copper loss of 7.2 kW. At what load does it operate at maximum efficiency?
A.250 kVA
B.500 kVA
C.1,000 kVA
D.2,000 kVA
Explanation: Efficiency is maximum when the variable copper loss equals the constant core loss: x² × P_cu,FL = P_core, so x = √(P_core / P_cu,FL) = √(1.8 / 7.2) = √0.25 = 0.5. The transformer therefore reaches maximum efficiency at 50% load, 0.5 × 1,000 kVA = 500 kVA, which is useful for deciding how many transformers to keep energized.
10A three-phase transposed transmission line has flat horizontal conductor spacing with distance D between adjacent conductors (D_ab = D, D_bc = D, D_ca = 2D). What is the Geometric Mean Distance (GMD) of this line configuration?
A.1.26 * D
B.1.00 * D
C.1.41 * D
D.2.00 * D
Explanation: The Geometric Mean Distance for a three-phase line is the cube root of the product of the three distances between phase conductors: GMD = (D_ab * D_bc * D_ca)^(1/3) = (D * D * 2D)^(1/3) = (2 * D^3)^(1/3) = 2^(1/3) * D ≈ 1.2599 * D ≈ 1.26 * D. This equivalent spacing is used directly in inductance and capacitance formulas.

About the EGEL Plus Ingeniería Eléctrica Exam

Independent EGEL Plus Ingeniería Eléctrica practice by OpenExamPrep. The official Ceneval examination is in Spanish and has 200 items, mostly three-option multiple choice: 140 disciplinary items in Diseño de equipos y sistemas eléctricos, Construcción de equipos y sistemas eléctricos, Operación de equipos y sistemas eléctricos, and Pruebas y mantenimiento de equipos y sistemas eléctricos, and 60 transversal Lenguaje y Comunicación items. This bank is an English-language study adaptation with four-option multiple-choice questions, not an official translation or format simulation. Disciplinary stems and explanations are in English. Language and communication items keep their Spanish passages and answer options, because Spanish usage is the skill being tested, and give their instructions and explanations in English.

Exam sponsor: Centro Nacional de Evaluación para la Educación Superior (Ceneval). The requirements and fees below concern the certification or admission exam, separate from our free practice resources.

Assessment

200 items, mostly three-option multiple choice: 140 disciplinary items (Diseño de equipos y sistemas eléctricos 36, Construcción de equipos y sistemas eléctricos 30, Operación de equipos y sistemas eléctricos 44, Pruebas y mantenimiento de equipos y sistemas eléctricos 30) and 60 transversal items in Comprensión Lectora and Redacción Indirecta.

Time Limit

Two sessions of 4.5 hours each on the same day (9 hours in total)

Passing Score

Each area and each section is reported on the Índice Ceneval (700-1300): 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio, 1150-1300 Sobresaliente. The global result is weighted toward the disciplinary section: Satisfactorio or better there earns at least a Testimonio de Desempeño Satisfactorio, and a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación

Exam / Certification Fees

MXN 1,885 for the 2026 national Examen desde casa; institutional administrations may charge a different amount

Exam sponsor website

Fees, eligibility, and exam policies can change. Confirm them with the exam sponsor before applying or paying.

Official sources

Our practice resources: topics covered

We aim to reflect publicly available exam outlines and topic information in our study resources. Coverage, format, and difficulty may differ from the actual exam, and we cannot guarantee that every detail is accurate or current. Confirm exam requirements, fees, and policies with the official exam sponsor.

36 of 140 disciplinary items

Diseño de equipos y sistemas eléctricos

Planning and projection (17), modeling and simulation (9), and design project development (10)

30 of 140 disciplinary items

Construcción de equipos y sistemas eléctricos

Construction planning (8), equipment, materials and components (12), and construction execution (10)

44 of 140 disciplinary items

Operación de equipos y sistemas eléctricos

Commissioning (8), operation analysis (15), operation optimization (13), and control, protection and measurement (8)

30 of 140 disciplinary items

Pruebas y mantenimiento de equipos y sistemas eléctricos

Measuring equipment and tests (17), and maintenance plans and programs (13)

60 of 200 total items

Lenguaje y Comunicación

Reading comprehension of academic, literary and public-interest texts (30 items) and indirect writing, which asks candidates to choose the version of a text that is correct, coherent and well punctuated (30 items)

Preparing for the EGEL Plus Ingeniería Eléctrica Exam

What You Need to Know

  • Passing score: Each area and each section is reported on the Índice Ceneval (700-1300): 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio, 1150-1300 Sobresaliente. The global result is weighted toward the disciplinary section: Satisfactorio or better there earns at least a Testimonio de Desempeño Satisfactorio, and a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación
  • Assessment: 200 items, mostly three-option multiple choice: 140 disciplinary items (Diseño de equipos y sistemas eléctricos 36, Construcción de equipos y sistemas eléctricos 30, Operación de equipos y sistemas eléctricos 44, Pruebas y mantenimiento de equipos y sistemas eléctricos 30) and 60 transversal items in Comprensión Lectora and Redacción Indirecta.
  • Time limit: Two sessions of 4.5 hours each on the same day (9 hours in total)
  • Exam / certification fees: MXN 1,885 for the 2026 national Examen desde casa; institutional administrations may charge a different amount Official sources

Using Our Practice Resources

  • Work through all 100 available questions
  • Review every answer and explanation
  • Track weak areas and revisit them
  • Use our AI tutor for tough concepts

EGEL Plus Ingeniería Eléctrica: Suggested Study Strategy

1Operation of electrical equipment and systems is the largest area (44 items): practice per-unit calculations, power flow, fault currents, power factor correction and transformer load sharing.
2Review installation design under NOM-001-SEDE-2012: continuous-load factors, ampacity adjustment, voltage drop, grounding conductors and motor branch-circuit protection. Ceneval publishes the NOM text with the formularios.
3Study protection and measurement: ANSI device numbers, overcurrent coordination, differential and distance relays, and CT saturation.
4Prepare for testing and maintenance: insulation resistance and polarization index, TTR, dissolved gas analysis, infrared thermography criteria, and condition-based maintenance programs.
5Prepare for Lenguaje y Comunicación by reading academic articles, essays and public notices in Spanish, and by reviewing agreement, punctuation, accentuation and connectors.

Frequently Asked Questions

What is the EGEL Plus Ingeniería Eléctrica?

The EGEL Plus Ingeniería Eléctrica (EGEL Plus IELEC) is Ceneval's national exit examination for graduates of the Licenciatura en Ingeniería Eléctrica and related programs. It measures the knowledge and skills considered indispensable at the end of the degree, plus Spanish reading comprehension and indirect writing. Institutions may use the result as a graduation requirement, a titulación option or part of a course grade, under their own rules; a Testimonio does not by itself determine the award of the degree or the cédula profesional.

How many questions are on the official EGEL Plus IELEC and how long is it?

The official exam has 200 items: 140 disciplinary items (Diseño de equipos y sistemas eléctricos 36, Construcción de equipos y sistemas eléctricos 30, Operación de equipos y sistemas eléctricos 44, Pruebas y mantenimiento de equipos y sistemas eléctricos 30) and 60 Lenguaje y Comunicación items (30 reading comprehension and 30 indirect writing). It is given on one day in two sessions of 4.5 hours each (9 hours). About 15% of the items are pilot items that do not count toward the result.

How is the EGEL Plus IELEC scored?

Each area and section is reported on the Índice Ceneval from 700 to 1300: 700-999 Aún no satisfactorio, 1000-1149 Satisfactorio and 1150-1300 Sobresaliente. The global result follows a conjunctive rule weighted toward the disciplinary section: Satisfactorio or better in the disciplinary section earns at least a Testimonio de Desempeño Satisfactorio, while a Testimonio de Desempeño Sobresaliente requires Sobresaliente in the disciplinary section and at least Satisfactorio in Lenguaje y Comunicación. Candidates with a global Sobresaliente who take the exam for the first time within one year of finishing the degree are eligible for the Premio Ceneval al Desempeño de Excelencia-EGEL.

Can I use a calculator or formula sheet on the EGEL Plus IELEC?

Yes. The official guide allows a non-programmable scientific calculator, which may not be shared between candidates, and a formulario (formula sheet) is available on the exam platform. Ceneval publishes the formulario on its EGEL portal, so you can study with it in advance.

Why is this practice bank in English if the official exam is in Spanish?

The official Ceneval exam is in Spanish. This bank is an independent English-language study adaptation with four-option questions, not an official translation or format simulation. Disciplinary questions and explanations are in English so you can review the engineering content. Language and communication items keep their Spanish passages and options because they test Spanish usage, and their instructions and explanations are in English.

What reference material does Ceneval provide for this exam?

Ceneval publishes a formulario for EGEL Plus IELEC and, alongside it on the EGEL portal, the text of NOM-001-SEDE-2012 (Instalaciones eléctricas, utilización). The exam is taken online, and the formulario is available on the exam platform.